mysql ranking on sum and best score - mysql

Question

i have a table with this structure:
score_id | user_id | category | subcategory | score
1 | 1 | game | 0 | 100
2 | 1 | game | 0 | 200
3 | 1 | quiz | 0 | 2000
4 | 1 | quiz | 1 | 1000
5 | 1 | game | 0 | 10
6 | 1 | game | 1 | 10
7 | 1 | game | 2 | 100
8 | 1 | game | 1 | 500
9 | 2 | game | 0 | 600
and i need different query mysql:
1) ranking of all team grouped by user_id sum of all best result beetween all records of user for category and subcategory
expected result
user_id | total_score | ranking
1 | 3310 | 1
2 | 600 | 2
where
3310 = (200 + 10 + 100+1000+2000)
200 is the best result of game 0,
10 is the best result of game 1,
100 is the best result of game 2,
2000 is the best result of quiz 0
1000 is the best result of quiz 1
600 = (600)
600 is the best result of game 0,
SOLUTION by #Strawberry (thank you)
SELECT a.*
, #i:=#i+1 rank
FROM
( SELECT user_id
, SUM(subtotal) total
FROM
( SELECT user_id
, category
, subcategory
, MAX(score) subtotal
FROM my_table
GROUP
BY user_id
, category
, subcategory
) x
GROUP
BY user_id
) a
JOIN
( SELECT #i:=0) vars
ORDER
BY total DESC;
2) ranking of all team grouped by user_id sum of all best result beetween all records of user for category and subcategory for only game or quiz
expected result game
user_id | total_score | ranking
2 | 600 | 1
1 | 310 | 2
where
600 = (600)
600 is the best result of game 0,
310 = (200 + 10 + 100)
200 is the best result of game 0,
10 is the best result of game 1,
100 is the best result of game 2,
expected result quiz
user_id | total_score | ranking
1 | 3000 | 1
2 | 0 | 2
where
3000 = (200 + 10 + 100)
2000 is the best result of quiz 0
1000 is the best result of quiz 1
0= (0)
(user_id= 2 don't play quiz)
BASED ON SOLUTION by #Strawberry (thank you)
SELECT a.*
, #i:=#i+1 rank
FROM
( SELECT user_id
, SUM(subtotal) total
FROM
( SELECT user_id
, category
, subcategory
, MAX(score) subtotal
FROM my_table
WHERE category = 'game' // or 'quiz
GROUP
BY user_id
, category
, subcategory
) x
GROUP
BY user_id
) a
JOIN
( SELECT #i:=0) vars
ORDER
BY total DESC;
3) ranking of all team grouped by user_id sum of all best result beetween all records of user for category and subcategory for only game or quiz with specific subcategory
expected result game 0
user_id | total_score | ranking
2 | 600 | 1
1 | 310 | 2
where
600 = (600)
600 is the best result of game 0,
200 = (200 )
200 is the best result of game 0,
BASED ON SOLUTION by #Strawberry (thank you)
SELECT a.*
, #i:=#i+1 rank
FROM
( SELECT user_id
, SUM(subtotal) total
FROM
( SELECT user_id
, category
, subcategory
, MAX(score) subtotal
FROM my_table
WHERE category = 'game'
AND subcategory = '0'
GROUP
BY user_id
, category
, subcategory
) x
GROUP
BY user_id
) a
JOIN
( SELECT #i:=0) vars
ORDER
BY total DESC;
4) get total score of single user (ex user_id=1 ) for query 1
5) get ranking of single user (ex user_id=1 ) for query 1
6) get total score of single user (ex user_id=1 ) for query 2
7) get ranking of single user (ex user_id=1 ) for query 2
8) get total score of single user (ex user_id=1 ) for query 3
9) get ranking of single user (ex user_id=1 ) for query 3
thank you!

Answer 1

Here's the first one. Using this, show us your best efforts for the remainder...
SELECT a.*
, #i:=#i+1 rank
FROM
( SELECT user_id
, SUM(subtotal) total
FROM
( SELECT user_id
, category
, subcategory
, MAX(score) subtotal
FROM my_table
GROUP
BY user_id
, category
, subcategory
) x
GROUP
BY user_id
) a
JOIN
( SELECT #i:=0) vars
ORDER
BY total DESC;
Note that this solution doesn't account for ties.