Trying to scrape the image source using Beautiful Soup and Python [duplicate] - html

Question

I am trying to extract the content of a single "value" attribute in a specific "input" tag on a webpage. I use the following code:
import urllib
f = urllib.urlopen("http://58.68.130.147")
s = f.read()
f.close()
from BeautifulSoup import BeautifulStoneSoup
soup = BeautifulStoneSoup(s)
inputTag = soup.findAll(attrs={"name" : "stainfo"})
output = inputTag['value']
print str(output)
I get TypeError: list indices must be integers, not str
Even though, from the Beautifulsoup documentation, I understand that strings should not be a problem here... but I am no specialist, and I may have misunderstood.
Any suggestion is greatly appreciated!

Answer 1

.find_all() returns list of all found elements, so:
input_tag = soup.find_all(attrs={"name" : "stainfo"})
input_tag is a list (probably containing only one element). Depending on what you want exactly you either should do:
output = input_tag[0]['value']
or use .find() method which returns only one (first) found element:
input_tag = soup.find(attrs={"name": "stainfo"})
output = input_tag['value']

Answer 2

In Python 3.x, simply use get(attr_name) on your tag object that you get using find_all:
xmlData = None
with open('conf//test1.xml', 'r') as xmlFile:
xmlData = xmlFile.read()
xmlDecoded = xmlData
xmlSoup = BeautifulSoup(xmlData, 'html.parser')
repElemList = xmlSoup.find_all('repeatingelement')
for repElem in repElemList:
print("Processing repElem...")
repElemID = repElem.get('id')
repElemName = repElem.get('name')
print("Attribute id = %s" % repElemID)
print("Attribute name = %s" % repElemName)
against XML file conf//test1.xml that looks like:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<root>
<singleElement>
<subElementX>XYZ</subElementX>
</singleElement>
<repeatingElement id="11" name="Joe"/>
<repeatingElement id="12" name="Mary"/>
</root>
prints:
Processing repElem...
Attribute id = 11
Attribute name = Joe
Processing repElem...
Attribute id = 12
Attribute name = Mary

Answer 3

For me:
<input id="color" value="Blue"/>
This can be fetched by below snippet.
page = requests.get("https://www.abcd.com")
soup = BeautifulSoup(page.content, 'html.parser')
colorName = soup.find(id='color')
print(colorName['value'])

Answer 4

If you want to retrieve multiple values of attributes from the source above, you can use findAll and a list comprehension to get everything you need:
import urllib
f = urllib.urlopen("http://58.68.130.147")
s = f.read()
f.close()
from BeautifulSoup import BeautifulStoneSoup
soup = BeautifulStoneSoup(s)
inputTags = soup.findAll(attrs={"name" : "stainfo"})
### You may be able to do findAll("input", attrs={"name" : "stainfo"})
output = [x["stainfo"] for x in inputTags]
print output
### This will print a list of the values.

Answer 5

I would actually suggest you a time saving way to go with this assuming that you know what kind of tags have those attributes.
suppose say a tag xyz has that attritube named "staininfo"..
full_tag = soup.findAll("xyz")
And i wan't you to understand that full_tag is a list
for each_tag in full_tag:
staininfo_attrb_value = each_tag["staininfo"]
print staininfo_attrb_value
Thus you can get all the attrb values of staininfo for all the tags xyz

Answer 6

you can also use this :
import requests
from bs4 import BeautifulSoup
import csv
url = "http://58.68.130.147/"
r = requests.get(url)
data = r.text
soup = BeautifulSoup(data, "html.parser")
get_details = soup.find_all("input", attrs={"name":"stainfo"})
for val in get_details:
get_val = val["value"]
print(get_val)

Answer 7

You could try to use the new powerful package called requests_html:
from requests_html import HTMLSession
session = HTMLSession()
r = session.get("https://www.bbc.co.uk/news/technology-54448223")
date = r.html.find('time', first = True) # finding a "tag" called "time"
print(date) # you will have: <Element 'time' datetime='2020-10-07T11:41:22.000Z'>
# To get the text inside the "datetime" attribute use:
print(date.attrs['datetime']) # you will get '2020-10-07T11:41:22.000Z'

Answer 8

I am using this with Beautifulsoup 4.8.1 to get the value of all class attributes of certain elements:
from bs4 import BeautifulSoup
html = "<td class='val1'/><td col='1'/><td class='val2' />"
bsoup = BeautifulSoup(html, 'html.parser')
for td in bsoup.find_all('td'):
if td.has_attr('class'):
print(td['class'][0])
Its important to note that the attribute key retrieves a list even when the attribute has only a single value.

Answer 9

Here is an example for how to extract the href attrbiutes of all a tags:
import requests as rq
from bs4 import BeautifulSoup as bs
url = "http://www.cde.ca.gov/ds/sp/ai/"
page = rq.get(url)
html = bs(page.text, 'lxml')
hrefs = html.find_all("a")
all_hrefs = []
for href in hrefs:
# print(href.get("href"))
links = href.get("href")
all_hrefs.append(links)
print(all_hrefs)

Answer 10

You can try gazpacho:
Install it using pip install gazpacho
Get the HTML and make the Soup using:
from gazpacho import get, Soup
soup = Soup(get("http://ip.add.ress.here/")) # get directly returns the html
inputs = soup.find('input', attrs={'name': 'stainfo'}) # Find all the input tags
if inputs:
if type(inputs) is list:
for input in inputs:
print(input.attr.get('value'))
else:
print(inputs.attr.get('value'))
else:
print('No <input> tag found with the attribute name="stainfo")