I'm trying to get all results of my table with a GROUP BY on 2 columns and get the last insertions.
"Prices" table :
My Request :
SELECT DISTINCT p.*
FROM prices p
JOIN (
SELECT MAX(created_at) as "last_created"
FROM prices
WHERE station_id = 27210003
GROUP BY station_id, fuel_id) as sub
ON sub.last_created = p.created_at
WHERE p.station_id = 27210003
GROUP BY p.station_id, p.fuel_id
Results are 3 lines but wrong line because not last created in my DB -_-'
Please help me !!! >_<'
Thx
Since you're selecting a specific station_id in the WHERE clause, you don't need to include that in GROUP BY.
The subquery has to return the columns you're grouping on, and then you have to include them in the ON clause.
And you don't need GROUP BY in the outer query, since the JOIN should ensure that there's just one row for each fuel_id (unless there are duplicate created_at for the same fuel_id and station_id).
SELECT DISTINCT p.*
FROM prices p
JOIN (
SELECT fuel_id, MAX(created_at) as "last_created"
FROM prices
WHERE station_id = 27210003
GROUP BY fuel_id) as sub
ON sub.last_created = p.created_at AND sub.fuel_id = p.fuel_id
WHERE p.station_id = 27210003
Related
There are three tables
Inventory - Which contains the stock information
Order - Which contains the store information of an order
OrderParts - Which contains the Parts associated with the order
Inventory Table
Order Table
Order Parts Table
Below Expected Report needs to be generated
Query Tried to achieve the above result
SELECT
inventory.partNumber, inventory.storeId, SUM(parts.quantity) as orderedQuantity,
inventory.availableQuantity
FROM
(SELECT *, SUM(availableQuantity) AS availQty
FROM
inventory AS inventory
GROUP BY storeId , partNumber) AS inventory
LEFT JOIN
(SELECT
*
FROM
order
GROUP BY storeId) AS order ON order.storeId = inventory.storeId
LEFT JOIN
(SELECT
*
FROM
orderParts) AS parts ON inventory.partNumber = parts.partNumbe
where inventory.partNumber in ("A1234", "B1234");
GROUP BY order.storeId , parts.partNumber
Getting null for Ordered Quantity
Kindly let me know the way to get the cumulative Ordered quantity as expected. Thanks in Advance.
A relatively simple method is union all and aggregation:
select storeid, partnumber,
sum(availableqty) as availableqty,
sum(orderedqty) as orderedqty
from (select storeid, partnumber, availableqty, 0 as orderedqty
from inventory
union all
select o.storeid, op.partnumber, 0, op.quantity
from orderparts op join
orders o
on op.ordernumber = o.ordernumber
) sp
group by storeid, partnumber;
Your question doesn't explicitly describe the filters, but you can add filters in either the subqueries or the outer query.
Actually, i did counted distinct empid rows according to dates. But the problem is i get only one empid record of that specific dates.Please let me know how to get all empid records. Here is my sql query.
$sql = "
SELECT COUNT(DISTINCT subcount.empid) AS CountOf
, subcount.name
, subcount.date
, subcount.empid
, calendar.cdate
FROM subcount
, calendar
WHERE subcount.date = calendar.cdate
GROUP
BY subcount.date
";
Here is sql database.
For example, When you look at 2020-11-10 there are two empid with 10 and 7.
When i tried to get both records i get only empid 10 record or 7 record, though i need both record counts:
Here is the output:
Please help me on this.
I think what you are asking is to get list of employees with count of their submissions on a given date, this could show do it:
SELECT cnt.empid AS EmpId
, sc.Name
, cnt.`date` AS Timestamp
, cnt.CountOf AS SubmissionCount
FROM subcount AS sc
INNER JOIN
(
SELECT subcount.empid
subcount.`date`,
count(*) AS CountOf
FROM subcount
INNER JOIN calendar
ON subcount.`date` = calendar.cdate
GROUP BY
subcount.`date`, subcount.empid
) AS cnt
ON sc.empid == cnt.empid
It uses nested SELECT with GROUP BY to calculate count per employee (empid) and date (not only employee). Outer SELECT join nested SELECT to get subcount.Name piece of data which isn't retrieved in nested SELECT so it needs to be retrieved using outer SELECT.
GROUP BY ___ means result rows per ___. If you group by employee ID, you get one row per employee ID. If you want one row per employee ID and date, group by employee ID and date.
