I am trying to use RabbitMQ HTTP REST client to publish messages into the queue. I am using the following url and request
http://xxxx/api/exchanges/xxxx/exc.notif/publish
{
"routing_key":"routing.key",
"payload":{
},
"payload_encoding":"string",
"properties":{
"headers":{
"notif_d":"TEST",
"notif_k": ["example1", "example2"],
"userModTime":"timestamp"
}
}
}
And getting back from the rabbit the following response:
{"error":"bad_request","reason":"payload_not_string"}
I have just one header set:
Content-Type:application/json
I was trying to set the
"payload_encoding":"base64",
but it didn't help. I am new to rabbit any response is welcome.
Try with
{
"properties": {
"content-type": "application/json"
},
"routing_key": "testKey",
"payload": "1234",
"payload_encoding": "string"
}
Working example. We need simple to escape doublequotes.
It is important that the colon is outside of the quotes, as this causes inexplicable errors.
{
"properties": {},
"routing_key": "q_testing",
"payload": "{
\"message\": \"message from terminal\"
}",
"payload_encoding": "string"
}
I managed to send content-type using underscore "_" instead of dash.
See here for list of valid properties.
See RabbitMQ Management HTTP API for some examples.
To publish a json message using curl to rabbit exchange:
curl -i -u guest:guest -XPOST --data '{"properties":\
{"content_type":"application/json"}, \
"routing_key":"", \
"payload":"{\"foo\":\"bar\"}",\
"payload_encoding":"string"}' \
"http://localhost:15672/api/exchanges/%2f/exchange_name/publish"
content_type is written using underscore, routing_key is empty to send a message to exchange, not to particular queue.
To use a JSON formatted payload you have to encode it in base64 and use the "payload_encoding": "base64" attribute.
Related
I want to build a request in insomnia to upload person, documents and it's files
How can I put a multipart file inside a JSON object? I don't want to deal with string base64 because it's too big and too slow to travel over the network.
I have a rest api made with spring boot and kotlin that will receive this JSON file.
Here's some code for what I want to achieve:
curl --request POST \
--url http://localhost:8080/ \
--header 'content-type: multipart/form-data; boundary=--
-011000010111000001101001' \
--form 'person={
"first_name": "Foo",
"last_name": "Fighters"
}' \
--form 'document=[
{
"document_name": "test1",
"document_description":"test1",
"document_file": "multipart file1"
},
{
"document_name": "test2",
"document_description":"test2",
"document_file": "multipart file2"
},
{
"document_name": "testN",
"document_description":"testN",
"document_file": "multipart fileN"
}
]'
Where the key document_file value stands for the file itself, not a String.
Some pictures to make it clear:
Here is the overview of the multipart
Person detail:
Document detail:
I need to know what files are from what documents, and I can have 0 or many documents related to the person.
Therefore, that's why adding 1 file for each document I want to create won't work. It needs to be inside the object(just like presented in the images) that way I know that file-X is from document-X and vice-versa.
Thanks in advance!
I do not understand the documentation for the JSON package defining the URLs. I am using curl. I am able to pass my key to the API. I am having trouble with the url data. Below is what I have tried without success. Any help would be appreciated.
enter code here
--data '{
"lookupStrategy": "FETCH_LIVE_DOC",
"urls": [
"originalURL":"https://www.myurl.com/index.html", \
"ampURL":"https://www.myurl.com/index.html", \
"cdnAmpUrl":"https://www-myurl-com.cdn.ampproject.org/c/s/index.html"
]
}'
Your JSON should be:
{
"lookupStrategy": "FETCH_LIVE_DOC",
"urls": [
"https://www.myurl.com/index.html",
"https://www.myurl.com/index.html",
"https://www-myurl-com.cdn.ampproject.org/c/s/index.html"
]
}
Looks like you are using the return data schema.
