Here is the sql that I am trying to insert and I get a error.
insert into instruments (symbol,exchange,FullName,IPOYear,Sector,Industry)
values('PIH','Nasdaq','1347 Property Insurance Holdings, Inc.','Finance','Property-Casualty Insurers','http://www.nasdaq.com/symbol/pih')
here is my ddl and I don't find anything wrong with my sql.
CREATE TABLE `instruments` (
`id` INT(10) NOT NULL AUTO_INCREMENT,
`symbol` VARCHAR(100) NOT NULL,
`exchange` VARCHAR(50) NOT NULL,
`FullName` VARCHAR(100) NULL DEFAULT NULL,
`IPOYear` VARCHAR(10) NULL DEFAULT NULL,
`Sector` VARCHAR(20) NULL DEFAULT NULL,
`Industry` VARCHAR(100) NULL DEFAULT NULL,
`LastUpdated` DATETIME NULL DEFAULT NULL,
PRIMARY KEY (`id`)
Sector VARCHAR(20) NULL DEFAULT NULL
You limited Sector to 20 characters and inserted 26.
Make it like this Sector VARCHAR(30) NULL DEFAULT NULL and it should work
Related
I'm struggling to code this table as it's giving me a #1064 error, and this corresponds to a few potential issues. If someone could point out where I've made a mistake that would be great.
Here is an image of the code I've typed, and the error I've received:
The code:
CREATE TABLE `RENRMyLUoX`.`movie`(
`mID` INT(20) NOT NULL,
`title` VARCHAR(50) NULL DEFAULT NULL,
`relYear` YEAR(4) NULL DEFAULT NULL,
`category` VARCHAR(50) NULL DEFAULT NULL,
`runTime` INT(20) NOT NULL,
`studioName` VARCHAR(50) NULL DEFAULT NULL,
`description` VARCHAR(50) NULL DEFAULT NULL,
`rating` DOUBLE(20) NULL DEFAULT NULL,
PRIMARY KEY(`mID`(20))
) ENGINE = InnoDB CHARSET = latin1 COLLATE latin1_bin;
The DOUBLE datatype should be specified as either DOUBLE or DOUBLE(m, d). I don't understand what (20) is supposed to do... you can simply omit it:
rating DOUBLE NULL DEFAULT NULL,
TRY BELOW CODE
CREATE TABLE RENRMyLUoX.movie(
mID INT(20) NOT NULL,
title VARCHAR(50) NULL DEFAULT NULL,
relYear YEAR(4) NULL DEFAULT NULL,
category VARCHAR(50) NULL DEFAULT NULL,
runTime INT(20) NOT NULL,
studioName VARCHAR(50) NULL DEFAULT NULL,
description VARCHAR(50) NULL DEFAULT NULL,
rating DOUBLE(20) NULL DEFAULT NULL)ENGINE = InnoDB CHARSET = latin1 COLLATE latin1_bin;
ALTER TABLE RENRMyLUoX.movie
ADD PRIMARY KEY (mID)
ALTER TABLE RENRMyLUoX.movie
MODIFY mID int(20) NOT NULL AUTO_INCREMENT;
COMMIT;
Trying to set up a user profile page for a job site. The database I plan to use is the MySQL database.
Looking into a few database design I came up with this schema.
