How can i color the navigation bar like this?
Black in the top left corner and blue in the bottom right corner and make a gradient in between them.
No. 1 this is not the right way you ask for,
I have the concept that's why I'm giving you, Next time you ask any question please check this,
Stack Overflow is not a free code writing service. You are expected to try to write the code yourself. After doing more research if you have a problem you can post what you've tried with a clear explanation of what isn't working and providing Minimal, Complete, and Verifiable example. I suggest you to read How to Ask a good question.
And for now try this,
.box{
width: 150px;
height: 50px;
border-radius: 0px 0px 0px 7px;
background: rgba(0,0,0,1);
background: -moz-linear-gradient(-45deg, rgba(0,0,0,1) 0%, rgba(0,0,0,1) 34%, rgba(44,153,221,1) 100%);
background: -webkit-gradient(left top, right bottom, color-stop(0%, rgba(0,0,0,1)), color-stop(34%, rgba(0,0,0,1)), color-stop(100%, rgba(44,153,221,1)));
background: -webkit-linear-gradient(-45deg, rgba(0,0,0,1) 0%, rgba(0,0,0,1) 34%, rgba(44,153,221,1) 100%);
background: -o-linear-gradient(-45deg, rgba(0,0,0,1) 0%, rgba(0,0,0,1) 34%, rgba(44,153,221,1) 100%);
background: -ms-linear-gradient(-45deg, rgba(0,0,0,1) 0%, rgba(0,0,0,1) 34%, rgba(44,153,221,1) 100%);
background: linear-gradient(135deg, rgba(0,0,0,1) 0%, rgba(0,0,0,1) 34%, rgba(44,153,221,1) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#000000', endColorstr='#2c99dd', GradientType=1 );
}
<div class="box"></div>
If you wish to learn how linear-gradients work i would go here: MDN linear-gradient
.link {
width: 100px;
height: 1.5em;
display: inline-block;
background: linear-gradient(135deg, black 30%, DeepSkyBlue 100%);
}
<nav>
<a class="link"></a>
<a class="link"></a>
<a class="link"></a>
<a class="link"></a>
</nav>
This might be what you are looking for.
.box {
background: rgba(0,0,0,1);
background: -moz-linear-gradient(-45deg, rgba(0,0,0,1) 18%, rgba(3,152,252,1) 100%);
background: -webkit-gradient(left top, right bottom, color-stop(18%, rgba(0,0,0,1)), color-stop(100%, rgba(3,152,252,1)));
background: -webkit-linear-gradient(-45deg, rgba(0,0,0,1) 18%, rgba(3,152,252,1) 100%);
background: -o-linear-gradient(-45deg, rgba(0,0,0,1) 18%, rgba(3,152,252,1) 100%);
background: -ms-linear-gradient(-45deg, rgba(0,0,0,1) 18%, rgba(3,152,252,1) 100%);
background: linear-gradient(135deg, rgba(0,0,0,1) 18%, rgba(3,152,252,1) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#000000', endColorstr='#0398fc', GradientType=1 );
height: 80px;
width: 200px;
}
<div class='box'></div>
Related
I am using linear gradient to generate two sections of a div with a trapezium-like border. I am not able to get a crisp boundary between the two colors, I get a very narrow region of gradient - I have been able to reduce it, but I haven't been able to reduce it completely.
This is the code I have used:
.buyers-div {
width: 100%;
height: 500px;
background: -moz-linear-gradient(337deg, #FFFFFF 50%, #FFFFFF 49%, #197f88 50%, #197f88 100%);
/* ff3.6+ */
background: -webkit-gradient(linear, left top, right bottom, color-stop(0%, #FFFFFF), color-stop(49%, #FFFFFF), color-stop(50%, #197f88), color-stop(100%, #197f88));
/* safari4+,chrome */
background: -webkit-linear-gradient(337deg, #FFFFFF 50%, #FFFFFF 49%, #197f88 50%, #197f88 100%);
/* safari5.1+,chrome10+ */
background: -o-linear-gradient(337deg, #FFFFFF 50%, #FFFFFF 49%, #197f88 50%, #197f88 100%);
/* opera 11.10+ */
background: -ms-linear-gradient(337deg, #FFFFFF 50%, #FFFFFF 49%, #197f88 50%, #197f88 100%);
/* ie10+ */
background: linear-gradient(113deg, #FFFFFF 50%, #FFFFFF 49%, #197f88 50%, #197f88 100%);
/* w3c */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#FFFFFF', endColorstr='#197f88', GradientType=1);
/* ie6-9 */
}
<div class="buyers-div"></div>
Your declaration of the gradient produces a step of 1% between #ffffffand #197f88. Change this from
background: linear-gradient(113deg, #FFFFFF 50%, #FFFFFF 49%, #197f88 50%, #197f88 100%);
to
background: linear-gradient(113deg, #FFFFFF 0%, #FFFFFF 50%, #197f88 50%, #197f88 100%);
and you get crisp boundaries (but the angle is rather suboptimal):
.buyers-div {
width: 100%;
height: 500px;
background: -moz-linear-gradient(337deg, #FFFFFF 0%, #FFFFFF 50%, #197f88 50%, #197f88 100%);
/* ff3.6+ */
