I have a "transaction_status" table:
id transaction_id status
1 12 0
2 13 0
3 12 -1
4 14 0
5 13 -1
6 15 0
[END OF TABLE]
I need to get the transaction ids which only have a record with status=0.
For example this is what I am looking for from the above table:
id transaction_id status
4 14 0
6 15 0
So far I am trying:
SELECT id, transaction_id, status
FROM transaction_status
WHERE status = 0 OR status = -1
ORDER BY status ASC
GROUP BY txn_id
HAVING status = 0
Made a small change in the having clause.
SELECT id, transaction_id, status
FROM transaction_status
WHERE status = 0 OR status = -1
GROUP BY transaction_id
HAVING min(status) = 0
I also removed order by as it does not make any sense
Use GROUP BY and in having clause check for both min and max status is 0.
Query
select `transaction_id`
from `your_table_name`
group by`transaction_id`
having min(`status`) = 0 and max(`status`) = 0;
I think the easiest way to handle this is to use conditional aggregation by transaction_id and count which IDs have only a status of 0 associated with them. Do this in a subquery, and then join back to your main table to retrieve the full matching records which you want.
SELECT t1.*
FROM transaction_status t1
INNER JOIN
(
SELECT transaction_id
FROM transaction_status
GROUP BY transaction_id
HAVING SUM(CASE WHEN status <> 0 THEN 1 ELSE 0 END) = 0
) t2
ON t1.transaction_id = t2.transaction_id
ORDER BY t1.id DESC
Related
Suppose, I have a table t1 looking like
id
value1
value2
wk_id
1
2
0
1
1
1
1
2
1
3
0
3
2
2
1
2
2
2
0
3
3
1
0
2
3
2
0
4
3
3
0
5
And I want to sum up the value1 till non-zero value appears on the value2 for first time.
End product must look like this:
id
value1
1
2
2
0
3
6
How to perform this in SQL?
If your MySQL version support window function you can try to use SUM window function with condition aggregate function be a flag to represent your logic (till non-zero value appears on the value2 for first time)
Then do condition aggregate function again.
Query #1
SELECT id,
SUM(CASE WHEN flag = 0 THEN value1 ELSE 0 END) value1
FROM (
SELECT *,
SUM(CASE WHEN value2 = 1 THEN -1 ELSE 0 END) OVER(PARTITION BY ID ORDER BY wk_id) flag
FROM T
) t1
GROUP BY id;
id
value1
1
2
2
0
3
6
View on DB Fiddle
WITH cte AS (
SELECT *,
CASE WHEN SUM(value2) OVER (partition by id ORDER BY wk_id) = 0
THEN SUM(value1) OVER (partition by id ORDER BY wk_id)
ELSE 0
END sum_value1
FROM test
ORDER BY id, wk_id
)
SELECT id, MAX(sum_value1) sum_value1
FROM cte
GROUP BY id;
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=0fcdca008e4a821f952de4d608434bcf
One option is a NOT EXISTS clause, looking for the stop row (the first row with value2 = 1).
select id, sum(value1)
from mytable
where not exists
(
select null
from mytable stoprow
where stoprow.id = mytable.id
and stoprow.wk_id <= mytable.wk_id
and stoprow.value2 = 1
)
group by id
order by id;
Aggregating on a calculated rolling total of value2 can also be done via a self-join.
select id
, sum(if(roll_tot_value2=0,value1,0)) as total
from
(
select t1a.id, t1a.wk_id, t1a.value1
, sum(t1b.value2) as roll_tot_value2
from t1 as t1a
join t1 as t1b
on t1b.id = t1a.id
and t1b.wk_id <= t1a.wk_id
group by t1a.id, t1a.wk_id, t1a.value1
) q
group by id;
id
total
1
2
2
0
3
6
Test on db<>fiddle here
You can use a subquery:
select t.id, coalesce(
(select sum(t2.value1) from t1 t2 where t2.value2 = 0 and t2.id = t.id
and (not exists (select 1 from t1 t3 where t3.value2 = 1 and t3.id = t.id)
or t2.wk_id < (select min(t4.wk_id) from t1 t4 where t4.id = t.id and t4.value2 = 1))), 0)
from t1 t group by t.id
i need a query that should first look the oldest order which has status 0 (zero). and retrieves all the similar orders of that kind(matches exact total qty, itemSku and number of distinct items ordered).
