I have this mySQL statement:
SELECT (SELECT COUNT(id) from online_users WHERE name='lol') as online, id, name, city
FROM players
WHERE name='lol'
AND last_action < date_sub(now(), interval 1 hour)
however I want the last_action interval to vary; 1 minute if online is 1, and 1 hour if online is 0
Can this be done all in one query? How so?
SELECT (SELECT COUNT(id) from online_users WHERE name='lol') as online, id, name, city
FROM players
WHERE name='lol'
AND last_action < date_sub(now(), interval 1 CASE WHEN online=0 THEN hour ELSE MINUTE END)
Try above code.
Hope this will help.
You could use an OR condition, like this:
SELECT (SELECT COUNT(id) from online_users WHERE name='lol') as online, id, name, city
FROM players
WHERE name='lol'
AND ((last_action < date_sub(now(), interval 1 hour) AND online = 1) OR (last_action < date_sub(now(), interval 1 minute) AND online = 0))
Related
This seems like an easy task but my basic sql knowledge is failing me as I'm still learning.
Basically, I'm trying to combine:
SELECT DATE(created) DATE, COUNT(DISTINCT created) newpost FROM surveys
WHERE created >= Last_day(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND created < last_day(CURRENT_DATE) + INTERVAL 1 DAY GROUP BY DATE(created);
and
SELECT DATE(TIMESTAMP) DATE,subs FROM trafficstats
WHERE TIMESTAMP >= LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND TIMESTAMP < LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY;
into one query that will return data, grouped by date, into two additional columns - newposts and subs.
I've tried using UNION, which doesn't seem to be giving me the output I want. It combined the data into one column (newpost), and also didn't group by date.
I'm still fairly new to writing MySQL queries, and I've tried searching for answers to no avail. Hoping to seek the knowledge of those smarter than me here.
You could use JOIN
select t1.DATE, t1.newpost, t2.subs
from (
SELECT DATE(created) DATE, COUNT(DISTINCT created) newpost
FROM surveys
WHERE created >= Last_day(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND created < last_day(CURRENT_DATE) + INTERVAL 1 DAY
GROUP BY DATE(created)
) t1
left join (
SELECT DATE(TIMESTAMP) DATE, subs
FROM trafficstats
WHERE TIMESTAMP >= LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND TIMESTAMP < LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY
) t2 on t1.DATE = t2.DATE
I guess you want one row per distinct date, with two different count values shown.
This kind of query is slightly tricker than it seems at first glance, because the two summary queries might have different sets of dates.
So you need to start with a subquery that yields all possible dates of interest. You then need to LEFT JOIN each summary query to it. You must use LEFT JOIN instead of the ordinary inner JOIN, because LEFT JOIN doesn't suppress rows from the right side of the join when they don't match any rows from the left side.
Here goes:
All your dates. Notice the UNION operation is a setwise (duplicate-removing) union operation.
SELECT DISTINCT DATE(created) DATE FROM newpost
WHERE created >= Last_day(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND created < last_day(CURRENT_DATE) + INTERVAL 1 DAY
UNION
SELECT DISTINCT DATE(TIMESTAMP) DATE FROM trafficstats
WHERE TIMESTAMP >= LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND TIMESTAMP < LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY
Then you need your two summary subqueries. The first one is this. Notice that I changed COUNT(DISTINCT created) to COUNT(*) because I don't understand the logic behind the DISTINCT there. Can you have more than one row for a single post; do you tell them apart by timestamp? If you have a row for each post you should COUNT(*).
SELECT DATE(created), COUNT(*) newposts
FROM newpost
GROUP BY DATE(created)
The second summary is this. Again, I counted rows.
SELECT DATE(TIMESTAMP), COUNT(*) subs
FROM trafficstats
GROUP BY DATE(TIMESTAMP)
Finally, join those three subqueries like so. You get the dates from the first subquery, and the summary-by-date information from the second two subqueries.