background: -webkit-gradient(linear, left top, right bottom, color-stop(0%, #FFFFFF), color-stop(50%, #FFFFFF), color-stop(50%, #197f88), color-stop(100%, #197f88));
/* safari4+,chrome */
background: -webkit-linear-gradient(337deg, #FFFFFF 0%, #FFFFFF 50%, #197f88 50%, #197f88 100%);
/* safari5.1+,chrome10+ */
background: -o-linear-gradient(337deg, #FFFFFF 0%, #FFFFFF 50%, #197f88 50%, #197f88 100%);
/* opera 11.10+ */
background: -ms-linear-gradient(337deg, #FFFFFF 0%, #FFFFFF 50%, #197f88 50%, #197f88 100%);
/* ie10+ */
background: linear-gradient(113deg, #FFFFFF 0%, #FFFFFF 50%, #197f88 50%, #197f88 100%);
/* w3c */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#FFFFFF', endColorstr='#197f88', GradientType=1);
/* ie6-9 */
}
<div class="buyers-div"></div>
On A Collection of Separator Styles there you can see many different and sharp separator styles. May it's helpful for your approach.
I have created a solution which uses position relative/absolute and Before pseudo-element. Here it's:
//HMTL(PUG)
.buyers-div
CSS(SASS)
.buyers-div
position:relative
width: 100%
height: 500px
background-color: #197f88
overflow: hidden
&:before
content: ''
position: absolute
width: 100%
height: 500px
background-color: white
left: -50%
transform: skew(-45deg)
Check the SOLUTION
THANKS, T04435
I have an image section with a gradient layer that was built into the stylesheet of the theme. What in this block of code do I need to change to reduce the gradient?
.image-section {
background: -moz-linear-gradient(top, rgba(0,0,0,0.2) 0%, rgba(0,0,0,0.5) 30%, rgba(0,0,0,0.8) 80%, rgba(0,0,0,0.9) 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.2)), color-stop(30%,rgba(0,0,0,0.5)), color-stop(80%,rgba(0,0,0,0.8)), color-stop(100%,rgba(0,0,0,0.9)));
background: -webkit-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.5) 30%,rgba(0,0,0,0.8) 80%,rgba(0,0,0,0.9) 100%);
background: -o-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.5) 30%,rgba(0,0,0,0.8) 80%,rgba(0,0,0,0.9) 100%);
background: -ms-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.5) 30%,rgba(0,0,0,0.8) 80%,rgba(0,0,0,0.9) 100%);
background: linear-gradient(to bottom, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.5) 30%,rgba(0,0,0,0.8) 80%,rgba(0,0,0,0.9) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#33000000', endColorstr='#e6000000',GradientType=0 );
display: table;
overflow: hidden;
table-layout: fixed;
width: 100%;
}
Any help with handling this block of code is appreciated.
To reduce the gradient you should change the background gradient values for example :
background: -moz-linear-gradient(top, rgba(0,0,0,0.2) 0%, rgba(0,0,0,0.5) 30%, rgba(0,0,0,0.8) 80%, rgba(0,0,0,0.9) 100%);
The previous style it start with opacity 0.2 at 0% of the height and end with opacity 0.9 at 100% of the height, you can change those opacity values as you need.
let say that you want to start with 0.2 and end with 0.5, the style should be like this :
background: -moz-linear-gradient(to bottom, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%)
the style :
.image-section {
background: -moz-linear-gradient(top, rgba(0,0,0,0.2) 0%, rgba(0,0,0,0.3) 30%, rgba(0,0,0,0.4) 80%, rgba(0,0,0,0.5) 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.2)), color-stop(30%,rgba(0,0,0,0.3)), color-stop(80%,rgba(0,0,0,0.4)), color-stop(100%,rgba(0,0,0,0.5)));
background: -webkit-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%);
background: -o-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%);
background: -ms-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%);
background: linear-gradient(to bottom, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#33000000', endColorstr='#e6000000',GradientType=0 );
display: table;
overflow: hidden;
table-layout: fixed;
width: 100%;
}
Demo : https://jsfiddle.net/IA7medd/rnjunkod/
I have a box that I'm trying to add some gradient to and it works in Chrome and other browsers except for IE10+ Below is my CSS code:
.box-gradient {
position:absolute;
width:100%;
height:100%;
border-radius:10px;
-moz-border-radius:10px;
-webkit-border-radius:5px;
background: -moz-linear-gradient(left, #CCCCCC 0%, #EEEEEE 50%, #EEEEEE 50%, #CCCCCC 100%);
background: -webkit-gradient(linear, left top, right top, color-stop(0%,#CCCCCC),color-stop(50%,#EEEEEE), color-stop(50%,#EEEEEE), color-stop(100%,#CCCCCC));
}
Thanks in advance!!