First, the user management tables
CREATE TABLE `user` (
`user_id` int(11) NOT NULL,
`firstname` varchar(32) NOT NULL,
`lastname` varchar(32) NOT NULL,
`email` varchar(96) NOT NULL,
`mobile_number` varchar(32) NOT NULL,
`password` varchar(40) NOT NULL,
`salt` varchar(9) NOT NULL,
`address_id` int(11) NOT NULL DEFAULT '0',
`ip` varchar(40) NOT NULL,
`status` tinyint(1) NOT NULL,
`approved` tinyint(1) NOT NULL,
`registration_date` datetime NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
CREATE TABLE `user_address` (
`user_id` int(11) NOT NULL,
`city` varchar(128) NOT NULL
`work_city` varchar(128) NOT NULL,
`postal_code` varchar(10) NOT NULL,
`country_id` int(11) NOT NULL DEFAULT '0'
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
CREATE TABLE `user_description` (
`user_id` int(11) NOT NULL,
`description` text NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
and then the education table and work experience
CREATE TABLE `education_detail` (
`user_id` int(11) NOT NULL,
`certificate_degree_name` varchar(255) DEFAULT NULL,
`major` varchar(255) DEFAULT NULL,
`institute_university_name` varchar(255) DEFAULT NULL,
`start_date` date NOT NULL DEFAULT '0000-00-00',
`completion_date` date NOT NULL DEFAULT '0000-00-00'
)
CREATE TABLE `experience_detail` (
`user_id` int(11) NOT NULL,
`is_current_job` int(2) DEFAULT NULL,
`start_date` date NOT NULL DEFAULT '0000-00-00',
`end_date` date NOT NULL DEFAULT '0000-00-00',
`job_title` varchar(255) DEFAULT NULL,
`company_name` varchar(255) DEFAULT NULL,
`job_location_city` varchar(255) DEFAULT NULL,
`job_location_state` varchar(255) DEFAULT NULL,
`job_location_country` varchar(255) DEFAULT NULL,
`job_description` varchar(255) DEFAULT NULL
)
Note that user_id in table user_address, user_description, education_detail and experience_detail is a foreign key referencing it to the table user.
There are a few more table like skills, certification etc to which I plan on using user_id as a FK.
My question, is this database design good enough? Can you suggest me what should be done more to make the design much better?
Keep in mind not all will have work experience, some may be freshers.
Use InnoDB, not MyISAM. (There are many Q&A explaining 'why'.)
NULL or an empty string is perfectly fine for a missing description. Do you have any further argument for disliking such? (Meanwhile, InnoDB is more efficient at handling optional big strings.)
Every table should have a PRIMARY KEY; you don't seem to have any. The first table probably needs user_id as the PK. Read about AUTO_INCREMENT.
As with description, why is address in a separate table?
May I suggest this for country name/code/id:
country_code CHAR(2) CHARACTER SET ascii
Education is 1:many from users, so user_id cannot be the PK. Ditto for jobs.
I stumbled upon weird behavior in MySQL.
Lets say that I have only one record in table
| id | oib |
|----|-----|
| 1 | 5 |
Field oib is unique.
INSERT INTO `test` (`id`, `oib`) VALUES (NULL, '6')
I get following exception
Duplicate entry '5' for key 'oib_UNIQUE'
And this keeps going on no matter what value I try to save.
Anyone have idea what could cause this. I've never seen it.
UPDATE:
Here is CREATE TABLE statement:
CREATE TABLE IF NOT EXISTS `user` (
`id` int(25) NOT NULL AUTO_INCREMENT,
`email` varchar(45) DEFAULT NULL,
`password` varchar(255) DEFAULT NULL,
`first_name` varchar(45) DEFAULT NULL,
`last_name` varchar(45) DEFAULT NULL,
`dob` int(25) DEFAULT NULL,
`address` varchar(255) DEFAULT NULL,
`zip` int(6) DEFAULT NULL,
`oib` int(11) DEFAULT NULL,
`position` tinyint(4) DEFAULT NULL,
`role` varchar(45) DEFAULT NULL,
`status` tinyint(4) DEFAULT NULL,
`note` mediumtext,
PRIMARY KEY (`id`),
UNIQUE KEY `email_UNIQUE` (`email`),
UNIQUE KEY `oib_UNIQUE` (`oib`)
)
You cannot insert null value in id primary key
Are you sure your table have one record for oib = '5' ?
You cannot insert null into primary key.
I need to search records in the table which contains millions of records. I have recently updated Mysql version from 5.1 to 5.6.
I was using like in query which was taking around 15 sec to 30 sec.
Currently I have modified query to use MATCH... AGAINST feature of mysql 5.6 INNODB. My query goes like this.
SELECT JOB.IDJOB, JOB.IDEMPLOYER .....
