i have a mysql table
id cid c_name keywords
1 28 Stutgart BW,Mercedes,Porsche,Auto,Germany
2 34 Roma Sezar,A.S. Roma
3 28 München BMW,Oktober Fest,Auto,Germany
i need a query to show keywords from cid=28 but i want to see only 1 time a keyword, like (BW,Mercedes,Porsche,Auto,Bmw,Oktober Fest,Germany)
i dont want to list 2 time a keyword, how can resolve this problem?
i have tried distinct but could not get what i want
Split it before adding it all up with DISTINCT.Of course,better is to normalize your data(no more than 1 value in a column)
SELECT
GROUP_CONCAT( DISTINCT SUBSTRING_INDEX(SUBSTRING_INDEX(keywords, ',', n.digit+1), ',', -1)) keyword
FROM
t
INNER JOIN
(SELECT 0 digit UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6) n
ON LENGTH(REPLACE(keywords, ',' , '')) <= LENGTH(keywords)-n.digit
WHERE cid=28
See it working
If you want to get a dynamic output then you can use the following query to get a distinct comma delimited values in a single record.
Note: here doesn't matter how many values are in comma delimited row & it's fetched distinct record from a number of rows based on your condition
$tag_list = DB::select('SELECT
TRIM(TRAILING "," FROM REPLACE(GROUP_CONCAT(DISTINCT keywords, ","),",,",",")) tag_list
FROM
test
WHERE id = 28');
$unique_tags = implode(',', array_unique(explode(",",$result[0]->search_tags)));
Related
how to split comma separated string from one column and turn it into several columns?
this is my table:
SELECT id,lik FROM `tbl_users_posts` WHERE id=1;
id lik
-------------
1 10,11,12,13,14,15
how can i split 'lik' column and get this result?
id lik
-------------
1 10
1 11
1 12
1 13
1 14
1 15
displays id 1 in the first row and split the 'lik' column into pieces in the second row and displays it one by one
Unfortunately MySQL doesn't have a split string functions. One way is create a temporary table as following with the max values of the largest row:
create temporary table numbers as (
select 1 as n
union select 2 as n
union select 3 as n
union select 4 as n
union select 5 as n
union select 6 as n
union select 7 as n
union select 8 as n
);
Then you can use substring_index to accomplish the desired result
select id,
substring_index( substring_index(lik, ',', n),',', -1) as lik
from tbl_users_posts
join numbers on char_length(lik) - char_length(replace(lik, ',', '')) >= n - 1
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=84bc1b4e60a7feea5af0d0b568bc7bcb
Edit.
Another method if you have MySQL 8+ for the lik string to split into thousands of pieces without a loop is create an temporary table using recursive cte as follows:
CREATE TEMPORARY TABLE numbers WITH RECURSIVE cte AS
( select 1 as n
union all
select n +1
from cte
limit 1000
)
SELECT * FROM cte;
And then use the same query as above:
select id,
substring_index( substring_index(lik, ',', n),',', -1) as lik
from tbl_users_posts
join numbers on char_length(lik) - char_length(replace(lik, ',', '')) >= n - 1
order by id asc;
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=9231202418ce9b17aef8609ad6875fbe
If the lik is a number that can be found in the database you can do:
select p.id, t.lik_id
from table_containing_lik t
join tbl_users_posts p on find_in_set(t.lik_id, p.lik)
where p.id=1;
I have a field that includes files that have 'words' separated by an underscore, _, such as this:
`file_name`
MY_NEW_MOVIE.mov
HD_VIDEO_720p.mov
720p_DISNEY_MOVIE.mov
LG_TYLERPERRY_FEATURE_HD_8CH_EN_L9714343_16X9_235_2398_FINAL_FRSUB.srt
And I want to split on _ and get the count of each word after the split, meaining:
`word` `count`
MY 1
NEW 1
MOVIE 2
HD 1
VIDEO 1
720p 2
DISNEY 1
Would it be possible/feasible to do this in SQL? So far I have just gotten the perfunctory "remove the file extension", but not sure how I could split on the token and then count that:
select left(file_name, length(file_name) - length(substring_index(file_name, '.', -1))-1) from asset
Additionally,
The result you want can be achieved with a query derived from this answer, which uses a generated numbers table along with SUBSTRING_INDEX to split out all the words in each file_name. This is then used as a derived table to count the occurrence of each word. Note the numbers table must have sufficient values to cover the maximum number of words in a filename (12 for this sample data).
SELECT word, COUNT(*)
FROM (
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(LEFT(file_name, LENGTH(file_name)-4), '_', numbers.n), '_', -1) AS word
FROM (
select 1 n union all
select 2 union all select 3 union all select 4 union all
select 5 union all select 6 union all select 7 union all
select 8 union all select 9 union all select 10 union all
select 11 union all select 12
) numbers
JOIN asset ON LENGTH(file_name)
- LENGTH(REPLACE(file_name, '_', '')) >= numbers.n - 1
) w
GROUP BY word
Output (for your sample data):
word COUNT(*)
16X9 1
235 1
2398 1
720p 2
8CH 1
DISNEY 1
EN 1
FEATURE 1
FINAL 1
FRSUB 1
HD 2
L9714343 1
LG 1
MOVIE 2
MY 1
NEW 1
TYLERPERRY 1
VIDEO 1
Demo on dbfiddle
Assuming the filenames always have exactly three components, SUBSTRING_INDEX can get the job done here:
SELECT word, COUNT(*) AS count
FROM
(
SELECT SUBSTRING_INDEX(file_name, '_', 1) AS word FROM asset
UNION ALL
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(file_name, '_', 2), '_', -1) FROM asset
UNION ALL
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(file_name, '_', -1), '.', 1) FROM asset
) t
GROUP BY word;
Demo
Note: This answer was given based on the OP's original sample data, where all filenames had exactly three underscore-separate components. This answer will not work for the updated question.
