mysql get total values and total number from where clause - mysql

Question

I'm trying to write a mysql query which will return the total number of values from a column and also the total number of values based on a where clause from the same column.
I have a table like this:
+------------------------+-------+
| color | code |
+------------------------+-------+
| red | 200 |
| red | 202 |
| blue | 105 |
| yellow | 136 |
| green | 561 |
| red | 198 |
| blue | 414 |
| green | 11 |
| yellow | 600 |
| green | 155 |
| red | 865 |
| blue | 601 |
| green | 311 |
+------------------------+-------+
If I run this query:
select
color,
count(*) as count
from colors
where code > 0 &&
code <= 500
group by color
order by count(*) desc;
I get this result which is great because it's almost what I want:
+------------------------+-------+
| color | count |
+------------------------+-------+
| red | 3 |
| green | 3 |
| blue | 2 |
| yellow | 1 |
+------------------------+-------+
What I also need returned is the total number of values in the column, so the result table would look like this.
+------------------------+--------------+-------+
| color | total | count |
+------------------------+--------------+-------+
| red | 4 | 3 |
| green | 4 | 3 |
| blue | 3 | 2 |
| yellow | 2 | 1 |
+------------------------+--------------+-------+
So the total is the number of each value in the color column and count is the total amount which matches the where clause.
Thanks :)
Here is the link to SQLFiddle.
http://sqlfiddle.com/#!9/777f93/2

Answer 1

You need to use conditional aggregation to handle the counts and let the engine handle the total.
SELECT color
, count(*) as Total
, sum(case when code > 0 and code <= 500 then 1 else 0 end) as cnt
FROM colors
GROUP BY color
ORDER BY cnt desc;

Answer 2

You can use conditional aggregation:
select color,
count(*) as Total,
sum(code > 0 and code <= 500) as count_0_to_500
from colors
group by color
order by count_0_to_500 desc
It uses the fact that true evaluates to 1 and false evaluates to 0 in MySQL.
It's basically what xQbert answered just without a case expression.

Answer 3

You can JOIN your query with another query, e.g.:
select color, count(*) as count , a.total
from colors JOIN (
SELECT color, count(*) as `total` FROM colors GROUP BY color
) a ON colors.code = a.color
where code > 0 && code <= 500
group by color
order by count(*) desc;

Answer 4

You case use a case when statement to count only those items that meet your criteria. Like this:
Select
color
, count(*) as total
, SUM(CASE WHEN code > 0 && code <= 500 THEN 1 ELSE 0 END ) as Count
group by color order by count(*) desc;

Answer 5

You can do it using join query and table alias
select t1.color,t1.total,t2.count
FROM
(select color, count(*) as total from colors group by color) t1,
(select color, count(*) as `count` from colors where `code` > 0 && `code` <= 500 group by color) t2
WHERE
t1.color=t2.color order by `count` desc;
Here is the link to SQLFiddle.
http://sqlfiddle.com/#!9/777f93/2