Combining two queries and using HAVING - mysql

Question

My solution about this problem is by using 2 queries, but I am wondering if I can do it in one query only.
I have tables like these:
saved_docs
id | user_id | doc_id | date
-----------------------------------------------
1 | 2 | 1 | date
2 | 3 | 2 | date
3 | 2 | 3 | date
docs_list
id | url | title | date
-----------------------------------------
1 | url | title | date
2 | url | title | date
3 | url | title | date
What I want is first to get the doc_id on where the user_id is equal to user's id. Then, get the docs on where the id in the docs_list is equal to doc_id/s I get in saved_docs and order by the saved_docs' date.
This can be done on 2 queries, but if there is a possibility that I can do it in one only then I will go for it.
Here is my current mysql query:
SELECT docs_list.url, docs_list.title
FROM docs_list
INNER JOIN saved_docs
ON saved_posts.user_id = {$user_id}
ORDER BY saved_docs.date DESC
Note: I read about HAVING, problem is I do not know how to apply it to this query.
Current problem:
It is giving me all the docs in which is obvious because it does not give the right doc_id/s (automated). What do I need to do to make this the way I wanted to?
[SOLVED]
Note: Both etsa's and adam's answer solved my problem.

Answer 1

You can try this:
SELECT docs_list.url, docs_list.title
FROM docs_list
INNER JOIN saved_docs ON docs_list.id = saved_docs.doc_id
WHERE saved_posts.user_id = {$user_id}
ORDER BY saved_docs.date DESC

Answer 2

Sounds like you want to do it in the opposite order.
First find all docs saved by user {$user_id}, then fetch the info about those docs and sort the list.
SELECT docs_list.url, docs_list.title
FROM saved_docs
LEFT JOIN docs_list
ON docs_list.id = saved_docs.doc_id
WHERE saved_docs.user_id = {$user_id}
ORDER BY saved_docs.date DESC