I'm trying to export just one object with mongoexport, filtering by its ID.
I tried:
mongoexport -d "kb_development" -c "articles" -q "{'_id': '4e3ca3bc38c4f10adf000002'}"
and many variations, but it keeps saying
connected to: 127.0.0.1
exported 0 records
(and I'm sure there is such an object in the collection)
In mongo shell I would use ObjectId('4e3ca3bc38c4f10adf000002'), but it does not seem to work in the mongoexport query.
I think you should be able to use ObjectId(...) in the query argument to mongoexport:
mongoexport -d kb_development -c articles -q '{_id: ObjectId("4e3ca3bc38c4f10adf000002")}'
If that does not work, you can use the "strict mode" javascript notation of ObjectIds, as documented here:
mongoexport -d kb_development -c articles -q '{_id: {"$oid": "4e3ca3bc38c4f10adf000002"}}'
(Also note that strict mode JSON is the format produced by mongoexport)
You have to specify the _id field by using the ObjectId type. In your question it was specified as a string.
CODE ::
mongoexport -h localhost -d my_database -c sample_collection -q '{key:ObjectId("50584580ff0f089602000155")}' -o my_output_file.json
NOTE :: dont forgot quotes in query
My MongoDB verion: 3.2.4. when I use mongoexport tool in mongo shell：
NOT WORK:
-q '{"_id":ObjectId("5719cd12b1168b9d45136295")}'
-q '{_id: {"$oid": "5719cd12b1168b9d45136295"}}'
WORKs:
-q "{_id:ObjectId('5719cd12b1168b9d45136295')}"
- Though in mongo doc , it says that
You must enclose the query in single quotes (e.g. ') to ensure that it
does not interact with your shell environment.
- But, single quote(') does not work! please use double quote(")!
for mongoexport version: r4.2.3
mongoexport -q '{"_id": {"$oid": "4e3ca3bc38c4f10adf000002"}}'
and for a nested field
mongoexport -q '{"_id": {"$oid": "4e3ca3bc38c4f10adf000002"}}' --fields parentField.childField
You do not have to add ObjectId or $oid as suggested by answers above. As has been mentioned by #Blacksad, just get your single and double quotes right.
mongoexport -d kb_development -c articles -q '{_id:"4e3ca3bc38c4f10adf000002"}'
many of the answers provided here didn't work for me, the error was with my double quotes. Here is what worked for me:
mongoexport -h localhost -d database_name -c collection_name -q {_id:ObjectId('50584580ff0f089602066633')} -o output_file.json
remember to use single quote only for the ObjectId string.
Related
I am new to shell scripting and MQTT.
I need to publish a JSON file using MQTT. We can do it by storing the JSON contents in a shell variable. But it is not working for me.
my shell script:
#!/bin/sh
var1='{"apiVersion":"2.1","data":{"id":"4TSJhIZmL0A","uploaded":"2008-07-15T18:11:59.000Z","updated":"2013-05-01T21:01:49.000Z","uploader":"burloandbardsey","category":"News","title":"bbc news start up theme","description":"bbc","thumbnail":{"sqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/default.jpg","hqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/hqdefault.jpg"},"player":{"default":"http://www.youtube.com/watch?v=4TSJhIZmL0A&feature=youtube_gdata_player","mobile":"http://m.youtube.com/details?v=4TSJhIZmL0A"},"content":{"5":"http://www.youtube.com/v/4TSJhIZmL0A?version=3&f=videos&app=youtube_gdata","1":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp","6":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYESARFEgGUgZ2aWRlb3MM/0/0/0/video.3gp"},"duration":15,"aspectRatio":"widescreen","rating":4.6683936,"likeCount":"354","ratingCount":386,"viewCount":341066,"favoriteCount":0,"commentCount":155,"accessControl":{"comment":"allowed","commentVote":"allowed","videoRespond":"allowed","rate":"allowed","embed":"allowed","list":"allowed","autoPlay":"allowed","syndicate":"allowed"}}}'
mosquitto_pub -h localhost -t test -m "$var1"
echo "$var1"
my Mosquitto commands:
Publisher: `mosquitto_pub -h localhost -t "test" -m "{"Contents":$var1}"
Subscriber: mosquitto_sub -h localhost -t "test"
Output I got:
{"Contents":}
Expected Output:
{"Contents":{"name":"Harini", "age":24, "city":"NewYork", "message":"Hello world"}}
I can get the output only at the terminal because of echo. But I want to publish and subscribe to the contents of the shell variable(var1)
Please help me out to get the output. Whether I need to add some more code in the shell script. I don't know how to proceed. Or can you suggest any other method.