***OrdersTable***
ID OrderNumber CustomerId Status created_at
1 123456 1 0 2018-01-01
2 234567 1 0 2018-01-02
3 345678 1 0 2018-01-03
4 456789 1 0 2018-01-04
***PurchasedProductsTable***
OrderId itemSku Qty
1 1000001 1
1 1000002 2
2 1000001 3
3 1000001 1
3 1000002 2
4 1000001 3
In the above table the query should first look at the oldest (created_at ASC) order (i.e with Id 1) having status 0 (in order table). and along with that order it should retrieves all the other orders that matches the same itemSku, qty and total distinct items count (in purchasedProducts table).
here order 1 and 3 matches the same itemSKu (1000001 and 1000002) and qty ( 1 and 2) and both have (2) distinct items count respectively so order 1 and 3 should be retrived at first.and when i marked order 1 and 3 as shipped (i.e chang status to 2).
and if i run query again it should retrive similar oders. now order 2 and 4 as order 2 and 4 are similar orders. (have same itemSkus (1000001, Qty (3) and distinct items count (1)).
please help thanks
You have to go trough your tables two times :)
Something like this :
SELECT DISTINCT O2.ID
FROM OrdersTable O1
INNER JOIN PurchasedProductsTable P1 ON O1.ID = P1.OrderId
INNER JOIN PurchasedProductsTable P2 ON P1.itemSku = P2.itemSku
AND P1.Qty = P2.Qty
INNER JOIN OrdersTable O2 ON O2.ID = P2.OrderId
WHERE O1.ID =
(SELECT ID FROM OrdersTable WHERE Status = 0
ORDER BY created_at ASC LIMIT 1)
AND (SELECT COUNT(*) FROM PurchasedProductsTable WHERE OrderId = O1.ID)
= (SELECT COUNT(*) FROM PurchasedProductsTable WHERE OrderId = O2.ID)
ORDER BY O2.ID ASC;
https://www.db-fiddle.com/f/65t9GgSfqMpzNVgnrJp2TR/2
You can get the earliest order via a limit and ordered by the date.
Then you can left join to get that order and any other order that at least has the same items.
Then once you have those order id's from the sub-query result, you can get the order details.
SELECT o.*
FROM
(
SELECT DISTINCT ord2.ID as OrderId
FROM
(
SELECT ID, CustomerId, Status
FROM OrdersTable
WHERE Status = 0
ORDER BY created_at
LIMIT 1
) AS ord1
JOIN PurchasedProductsTable AS pprod1
ON pprod1.OrderId = ord1.ID
LEFT JOIN OrdersTable ord2
ON ord2.CustomerId = ord1.CustomerId
AND ord2.Status = ord1.Status
LEFT JOIN PurchasedProductsTable pprod2
ON pprod2.OrderId = ord2.ID
AND pprod2.itemSku = pprod1.itemSku
AND pprod2.Qty = pprod1.Qty
GROUP BY ord1.CustomerId, ord1.ID, ord2.ID
HAVING COUNT(pprod1.itemSku) = COUNT(pprod2.itemSku)
) q
JOIN OrdersTable AS o ON o.ID = q.OrderId;
Test on RexTester here
Have three columns
ID User Quantity Date
1 x 0 2016-01-01
2 x 2 2016-01-02
3 x 0 2016-01-03
4 x 0 2016-01-04
5 xx 0 2016-01-01
6 xx 2 2016-01-02
7 xx 0 2016-01-03
8 xx 8 2016-01-04
9 xx 0 2016-01-06
10 xx 0 2016-01-04
Now How do i get user wise first of the latest sequence of 0 entry for x user ID=3,xx ID=9.
It's a bit complex, because we need to find the last not 0 entry for a name. (I would naturally tend to sort by date, but you said ID is what to go for.)
SELECT t1.name, max(t1.id) as check_id FROM table t1 WHERE quantity > 0 GROUP BY name
Now you can get the lowest number for each name that is higher than the given check_id:
SELECT name, min(t2.id) FROM table t2
JOIN (SELECT t1.name, max(t1.id) as check_id FROM table t1 WHERE quantity > 0 GROUP BY name) as a ON a.name=t2.name
WHERE t2.quantity = 0 AND t2.id > a.id
GROUP BY t2.name
There's one problem. It will exclude everyone with only 0 quantity. If this could happen you need another query with the following code (to get only 0 values)
SELECT name, min(id) as check_id, sum(quantity) as qty_sum FROM table
GROUP BY name
HAVING qty_sum = 0
As already mentioned, the first step is to identify the last dataset with a positive quantity by each user. The lowest ID of all following datasets would be what you seek. In other words, you need to look for MAX(ID) of all positive entries and apply MIN(ID) on all entries with a higher ID. In one query:
SELECT `User`, MIN(`ID`) FROM t `mainquery`
WHERE `ID` > (
SELECT MAX(`ID`) FROM t `subquery`
WHERE `Quantity` > 0 AND `mainquery`.`User` = `subquery`.`User`
GROUP BY `User`
)
GROUP BY `User`
With the data from your example, this query returns:
User MIN(`ID`)
x 3
xx 9
Test it here: http://sqlfiddle.com/#!9/3c487/1/0
Try This:
SELECT t1.user,min(t1.id) as ID,quantity,date from tablename t1
JOIN
(SELECT MAX(id) as qid,user FROM tablename WHERE Quantity>0 GROUP BY user) t2
ON t2.user=t1.user
WHERE t1.id>t2.qid
AND t1.Quantity=0
GROUP BY t1.user
Before a user starts a private chat (between 2 members, not a group chat) I want to check and see if there is already a chat consisting of only these two members. In case they've deleted the chat on their end, when they go to message that same user again I want it to merge with the old chat instead of starting a duplicate chat for the same two members.