I'm using conversocial API:
https://api-docs.conversocial.com/1.1/reports/
Using the sample from the documentation, as after all tweaks I receive this "output"
{
"report": {
"name": "dump", "generation_start_date": "2012-05-30T17:09:40",
"url": "https://api.conversocial.com/v1.1/reports/5067",
"date_from": "2012-05-21",
"generated_by": {
"url": "https://api.conversocial.com/v1.1/moderators/11599",
"id": "11599"
},
"generated_date": "2012-05-30T17:09:41",
"channel": {
"url": "https://api.conversocial.com/v1.1/channels/387",
"id": "387"
},
"date_to": "2012-05-28",
"download": "https://s3.amazonaws.com/conversocial/reports/70c68360-1234/#twitter-from-may-21-2012-to-may-28-2012.zip",
"id": "5067"
}
}
Currently, I can sort this JSON output to download only and will receive this output
{
"report" : {
"download" : "https://s3.amazonaws.com/conversocial/reports/70c68360-1234/#twitter-from-may-21-2012-to-may-28-2012.zip"
}
}
Is it anyway of automating this process by using CURL, to make curl download this file?
To download I'm planning to use simple way as:
curl URL_LINK > FILEPATH/EXAMPLE.ZIP
Currently thinking is there is a way to replace URL_LINK with download link?? Or any other way, method, way around????
Give a try to this:
curl $(curl -s https://httpbin.org/get | jq ".url" -r) > file
Just replace your url and the jq params, based in your json, thay may be:
jq ".report.download" -r
The -r will remove the double quotes "
The way it works is by using a command substitution $():
$(curl -s https://httpbin.org/get | jq ".url" -r)
This will fetch you URL and extract the new URL from the returned JSON using jq the one later is passed to curl as an argument.
I'm trying to make a HTTP form POST request to http://example.co.uk.
I used curl http://example.co.uk -d #example.json. However it gives me error saying it should only contain single field called application.
example.json file:
{"application":[
{
"name":"John",
"email":"john#example.com",
"github":"https://github.com/john",
"twitter":"https://twitter.com/john",
}
]
}
What's the correct way to do it? Any help will be appreciated. Thanks
You'll need to indicate to the server that the content type is JSON instead of the standard form-encoded data, so use:
curl -H "Content-Type: application/json" http://example.co.uk -d #example.json
Also, your JSON file should be valid JSON i.e. without any ending/redundant , characters, so:
{"application":[
{
"name":"John",
"email":"john#example.com",
"github":"https://github.com/john",
"twitter":"https://twitter.com/john"
}
]
}
Check the contents at http://jsonlint.com
I am trying to log the request body of requests to my api and nginx is turning all quotes (and some other characters like spaces and tabs) into hexadecimal characters.
Here is my log format
log_format postdata '{"ts": "$time_iso8601", "status": $status, "req": "$uri", "meth": "$request_method", "body": "$request_body"}';
Here is what gets logged
{"ts": "2015-05-20T15:31:11-07:00", "status": 400, "req": "/v2/track", "meth": "POST", "body": {\x22id\x22:\x22user id\x22}}
How can I prevent this so that the resulting log line is
{"ts": "2015-05-20T15:31:11-07:00", "status": 400, "req": "/v2/track", "meth": "POST", "body": {"id":"user id"}}
Sinse 1.13 there is an "escape=none" parameter that turns off data escaping.
http://nginx.org/en/docs/http/ngx_http_log_module.html#log_format
log_format api_request_log escape=none '[$time_local] $request \n$request_body';
You can't stop from escaping it and will have to post process it.
Python2 example:
line = '{\x22id\x22:\x22user id\x22}'
line.decode('unicode_escape')
>> u'{"id":"user id"}'
Python3 example:
line = '{\x22id\x22:\x22user id\x22}'
bytes(line, 'utf-8').decode('unicode_escape')
>> '{"id":"user id"}'
Ruby example (from https://stackoverflow.com/a/18752208/2398354):
require 'yaml'
line = '{\x22id\x22:\x22user id\x22}'
YAML.load(%Q(---\n"#{line}"\n))
=> "{\"id\":\"user id\"}"
Note: This last example is useful if post processing a file with logstash
Hope this will be helpful for someone.
In order to log entire json request unescaped.
Do add in http block this configuration
http {
log_format postdata escape=json $request_body;
access_log /var/log/nginx/access.log postdata;
.....
}
Like others said, there is no way to fix this within nginx configuration.
But it is not difficult to post-process it. If the request body is JSON-formatted, you'll probably run into a lot of \x0A (newline) and \x22 (").
Just clear those out with sed before looking into the logfile.
Here is the command for you: LANG='' sed -E 's/(\\x0A|\\x22)//g' access.log