Of course, for this i used JsonParser, Here is my Code:
JsonParser parser = new JsonParser();
Object object = parser.parse(new FileReader("c:\\Projects\\elastic-search-single-log-result.json"));
JsonObject jobject = (JsonObject) object;
String message = jobject.get("msg").toString();
return message;
However, the msg is a stack trace enclosed by triple quotes, and it gives me a Malformed Json Exception, at the second line shown above.
I saw stuff about JsonReader having a getLenientMethod, I was wondering if there was something similar for this.
I fixed it --- I simply had to remove the triple quotes, and I get the JSON file from kibana (which formatted the stack trace a little differently). I hope this helps anyone in the future who will have the same problem
Related
I want to know how to convert a string of compact Json to pretty print so that I can parse it. I have searched for this question in stack overflow but it doesn't seem like anyone has asked it for codename one.
Right now I have a string of compact Json but it can not be parsed. This is the code:
String JsonData = "{\"document\":{ \"type\":\"PLAIN_TEXT\", \"content\":\"Ask not what your country can do for you, ask what you can do for your country.\" },\"encodingType\":\"UTF8\"}";
JsonResponse = Rest.
post("https://language.googleapis.com/v1/documents:analyzeSyntax?key=[API KEY").
jsonContent().
body(JsonData).
getAsJsonMap();
String JsonString = (JsonResponse.getResponseData()).toString();
JSONParser parser = new JSONParser();
Map<String, Object> results = null;
try {
results = parser.parseJSON(new StringReader(JsonString));
} catch (IOException e) {
e.printStackTrace();
System.out.println("fail");
}
System.out.println("results "+results);
But when I run this code I get a bunch of these responses:
[EDT] 0:0:3,269 - Expected null for key value while parsing JSON token at row: 1 column: 5 buffer: e
and
java.lang.NumberFormatException: For input string: "ee0"
How should I convert my string of compact Json (JsonString) to pretty print so that I can parse it? Alternatively, is there a way to directly parse the response (JsonResponse)?
Thank You
You are printing out a map not a JSON string as the JSON data is already parsed. If you just want to look at the network protocol for debugging the best way to do that is open the Network Monitor in the simulator where you will see all HTTP requests and can copy out the response body JSON.
However you can still convert a Map back to JSON using:
Log.p("results " + JSONParser.mapToJson(results));
Notice you should use Log.p() and Log.e() to log strings/exceptions as that would work better on the devices.
I have the following json, that is being populated by:
new Gson().toJson(batch.getProducts());
But when im adding it to my main JSONObject, the fact that it's a value of a json is doing all the json (even the keys) be escaped.
{"name":"Ufud","store":2,"products":"[{\"name\":\"Test2\",\"stock\":2,\"value\":19.9},{\"name\":\"Test2\",\"stock\":2,\"value\":19.9},{\"name\":\"Teste2\",\"stock\":2,\"value\":19.9}]"}
Is there any method to prevent this?
If you're going to manipulate your json in future you may consider converting it not into a string, but into a JsonElement which can be quite easily added to already existing JsonObject
JsonObject mainObject = getMainObject(); //method which creates your main object. You can change it to variable reference
JsonElement productsElement = new Gson().toJsonTree(batch.getProducts()); //converting your object into JsonElement
mainObject.add("products", productsElement); //insering products element into object.
String json = new Gson().toJson(mainObject); //converting object with products element into a json string
Please pardon me if this is a repeat question. I have been through some of the questions/answers with a similar requirement but somehow got a bit overwhelmed and confused at the same time. My requirement is:
I get a JSON string/object as a request parameter. ( eg: params.timesheetJSON )
I then have to parse/iterate through it.
Here is the JSON that my grails controller will be receiving:
{
"loginName":"user1",
"timesheetList":
[
{
"periodBegin":"2014/10/12",
"periodEnd":"2014/10/18",
"timesheetRows":[
{
"task":"Cleaning",
"description":"cleaning description",
"paycode":"payCode1"
},
{
"task":"painting",
"activityDescription":"painting description",
"paycode":"payCode2"
}
]
}
],
"overallStatus":"SUCCESS"
}
Questions:
How can I retrieve the whole JSON string from the request? Does request.JSON be fine here? If so, will request.JSON.timesheetJSON yield me the actual JSON that I want as a JSONObject?
What is the best way to parse through the JSON object that I got from the request? Is it grails.converters.JSON? Or is there any other easy way of parsing through? Like some API which will return the JSON as a collection of objects by automatically taking care of parsing. Or is programatically parsing through the JSON object the only way?
Like I said, please pardon me if the question is sounding vague. Any good references JSON parsing with grails might also be helpful here.
Edit: There's a change in the way I get the JSON string now. I get the JSON string as a request paramter.
String saveJSON // This holds the above JSON string.
def jsonObject = grails.converters.JSON.parse(saveJSON) // No problem here. Returns a JSONObject. I checked the class type.
def jsonArray = jsonArray.timesheetList // No problem here. Returns a JSONArray. I checked the class type.
println "*** Size of jsonArray1: " + jsonArray1.size() // Returns size 1. It seemed fine as the above JSON string had only one timesheet in timesheetList
def object1 = jsonArray[1] // This throws the JSONException, JSONArray[1] not found. I tried jsonArray.getJSONObject(1) and that throws the same exception.
