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I need convert this integer "1469416462" to datetime in format dd-mm-yyyy hh:mm:ss . Any ideas?
My Intent:
select CONVERT (datetime,1469416462)
The value 1469416462 looks like a Unix-Timestamp.
Unix-Timestamp: Seconds since 1.1.1970
So the solution would be easy like:
For MySQL:
SELECT from_unixtime(1469416462)
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I am trying to show the dates in (YYYY-MM-DD) format which is stored in (DD-MM-YYYY) format in the table.
Also please explain how to use year() function on (DD-MM-YYYY) date format.
assuming your data type is a string then you could use
for format(DD-MM-YYYY)
select year(str_to_date(yourcol, '%d-%m-%Y'))
or for format (YYYY-MM-DD)
select year(str_to_date(yourcol, '%Y-%m-%d'))
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I want to compare the dates of 2nd month.
Display only dates that are in second month
by using sql query
hope this will help you:
SELECT BirthDate FROM Employees where EXTRACT(MONTH FROM BirthDate)=2;
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I have a column in a MySQL table where dates are stored as a mm/dd/yyyy string. I need to preserve that column as is, so I have added a new column where I want to store that date as a timestamp. What would the query look like to take column a and convert it to a timestamp and put it into the new column b?
you can use STR_TO_DATE to convert your string like
select str_to_date('02/22/2013','%m/%d/%Y');
UPDATE YourTable set newCol = str_to_date(yourOldCol,'%m/%d/%Y');
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I have a date field in my table which is of the type varchar. It's in the format '15-jul-2015'. I want to convert it to date type in sql. The other questions where I looked for an answer didn't have answers to my perticular case. If the answer was there I couldn't find/understand it. I am new to sql and will really appreciate a detailed solution.
Use str_to_date:
SELECT STR_TO_DATE('15-jul-2015','%d-%M-%Y');
see the mysql documentation for more informations.
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Looking at the time functions but need help to convert time from
"18:00:00" to 6 PM in the SQL language.
You can convert the string to a time and then convert the value to a string using date_format():
select date_format(cast('18:00:00' as time), '%h %p')