Is there a way to assign instance variables declared in a super class, from a constructor in a sub class? I have gotten used to using BUILD() as constructor, but I am wondering if this is a good idea. I.e:
use v6;
class File
{
has $!filename;
}
class XmlFile is File
{
submethod BUILD(:$!filename)
{
}
}
my XmlFile $XF = XmlFile.new(filename => "test.xml");
The code above doesn’t work, prompting an error: "Attribute $!filename not declared in class XmlFile". Is it a matter of using the right accesser? Changing "!" to "." does not solve the problem.
You're halfway there. You have to make the correct two changes to your code:
class File {
has $.filename; # 1. Replace `!` with `.`
}
class XmlFile is File {
submethod BUILD(:$filename) { } # 2. Remove `!`
}
dd my XmlFile $XF = XmlFile.new(filename => "test.xml");
# XmlFile $XF = XmlFile.new(filename => "test.xml")
Replacing $!filename with $.filename in the File class generates a public accessor method (.filename) in that class.
(Note that attributes are technically always private to a class, i.e. always unavailable to other classes, even trusted ones. When you see the phrase "public attribute" it really means there's a "public accessor" that controls access to a corresponding underlying private attribute.)
Removing the ! twigil from the BUILD signature in the XmlFile class means you're no longer trying to reference a non-existent XmlFile attribute and instead just passing a named argument.
Per Object Construction:
Due to the default behavior of BUILDALL and BUILD submethods, named arguments to the constructor new derived from Mu can correspond directly to public attributes of any of the classes in the method resolution order, or to any named parameter of any BUILD submethod.
(There's that "public attribute" misnomer. It means "attributes with a matching public accessor".)
If you would like it to remain private, you can always add it directly to the subclass as well. (Perhaps you don't control the class you are subclassing?) You will, of course, have to be careful about which methods do which things between your class and subclass.
class File
{
has $!filename;
}
class XmlFile is File
{
has $!filename;
submethod BUILD(:$!filename)
{
}
}
my XmlFile $XF = XmlFile.new(filename => "test.xml");
You may also want to consider using a 'has a' relationship instead of a 'is a' relationship by making an attribute of class XmlFile that holds a class File depending on what you are trying to do.
The handles trait makes delegation to another class a particularly easy and useful option to direct subclassing.
class XmlFile
{
has File $!file handles<some methods>;
...
}
Related
I'd like to use ES6 public class fields:
class Superclass {
constructor() {
// would like to write modular code that applies to all
// subclasses here, or similarly somewhere in Superclass
this.example++; // does NOT WORK (not intialized)
//e.g. doStuffWith(this.fieldTemplates)
}
}
class Subclass extends Superclass {
example = 0
static fieldTemplates = [
Foo,
function() {this.example++},
etc
]
}
Problem:
ES6 public fields are NOT initialized before the constructors, only before the current constructor. For example, when calling super(), any child field will not yet have been defined, like this.example will not yet exist. Static fields will have already been defined. So for example if one were to execute the code function(){this.example++} with .bind as appropriate, called from the superclass constructor, it would fail.
Workaround:
One workaround would be to put all initialization logic after all ES6 public classes have been properly initialized. For example:
class Subclass extends Superclass {
example = 0
lateConstructor = (function(){
this.example++; // works fine
}).bind(this)()
}
What's the solution?
However, this would involve rewriting every single class. I would like something like this by just defining it in the Superclass.constructor, something magic like Object.defineProperty(this, 'lateConstructor', {some magic}) (Object.defineProperty is allegedly internally how es6 static fields are defined, but I see no such explanation how to achieve this programatically in say the mozilla docs; after using Object.getOwnPropertyDescriptor to inspect my above immediately-.binded-and-evaluated cludge I'm inclined to believe there is no way to define a property descriptor as a thunk; the definition is probably executed after returning from super(), that is probably immediately evaluated and assigned to the class like let exampleValue = eval(...); Object.defineProperty(..{value:exampleValue})). Alternatively I could do something horrible like do setTimeout(this.lateConstructor,0) in the Superclass.constructor but that would break many things and not compose well.
I could perhaps try to just use a hierarchy of Objects everywhere instead, but is there some way to implement some global logic for all subclasses in the parent class? Besides making everything lazy with getters? Thanks for any insight.
References:
Run additional action after constructor -- (problems: this requires wrapping all subclasses)
Can I create a thunk to run after the constructor?
No, that is not possible.
How to run code after class fields are initialized, in a sane way?
Put the code in the constructor of the class that defines those fields.
Is there some way to implement some global logic for all subclasses in the parent class?
Yes: define a method. The subclass can call it from its constructor.