You have to include a line for IE10+
background: -ms-linear-gradient(to left, #CCCCCC 0%, #EEEEEE 50%, #EEEEEE 50%, #CCCCCC 100%);
I have had this issue before. Adding compatibility for gradients can be a very strenuous job. I think you'd prefer using gradient generator
You need an un-prefixed linear gradient for IE10 to read. Something like this:
background: linear-gradient(to left, #CCCCCC 0%, #EEEEEE 50%, #EEEEEE 50%, #CCCCCC 100%);
You need to add an unprefixed version as well:
background: -webkit-gradient(linear, left top, right top, color-stop(0%,#CCCCCC),color-stop(50%,#EEEEEE), color-stop(50%,#EEEEEE), color-stop(100%,#CCCCCC));
background: -moz-linear-gradient(left, #CCCCCC 0%, #EEEEEE 50%, #EEEEEE 50%, #CCCCCC 100%);
background: -o-linear-gradient(left, #CCCCCC 0%, #EEEEEE 50%, #EEEEEE 50%, #CCCCCC 100%);
background: linear-gradient(to right, #CCCCCC 0%, #EEEEEE 50%, #EEEEEE 50%, #CCCCCC 100%);
There are plenty of tools available to help you handle various prefixes.
I have a horizontal gradient bar: example
I am wondering, how to make it vertical instead of horizontal, with about 20px height.
HTML:
<div class="seperator-gradient"></div>
CSS:
.seperator-gradient {
width: 100%;
height: 10px;
border-bottom: background: #c4c4c4;
background: -moz-linear-gradient(left, #ffffff 0%, #e3e3e3 10%, #b8b8b8 50%, #e3e3e3 90%, #fcfcfc 100%);
background: -webkit-gradient(linear, left top, right top, color-stop(0%,#ffffff), color-stop(10%,#e3e3e3), color-stop(50%,#b8b8b8), color-stop(90%,#e3e3e3), color-stop(100%,#fcfcfc));
background: -webkit-linear-gradient(left, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: -o-linear-gradient(left, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: -ms-linear-gradient(left, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: linear-gradient(to right, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#fcfcfc',GradientType=1 );
}
Try this:
.seperator-gradient {
width: 100%;
height: 10px;
border-bottom: background: #c4c4c4;
background: -moz-linear-gradient(left, #ffffff 0%, #e3e3e3 10%, #b8b8b8 50%, #e3e3e3 90%, #fcfcfc 100%);
background: -webkit-gradient(linear, left top, right top, color-stop(0%,#ffffff), color-stop(10%,#e3e3e3), color-stop(50%,#b8b8b8), color-stop(90%,#e3e3e3), color-stop(100%,#fcfcfc));
background: -webkit-linear-gradient(left, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: -o-linear-gradient(left, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: -ms-linear-gradient(left, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: linear-gradient(to right, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#fcfcfc',GradientType=1 );
transform: rotate(90deg);
-ms-transform: rotate(90deg);
-webkit-transform: rotate(90deg);
}
This will rotate what you have 90 degrees. I'm next to positive it's in the right direction, but if this goes the opposite way, change (90deg) to (270deg).