FROM JOB
WHERE ( ( JOB.ITJOBSTARTTYPE=2 AND JOB.DTPLANNEDEND >= '2015-07-06' )
OR ( JOB.ITJOBSTARTTYPE=1
AND ( ( JOB.ITJOBENDTYPE=2 ) OR ( JOB.DTJOBEND>='2015-07-06') )
)
OR ( JOB.ITJOBSTARTTYPE=3
AND ( (JOB.DTJOBEND >='2015-07-06') OR (JOB.ITJOBENDTYPE=2) )
)
)
AND MATCH(VCJOBTITLE, LVJOBCOMPANYDESCRIPTION, VCCOMPANYNAME,
VCSALARYDESC, VCCITY, VCQUALIFICATIONREQUIRED,VCJOBREFERENCE,
LVJOBKEYWORDS )
AGAINST ('test' IN NATURAL LANGUAGE MODE)
ORDER BY JOB.ITJOBBAND ASC,
JOB.VCRANKING DESC,
JOB.IDJOB DESC,
JOB.FJOBWEIGHT ASC
LIMIT 50;
Which takes 80- 120 seconds (3X slower )
If I remove ORDER BY it will load in 6 to 10 sec.
Is their any setting Or performance tunning we can apply here?
Edit: using show create table JOB;
CREATE TABLE `JOB` (
`idJob` int(11) NOT NULL AUTO_INCREMENT,
`idEmployer` int(10) DEFAULT NULL,
`vcJobTitle` varchar(255) NOT NULL,
`lvJobCompanyDescription` text,
`idBasket` int(10) DEFAULT NULL,
`dtActualgolive` datetime DEFAULT NULL COMMENT 'whenever job status become online',
`boImmediatelygolive` int(11) NOT NULL,
`dtRequestedgolive` date DEFAULT NULL,
`dtActualend` datetime DEFAULT NULL COMMENT 'when job is set to be archieved',
`dtPlannedend` date NOT NULL COMMENT 'when posting a job this is calculated. batch will look at this date. date on which regular jobs will be archievd, or date on which internship jobs will be changed to listing',
`dtRequestedend` date DEFAULT NULL COMMENT 'exact date on which employer wants jobs to be archieved',
`dtApplicationdeadline` date DEFAULT NULL COMMENT 'job will be converted to listing on this date',
`boDurationinweeks` int(11) NOT NULL COMMENT 'whether employer gave duration in weeks or not',
`itDurationweeks` int(2) DEFAULT NULL,
`boIsoncredit` int(11) NOT NULL,
`dtCreditend` date DEFAULT NULL,
`fJobbaseprice` float NOT NULL,
`fJobpriceafteradminitemdiscount` float NOT NULL COMMENT 'price after admin item discount',
`fJobpriceafterpromodiscount` float NOT NULL COMMENT 'price after promo discount',
`vcPromotioncode` varchar(50) DEFAULT NULL,
`vcCompanyname` varchar(100) NOT NULL,
`vcSalarydesc` varchar(255) NOT NULL,
`vcCity` varchar(100) NOT NULL,
`vcCounty` varchar(120) DEFAULT NULL,
`vcQualificationrequired` text,
`boWorkfromhome` int(11) NOT NULL,
`boResidential` int(11) NOT NULL,
`boIndoor` int(11) NOT NULL,
`boOutdoor` int(11) NOT NULL,
`boIndoorandoutdoor` int(11) NOT NULL,
`itJobstarttype` int(11) DEFAULT NULL COMMENT 'date,immidiate,always recruiting',
`dtJobstart` date DEFAULT NULL,
`itJobendtype` int(11) DEFAULT NULL COMMENT 'date,ongoing',
`dtJobend` date DEFAULT NULL,
`dtFeaturedstart` date DEFAULT NULL,
`dtFeaturedend` date DEFAULT NULL,
`itFulltimeparttime` int(11) NOT NULL COMMENT 'fulltime,parttime,both',
`boEveningtime` int(11) NOT NULL,
`boDaytime` int(11) NOT NULL,
`boWeekend` int(11) NOT NULL,
`boNewsletter` int(11) NOT NULL,
`vcApplyemail` varchar(500) DEFAULT NULL,
`vcApplyphone` varchar(200) DEFAULT NULL,
`vcApplyaddress` varchar(100) DEFAULT NULL,
`vcApplyURL` varchar(500) DEFAULT NULL,
`boRequirephone` int(11) DEFAULT NULL,
`boRequireaddress` int(11) DEFAULT NULL,
`boRequirecv` int(11) DEFAULT NULL,
`boFeatured` int(11) NOT NULL,
`blLogo` longblob,
