I want to add order totals together and then group them by site owner
I have 3 tables
orders
subtotal | site
site_data
site_owner | record_id
site
record_id
the relationship between these are
sites.site_data = site_data.record_id
sites.record_id = orders.site
currently this is what I have
SELECT site_data.site_owner,
SUM('orders.subtotal')
FROM site_data
INNER JOIN site ON site.site_data = site_data.record_id
INNER JOIN orders ON site.record_id = orders.site
group by site_data.site_owner
but the output is as follows
site_owner | SUM('orders,subtotal')
Mr Foo | 0
Mr Bar | 0
all the orders totals are 0 and I am not sure why I have done a sum on this field before and not had an issue so must be to do with the grouping.
You should not use quotes inside SUM function
SELECT site_data.site_owner,
SUM(orders.subtotal)
FROM site_data
INNER JOIN site ON site.site_data = site_data.record_id
INNER JOIN orders ON site.record_id = orders.site
group by site_data.site_owner
Related
I have 3 tables: order, item and render.
1 order can have multiple items and each item has one render entry with status.
I want to have the order id's and date which have ALL its items with rendered 'done'.
In the example it would be the order 1 only, which has its 2 items (1 and 2) with status done in render table
order table
id| date
1 | 2021-12-10
2 | 2021-12-11
item table
id|order_id
1 | 1
2 | 1
3 | 2
4 | 2
render table
id|item_id| status
1 |1 | done
2 |2 | done
3 |3 | done
4 |4 | running
I would like to have it with JOIN statements. I've tried this but it does not work like expected (it returns both, order 1 and 2):
SELECT o.id, o.date
FROM order AS o
JOIN item AS i ON o.id = i.order_id
JOIN render r1 ON (i.`id` = r1.item_id AND r1.status = 'done')
LEFT JOIN render r2 ON (i.`id` = r2.item_id AND r2.status <> 'done')
AND r2.item_id IS NULL;
Any ideas? thank you in advance!
SELECT t1.id
, t1.date
FROM order
t1
WHERE t1.id NOT IN
(
SELECT o.id
FROM order
o
JOIN item
i
ON i.order_id = o.id
JOIN render
r
ON r.item_id = i.id
WHERE r.status <> 'done'
)
The choice of some column names is unfortunate, making the join conditions painful for a maintainer to read: it is not immediately obvious at a glance what kind if IDs the id columns refer to.
I would rename the following columns:
TABLE COLUMN_NAME BETTER_COLUMN_NAME
------ ----------- ------------------
order id order_id
order date order_date
item id item_id
render id render_id
render status render_status
I also disagree with the o / i / r table aliases, but arguments are in room 12A, just along the corridor.
Here I post what it eventually worked best for me in case it helps anybody :)
SELECT o.id, o.date
FROM order AS o
JOIN item AS i ON o.id = i.order_id
LEFT JOIN render r ON (r.item_id = i.id)
GROUP BY o.id
HAVING GROUP_CONCAT(DISTINCT IFNULL(r.status, "NULL")) = 'done';
In the HAVING clause I concatenate the statuses, remove all duplicates and check that only “done” is there. Since I needed to have a LEFT JOIN against render I explicitly set to “NULL“ the returned null rows.
I just can't figure out how to get average rating and count comments from my mysql database.
I have 3 tables (activity, rating, comments) activity contains the main data the "activities", rating holds the ratings and comments - of course, the ratings.
activity_table
id | title |short_desc | long_desc | address | lat | long |last_updated
rating_table
id | activityid | userid | rating
comment_table
id | activityid | userid | rating
I'm now trying to the data from activity plus the comment_counts and average_rating in one query.
SELECT activity.*, AVG(rating.rating) as average_rating, count(comments.activityid) as total_comments
FROM activity LEFT JOIN
rating
ON activity.aid = rating.activityid LEFT JOIN
comments
ON activity.aid = comments.activityid
GROUP BY activity.aid
...doesn't do the job. It gives me the right average_rating, but the wrong amount of comments.
Any ideas?
Thanks a lot!
You are aggregating along two different dimensions. The Cartesian product generated by the joins affects the aggregation.
So, you should aggregate before the joins:
SELECT a.*, r.average_rating, COALESCE(c.total_comments, 0) as total_comments
FROM activity a LEFT JOIN
(SELECT r.activityid, AVG(r.rating) as average_rating
FROM rating r
GROUP BY r.activityid
) r
ON a.aid = r.activityid LEFT JOIN
(SELECT c.activityid, COUNT(*) as total_comments
FROM comments c
GROUP BY c.activityid
) c
ON a.aid = c.activityid;
Notice that the outer GROUP BY is no longer needed.
