I Have this result in for my SQL query
and I want to convert it like this
You could use (a fake) aggregation function and group by
select type_revenue
, max(case when location_name ='30juin' then amount else 0 end) 30Jui
, max(case when location_name ='Bandal' then amount else 0 end) Bandal
from my_tbale
group by type_revenue
Related
With this example iformation table:
How can i output this information?
I'm trying this query,
but it's just returning me the total number of 'PART' rows for each 'NAMES'.
SELECT
NAMES
, SUM(PART = "F001") AS SUM_F001
, SUM(PART = "F002") AS SUM_F002
, SUM(PART = "F003") AS SUM_F003
FROM
MY_TABLE
GROUP BY NAMES ASC
You are pretty close with your current query.
But you need to use the query below to correctly pivot.
SELECT
NAMES
, MAX(CASE WHEN PART = 'F001' THEN QTY ELSE 0 END) AS F001
, MAX(CASE WHEN PART = 'F002' THEN QTY ELSE 0 END) AS F002
, MAX(CASE WHEN PART = 'F003' THEN QTY ELSE 0 END) AS F003
, SUM(QTY) AS alias
FROM
FROM
MY_TABLE
GROUP BY
NAMES # Don't use ASC OR DESC on GROUP BY because it's deprecated
ORDER BY
NAMES ASC
U can use the query as follows
SELECT NAMES , SUM(CASE WHEN PART = 'F001' THEN 1 ELSE 0 END) AS F001 , SUM(CASE WHEN PART = 'F002' THEN 1 ELSE 0 END) AS F002 , SUM(CASE WHEN PART = 'F003' THEN 1 ELSE 0 END) AS F003 , SUM(QTY) AS alias FROM FROM MY_TABLE GROUP BY NAMES ORDER BY NAMES ASC
in my Table attendance
Insert Into tblAttendance(cEmpID,cCode,dDate,notMin) Values
('1000','R' , 120,'2016-10-27'),
('1000','R' , 120,'2016-10-28'),
('1000','S' , 120,'2016-10-29'),
('1000','L' , 120,'2016-10-30'),
('1001','R' , 120,'2016-10-27'),
('1001','R' , 120,'2016-10-28'),
('1001','S' , 120,'2016-10-29'),
('1001','L' , 120,'2016-10-30')
i need to sum all OT Min. per Code
the output something like this..
EmpID,R-Total,S-Total,L-Total
here's my Sample Query
Select (Select sum(nOTMin) from tblattenddetail Where cCode='R') 'R-Total',
(Select sum(nOTMin) from tblattenddetail Where cCode='S') 'S-Total',
(Select sum(nOTMin) from tblattenddetail Where cCode='L') 'L-Total'
i need to Include the cEmpID..
Please Help me how will i revise this to Include the cEmpID..
You can use a case expression to conditionally aggregate the correct values. This should do what you want:
SELECT
cEmpID,
SUM(CASE WHEN cCode='R' THEN nOTMin ELSE 0 END) AS 'R-Total',
SUM(CASE WHEN cCode='S' THEN nOTMin ELSE 0 END) AS 'S-Total',
SUM(CASE WHEN cCode='L' THEN nOTMin ELSE 0 END) AS 'L-Total'
FROM tblAttendance
GROUP BY cEmpID
Sample SQL Fiddle
I want to know the difference between these two queries: The first query is giving me all the records and its just fine.
Select * from table1 where tender_id='$tender_id' group by supplier_name
But in the following query I have added a sum(case), but I am not getting the desired output. The first query is showing all the records, but the second query is not showing all the records. What mistake am I making?
select cs.*, tender_id,
SUM(CASE WHEN ifmain = 'Yes' THEN total_inr ELSE 0 END) AS maintotal,
SUM(CASE WHEN ifmain = 'No' THEN total_inr ELSE 0 END) AS subtotal
from table1 cs
where cs.tender_id='$tender_id'
group by cs.supplier_name
I want to know if the second query can display all the records with conditions (tender_id)? or its iterating more?
In standard SQL, a query that includes a GROUP BY clause cannot refer
to nonaggregated columns in the select list that are not named in the
GROUP BY clause.
see (for example) https://dev.mysql.com/doc/refman/5.0/en/group-by-handling.html
MySQL has a an unfortunate (and in my opinion incorrect) default behavior when using a GROUP BY clause. This query would NOT be valid in most SQL databases:
Select * from table1 where tender_id='$tender_id' group by supplier_name
and it would not be valid in MySQL either if the ONLY_FULL_GROUP_BY SQL mode has been enabled.