`itJobstatus` int(1) DEFAULT NULL COMMENT 'online,offline',
`itEmailedtofriendcount` int(5) DEFAULT NULL COMMENT 'keeps count of how many times users clicked on link email this to friend',
`itDeadlinetype` int(1) DEFAULT NULL,
`idInternshiptypemaster` int(11) DEFAULT NULL,
`vcLengthofscheme` varchar(100) DEFAULT NULL,
`dtInternshiplistingend` date DEFAULT NULL COMMENT 'date when internship job will archieve',
`itJobband` int(2) DEFAULT NULL,
`boGraduate` int(11) NOT NULL,
`boInternship` int(11) NOT NULL,
`boGaptemp` int(11) NOT NULL,
`boParttimeholiday` int(11) NOT NULL,
`boEntrylevel` int(11) NOT NULL DEFAULT '0',
`boHundredPercentDiscountApplicable` int(11) NOT NULL,
`vcContactdetails` varchar(100) DEFAULT NULL,
`vcJobreference` varchar(100) DEFAULT NULL COMMENT 'for importing totaljobs feeds',
`vcJoburlparam` varchar(100) DEFAULT NULL COMMENT 'for importing totaljobs url params',
`dtPutInCurrentBand` datetime DEFAULT NULL COMMENT 'date when job is online and put in band 3',
`itInitcountycount` int(2) NOT NULL,
`created_at` datetime DEFAULT NULL,
`updated_at` datetime DEFAULT NULL,
`lvJobkeywords` text,
`fJobweight` decimal(10,2) DEFAULT '1.00' COMMENT 'Holds the job weight ranging between 0 to 1 (1 being the highest weight)',
`dtReinstatedOn` datetime DEFAULT NULL,
`boIncludeiniframe` int(11) DEFAULT NULL,
`boIsAdvertFeatured` int(11) DEFAULT NULL,
`itincludexml` int(1) DEFAULT '1',
`boAddtojobalert` int(11) DEFAULT '1',
`vcRanking` int(11) DEFAULT '999999',
`itIncludeUkptj` int(11) DEFAULT '1',
PRIMARY KEY (`idJob`),
KEY `JOB_I_1` (`idEmployer`,`itJobstatus`),
KEY `JOB_I_2` (`itJobstatus`,`boGaptemp`,`dtJobstart`),
KEY `JOB_I_3` (`itJobstatus`,`boGraduate`,`dtJobstart`),
KEY `JOB_I_4` (`itJobstatus`,`boInternship`,`dtJobstart`),
KEY `JOB_I_5` (`itJobstatus`,`boParttimeholiday`,`dtJobstart`),
KEY `FI_JOB_idOrder_ORDER_idOrder` (`idBasket`),
KEY `FI_JOB_vcPromotioncode_PROMOTION_vcPromotioncode` (`vcPromotioncode`),
KEY `FI_JOB_idInternshiptype_ITTM_idInternshiptypemaster` (`idInternshiptypemaster`),
KEY `JOB_I_6` (`created_at`),
KEY `boEntrylevel` (`boEntrylevel`),
KEY `itJobband` (`itJobband`),
FULLTEXT KEY `index_ft_search` (`vcJobTitle`,`lvJobCompanyDescription`,`vcCompanyname`,`vcSalarydesc`,`vcCity`,`vcQualificationrequired`,`vcJobreference`,`lvJobkeywords`),
CONSTRAINT `fk_JOB_idEmployer_EMPLOYER_idEmployer` FOREIGN KEY (`idEmployer`) REFERENCES `EMPLOYER` (`idEmployer`),
CONSTRAINT `fk_JOB_idInternshiptype_ITTM_idInternshiptypemaster` FOREIGN KEY (`idInternshiptypemaster`) REFERENCES `INTERNSHIPTYPEMASTER` (`idInternshiptypemaster`),
CONSTRAINT `fk_JOB_idOrder_ORDER_idOrder` FOREIGN KEY (`idBasket`) REFERENCES `BASKET` (`idBasket`),
CONSTRAINT `fk_JOB_vcPromotioncode_PROMOTION_vcPromotioncode` FOREIGN KEY (`vcPromotioncode`) REFERENCES `PROMOTION` (`vcPromotioncode`)
) ENGINE=InnoDB AUTO_INCREMENT=1739324 DEFAULT CHARSET=latin1 |
Edit:
Without sort:
With Sort:
Can anyone explain why Mysql is giving me error 1280 ("wrong index for 'fk_chart_aid_aid' ") error whend I try to create the "CHART OF ACCOUNTS" table. I'm completly confused here. How can I fix this so I can create the table? The "ACCOUNT" table already exists in the database and has data in it.
