Hi I am working on a Angular4 application and for UI I am using Primeng.
I have a multi-select element which behaves pretty much the same as it does over here https://www.primefaces.org/primeng/#/multiselect
The only thing I want different is on the drop-down, when "X" (close) button is clicked, I want it to clear all the selection instead of closing the drop-down itself.
Is there any way to achieve that in primeng ?
Help is appreciated !
You can manually trigger the checkbox in the left by jquery.
declare var jquery:any;
declare var $ :any;
$('.ui-chkbox-box.ui-widget.ui-corner-all.ui-state-default').trigger('click')
or you make the value of the p-multiselect equal to [].
Ex.
//html
<p-multiSelect #multiselect>
<button type="button" (click)="functionToClear(multiselect)"</button>
</p-multiselect>
//ts
functionToClear(multiselect): void {
multiselect.value = [];
}
It isn't possible, but you can clear all the selection by clicking the checkbox in the left corner twice.
While it isn't a supported functionality of the Multiselect PrimeNg component, if you really want it to do that, you would have to manually edit the component, multiselect.js, and modify the close(event) function to do what you want.
you can use formGroup and try to clear value following way:
html:
<ng-multiselect-dropdown [(ngModel)]="data"
[data]="fetchedData" [settings]="customeSettings"
formControlName="myControl">
</ng-multiselect-dropdown>
.ts:
this.form_name.controls.myControl.setValue("");
normally the multi-select input in primeng is binded to a property that holds the selected members, usually an array.
you can use a reset button for example that when clicked, it will empty that propery/array and this will clear all the selected check boxes of the multi-select.
Since PrimeNg version 13, you can use [showClear]="true" property to display an 'X' icon next to the control value.
Related
Can someone help me out here on how to add passengers count dropdown form like on the image below. i have been searching all over but cannot seem to find any demo or help.
thanks for your help
This is a solution using pure HTML, CSS, and jQuery. For a Bootstrap-specific answer, How use input field as toggle for bootstrap 4 dropdown may help.
Moving on.
You should create a normal number type form and add a disabled attribute in the input tag so that no cursor appears when you click the form (<input type="number" disabled>). Then, just create a dropdown menu (probably a <div> with an absolute position right under the input) with a classname of your choice (assuming in this answer that you choose .passengerInput as the classname).
You can hide the dropdown by default using the $(".passengerInputDropdown").hide() method in the body of your JS.
Then, when you click the form, using the $(".passengerInput").toggle() method, do something to the effect of:
$(".passengerInput").on("click", () => {
$(".passengerInputDropdown").toggle();
})
Let me know if this helps!
Here is the link for an example of the issue I will attempt to describe. In the chips autocomplete example, click the text box to select a new fruit.
Now, before clicking anywhere else, click again on the text box as you did before.
This should result in no options showing up. The issue here is that the user must either begin keying in a new selection or first click another element in the window before matchip will show the options to choose from. I am wondering if there is a way to fix this issue. I would like a user to be able to choose a selection from the list and then immediately click the text box as they had before and make a new selection.
I'm using mat-chip-list inside an outer *ngFor iterating over a FormArray.
Here is what I'have done. It's pretty efficient :
<input
#validatorInput
#operationTrigger="matAutocompleteTrigger"
[formControl]="contactCtrl"
[matAutocomplete]="auto"
[matChipInputFor]="chipList"
(blur)="contactCtrl.setValue(''); validatorInput.value='';"
(click)="contactCtrl.setValue(''); validatorInput.value=''; operationTrigger.openPanel()">
The trick is
Always clear your html input and your (shared) formControl with an empty and not null value each time the blur and click events occur.
Do NOT do this 'clear' on the input focus event. (Because when you delete the last chip, the input is auto-focus and you will have the famous Expression has changed after it was checked.
Call operationTrigger.openPanel(); when the user click on the input
Setting contactCtrl.setValue(''); allows your autocomplete panel to be automatically opened when you call operationTrigger.openPanel()
Setting validatorInput.value=''; is just a way to properly sync your formControl with the html input to ensure a good UX/UI behavior.
Inside my formArray, the formControl is the same for all the inputs but it does not matter since the user can only manipulate one input at a given time
Since you didn't post your code and you mention the example on the material site I'm going to do it as a fork of the stackblitz example they have on their site.
But this will allow you to open the autocomplete panel again despite having had the cursor there and choosing an option previously.
// Using MatAutocompleteTrigger will give you access to the API that will allow you to
// to open the panel or keep it open
...