SELECT dates.DATE, posts.newposts, subs.subs
FROM ( /* date subquery */ ) dates
LEFT JOIN ( /* posts subquery */ ) posts ON dates.DATE = posts.DATE
LEFT JOIN ( /* subs subquery */ ) subs ON dates.DATE = subs.DATE
ORDER BY dates.DATE
Putting it all together:
SELECT dates.DATE, posts.newposts, subs.subs
FROM (
SELECT DISTINCT DATE(created) DATE FROM newpost
WHERE created >= Last_day(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND created < last_day(CURRENT_DATE) + INTERVAL 1 DAY
UNION
SELECT DATE(TIMESTAMP) DATE FROM trafficstats
WHERE TIMESTAMP >= LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND TIMESTAMP < LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY
) dates
LEFT JOIN (
SELECT DATE(created), COUNT(*) newposts
FROM newpost
GROUP BY DATE(created)
) posts ON dates.DATE = posts.DATE
LEFT JOIN (
SELECT DATE(TIMESTAMP), COUNT(*) subs
FROM trafficstats
GROUP BY DATE(TIMESTAMP)
) subs ON dates.DATE = subs.DATE
ORDER BY dates.DATE
I have a MYSQL COUNT Status that is working great by counting records greater than CURDATE. How do I specify this query to ONLY count tomorrow based on CURDATE for the column specified?
SELECT COUNT(ID) as total_count
FROM HTG_ScheduleRequest
WHERE (ScheduleDateCurrent > CURDATE())
AND JobStatus = '3'
GROUP BY SSR
The "easy" way is:
WHERE date(ScheduleDateCurrent) = date_add(CURDATE(), interval 1 day) AND JobStatus = '3'
The better way is:
WHERE JobStatus = '3' AND
ScheduleDateCurrent >= date_add(CURDATE(), interval 1 day) AND
ScheduleDateCurrent < date_add(CURDATE(), interval 2 day)
The reason this is better is because it can take advantage of an index on JobStatus, ScheduleDateCurrent, if one is available.
The following query would do the trick
SELECT COUNT(ID) as total_count
FROM HTG_ScheduleRequest
WHERE (ScheduleDateCurrent BETWEEN DATE_ADD(DATE(CURDATE()), INTERVAL 1 DAY)
AND DATE_ADD(DATE(CURDATE()), INTERVAL 2 DAY))
AND JobStatus = '3'
GROUP BY SSR
To count only the rows having tomorrow's date (and non-NULL ID), you could do this:
SELECT COUNT(ID) as total_count
FROM HTG_ScheduleRequest
WHERE (ScheduleDateCurrent = ADDDATE(CURDATE(),1))
AND JobStatus = '3'
GROUP BY SSR
I'm having problems with timediff and DATE_SUB. Here is my MYSQL query:
SELECT id, clock_user_id, clock_date,
(Select clock_time from aura_clock where aura_clock.clock_type = 'Start' and
aura_clock.clock_date = t1.clock_date) as start, (Select clock_time
from aura_clock where aura_clock.clock_type = 'Stop'
and aura_clock.clock_date =
t1.clock_date) as Stop,
THE PROBLEM START HERE
TIMEDIFF((select clock_time FROM aura_clock t
WHERE t.clock_date = t1.clock_date AND t.clock_time > t1.clock_time
ORDER BY t.clock_time LIMIT 1), MIN(clock_time)) as spent
FROM aura_clock t1 WHERE t1.clock_date >= DATE_SUB(DATE_SUB(CURDATE(), INTERVAL
WEEKDAY(CURDATE()) DAY),INTERVAL 15 day)
AND t1.clock_date < DATE_SUB(curdate(),INTERVAL DAYOFWEEK(curdate()) + 6 day)
GROUP BY clock_date
The result is :
Now, I want to subtract 1 hour from the time spent using DATE_SUB but it didn't work.
as mirkobrankovic wrote:
((TIMEDIFF((select clock_time FROM aura_clock t
WHERE t.clock_date = t1.clock_date AND t.clock_time > t1.clock_time
ORDER BY t.clock_time LIMIT 1), MIN(clock_time))) - INTERVAL 1 HOUR) AS new_spent
should work
EDIT:
The best i got is time in seconds :
http://sqlfiddle.com/#!2/18160/66/0
a lot depends on MYSQL version
First of all: sorry for the title, but maybe I will find a better one later.