Thanks for the help.
MYSQL Server version: 5.1.54
CHART OF ACCOUNTS:
DROP TABLE IF EXISTS `rst`.`acctg_chart_of_accounts` ;
CREATE TABLE IF NOT EXISTS `rst`.`acctg_chart_of_accounts` (
`acctg_chart_of_accounts_id` INT UNSIGNED NOT NULL AUTO_INCREMENT ,
`account_id` INT UNSIGNED NOT NULL ,
`account_nbr` VARCHAR(45) NULL ,
`description` VARCHAR(45) NULL ,
`account_type` INT UNSIGNED NULL ,
`commissionable` TINYINT UNSIGNED NULL ,
`hidden` TINYINT UNSIGNED NULL ,
`deduct_balance_from_owner_check` TINYINT UNSIGNED NULL ,
PRIMARY KEY (`acctg_chart_of_accounts_id`) ,
CONSTRAINT `fk_chart_aid_aid`
FOREIGN KEY (`account_id` )
REFERENCES `rst`.`account` (`account_id` )
ON DELETE CASCADE
ON UPDATE CASCADE)
ENGINE = InnoDB;
CREATE INDEX `fk_chart_aid_aid` ON `rst`.`acctg_chart_of_accounts` (`account_id` ASC) ;
ACCOUNTS TABLE THAT IS BEING REFERENCED:
CREATE TABLE IF NOT EXISTS `account` (
`account_id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`account_status_id` int(10) unsigned NOT NULL,
`company_name` varchar(155) DEFAULT NULL,
`address1` varchar(155) DEFAULT NULL,
`address2` varchar(155) DEFAULT NULL,
`city` varchar(155) DEFAULT NULL,
`state` varchar(155) DEFAULT NULL,
`zip` varchar(45) DEFAULT NULL,
`country` varchar(255) DEFAULT NULL,
`work_phone` varchar(45) DEFAULT NULL,
`mobile_phone` varchar(45) DEFAULT NULL,
`time_zone` varchar(45) DEFAULT NULL,
`subdomain` varchar(155) DEFAULT NULL,
`cname_URL` varchar(255) DEFAULT NULL,
`promotion_code` varchar(45) DEFAULT NULL,
`can_we_contact_you` tinyint(4) DEFAULT NULL COMMENT '0=false, 1=true',
`units_managed_nbr` varchar(10) DEFAULT NULL,
`a_hear_about_us_list_id` tinyint(3) unsigned DEFAULT NULL COMMENT 'populated from dropdown list.',
`receive_special_offers` tinyint(4) DEFAULT NULL,
`receive_announcements` tinyint(4) DEFAULT NULL,
`receive_newsletter` tinyint(4) DEFAULT NULL,
`create_ts` timestamp NULL DEFAULT NULL,
`expires` timestamp NULL DEFAULT NULL,
`storage_capacity` varchar(255) DEFAULT NULL COMMENT '1073741824 = 1GB',
`logo` varchar(455) DEFAULT NULL,
`max_active_connections` int(11) DEFAULT '3',
`_product_id` int(11) DEFAULT NULL,
`report_footer` varchar(455) DEFAULT NULL,
`welcome_dialog` tinyint(4) DEFAULT '1',
`ARB_subscription_id` int(11) DEFAULT NULL,
`trashbin` tinyint(4) NOT NULL DEFAULT '1',
PRIMARY KEY (`account_id`),
KEY `fk_account_account_status_id` (`account_status_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=58 ;
Are you getting the error after the CREATE TABLE statement, or after the subsequent CREATE INDEX?
Looks like you are attempting to name both a FOREIGN KEY constraint and an INDEX fk_chart_aid_aid. Try choosing a different name for either one of them.
Also, in the accounts table, account_id is INT(10). Try also to change the column definition in acctg_chart_of_accounts to:
`account_id` INT(10) UNSIGNED NOT NULL ,
Though, I think that mysql defaults type INT to INT(10) anyway...
I met the same issue; tried manually rename the index to a different name but don't like the idea of 'manually' and neither I don't really understand why we need to generate the index separately. so I decide to generate it within the create statement by unchecking the option of 'generate separate index statement' in 'forwarding engineer', and this fix the issue.