Just thought of a workaround (that is hierarchically composable). To answer my own question, in a somewhat unfulfilling way (people should feel free to post better solutions):
// The following illustrates a way to ensure all public class fields have been defined and initialized
// prior to running 'constructor' code. This is achieved by never calling new directly, but instead just
// running Someclass.make(...). All constructor code is instead written in an init(...) function.
class Superclass {
init(opts) { // 'constructor'
this.toRun(); // custom constructor logic example
}
static make() { // the magic that makes everything work
var R = new this();
R.init(...arguments);
return R;
}
}
class Subclass extends Superclass {
subclassValue = 0 // custom public class field example
init(toAdd, opts) { // 'constructor'
// custom constructor logic example
this.subclassValue += toAdd; // may use THIS before super.init
super.init(opts);
// may do stuff afterwards
}
toRun() { // custom public class method example
console.log('.subclassValue = ', this.subclassValue);
}
}
Demo:
> var obj = Subclass.make(1, {});
.subclassValue = 1
> console.log(obj);
Subclass {
subclassValue: 1
__proto__: Superclass
}
I want to apply a new class to the same var name.
My code:
public var One:Word;
//later called
One = new Word();
// later changed
One = new redWord();
How do I change the var "One" from the class name "Word" to the new class name "redWord"?
You can use class wildcards if you want to be able to assign variables of multiple types to a var:
public var One:*;
Alternatively if both of your classes extend the same class you can use that as the base class for your var:
public class Words{
...
}
public class Poem extends Words{
...
}
public class Prose extends Words{
...
}
public var Soliloquy:Words;
By convention, variable names use lower case and class names use upper case. I would recommend changing One to one and redWord to RedWord.
To be able to assign to One instances of both Word and redWord, it must be declared of a type that is compatible with both. A possibility would be Object, but that may be too generic. Check if there is a common superclass to Word and redWord, and make One of that type.
The more specific your type is, the more errors you will discover at compile time, and the less nasty surprises you will be likely to find at runtime.
Using this abstract class:
#JsonTypeInfo(use = Id.NAME, include = As.PROPERTY, property = "type")
#JsonSubTypes({ #JsonSubTypes.Type(value = PostingTaskInstanceDto.class, name = "TI") })
public abstract class BasePostingDto {}
and this inherited class:
public class PostingTaskInstanceDto extends BasePostingDto {}
I get correct serialization for a single object. This works, using Spring-MVC:
#RequestMapping("/{id}")
#ResponseBody
public BasePostingDto findById(#PathVariable("id") Long id) {
return createDto(postingService.findById(id));
}
But if I retrieve a List of BasePostingDto from the remote controller, the type property is missing:
#RequestMapping("/by-user/all")
#ResponseBody
public List<BasePostingDto> findByUser() {
return createDtoList(postingService.findByUser(AuthUtils.getUser()));
}
Why is this and how can I force the type property?
Update: the type property is also included if I change List<BasePostingDto> to BasePostingDto[], however I would prefer to go with the List.
It sounds like the framework you are using (and which uses Jackson under the hood) is not passing full generics-aware type information.
I don't know how that can be fixed (it is problem with integration by framework, and not something Jackson can address), but the usual work around is for you to use sub-class of List:
public class PostingDtoList extends List<BasePostingDto> { }
and use that in signature, instead of generic type. This solves the issue because then the generic type signature is retained (since it is stored in super type declaration, and accessible via type-erased PostingDtoList class!).
In generally I think it is best to avoid using generic List and Map types as root type (and instead use POJO); partly because of problems issued (there are bigger problems when using XML for example). But it can be made to work if need be.
I need a little help understanding how classes work in Actionscript 3. I understand you start with "package" and why and then go to import any necessary libraries, as well as then naming the class and stating if it's public/private and extends anything.
After that is what I don't understand. It seems you write "(public) function class name()
I don't understand why you do this and what goes in the curly brackets.
I've probably missed a bit of earlier reading because I've done a little reading but I can't seem to get it.
Could someone try explain it to me? Thanks.
ActionScript 3 Classes
The package statement.
Okay, so firstly like you mentioned, a class must be wrapped by a package1. This gives us the first block, where you need to define the class.
package
{
// Your class here.
}
The package statement reflects the location of the class relative to the .fla2. For example, if you have a folder "classes" within the same directory as the project .fla, then classes within that folder will need a package statement that reflects that:
package classes
{
// Your class here.
}
Defining the class.
Within a package statement, you may insert one class. Do not confuse this with the package itself, which can contain many classes - each class just needs to have its own file with the same package statement.