SELECT any_value(s.name), s.`date`, s.empid, c.cdate, count(*)
FROM subcount s
JOIN calendar c on c.cdate = s.`date`
GROUP BY s.`date`, s.empid
ORDER BY s.`date`, s.empid;
I expect a calendar table to have one row per date, so there is exactly one cdate for a result row. The name, however, can be different from row to row, so we must tell the DBMS, which to pick. With ANY_VALUE I tell it that I don't care which.
This is a slight variant of the question I asked here
SQL Query for getting maximum value from a column
I have a Person Table and an Activity Table with the following data
-- PERSON-----
------ACTIVITY------------
I have got this data in the database about users spending time on a particular activity.
I intend to get the data when every user has spent the maximum number of hours.
My Query is
Select p.Id as 'PersonId',
p.Name as 'Name',
act.HoursSpent as 'Hours Spent',
act.Date as 'Date'
From Person p
Left JOIN (Select MAX(HoursSpent), Date from Activity
Group By HoursSpent, Date) act
on act.personId = p.Id
but it is giving me all the rows for Person and not with the Maximum Numbers of Hours Spent.
This should be my result.
You have several issues with your query:
The subquery to get hours is aggregated by date, not person.
You don't have a way to bring in other columns from activity.
You can take this approach -- joins and group by, but it requires two joins:
select p.*, a.* -- the columns you want
from Person p left join
activity a
on a.personId = p.id left join
(select personid, max(HoursSpent) as max_hoursspent
from activity a
group by personid
) ma
on ma.personId = a.personId and
ma.max_hoursspent = a.hoursspent;
Note that this can return duplicates for a given person -- if there are ties for the maximum.
This is written more colloquially using row_number():
select p.*, a.* -- the columns you want
from Person p left join
(select a.*,
row_number() over (partition by a.personid order by a.hoursspent desc) as seqnum
from activity a
) a
on a.personId = p.id and a.seqnum = 1
ma.max_hoursspent = a.hoursspent;
SELECT *
FROM table
INNER JOIN
(SELECT itemno, MAX(last_updated) as TopDate
FROM table
WHERE userID = 'user'
GROUP BY itemno) AS EachItem ON
EachItem.TopDate = table.last_updated
AND EachItem.itemno = table.itemno
I have taken the solution above from a previous post and modified it to work with one of the functions that I have created but I now want to use this same query but adapt it to order the result by max(last_updated) (which is a timestamp in my table) and also max(qty_sold).
Basically I have multiple duplicates of itemnos in the table but only want to return the rows with the latest date and highest qty_sold for every row where a certain user ID is specified.
Many thanks in advance, I have spent hours searching and can't figure this out as I am fairly new to mysql.
Solved my own question after more trying by adding ORDER BY qty_sold DESC to the end.
SELECT *
FROM table
INNER JOIN
(SELECT itemno, MAX(last_updated) as TopDate
FROM table
WHERE userID = 'user'
GROUP BY itemno) AS EachItem ON
EachItem.TopDate = table.last_updated
AND EachItem.itemno = table.itemno
ORDER BY qty_sold DESC
im geting this error when trying to do 2 counts inside of my query
first ill show you the query:
$sql = mysql_query("select c.id, c.number, d.name,
(select count(*) from `parts` where `id_container`=c.id group by `id_car`) as packcount,
(select count(*) from `parts` where `id_container`=c.id) as partcount
from `containers` as c
left join `destinations` as d on (d.id = c.id_destination)
order by c.number asc") or die(mysql_error());
now the parts table has 2 fields that i need to use in the count:
id_car
id_container
id_car = the ID of the car the part is for
id_container = the ID of the container the part is in
for packcount all i want is a count of the total cars per container
for partcount all i want it a count of the total parts per container
It's because of GROUP BY You're using
Try something like
(select count(distinct id_car) from `parts` where `id_container`=c.id)
in You're subquery (can't check right now)
EDIT
PFY - I think UNIQUE is for indexes
Your grouping in your first sub-query is causing multiple rows to be returned, you will probably need to run separate queries to get the results you are looking for.
This subquery may return more than one row.
(select count(*) from `parts` where `id_container`=c.id group by `id_car`) as packcount, ...
so, i'd suggest to try something of the following:
(select count(DISTINCT `id_car`) from `parts` where `id_container`=c.id) as packcount, ...
see: COUNT(DISTINCT) on dev.mysql.com
and: QA on stackoverflow