I asked this some minutes ago, but since I was not able to describe what I want I try it again :)
Here is my table structure:
http://sqlfiddle.com/#!2/b25f9/37
The table is used to store user sessions.
Out of this I would like to generate a stacked bar chart that should show how many active users I have. My idea was that I group the users based on their online-times of the last days like this
Lets say its friday:
Group B: Users that were online thursday (and today)
Group C: Users that were not online thursday but wednesday (and today)
Group D: Users that were not online thursday or wednesday but tuesday (and today)
Group E: Users that were not online thursday, wednesday or tuesday but last monday, sunday or saturday (and today)
Group A: Users that do not match the other groups (but were only today)
I only want to know the number of users in those groups (for a specific day)
a user can only be in ONE of these groups (for the same day)
Another Update: Accidently (by copy&paste) had starttime = ... or starttime = ... but it should be starttime = ... or endtime = ...
UPDATE:
To explain my query in more detail (in the final query there are even more comments):
First we simply got
SELECT
...
FROM gc_sessions s
WHERE DATE(starttime) = CURDATE() OR DATE(endtime) = CURDATE()
That's nothing more like saying "give me all users whose session started today or ended today". Having to consider those two times again and again makes the query a bit clumsy, but actually it's not that complicated.
So, usually we would use the COUNT() function to count something, obviously, but since we want "conditional counting", we simply use the SUM() function and tell it when to add 1 and when not.
SUM (CASE WHEN ... THEN 1 ELSE 0 END) AS a_column_name
The SUM() function examines now each row in the result set of sessions from today. So for each user in this result set we look if this user was online the date we specify. It doesn't matter how many times he/she was online, so for performance reasons we use EXISTS. With EXISTS you can specify a subquery which stops as soon as something is found, so it doesn't matter what it returns when something is found, as long as it's not NULL. So don't get confused why I selected 1. In the subquery we have to connect the user which is currently examined from the outer query with the user from the inner query (subquery) and specify the time window. If all criterias meet count 1 else 0 like explained before.
SUM(CASE WHEN
EXISTS (SELECT 1 FROM gc_sessions sub_s WHERE s.user = sub_s.user
AND ((date(starttime) = CURDATE() - INTERVAL 1 DAY)
OR (date(endtime) = CURDATE() - INTERVAL 1 DAY)))
THEN 1 ELSE 0 END) AS todayAndYesterday,
Then we make a column for each condition and voila, you have all you need in one query. So with your updated question your criteria has changed, we just have to add more rules:
SELECT
/*this is like before*/
SUM(CASE WHEN
EXISTS (SELECT 1 FROM gc_sessions sub_s WHERE s.user = sub_s.user
AND ((date(starttime) = CURDATE() - INTERVAL 1 DAY)
OR (date(endtime) = CURDATE() - INTERVAL 1 DAY)))
THEN 1 ELSE 0 END) AS FridayAndThursday,
SUM(CASE WHEN
EXISTS (SELECT 1 FROM gc_sessions sub_s WHERE s.user = sub_s.user