A class definition is made up of up to 5 parts:
The namespace. A class can be internal or public. An internal class can only be seen by classes within the same package, whereas public classes can be seen from anywhere in the project.
The class name.
A base class (optional). If a base class is defined, then your new class will act as an extension to that class, inheriting all of the qualities of the base class.
An interface to implement (optional). Interfaces are an advanced topic thus I suggest you forget about these for now until your AS3 and OOP have evolved.
If you wanted to create a class called "Person" within the package classes, then we would end up with:
package classes
{
public class Person
{
// Class qualities here.
}
}
Properties.
Classes can contain properties. Properties are defined using the var keyword. They may belong to one of a number of namespaces (including your own) and are used to hold values that belong to your class. Properties are most commonly found clustered together at the top of your class.
Our Person class may enjoy the properties height and weight:
package classes
{
public class Person
{
// Properties.
public var height:Number = 1.70;
public var weight:Number = 67.5;
}
}
These properties can be accessed via any instance of Person that you create. Each instance will have its own set of these properties.
Class constructors (I believe this is what you're asking about).
Constructors are used to hold logic that should be run as soon as an instance of your class is created. The class constructor has the same name as the class itself. It must be public and it does not return anything. Constructors can accept arguments, which are typically used to pass in references to dependencies for that class or required values.
package classes
{
public class Person
{
// Properties.
public var height:Number = 1.70;
public var weight:Number = 67.5;
// Constructor.
public function Person(height:Number, weight:Number)
{
this.height = height;
this.weight = weight;
}
}
}
Methods.
Methods are used to hold logic that can be run when calling that method. Methods often return values and can accept arguments. Methods can belong to any namespace that you would expect properties to be able to belong to.
We may want to be able to easily determine the BMI of each instance of Person that we create, so we should create a method for that:
package classes
{
public class Person
{
// Properties.
public var height:Number = 170;
public var weight:Number = 65.5;
// Constructor.
public function Person(height:Number, weight:Number)
{
this.height = height;
this.weight = weight;
}
// Determine my BMI and return the result.
public function getBMI():Number
{
return weight / (height * height);
}
}
}
Instances.
Now that we've defined our new class, we can create instances of this class using the new keyword. This can be done from anywhere that can access the Person class, which in this case is anywhere in the project because we've made the class public.
Though the class is public, accessing it from anywhere outside of the package it belongs in will require the use of an import statement. This statement will need to be used within any class that belongs to a different package. The import statement follows the same name used for the package and includes the name of the class you want to include on the end:
import classes.Person;
Once you've imported Person, you can create instances of it and assign them to a variable with different height and weight values:
var marty:Person = new Person(71, 1.76);
var bruce:Person = new Person(96.4, 1.72);
We can then obtain the BMI for each person using their getBMI() method:
trace(marty.getBMI()); // 22.9
trace(bruce.getBMI()); // 32.6
1 You can place classes outside of a package which can be referred to in the same .as file.
2 You can add more source paths, and packages can be relative to that.
The function that have the same name as class is a constructor. In curly brackets is basically part of code that will execute instantly when object will be created. Try to search info about constructors, they exist I think in every object oriented programming language (I may be wrong), so you have a lot of resources.
You can also read about this concept on Wikipedia.
The function that is named the same as the class is the constructor. It's optional, so you can leave it out if you don't need it. A default constructor will be added, which essentially does nothing.
The constructor lets you write code that executes immediately after an instance of the class is created (ie when another bit of code runs new ClassName(). You would typically use it to initialise some variables that are used by the class. Defining a constructor also lets you handle constructor arguments, which other code can pass when they use the new operator.
So I have made this simple interface:
package{
public interface GraphADT{
function addNode(newNode:Node):Boolean;
}
}
I have also created a simple class Graph:
package{
public class Graph implements GraphADT{
protected var nodes:LinkedList;
public function Graph(){
nodes = new LinkedList();
}
public function addNode (newNode:Node):Boolean{
return nodes.add(newNode);
}
}
last but not least I have created another simple class AdjacancyListGraph:
package{
public class AdjacancyListGraph extends Graph{
public function AdjacancyListGraph(){
super();
}
override public function addNode(newNode:AwareNode):Boolean{
return nodes.add(newNode);
}
}
Having this setup here is giving me errors, namely:
1144: Interface method addNode in namespace GraphADT is implemented with an incompatible signature in class AdjacancyListGraph.
Upon closer inspection it was apparent that AS3 doesn't like the different parameter types from the different Graph classes newNode:Node from Graph , and newNode:AwareNode from AdjacancyListGraph
However I don't understand why that would be a problem since AwareNode is a subClass of Node.