Try this code:
background-image: -webkit-gradient(
linear,
right bottom,
left bottom,
color-stop(0, #FAF5F5),
color-stop(0.55, #E0362D)
);
background-image: -o-linear-gradient(left, #FAF5F5 0%, #E0362D 55%);
background-image: -moz-linear-gradient(left, #FAF5F5 0%, #E0362D 55%);
background-image: -webkit-linear-gradient(left, #FAF5F5 0%, #E0362D 55%);
background-image: -ms-linear-gradient(left, #FAF5F5 0%, #E0362D 55%);
background-image: linear-gradient(to left, #FAF5F5 0%, #E0362D 55%);
You could use different css gradient creator also :D
This is what I came up with (note that the percentages maybe should be changed a little bit if you want it to have a such a small height). Anyway, for large heights this looks great:
JSFiddle
.seperator-gradient {
width: 100%;
height: 10px;
border-bottom: background: #c4c4c4;
background: -moz-linear-gradient(, #ffffff 0%, #e3e3e3 10%, #b8b8b8 50%, #e3e3e3 90%, #fcfcfc 100%);
background: -webkit-gradient(linear, center top, center top, color-stop(0%,#ffffff), color-stop(10%,#e3e3e3), color-stop(50%,#b8b8b8), color-stop(90%,#e3e3e3), color-stop(100%,#fcfcfc));
background: -webkit-linear-gradient(left, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: -o-linear-gradient(left, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: -ms-linear-gradient(left, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: linear-gradient(to right, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#fcfcfc',GradientType=1 );
}
Check the "ultimate css gradient generator", this is the best tool to make gradients, it will generate them the most crossbrowser way. http://www.colorzilla.com/gradient-editor/
I'm not sure if you want to make the bar vertical or the gradient, so I'll answer both. If you mean the bar then change:
width: 100%;
height: 10px;
to
width: 10px // or however wide you want it
height: 20px
If you mean the gradient needs to be vertical, use:
.seperator-gradient {
width: 100%;
height: 10px;
border-bottom: background: #c4c4c4;
background: -moz-linear-gradient(top, #ffffff 0%, #e3e3e3 10%, #b8b8b8 50%, #e3e3e3 90%, #fcfcfc 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#ffffff), color-stop(10%,#e3e3e3), color-stop(50%,#b8b8b8), color-stop(90%,#e3e3e3), color-stop(100%,#fcfcfc));
background: -webkit-linear-gradient(top, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: -o-linear-gradient(top, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: -ms-linear-gradient(top, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
background: linear-gradient(to bottom, #ffffff 0%,#e3e3e3 10%,#b8b8b8 50%,#e3e3e3 90%,#fcfcfc 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#fcfcfc',GradientType=0 );
I've got the following background properties I want to apply to an element:
background: url('../img/bg.png') !important;
background: -moz-linear-gradient(left, rgba(0,0,0,1) 0%, rgba(0,0,0,0) 50%, rgba(0,0,0,1) 100%) !important;
background: -webkit-gradient(linear, left top, right top, color-stop(0%,rgba(0,0,0,1)), color-stop(50%,rgba(0,0,0,0)), color-stop(100%,rgba(0,0,0,1))) !important;
background: -webkit-linear-gradient(left, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%) !important;
background: -o-linear-gradient(left, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%) !important;
background: -ms-linear-gradient(left, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%) !important;
background: linear-gradient(to right, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%) !important;
I want the image to be displayed first, and the gradient over it. Is it possible to do this?
Because gradients are considered images for the purposes of background (or pretty much any CSS property that takes an image), you can simply list the image after the gradient with a comma. The caveat is that because you have so many prefixes, you need to repeat the image URL for each one:
background: -moz-linear-gradient(left, rgba(0,0,0,1) 0%, rgba(0,0,0,0) 50%, rgba(0,0,0,1) 100%), url('../img/bg.png') !important;
background: -webkit-gradient(linear, left top, right top, color-stop(0%,rgba(0,0,0,1)), color-stop(50%,rgba(0,0,0,0)), color-stop(100%,rgba(0,0,0,1))), url('../img/bg.png') !important;
background: -webkit-linear-gradient(left, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%), url('../img/bg.png') !important;
background: -o-linear-gradient(left, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%), url('../img/bg.png') !important;
background: linear-gradient(to right, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%), url('../img/bg.png') !important;
I left the !important tokens in but you should probably remove them if they aren't there for any specific purpose. I did remove the -ms-linear-gradient() line though, because it's absolutely not needed.
It's probably going to require two elements, but you can use a pseudo-element to make things a little cleaner. FIDDLE.
#yourelement {
position: relative;
background: -moz-linear-gradient(left, rgba(0,0,0,1) 0%, rgba(0,0,0,0) 50%, rgba(0,0,0,1) 100%) !important;
background: -webkit-gradient(linear, left top, right top, color-stop(0%,rgba(0,0,0,1)), color-stop(50%,rgba(0,0,0,0)), color-stop(100%,rgba(0,0,0,1))) !important;
background: -webkit-linear-gradient(left, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%) !important;
background: -o-linear-gradient(left, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%) !important;
background: -ms-linear-gradient(left, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%) !important;
background: linear-gradient(to right, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%,rgba(0,0,0,1) 100%) !important;
}
#yourelement:after {
content: '';
position: absolute;
left: 0;
top: 0;
right: 0;
bottom: 0;
z-index: -1;
background: url('../img/bg.png') !important;
}
I just tried it and with luck this worked in my safari browser.
background: url('img.png'), -webkit-linear-gradient(left, rgba(0, 0, 0, 1) 0%,transparent 50%,rgba(0, 0, 0, 1) 100%);
so in your case you would use
background: -webkit-gradient(linear, left top, right top, color-stop(0%,rgba(0, 0, 0, 1)), color-stop(50%,transparent), color-stop(100%,rgba(0, 0, 0, 1))), url('../img/bg.png');
Here is a fiddle