This is my structure
`chats` table
id created_time
1 [TIMESTAMP]
2 [TIMESTAMP]
`chats.parties` table
id chat_id member_id invited_by
1 1 1 0 // creator of chat
2 1 2 1
3 1 3 1
4 2 1 0
5 2 2 1
Group by chat_id but only return results that contain a row with member_id=1 and member_id=2; no more, no less.
In the case of the tables above, only the chat_id=2 row(s) would be returned because chat_id=1 contains a 3rd member.
Is this possible with raw SQL? I'd prefer to not loop through in php as it would take a while with a lot of chats.
Here are two different ways to get the result you are looking for:
-- using conditional aggregation
select chat_id from chat_parties
group by chat_id
having sum(case when member_id = 1 then 1 else 0 end) > 0
and sum(case when member_id = 2 then 1 else 0 end) > 0
and sum(case when member_id not in (1, 2) then 1 else 0 end) = 0
-- using a correlated subquery
select chat_id from chat_parties c1
where member_id in (1,2)
and not exists (
select 1 from chat_parties where chat_id = c1.chat_id and member_id not in (1,2)
)
group by chat_id having count(distinct member_id) = 2
Change the table names to fit your actual setup.
Using conditional COUNT
SQL Fiddle Demo
SELECT c.`id`
FROM chats c
LEFT JOIN chats_parties cp
ON c.`id`= cp.`chat_id`
GROUP BY c.`id`
HAVING COUNT(case when `member_id` = 1 then 1 END) >= 1
AND COUNT(case when `member_id` = 2 then 1 END) >= 1
AND COUNT(DISTINCT `member_id` ) = 2
I've got a database table with logs which has 3 columns:
date | status | projectId
status can be either 0 or 1, primary key is on date and projectID
I'm trying to find out how many times a projectID had status 0 since the last time it was 1.
so if there would be only one projectId
date | status | projectId
1 0 3
2 0 3
3 1 3
4 1 3
5 0 3
6 0 3
this should return 2 (row 5 and 6 are 0 and row 4 is 1)
The thing that makes it hard for me is that I have to maintain the order of date. What would be a good way to tackle such problems, and this one in particular?
Here is how you would do it for one project:
select count(*)
from logs l
where status = 0 and
projectid = 3 and
date > (select max(date) from logs where projectid = 3 and status = 1)
Here is how you would do it for all projects:
select l.projectId, count(l1.projectId)
from logs l left outer join
(select projectId, max(date) as maxdate
from logs
where status = 1
group by projectId
) l1
on l.projectId = l1.projectId and
l.date > l1.date and
l.status = 0
group by l.projectId;
here you have an option in just one select.
http://sqlfiddle.com/#!2/6ce87/11
select *
from logs
where status=0 and date > (select date from logs where status=1 order by date desc limit 1)
Here's one way to get the result for all project_id:
SELECT m.project_id
, COUNT(1) AS mycount
FROM ( SELECT l.project_id
, MAX(l.date) AS latest_date
FROM mytable l
WHERE l.status = 1
) m
JOIN mytable t
ON t.project_id = m.project_id
AND t.date > m.latest_date
AND t.status = 0
If you need only a subset of project_id, the predicate should be added to the WHERE clause in the inline view query:
WHERE l.status = 1
AND l.project_id IN (3,5,7)
EDIT
That query does not return a row if there is no status=0 row after the latest status=1 row. To return a zero count, this could be done with an outer join.
SELECT m.project_id
, COUNT(t.status) AS mycount
FROM ( SELECT l.project_id
, MAX(l.date) AS latest_date
FROM mytable l
WHERE l.status = 1
AND l.project_id IN (3)
) m
LEFT
JOIN mytable t
ON t.project_id = m.project_id
AND t.date > m.latest_date
AND t.status = 0
For optimum performance, the statement could make use of an index with leading columns of project_id and date (in that order) and including the status column, e.g.
ON mytable (`project_id`,`date`,`status`)