The following works just fine, it's all about which quotes you use where:
#!/bin/sh
var1='{"name":"Harini", "age":24, "city":"NewYork","message":"Hello world"}'
echo $var1
mosquitto_pub -t test -m "{\"Content\": $var1}"
You need to wrap the -m argument in quotes because it contains spaces, which in turn means you need to escape the " round Content.
Wrapping the content of var1 in single quotes means you don't need to escape the double quotes in it.
I'm trying to write a sample script where I'm generating names like 'student-101...student-160'. I need to post JSON data and when I do, I get a JSON parse error.
Here's my script:
name="student-10"
for i in {1..1}
do
r_name=$name$i
echo $r_name
curl -i -H 'Authorization: token <token>' -d '{"name": $r_name, "private": true}' "<URL>" >> create_repos_1.txt
echo created $r_name
done
I always get a "Problems parsing JSON" error. I've tried various combination of quotes, etc but nothing seems to work!
What am I doing wrong?
First, your name property is a string, so you need to add double quotes to it in your json.
Second, using single quotes, bash won't do variable expansion: it won't replace $r_name with the variable content (see Expansion of variable inside single quotes in a command in bash shell script for more information).
In summary, use:
-d '{"name": "'"$r_name"'", "private": true}'
Another option is to use printf to create the data string:
printf -v data '{"name": "%s", "private": true}' "$r_name"
curl -i -H 'Authorization: token <token>' -d "$data" "$url" >> create_repos_1.txt
Don't; use jq (or something similar) to build correctly quoted JSON using variable inputs.
name="student-10"
for i in {1..1}
do
r_name=$name$i
jq -n --arg r_name "$r_name" '{name: $r_name, private: true}' |
curl -i -H 'Authorization: token <token>' -d #- "<URL>" >> create_repos_1.txt
echo created $r_name
done
The #- argument tells curl to read data from standard input (via the pipe from jq) to use for -d.
Something like "{\"name\": \"$r_name\", \"private\": true}" may work, but it is ugly and will also fail if r_name contains any character which needs to be quoted in the resulting JSON, such as double quotes or ASCII control characters.
How can I change this curl command to make it work
It is something about using the $# param that github starts complaining
function create_repo(){
curl -u 'USER' https://api.github.com/user/repos -d '{"name":$#}'
}
It works if I hardcode the param as a string
Your command uses a singly-quoted string, inside which variables are usually not interpolated (though you haven't specified a particular shell).
Try this instead:
function create_repo(){
curl -u 'USER' https://api.github.com/user/repos -d "{\"name\":\"$#\"}"
}
Note that we use \" instead of ' for our inner quotes because JSON requires double quotes.
i am trying to run following curl command from my ruby code
Kernel.system'curl -H "Content-Type:application/json" -H "Accept:application/json" -d "{\"project\":{\"name\":\"BB\",\"description\":\"Book\"}}" "http://localhost:3000/company/projects?auth_token=mRFWyxfdPKHsDb4HhyLP"'
I want to do something like
name = "BB"(using a variable)
and then executing
Kernel.system'curl -H "Content-Type:application/json" -H "Accept:application/json" -d "{\"project\":{\"name\":"#{name}",\"description\":\"Book\"}}" "http://localhost:3000/company/projects?auth_token=mRFWyxfdPKHsDb4HhyLP"'
but this approach is not working...its taking #{name} as string.
Please help me with this.Let me know if i am doing something wrong.
Thanks.
in order to enable string interpolation you will need to use double quotes in your string. The topic has been covered here: Double vs single quotes
also it would make your code better to read if you refactored it and assigned the parts to variables before joining them together into one string.
so:
host_name = 'stackoverflow.com'
Kernel.system 'curl -I #{host_name}'
will not work
whereas
Kernel.system "curl -I #{host_name}"
will
I want to export collection in mongodb using shell command:
I try the following command but fields with ":" (number:phone, number:fax) are not exported.
mongoexport --csv -d schemaName -c collectionName -q "{typeName:'user'}" -f "name, surname, e-mail, number:phone, number:fax" -o export.csv
I think that you have found a legitimate bug. The mongoexport tool is rarely used and the colon means something very specific when parsing JSON, so the tool is probably confused.
You can file the bug here: http://jira.mongodb.org/