I want a sql query to fetch invalid entries in ph_no such as entries which has text(a-z) or special characters or which are not 10 digit long or entries which are 10 digit long but has special character or text in it
I have used the following code
SELECT PH_NO FROM Table WHERE LENGTH(PH_NO)<=9
It is only fetching entries which are not 10 digit long but i want entries which are 10 digit long but contains text or special character as well
You can try using regular expresion in your where clause, you get when PH_NO length is less than 10, or when the length is 10 and is not in the regular expresion:
SELECT PH_NO
FROM table1
WHERE LENGTH(PH_NO)<=9 OR
(LENGTH(PH_NO)=10 AND PH_NO NOT REGEXP '^[[:digit:]]{10}$')
This query will help you achieving the specifics given by you
SELECT PH_NO FROM Table WHERE LENGTH(convert(PH_NO,signed))!=10;
The conver() will return 1 or 0 if PH_NO contains any character, so if your 10 digit PH_NO will contain any invalid entry than this query will give the right output.
Related
this is row in option column in table oc_cart
20,228,27,229
why no result found when value is 228 but result found when value is 20 like below :
select 1 from dual
where 228 in (select option as option from oc_cart)
and result found when I change value to 20 like
select 1 from dual
where 20 in (select option as option from oc_cart)
The option column data type is TEXT
In SQL, these two expressions are different:
WHERE 228 in ('20,228,27,229')
WHERE 228 in ('20','228','27','229')
The first example compares the integer 228 to a single string value, whose leading numeric characters can be converted to the integer 20. That's what happens. 228 is compared to 20, and fails.
The second example compares the integer 228 to a list of four values, each can be converted to different integers, and 228 matches the second integer 228.
Your subquery is returning a single string, not a list of values. If your oc_cart.option holds a single string, you can't use the IN( ) predicate in the way you're doing.
A workaround is this:
WHERE FIND_IN_SET(228, (SELECT option FROM oc_cart WHERE...))
But this is awkward. You really should not be storing strings of comma-separated numbers if you want to search for an individual number in the string. See my answer to Is storing a delimited list in a database column really that bad?
I have a csv file that contains phone numbers, some of them have 9 digits and some of them have 10. Is there a command that would allow the transformation of the column such that numbers that have only 9 digits will have a 0 appended in front of the numbers.
For example,
if the column has values "443332332" and "0441223332", I would like to have the value of the one with 9 digits changed to "0443332332"?
Sorry, I should have elaborated.
I was wondering if there was a command to do it in SQLlite easily? I prefer not to use excel to transform the column as if I can get it to working with sqllite it would be so much easier and faster.
A more generic solution would be:
select substr('0000000000'||'1234567', -10, 10) from table_name;
The above query would always return 10 digits and add leading zeroes to the missed out number of digits.
For example, the above query would return : 0001234567
For Update, use
UPDATE TABLE_NAME SET PHONE_NO = substr('0000000000'|| PHONE_NO, -10, 10);
If you're sure that just prepending a zero on strings with length 9 will work for your application, something simple will work:
SELECT CASE WHEN LENGTH(phone_number) = 9 THEN '0'||phone_number
ELSE phone_number
END AS phone_number
FROM your_table
;
You could also update the table, depending on your needs:
UPDATE your_table
SET phone_number = '0'||phone_number
WHERE LENGTH(phone_number) = 9
;
Open the .csv using Excel,
Add a filter to the column,
Sort from A-Z to get all the columns with 9 digits,
Then follow the steps here
http://office.microsoft.com/en-au/excel-help/keep-leading-zeros-in-number-codes-HA010342581.aspx
I'm working with 2 sets of data that were merged together, but they're inconsistent in their format. Some are 10 characters, all numbers. Others may have a separator : at position 4. I need to substring the first 4 characters. But if the 4th character is a : substring only the first 3 characters.
Does mysql have an IF functionality to determine the number of characters to substring based on the character in position 4?
select substring(id, 1 , 3/4) from table1
You can treat the field like it's colon separated and do this to select only the first part:
SELECT SUBSTRING_INDEX(id, ':', 1)
See also: SUBSTRING_INDEX()
I have a varchar column that I am currently sorting by using: ORDER BY (col_name+0)
This column contains both digits and non-digits, and the result of this sorting is this:
D3
D111
M123-M124
M136
4
9
10
25
37b
132
147-149
168b
168ca
This sorting is almost perfect for our application, but with one exception: we want the items that start with letters to display after those that start with numbers. This being the ideal result:
4
9
10
25
37b
132
147-149
168b
168ca
D3
D111
M123-M124
M136
I'm hoping this can be achieved in the select statement, rather than needing to loop through everything in code again after the select. Any ideas?
You can use this:
ORDER BY
col_name regexp "^[^0-9]",
case when col_name regexp "^[0-9]" then col_name + 0
else mid(col_name, 2, length(col_name )-1) + 0 end,
col_name
this will put rows that begins with a digit at the top. If col_name begins with a digit, I'm sorting by it's numeric value, if not I'm sorting by the numeric value of the string beginning at the second character.
I'm trying to select a small set of records that match a patten I have a series of numbers in each row such as
1
2
3
some of them have sub numbers
3.1
3.2
4
5
I can select only the whole numbers using
REGEXP '^[0-9]+$'
I can select all rows that have a . in them like 3.1 3.2 etc using
REGEXP '[.]{1}'
but I can't seem to select for example only sub numbers that start with 3 I've tried
REGEXP '[^3.]{1,}'
but that returns all records
Ideally I want to return only records that are in the format of 3.1 I would like to define the start number and the dot so 3. then the second part match against the records
I hope this makes sense
I used '3\.[0-9]{1,}' - it matched.
Yours probably fails because of unescaped dot - ., which matches every character.
Escape characters with \
Format 3.d where d is digit:
3\\.[0-9]