AND ((date(starttime) = CURDATE() - INTERVAL 2 DAY)
OR (date(endtime) = CURDATE() - INTERVAL 2 DAY)))
/*this one here is a new addition, since you don't want to count the users that were online yesterday*/
AND NOT EXISTS (SELECT 1 FROM gc_sessions sub_s WHERE s.user = sub_s.user
AND ((date(starttime) = CURDATE() - INTERVAL 1 DAY)
OR (date(endtime) = CURDATE() - INTERVAL 1 DAY)))
THEN 1 ELSE 0 END) AS FridayAndWednesdayButNotThursday,
SUM(CASE WHEN
EXISTS (SELECT 1 FROM gc_sessions sub_s WHERE s.user = sub_s.user
AND ((date(starttime) = CURDATE() - INTERVAL 3 DAY) /* minus 3 days to get tuesday*/
OR (date(endtime) = CURDATE() - INTERVAL 3 DAY)))
/*this is the same as before, we check again that the user was not online between today and tuesday, but this time we really use BETWEEN for convenience*/
AND NOT EXISTS (SELECT 1 FROM gc_sessions sub_s WHERE s.user = sub_s.user
AND ((date(starttime) BETWEEN CURDATE() - INTERVAL 2 DAY AND CURDATE() - INTERVAL 1 DAY)
OR (date(endtime) BETWEEN CURDATE() - INTERVAL 2 DAY AND CURDATE() - INTERVAL 1 DAY)))
THEN 1 ELSE 0 END) AS FridayAndTuesdayButNotThursdayAndNotWednesday,
.../*and so on*/
FROM gc_sessions s
WHERE DATE(starttime) = CURDATE() OR DATE(endtime) = CURDATE()
So, I hope you get the idea now. Any more questions? Feel free to ask.
end of update
Answer to previous version of question:
select
SUM(CASE WHEN EXISTS (SELECT 1 FROM gc_sessions sub_s WHERE s.user = sub_s.user
AND ((date(starttime) = CURDATE() - INTERVAL 1 DAY)
OR (date(starttime) = CURDATE() - INTERVAL 1 DAY)))
THEN 1 ELSE 0 END) AS todayAndYesterday,
SUM(CASE WHEN EXISTS (SELECT 1 FROM gc_sessions sub_s WHERE s.user = sub_s.user
AND ((date(starttime) BETWEEN CURDATE() - INTERVAL 2 DAY AND CURDATE() - INTERVAL 1 DAY)
OR (date(starttime) BETWEEN CURDATE() - INTERVAL 2 DAY AND CURDATE() - INTERVAL 1 DAY)))
THEN 1 ELSE 0 END) AS todayAndYesterdayOrTheDayBeforeYesterday,
SUM(CASE WHEN EXISTS (SELECT 1 FROM gc_sessions sub_s WHERE s.user = sub_s.user
AND ((date(starttime) BETWEEN CURDATE() - INTERVAL 7 DAY AND CURDATE() - INTERVAL 1 DAY)
OR (date(starttime) BETWEEN CURDATE() - INTERVAL 7 DAY AND CURDATE() - INTERVAL 1 DAY)))
THEN 1 ELSE 0 END) AS todayAndWithinTheLastWeek
from gc_sessions s
where date(starttime) = CURDATE()
or date(endtime) = CURDATE()
Instead of relying on session table, I suggest you to create separate table, which stores 2 fields, date and user_id.
Every time user logs-in you need to insert new entry into this table.
This way you will be able to retrieve all the 3 requirement of yours.
Example table:
CREATE TABLE `test`.`user_login_history` (
`id` INTEGER UNSIGNED NOT NULL AUTO_INCREMENT,
`userid` INTEGER UNSIGNED NOT NULL,
`date` DATETIME NOT NULL,
PRIMARY KEY (`id`)
)
ENGINE = InnoDB;
Once a user login, check whether he/she has login today or not:
select count(*) from user_login_history where
userid = 1 and `date` = '2013-01-28 00:00:00';
If the returned value is 1, means he/she has login today. no changes needed.
but, if the returned value is 0, means he/she has not login today. So record it down.
insert into user_login_history(userid,`date`)values(1,'2013-01-28 00:00:00');
Q1. How many users were online TODAY that were also online YESTERDAY?