I strongly recommend you treat all queries using GROUP BY as needing ALL non-aggregating columns in that clause. e.g.
select
cs.supplier_name
, SUM(CASE WHEN ifmain = 'Yes' THEN total_inr ELSE 0 END) AS maintotal
, SUM(CASE WHEN ifmain = 'No' THEN total_inr ELSE 0 END) AS subtotal
from table1 cs
where cs.tender_id='$tender_id'
group by
cs.supplier_name
If you need extra columns then e.g.
select
cs.supplier_name
, tender_id
, SUM(CASE WHEN ifmain = 'Yes' THEN total_inr ELSE 0 END) AS maintotal
, SUM(CASE WHEN ifmain = 'No' THEN total_inr ELSE 0 END) AS subtotal
from table1 cs
where cs.tender_id='$tender_id'
group by
cs.supplier_name
, tender_id
and so on. Of course as you include more columns in the group by clause you may increase the number of rows produced, but that is how GROUP BY should work.
I have seperate queries but i need to reduce the no so put all in one
select count(applicant_id) as registered from student_application where filter_status=0 AND
select count(applicant_id) as filer_select from student_application where filter_status=1 AND
select count(applicant_id) as filter_reject from student_application where filter_status=2
but this shows some errors
Use CASE expression.
Query
select
count(case when filter_status = 0 then applicant_id else null end) as registered,
count(case when filter_status = 1 then applicant_id else null end) as filer_select,
count(case when filter_status = 2 then applicant_id else null end) as filer_reject
from student_application;
SQL Fiddle
You could also use group_by, with the where clause if you're looking for a subset rather than all possible values of filter_status:
SELECT filter_status, COUNT(*)
FROM student_application
WHERE filter_status in (0, 1, 2)
GROUP BY filter_status;
I am trying to get the count of females and males in the gender field of a table.
Is there a way to get the count of each in one query?
Something like:
select * from table count(where gender = 'm') as total_males, count(where gender = 'f') as total_females;
or will it require two queries?
select count(*) from table where gender = 'm';
select count(*) from table where gender = 'f';
This is basically a PIVOT. MySQL does not have a pivot so you can use an aggregate function with a CASE statement to perform this:
select
sum(case when gender = 'm' then 1 else 0 end) Total_Male,
sum(case when gender = 'f' then 1 else 0 end) Total_Female
from yourtable
See SQL Fiddle with Demo
Or using COUNT:
select
count(case when gender = 'm' then 1 else null end) Total_Male,
count(case when gender = 'f' then 1 else null end) Total_Female
from yourtable;
See SQL Fiddle with Demo
Something like this will work:
SELECT SUM(IF(t.gender='m',1,0)) AS total_males
, SUM(IF(t.gender='f',1,0)) AS total_females
FROM mytable t
The "trick" here is that we are using a conditional test to return either a 0 or a 1 for each row, and then adding up the 0's and 1's. To make this a little more clear, I am using the SUM aggregate function rather than COUNT, although COUNT could be used just as easily, though we'd need to return a NULL in place of the zero.
SELECT COUNT(IF(t.gender='m',1,NULL)) AS total_males
, COUNT(IF(t.gender='f',1,NULL)) AS total_females
FROM mytable t
Consider that the two expressions in the SELECT list of this query:
SELECT COUNT(1)
, SUM(1)
FROM mytable t
Will return the same value.
If you want to avoid the MySQL IF function, this can also be done using the ANSI SQL CASE expression:
SELECT SUM( CASE WHEN t.gender = 'm' THEN 1 ELSE 0 END )) AS total_males
, SUM( CASE WHEN t.gender = 'f' THEN 1 ELSE 0 END )) AS total_females
FROM mytable t
select sum(case when gender='m' then 1 else null end) as total_males, sum(case when gender='f' then 1 else null end) as total_females from ...
Should work just fine!
If your only issue is to avoid two queries, you can always write two queries as subselects of one query.
Select (select 1 from dual) as one, (select 2 from dual) as two from dual
This would work for your scenario, too.