Is there any way I can make my code work, while keeping the integrity of the code?
Simple answer:
If you don't really, really need your 'addNode()' function to accept only an AwareNode, you can just change the parameter type to Node. Since AwareNode extends Node, you can pass in an AwareNode without problems. You could check for type correctness within the function body :
subclass... {
override public function addNode (node:Node ) : Boolean {
if (node is AwareNode) return nodes.add(node);
return false;
}
}
Longer answer:
I agree with #32bitkid that your are getting an error, because the parameter type defined for addNode() in your interface differs from the type in your subclass.
However, the main problem at hand is that ActionScript generally does not allow function overloading (having more than one method of the same name, but with different parameters or return values), because each function is treated like a generic class member - the same way a variable is. You might call a function like this:
myClass.addNode (node);
but you might also call it like this:
myClass["addNode"](node);
Each member is stored by name - and you can always use that name to access it. Unfortunately, this means that you are only allowed to use each function name once within a class, regardless of how many parameters of which type it takes - nothing comes without a price: You gain flexibility in one regard, you lose some comfort in another.
Hence, you are only allowed to override methods with the exact same signature - it's a way to make you stick to what you decided upon when you wrote the base class. While you could obviously argue that this is a bad idea, and that it makes more sense to use overloading or allow different signatures in subclasses, there are some advantages to the way that AS handles functions, which will eventually help you solve your problem: You can use a type-checking function, or even pass one on as a parameter!
Consider this:
class... {
protected function check (node:Node) : Boolean {
return node is Node;
}
public function addNode (node:Node) : Boolean {
if (check(node)) return nodes.add(node);
return false;
}
}
In this example, you could override check (node:Node):
subclass... {
override protected function check (node:Node) : Boolean {
return node is AwareNode;
}
}
and achieve the exact same effect you desired, without breaking the interface contract - except, in your example, the compiler would throw an error if you passed in the wrong type, while in this one, the mistake would only be visible at runtime (a false return value).
You can also make this even more dynamic:
class... {
public function addNode (node:Node, check : Function ) : Boolean {
if (check(node)) return nodes.add(node);
return false;
}
}
Note that this addNode function accepts a Function as a parameter, and that we call that function instead of a class method:
var f:Function = function (node:Node) : Boolean {
return node is AwareNode;
}
addNode (node, f);
This would allow you to become very flexible with your implementation - you can even do plausibility checks in the anonymous function, such as verifying the node's content. And you wouldn't even have to extend your class, unless you were going to add other functionality than just type correctness.
Having an interface will also allow you to create implementations that don't inherit from the original base class - you can write a whole different class hierarchy, it only has to implement the interface, and all your previous code will remain valid.
I guess the question is really this: What are you trying to accomplish?
As to why you are getting an error, consider this:
public class AnotherNode extends Node { }
and then:
var alGraph:AdjacancyListGraph = new AdjacancyListGraph();
alGraph.addNode(new AnotherNode());
// Wont work. AnotherNode isn't compatable with the signature
// for addNode(node:AwareNode)
// but what about the contract?
var igraphADT:GraphADT = GraphADT(alGraph);
igraphADT.addNode(new AnotherNode()); // WTF?
According to the interface this should be fine. But your implemenation says otherwise, your implemenation says that it will only accept a AwareNode. There is an obvious mismatch. If you are going to have an interface, a contract that your object should follow, then you might as well follow it. Otherwise, whats the point of the interface in the first place.
I submit that architecture messed up somewhere if you are trying to do this. Even if the language were to support it, I would say that its a "Bad Idea™"
There's an easier way, then suggested above, but less safe:
public class Parent {
public function get foo():Function { return this._foo; }
protected var _foo:Function = function(node:Node):void { ... }}
public class Child extends Parent {
public function Child() {
super();
this._foo = function(node:AnotherNode):void { ... }}}
Of course _foo needs not be declared in place, the syntax used is for shortness and demonstration purposes only.
You will loose the ability of the compiler to check types, but the runtime type matching will still apply.
Yet another way to go about it - don't declare methods in the classes they specialize on, rather make them static, then you will not inherit them automatically:
public class Parent {
public static function foo(parent:Parent, node:Node):Function { ... }}
public class Child extends Parent {
public static function foo(parent:Child, node:Node):Function { ... }}
Note that in second case protected fields are accessible inside the static method, so you can achieve certain encapsulation. Besides, if you have a lot of Parent or Child instances, you will save on individual instance memory footprint (as static methods therefore static there exists only one copy of them, but instance methods would be copied for each instance). The disadvantage is that you won't be able to use interfaces (can be actually an improvement... depends on your personal preferences).