select count(*) from user_login_history u where
u.`date` = '2013-01-28 00:00:00' and
(
select count(*) from user_login_history v where
v.`date` = '2013-01-27 00:00:00' and
v.userid = u.userid
) = 1;
Q2. How many users were online TODAY that were also online within in the last TWO DAYS
select count(*) from user_login_history u where
u.`date` = '2013-01-28 00:00:00' and
(
select count(*) from user_login_history v where
v.`date` >= '2013-01-26 00:00:00' and
v.`date` <= '2013-01-27 00:00:00' and
v.userid = u.userid
) > 0;
Q3. How many users were online TODAY that were also online within the last 7 DAYS
select count(*) from user_login_history u where
u.`date` = '2013-01-28 00:00:00' and
(
select count(*) from user_login_history v where
v.`date` >= '2013-01-21 00:00:00' and
v.`date` <= '2013-01-27 00:00:00' and
v.userid = u.userid
) > 0;
For yesterday
select id from gc_sessions where id in
(
select id
from gc_sessions
where starttime > subdate(current_date, 2)
and endtime < subdate(current_date, 1)
)
and starttime > subdate(current_date, 1);
For 2 Days
select id from gc_sessions where id in
(
select id
from gc_sessions
where starttime > subdate(current_date, 3)
and endtime < subdate(current_date, 1)
)
and starttime > subdate(current_date, 1);
For 7 Days
select id from gc_sessions where id in
(
select id
from gc_sessions
where starttime > subdate(current_date, 8)
and endtime < subdate(current_date, 1)
)
and starttime > subdate(current_date, 1);
You need to add a subquery that loads the data from the specified range (eg, 1day/2day/7days) and compares it with the data for the current day.
set #range = 7;
select * from gc_sessions
WHERE user in (SELECT user from gc_sessions
where starttime between subdate(current_date, #range) AND subdate(current_date, 1))
AND starttime > subdate(current_date, 0)
Where #range holds information about the number of days. See your expanded sql fiddle at - http://sqlfiddle.com/#!2/9584b/24
SELECT today.user
, GROUP_CONCAT(DISTINCT today.ip) ip
FROM gc_sessions today
JOIN gc_sessions yesterday
ON DATE(yesterday.starttime) = DATE(today.starttime) - INTERVAL 1 DAY
AND today.user = yesterday.user
WHERE DATE(today.starttime) = '2013-01-10'
GROUP
BY today.user;
I am doing a query to get the number of builds per day from our database for the last 30 days. But it has become needed to marked days where there were no builds also.
In my WHERE clause I use submittime to determine whether there were builds, how could I modify this to include days that have COUNT(id) == 0 but only in the last 30 days.
Original Query:
SELECT COUNT(id) AS 'Past-Month-Builds',
CONCAT(MONTH(submittime), '-', DAY(submittime)) as 'Month-Day'
FROM builds
WHERE DATE(submittime) >= DATE_SUB(CURDATE(), INTERVAL 30 day)
GROUP BY MONTH(submittime), DAY(submittime);
What I've Tried:
SELECT COUNT(id) AS 'Past-Month-Builds',
CONCAT(MONTH(submittime), '-', DAY(submittime)) as 'Month-Day'
FROM builds
WHERE DATE(submittime) >= DATE_SUB(CURDATE(), INTERVAL 30 day)
OR COUNT(id) = 0
GROUP BY MONTH(submittime), DAY(submittime);
You need a table of dates, then left join to the builds table.
Something like this:
SELECT
COUNT(id) AS 'Past-Month-Builds',
CONCAT(MONTH(DateTable.Date), '-', DAY(DateTable.Date)) as 'Month-Day'
FROM DateTable
LEFT JOIN builds ON DATE(builds.submittime) = DateTable.Date
WHERE DateTable.Date >= DATE_SUB(CURDATE(), INTERVAL 30 day)
GROUP BY MONTH(submittime), DAY(submittime);