How to Write query for MySQL - mysql

Question

I have two tables as:
mysql> select * from survey;
+-----------+-----------+----------+--------+-----------+
| survey_id | client_id | stage_id | by_ref | no_branch |
+-----------+-----------+----------+--------+-----------+
| 2 | 65 | 72 | P | 15 |
| 3 | 67 | 72 | D | 2 |
+-----------+-----------+----------+--------+-----------+
2 rows in set (0.07 sec)
mysql> select * from allcode where code_type="MARKETING_STAGES";
+------------------+---------+------+--------------------+
| code_type | code_id | srno | code_name |
+------------------+---------+------+--------------------+
| MARKETING_STAGES | 72 | 1 | Enquiry |
| MARKETING_STAGES | 73 | 3 | Meeting |
| MARKETING_STAGES | 74 | 4 | Presentation |
| MARKETING_STAGES | 75 | 5 | Review / Follow up |
| MARKETING_STAGES | 76 | 6 | Negotiation |
| MARKETING_STAGES | 77 | 7 | Order |
| MARKETING_STAGES | 78 | 8 | Agreement |
| MARKETING_STAGES | 162 | 9 | Complete |
| MARKETING_STAGES | 163 | 2 | Tender |
+------------------+---------+------+--------------------+
9 rows in set (0.04 sec)
I want to update stage_id of survey table to next value which will be fetch from allcode code_id.
Right now I have client_id i.e. 65 from survey table, and want to update stage_id to 163 ( i.e. Next code_id from allcode table on sorting based on srno )
What I have tried till is
update survey as s
set s.stage_id=
(select code_id from allcode
where code_id > (select stage_id from (select * from survey where client_id=65 )as su)
and code_type="MARKETING_STAGES"
limit 1)
where client_id=65;
This query update stage_id of allcode to 73 and I want it to be updated to 163 (Depending on srno)

Answer 1

I would use joins in the update to get the next code_id based on srno:
update survey s
inner join allcode a1 on s.stage_id=a1.code_id
inner join allcode a2 on a1.srno=a2.srno-1
set s.stage_id=a2.code_id
where a1.code_type='MARKETING_STAGES' and a2.code_type='MARKETING_STAGES' and s.client_id=65
I assumed that srno field increments by 1 without any gaps. The purpose of the 1st join is to get the current stage_id's srno. Then the 2nd join gets the stage_id for the next srno.

Answer 2

You were missing an order by before limit in subquery.
So without touching your rest of the query, I just tried adding an order by and it seems to update first stage id from 72 to 163 as you want.
Rextester Demo
update survey as s
set s.stage_id=
(select code_id from allcode
where code_id > (select stage_id from (select * from survey where client_id=65 )as su)
and code_type="MARKETING_STAGES"
ORDER BY SRNO
limit 1)
where client_id=65;