I cannot find the answer to my problem here on stackoverflow. I have a query that spans 3 tables:
newsitem
+------+----------+----------+----------+--------+----------+
| Guid | Supplier | LastEdit | ShowDate | Title | Contents |
+------+----------+----------+----------+--------+----------+
newsrating
+----+----------+--------+--------+
| Id | NewsGuid | UserId | Rating |
+----+----------+--------+--------+
usernews
+----+----------+--------+----------+
| Id | NewsGuid | UserId | ReadDate |
+----+----------+--------+----------+
Newsitem obviously contains newsitems, newsrating contains ratings that users give to newsitems, and usernews contains the date when a user has read a newsitem.
In my query I want to get every newsitem, including the number of ratings for that newsitem and the average rating, and how many times that newsitem has been read by the current user.
What I have so far is:
select newsitem.guid, supplier, count(newsrating.id) as numberofratings,
avg(newsrating.rating) as rating,
count(case usernews.UserId when 3 then 1 else null end) as numberofreads from newsitem
left join newsrating on newsitem.guid = newsrating.newsguid
left join usernews on newsitem.guid = usernews.newsguid
group by newsitem.guid
I have created an sql fiddle here: http://sqlfiddle.com/#!9/c8add/8
Both count() calls don't return the numbers I want. numberofratings should return the total number of ratings for that newsitem (by all users). numberofreads should return the number of reads for the current user for that newsitem.
So, newsitem with guid d104c330-c319-40e8-8be3-a7c4f549d35c should have 2 ratings and 3 reads for the current user with userid = 3.
I have tried conditional counts and sums, but no success yet. How can this be accomplished?
The main problem that I see is that you're joining in both tables together, which means that you're going to effectively be multiplying out by both numbers, which is why your counts aren't going to be correct. For example, if the Newsitem has been read 3 times by the user and rated by 8 users then you're going to end up getting 24 rows, so it will look like it has been rated 24 times. You can add a DISTINCT to your COUNT of the ratings IDs and that should correct that issue. Average should be unaffected because the average of 1 and 2 is the same as the average of 1, 1, 2, & 2 (for example).
You can then handle the reads by adding the userid to the JOIN condition (since it's an OUTER JOIN it shouldn't cause any loss of results) instead of in a CASE statement for your COUNT, then you can do a COUNT on distinct id values from Usernews. The resulting query would be:
SELECT
I.guid,
I.supplier,
COUNT(DISTINCT R.id) AS number_of_ratings,
AVG(R.rating) AS avg_rating,
COUNT(DISTINCT UN.id) AS number_of_reads
FROM
NewsItem I
LEFT OUTER JOIN NewsRating R ON R.newsguid = I.guid
LEFT OUTER JOIN UserNews UN ON
UN.newsguid = I.guid AND
UN.userid = #userid
GROUP BY
I.guid,
I.supplier
While that should work, you might get better results from a subquery, as the above needs to explode out the results and then aggregate them, perhaps unnecessarily. Also, some people might find the below to be a little clearer.
SELECT
I.guid,
I.supplier,
R.number_of_ratings,
R.avg_rating,
COUNT(*) AS number_of_reads
FROM
NewsItem I
LEFT OUTER JOIN
(
SELECT
newsguid,
COUNT(*) AS number_of_ratings,
AVG(rating) AS avg_rating
FROM
NewsRating
GROUP BY
newsguid
) R ON R.newsguid = I.guid
LEFT OUTER JOIN UserNews UN ON UN.newsguid = I.guid AND UN.userid = #userid
GROUP BY
I.guid,
I.supplier,
R.number_of_ratings,
R.avg_rating
I'm with Tom you should use a subquery to calculate the user count.
SQL Fiddle Demo
SELECT NI.guid,
NI.supplier,
COUNT(NR.ID) as numberofratings,
AVG(NR.rating) as rating,
user_read as numberofreads
FROM newsitem NI
LEFT JOIN newsrating NR
ON NI.guid = NR.newsguid
LEFT JOIN (SELECT NewsGuid, COUNT(*) user_read
FROM usernews
WHERE UserId = 3 -- use a variable #user_id here
GROUP BY NewsGuid) UR
ON NI.guid = UR.NewsGuid
GROUP BY NI.guid,
NI.supplier,
numberofreads;
I'd like to SELECT a count of the number of customers, the sum of customer order totals, and a count of customers in specific states.