I have two tables Posts, categories. Here in the posts table I stored the category values as comma separated string like this 5,8,23,7. While displaying the posts, I just want to show the post categories as comma separated like this Flower, Birds, Animals. So I tried some queries nothing helped me to get it. The Posts Table Example.
ID Post title categories
3 Example Post 5,7,23,8
And the Categories Table will be like this
ID name
5 Flowers
7 Animals
8 Birds
23 Naturals
And I want result like this
ID Post Tile Category
3 Example Post Flowers, Animals, Birds
For that I tried this query but didn't help me to get it .
SELECT post.ID, post.Post_title, (SELECT cat.name FROM Categories as cat WHERE cat.ID IN (post.category)) AS Categories FROM Posts as post
And it returns only one category, it retrieves the first category name only.
If you simply must use that schema, you could try something like this:
select P.ID, P.Title, (
select group_concat(C.name SEPARATOR ', ')
from Categories C
where LOCATE(CONCAT(C.ID, ','), P.categories) > 0
or LOCATE(CONCAT(', ', C.ID), P.categories) > 0
) as categories
from Post P;
It's hacky because in a comma separated list either a value occurs before a comma or after a comma, taking into account values at the beginning or end of the list. You can't just do a straight substring, because otherwise you'll get a category ID of 5 matched to a 'categories' value of '1, 2, 555'.
EDIT: Updated to consider the fact that Posts.categories is a CSV value.
You need to use the GROUP_CONCAT() function, and also the trick posted in SQL split comma separated row in order to split the JOIN CSV and then create the output CSV:
SELECT
Posts.ID,
Posts.Post_title,
GROUP_CONCAT(Categories.name SEPARATOR ',') AS `Category`
FROM Posts
INNER JOIN Categories
ON Categories.ID IN (
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(Posts.categories, ',', n.n), ',', -1) value
FROM (
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(Posts.categories) - LENGTH(REPLACE(Posts.categories, ',', '')))
ORDER BY value
)
GROUP BY
Posts.ID,
Posts.Post_title
Fiddle: http://sqlfiddle.com/#!9/b1ddc9/4
I believe you can use group_concat? Just join the Categories table and group_concat the name group_concat(name)
as for the JOIN try to use find_in_set(Categories.ID, Post.ID) > 0
Thou this approach may not work if the comma delimited Category ID has space i.e. 1, 2 etc...But if you are saving it accurately this may work.
Something like this:
Select UNIQUE_VALUES('1,2,3,5,3,4,2,1,2,3,1,4') as CSVUnique
The result of this will be:
CSVUnique
1,2,3,5,4
Thanks!
No way with mysql for getting unique like this way.
First it's bad that you storing values like this way. You should use parent child tables for storing such data instead of storing com,a separated values. Or should filter such duplicates before inserting.
Normalize your database.
get values from table and use php explode() , and use array_unique to remove duplicate values.
Here is one way
CREATE TABLE t
( vals VARCHAR (100));
INSERT INTO t VALUES('1,2,3,5,3,4,2,1,2,3,1,4');
SELECT
GROUP_CONCAT(DISTINCT SUBSTRING_INDEX(SUBSTRING_INDEX(vals, ',', n.digit+1), ',', -1)) val
FROM
t
INNER JOIN
(SELECT 0 digit UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6) n
ON LENGTH(REPLACE(vals, ',' , '')) <= LENGTH(vals)-n.digit;
See it working
I have a table with a varchar(255) field. I want to get (via a query, function, or SP) the number of occurences of each word in a group of rows from this table.
If there are 2 rows with these fields:
"I like to eat bananas"
"I don't like to eat like a monkey"
I want to get
word | count()
---------------
like 3
eat 2
to 2
i 2
a 1
Any idea? I am using MySQL 5.2.
#Elad Meidar, I like your question and I found a solution:
SELECT SUM(total_count) as total, value
FROM (
SELECT count(*) AS total_count, REPLACE(REPLACE(REPLACE(x.value,'?',''),'.',''),'!','') as value
FROM (
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(t.sentence, ' ', n.n), ' ', -1) value
FROM table_name t CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(t.sentence) - LENGTH(REPLACE(t.sentence, ' ', '')))
ORDER BY value
) AS x
GROUP BY x.value
) AS y
GROUP BY value
Here is the full working fiddle: http://sqlfiddle.com/#!2/17481a/1
First we do a query to extract all words as explained here by #peterm(follow his instructions if you want to customize the total number of words processed). Then we convert that into a sub-query and then we COUNT and GROUP BY the value of each word, and then make another query on top of that to GROUP BY not grouped words cases where accompanied signs might be present. ie: hello = hello! with a REPLACE
I would recommend not to do this in SQL at all. You're loading DB with something that it isn't best at. Selecting a group of rows and doing frequency calculation on the application side will be easier to implement, will work faster and will be maintained with less issues/headaches.
You can try this perverted-a-little way:
SELECT
(LENGTH(field) - LENGTH(REPLACE(field, 'word', ''))) / LENGTH('word') AS `count`
ORDER BY `count` DESC
This query can be very slow. Also, it looks pretty ugly.
I think you should do it like indexing, with additional table.
Whenever u create, update, or delete a row in your original table, you should update your indexing table. That indexing table should have the columns: word, and the number of occurrences.
I think you are trying to do too much with SQL if all the words are in one field of each row. I recommend to do any text processing/counting with your application after you grab the text fields from the db.