#ViewChild(MatAutocompleteTrigger, {static: false}) trigger: MatAutocompleteTrigger;
...
ngAfterViewInit() {
fromEvent(this.fruitInput.nativeElement, 'click')
.pipe(
tap(() => {
this.trigger.openPanel()
})
).subscribe()
}
Link to the full stackblitz:
https://stackblitz.com/edit/angular-sb38ig
I have a input field which I set focus to when my view loads in the following way:
ngAfterViewInit() {
this.focusInput.nativeElement.focus();
}
this works fine from within the ngAfterViewInit() function but when I try to do it in another part of my view when a button is clicked I get an exception saying that focusInput is undefined. After reading up a bit it seems like ngIf could be the cause of this as the part of the view that contains the input field #focusInput gets shown or hidden using ngIf. Is there any way I can check using ngOnChanges() or anything else whether the #focusInput input field is currently shown and if it is set focus to it?
It happens when you have ngIf or ngFor directives inside your template and your input can not be linked to focusInput property you added inside your class. Instead use this code:
<input type="text" #myInput />
{{ myInput.focus() }}
Just add {{ myInput.focus() }} right after input inside template
The simplest solution turned out to be writing a custom focus attribute directive. This helped a lot:
How to move focus on form elements the Angular way
I know its very late to answer your question. If you want focus after any click or view change so for this you need to call change detector.
You can call change detection after your view change or a click by calling detectchanges().
`constructor(private detRef:ChangeDetectorRef) {}
#ViewChild('name_input') input: ElementRef;
private buttonClick(): void {
this.detRef.detectChanges();
this.input.nativeElement.focus();
}`
Hope this will helpful.
I created a button
<button type="button" ng-click="chooseOptions()" id="chooseOptionButton" ng-bind="whatToDisplay()"></button>
Which shows a <div ng-show=appearOnChoice>on click and toggles back when clicking again!
$scope.chooseOptions=function(){
$scope.appearOnChoice=!$scope.appearOnChoice;
}
However, I also want this element to hide again, when the user clicks anywhere outside this div
element. How can I do this? I need strictly stick with AngularJS and not use jQuery.
Hope you can help me with that.
EDIT: I tried to adapt some of the events of bootstrap datepicker, but I am not sure how to apply it properly
$scope.$on('datepicker.focus', focusElement);
scope.$watch('isOpen', function(value) {
if (value) {
scope.$broadcast('datepicker.focus');
scope.position = appendToBody ? $position.offset(element) : $position.position(element);
scope.position.top = scope.position.top + element.prop('offsetHeight');
$document.bind('click', documentClickBind);
} else {
$document.unbind('click', documentClickBind);
}
});
var focusElement = function() {
$timeout(function() {
self.element[0].focus();
}, 0 , false);
};
How can I adapt this to my case?!
I think that you dont have to write a function, you can use ng-init to create a model, ng-show to show/hide the div based on the value of the model, and with ng-click change the value of the model. See example below:
var myapp = angular.module('myapp',[]);
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="myapp">
<div ng-init="showDiv = true;" >
<div ng-show="showDiv"> SHOOOOOOOOW </div>
<button ng-click="showDiv = !showDiv;">Click me</button>
</div>
</div>
You can set the model value to be false when the user is clicking everywhere else, and set it again to true when it clicks the button. If you made a fiddle I can help you easier :)
If the DIV has focus, then you can use the ng-blur directive on the DIV to run set appearOnChoice to false. However, if the DIV does not already have focus (which it won't if you are depending on the button to make it visible), you will need to manipulate the DOM in your code (to provide focus) OR create a custom directive to set focus so that the ng-blur directive will work. Check out possibilities for that with this link.
alternatively, you can add an ng-click directive to every clickable object on your view that will hide the DIV when fired. But I don't really think that's the best way to go...
The easiest and cleanest way to handle the click away is to register and event on the document that will remove the element when anything other than it, or its children, are clicked.
For an example of a service that does this see GitHub EnzeyNet/Services
Sorry about the lack of documentation there but after injecting the service you would use it like this.
var divElem
nzService.registerClickAwayAction(function() {
divElem.remove();
}, divElem);
I simply solved it by using a ui bootstrap dropdown. This comes along with an is-open option and closes on click outside.
Link to form
The form can be found at the link above.
Up until this morning the radio buttons and the form had been working as expected, however now users can't change their answer once they've picked from one of the two radio buttons even though they use the same input name. Using $("#volunteer-form input:radio[name='gender']:checked").val() I've found that the value is being correctly set and that the two buttons are still linked by a common name. Also, it appears possible to switch between the two using a bit of jQuery, like so:
$("#volunteer-form input[name=gender][value=male]").prop('checked', true);
Any ideas?
its because of your javascript block here:
$(document).ready(function() {
$('.inline').fancybox({
'maxWidth': 600
});
$('.form').click(function(event){
event.preventDefault();
});
});
when you are clicking on the radio button inside the form your preventDefault is stopping the change of radiobutton state ... or maybe you already knew that.
What is the intended purpose of including the preventDefault where you have it?