I know how to do this in two queries easily, however the same WHERE constraints will be used, so it seems like it would be better to do it in one query and avoid repetition. I'm eager to improve my SQL but I can't work out how to combine them. Having them as two separate queries feels very clumsy.
Is there a way to combine them? What factors should I consider to determine if combining them is a good idea?
Customers Table
*-------------*-------------*--------------*------------*
| ID_Customer | ID_State | Name | ...etc... |
*-------------*-------------*--------------*------------*
States Table
*-------------*-------------*
| ID_State | Name |
*-------------*-------------*
Orders Table
*----------*-------------*--------------*------------*
| ID_Order | ID_Customer | ...etc... | Total |
*----------*-------------*--------------*------------*
Query 1.1 - Select Count of Customers and Count of Customers in specific states
SELECT
COUNT(*) AS Customers,
SUM(States.Name = 'California') AS California_Customers,
SUM(States.Name = 'New York') AS NewYork_Customers
FROM Customers
INNER JOIN States ON Customers.ID_State = States.ID_State
Query 1.2 - Select Sum of Customer Order Totals
SELECT
SUM(Total) AS SumOfOrderTotals
FROM Orders
INNER JOIN Customers ON Customers.ID_Customer = Orders.ID_Customer
Query 2 - An attempt at combining the queries into one (does not work)
SELECT
COUNT (DISTINCT(Customers.ID_Customer)) AS Customers,
SUM (Orders.Total) AS SumOfOrderTotals,
SUM (States.Name = 'California') AS California_Customers,
SUM (States.Name = 'New York') AS NewYork_Customers
FROM
Customers
INNER JOIN Orders ON Customers.ID_Customer = Orders.ID_Customer
INNER JOIN States ON Customers.ID_State = States.ID_State
Obviously this does not work as it is because the INNER JOIN between Customers and Orders means that States.Names are counted xN (where N is the number of orders a customer has) for each customer, making those totals wrong.
I considered a Subquery, however I'm not sure how to apply one in this case (if that is what I should be doing).
You need to do the aggregation before the join or use subqueries:
SELECT COUNT(DISTINCT(c.ID_Customer)) AS Customers,
o.SumOfOrderTotals,
SUM(s.Name = 'California') AS California_Customers,
SUM(s.Name = 'New York') AS NewYork_Customers
FROM Customers c JOIN
States s
ON c.ID_State = s.ID_State CROSS JOIN
(SELECT SUM(Total) as SumOfOrderTotals
FROM Orders o
) o;
You could also write this as:
SELECT COUNT(DISTINCT(c.ID_Customer)) AS Customers,
(SELECT SUM(Total)
FROM Orders o
) as SumOfOrderTotals,
SUM(s.Name = 'California') AS California_Customers,
SUM(s.Name = 'New York') AS NewYork_Customers
FROM Customers c JOIN
States s
ON c.ID_State = s.ID_State;
You place the subquery where you would have placed any additional field, as another thing in the SELECT clause.
SELECT
COUNT(*) AS Customers,
SUM(States.Name = 'California') AS California_Customers,
SUM(States.Name = 'New York') AS NewYork_Customers,
(SELECT SUM(Total) FROM Orders) AS SumOfOrderTotals
FROM Customers
INNER JOIN States ON Customers.ID_State = States.ID_State;
I'm trying to count several joined tables but without any luck, what I get is the same numbers for every column (tUsers,tLists,tItems). My query is:
select COUNT(users.*) as tUsers,
COUNT(lists.*) as tLists,
COUNT(items.*) as tItems,
companyName
from users as c
join lists as l
on c.userID = l.userID
join items as i
on c.userID = i.userID
group by companyID
The result I want to get is
---------------------------------------------
# | CompanyName | tUsers | tlists | tItems
1 | RealCoName | 5 | 2 | 15
---------------------------------------------
what modifications do i have to do to my query to get those results?
Cheers
Try this
SELECT u.userID, companyName,
Count(DISTINCT l.listid) as tLists, Count(DISTINCT i.items) as tItems
FROM users u
LEFT JOIN lists l ON u.userID=l.userID
LEFT JOIN items i ON u.userID=i.userID
GROUP BY u.companyID
You can do it by using sub query
select (select count(*) from users where userID=YourUserID) tUsers,
(select count(*) from lists where userID=YourUserID) as tLists,
(select count(*) from items where userID=YourUserID) as tItems,
companyName
from company group by companyID