How to insert data into a Hive(0.13.1) table? - mysql

I am using Hive version 0.13.1. While trying to insert data into an existing table getting an error while using the below query:
CREATE TABLE table1 (order_num int, payment_type varchar(20), category varchar(20));
INSERT INTO TABLE table1 VALUES (151, 'cash', 'lunch');
ERROR :
ParseException line 1:25 cannot recognize input near 'VALUES' '('
'151' in select clause
While searching, got everyone suggesting above query, but unfortunately it's not working for me. Is it due to different Hive version? I am getting this ambiguity due to link here Needs help to insert data to an existing table in Hive.

An insert values statement isn't available in Hive until version .14, so you will need to change your syntax to do a insert select statement.
INSERT INTO TABLE table1 SELECT 151, 'cash', 'lunch';
If you want to insert multiple values then you can union selects
INSERT INTO TABLE table1
SELECT 151, 'cash', 'lunch'
union all
SELECT 152, 'money', 'dinner';

Related

How to merge 2 tables in mySQL [duplicate]

I'm trying to write a query that extracts and transforms data from a table and then insert those data into another table. Yes, this is a data warehousing query and I'm doing it in MS Access. So basically I want some query like this:
INSERT INTO Table2(LongIntColumn2, CurrencyColumn2) VALUES
(SELECT LongIntColumn1, Avg(CurrencyColumn) as CurrencyColumn1 FROM Table1 GROUP BY LongIntColumn1);
I tried but get a syntax error message.
What would you do if you want to do this?
No "VALUES", no parenthesis:
INSERT INTO Table2(LongIntColumn2, CurrencyColumn2)
SELECT LongIntColumn1, Avg(CurrencyColumn) as CurrencyColumn1 FROM Table1 GROUP BY LongIntColumn1;
You have two syntax options:
Option 1
CREATE TABLE Table1 (
id int identity(1, 1) not null,
LongIntColumn1 int,
CurrencyColumn money
)
CREATE TABLE Table2 (
id int identity(1, 1) not null,
LongIntColumn2 int,
CurrencyColumn2 money
)
INSERT INTO Table1 VALUES(12, 12.00)
INSERT INTO Table1 VALUES(11, 13.00)
INSERT INTO Table2
SELECT LongIntColumn1, Avg(CurrencyColumn) as CurrencyColumn1 FROM Table1 GROUP BY LongIntColumn1
Option 2
CREATE TABLE Table1 (
id int identity(1, 1) not null,
LongIntColumn1 int,
CurrencyColumn money
)
INSERT INTO Table1 VALUES(12, 12.00)
INSERT INTO Table1 VALUES(11, 13.00)
SELECT LongIntColumn1, Avg(CurrencyColumn) as CurrencyColumn1
INTO Table2
FROM Table1
GROUP BY LongIntColumn1
Bear in mind that Option 2 will create a table with only the columns on the projection (those on the SELECT).
Remove both VALUES and the parenthesis.
INSERT INTO Table2 (LongIntColumn2, CurrencyColumn2)
SELECT LongIntColumn1, Avg(CurrencyColumn) FROM Table1 GROUP BY LongIntColumn1
I believe your problem in this instance is the "values" keyword. You use the "values" keyword when you are inserting only one row of data. For inserting the results of a select, you don't need it.
Also, you really don't need the parentheses around the select statement.
From msdn:
Multiple-record append query:
INSERT INTO target [(field1[, field2[, …]])] [IN externaldatabase]
SELECT [source.]field1[, field2[, …]
FROM tableexpression
Single-record append query:
INSERT INTO target [(field1[, field2[, …]])]
VALUES (value1[, value2[, …])
Remove VALUES from your SQL.
Remove "values" when you're appending a group of rows, and remove the extra parentheses. You can avoid the circular reference by using an alias for avg(CurrencyColumn) (as you did in your example) or by not using an alias at all.
If the column names are the same in both tables, your query would be like this:
INSERT INTO Table2 (LongIntColumn, Junk)
SELECT LongIntColumn, avg(CurrencyColumn) as CurrencyColumn1
FROM Table1
GROUP BY LongIntColumn;
And it would work without an alias:
INSERT INTO Table2 (LongIntColumn, Junk)
SELECT LongIntColumn, avg(CurrencyColumn)
FROM Table1
GROUP BY LongIntColumn;
Well I think the best way would be (will be?) to define 2 recordsets and use them as an intermediate between the 2 tables.
Open both recordsets
Extract the data from the first table (SELECT blablabla)
Update 2nd recordset with data available in the first recordset (either by adding new records or updating existing records
Close both recordsets
This method is particularly interesting if you plan to update tables from different databases (ie each recordset can have its own connection ...)
inserting data form one table to another table in different DATABASE
insert into DocTypeGroup
Select DocGrp_Id,DocGrp_SubId,DocGrp_GroupName,DocGrp_PM,DocGrp_DocType
from Opendatasource( 'SQLOLEDB','Data Source=10.132.20.19;UserID=sa;Password=gchaturthi').dbIPFMCI.dbo.DocTypeGroup
Do you want to insert extraction in an existing table?
If it does not matter then you can try the below query:
SELECT LongIntColumn1, Avg(CurrencyColumn) as CurrencyColumn1 INTO T1 FROM Table1
GROUP BY LongIntColumn1);
It will create a new table -> T1 with the extracted information

mySQL Error code 1136 with TRIGGER Syntax [duplicate]