Basically, I am looking to seamlessly iterate through the JSON string now.
I have wrote some code that explains how this can be done, that you can see below, but to be clear, first the answers to your questions:
Your JSON String as you wrote above will be the contents of your POST payload to the rest controller. Grails will use its data binding mechanism to bind the incomming data to a Command object that your should prepare. It has to have fields corresponding to the parameters in your JSON String (see below). After you bind your command object to your actual domain object, you can get all the data you want, by simply operating on fields and lists
The way to parse thru the JSON object is shown in my example below. The incomming request is esentially a nested map, with can be simply accessed with a dot
Now some code that illustrates how to do it.
In your controller create a method that accepts "YourCommand" object as input parameter:
def yourRestServiceMethod (YourCommand comm){
YourClass yourClass = new YourClass()
comm.bindTo(yourClass)
// do something with yourClass
// println yourClass.timeSheetList
}
The command looks like this:
class YourCommand {
String loginName
List<Map> timesheetList = []
String overallStatus
void bindTo(YourClass yourClass){
yourClass.loginName=loginName
yourClass.overallStatus=overallStatus
timesheetList.each { sheet ->
TimeSheet timeSheet = new TimeSheet()
timeSheet.periodBegin = sheet.periodBegin
timeSheet.periodEnd = sheet.periodEnd
sheet.timesheetRows.each { row ->
TimeSheetRow timeSheetRow = new TimeSheetRow()
timeSheetRow.task = row.task
timeSheetRow.description = row.description
timeSheetRow.paycode = row.paycode
timeSheet.timesheetRows.add(timeSheetRow)
}
yourClass.timeSheetList.add(timeSheet)
}
}
}
Its "bindTo" method is the key piece of logic that understands how to get parameters from the incomming request and map it to a regular object. That object is of type "YourClass" and it looks like this:
class YourClass {
String loginName
Collection<TimeSheet> timeSheetList = []
String overallStatus
}
all other classes that are part of that class:
class TimeSheet {
String periodBegin
String periodEnd
Collection<TimeSheetRow> timesheetRows = []
}
and the last one:
class TimeSheetRow {
String task
String description
String paycode
}
Hope this example is clear enough for you and answers your question
Edit: Extending the answer according to the new requirements
Looking at your new code, I see that you probably did some typos when writting that post
def jsonArray = jsonArray.timesheetList
should be:
def jsonArray = jsonObject.timesheetList
but you obviously have it properly in your code since otherwise it would not work, then the same with that line with "println":
jsonArray1.size()
shuold be:
jsonArray.size()
and the essential fix:
def object1 = jsonArray[1]
shuold be
def object1 = jsonArray[0]
your array is of size==1, the indexing starts with 0. // Can it be that easy? ;)
Then "object1" is again a JSONObject, so you can access the fields with a "." or as a map, for example like this:
object1.get('periodEnd')
I see your example contains errors, which lead you to implement more complex JSON parsing solutions.
I rewrite your sample to the working version. (At least now for Grails 3.x)
String saveJSON // This holds the above JSON string.
def jsonObject = grails.converters.JSON.parse(saveJSON)
println jsonObject.timesheetList // output timesheetList structure
println jsonObject.timesheetList[0].timesheetRows[1] // output second element of timesheetRows array: [paycode:payCode2, task:painting, activityDescription:painting description]
I am trying to parse some JSON objects which is made just of (string,string) pairs, in order to emulate Resjson behaviour. The file I am parsing contains this.
{
"greeting":"Hello world",
"_greeting.comment":"Hello comment.",
"_greeting.source":"Original Hello",
}
Please note the last comma is incorrect, and I also used http://jsonlint.com/ to test JSON syntax. It tells me it is incorrect, as I expected. My - slightly modified - code is :
string path = #"d:\resjson\example.resjson";
string jsonText = File.ReadAllText(path);
IDictionary<string, string> dict;
try
{
dict = JsonConvert.DeserializeObject<IDictionary<string, string>>(jsonText);
}
catch(Exception ex)
{
// code never reaches here
}
My above code returns the IDictionary with the 3 keys as if the formatting was correct. If I serialize back, the string obtained is without the last comma.
My questions are :
Is Newtonsoft.Json so permissive that it allows users slight errors ?
If so, can I set the permissiveness so that it is more strict ?
Is there a way to check if a string is valid JSON format, using
Newtonsoft.Json with and/or without the permissiveness?
using RestSharp is there a way to get the raw json string after it has been deserialized into an object? I need that for debugging purposes.
I'd like to see both the deserialized object and the originally received json string of that object. It's part of a much bigger json string, an item in an array and I only need that specific item json code that's got deserialized into the object.
To help you out this should work, this is a direct example of some of my work, so your's might be a bit different.
private void restClient()
{
string url = "http://apiurl.co.uk/json";
var restClient = new RestClient(url);
var request = new RestRequest(Method.GET);
request.AddParameter("apikey", "xxxxxxxxxx");
restClient.ExecuteAsync<Entry>(request, response =>
{
lstboxtop.Items.Add(response.Content);
});
}
The line lstboxtop is a listbox and using the response.content will literally print the whole api onto your app, if you call it first that would be what you are looking for