So I read the other posts but this question is unique. So this SQL dump file has this as the last entry.
INSERT INTO `wp_posts` VALUES(2781, 3, '2013-01-04 17:24:19', '2013-01-05 00:24:19'.
I'm trying to insert this value to the table...
INSERT INTO `wp_posts` VALUES(5, 5, '2005-04-11 09:54:35', '2005-04-11 17:54:35'
it gives me the error, "Column count doesn't match value count at row 1." So I'm lost on the concept of how the column and row apply here.
Doesn't 2781,3 mean row 2781 and column 3? And doesn't 5,5 mean row 5 and column 5?
The error means that you are providing not as much data as the table wp_posts does contain columns. And now the DB engine does not know in which columns to put your data.
To overcome this you must provide the names of the columns you want to fill. Example:
insert into wp_posts (column_name1, column_name2)
values (1, 3)
Look up the table definition and see which columns you want to fill.
And insert means you are inserting a new record. You are not modifying an existing one. Use update for that.
you missed the comma between two values or column name
you put extra values or an extra column name
You should also look at new triggers.
MySQL doesn't show the table name in the error, so you're really left in a lurch. Here's a working example:
use test;
create table blah (id int primary key AUTO_INCREMENT, data varchar(100));
create table audit_blah (audit_id int primary key AUTO_INCREMENT, action enum('INSERT','UPDATE','DELETE'), id int, data varchar(100) null);
insert into audit_blah(action, id, data) values ('INSERT', 1, 'a');
select * from blah;
select * from audit_blah;
truncate table audit_blah;
delimiter //
/* I've commented out "id" below, so the insert fails with an ambiguous error: */
create trigger ai_blah after insert on blah for each row
begin
insert into audit_blah (action, /*id,*/ data) values ('INSERT', /*NEW.id,*/ NEW.data);
end;//
/* This insert is valid, but you'll get an exception from the trigger: */
insert into blah (data) values ('data1');
MySQL will also report "Column count doesn't match value count at row 1" if you try to insert multiple rows without delimiting the row sets in the VALUES section with parentheses, like so:
INSERT INTO `receiving_table`
(id,
first_name,
last_name)
VALUES
(1002,'Charles','Babbage'),
(1003,'George', 'Boole'),
(1001,'Donald','Chamberlin'),
(1004,'Alan','Turing'),
(1005,'My','Widenius');
You can resolve the error by providing the column names you are affecting.
> INSERT INTO table_name (column1,column2,column3)
`VALUES(50,'Jon Snow','Eye');`
please note that the semi colon should be added only after the statement providing values
In my case i just passed the wrong name table, so mysql couldn't find the right columns names.

MySQL - Insert into a table and get the ID of this to insert into another table -- all in one query

I have a exercise_logs table with these columns:
user_id | exercise_name | mood_log_id | weight_log_id | stretch_log_id
I have three tables (mood_logs, weight_logs and stretch_logs) whose primary key is stored in the 3 last three respective columns in exercise_logs.
These are columns my mood_logs table:
id | mood_scale
So I want to create a new mood_logs entry and use the id from that and store that in exercise_log. But I want to do it all in one query.
Here's what I tried so far:
INSERT INTO `exercise_logs` (`exercise_name`, `user_id`, `mood_log_id`)
values('Breathing', 190, (INSERT INTO `mood_logs` (`mood_scale`)
values(9); LAST_INSERT_ID()))
But this does not work.
Is it possible to achieve this in one query?
Thank you so much.
You can try this
First query insert into mood_logs
INSERT INTO `mood_logs` (`mood_scale`)
values(9);
2nd Query insert into exercise_logs
INSERT INTO `exercise_logs` (`exercise_name`, `user_id`, `mood_log_id`)
values('Breathing', 190, (SELECT `mood_scale` FROM `mood_logs` WHERE `mood_scale` = 9))
You first need to INSERT a row into mood_logs.
As the latest inserted id is from the above statement.
You can use last_insert_id() directly within the second insert statement.
INSERT INTO `mood_logs` (`mood_scale`) values (9);
INSERT INTO `exercise_logs` (`exercise_name`, `user_id`, `mood_log_id`) values('Breathing', 190, last_insert_id());
This is assuming you're the only using the database. If someone else uses an INSERT statement before you can use the last_insert_id() then, the id MIGHT be equal to whatever id the latest insert statement.
Can also use variables to store the last_insert_id();
INSERT INTO `mood_logs` (`mood_scale`) values (9);
SET #arbitraryVariableName = last_insert_id();
INSERT INTO `exercise_logs` (`exercise_name`, `user_id`, `mood_log_id`) values('Breathing', 190, #arbitraryVariableName);

Adding entry inside a table in database

I wanted to add an entry inside a table in SQL database.
For example I have the following Database
CREATE TABLE `distributor_geneology` (
`distributor_gen_id` bigint(20) NOT NULL,
`user_id` varchar(24) NOT NULL,
`id` bigint(20) NOT NULL,
`sponsor_id` bigint(20) NOT NULL,
`rank` tinyint(4) NOT NULL
);
And I want to add an entry in sponsor_id or say id inside a database.
First, I imported the database in my SQL Workbench then In my SQL Workbench, I ran a command select * from distributor_geneology which gave me
Error Code: 1146. Table 'dba_db.distributor_genelogy' doesn't exist
[Question] How can I create/add Entry for ID (or sponsor ID or any other filed)?
One typical way which data would enter a MySQL database is via an INSERT statement:
INSERT INTO distributor_geneology (distributor_gen_id, user_id, id, sponsor_id, rank)
VALUES
(1, 1, 1, 1, 1);
I am inserting 1 everywhere, but you may alter the tuple with the values you want.
Another way to get data into a table is bulk loading via LOAD DATA.
For your first part of your question which is "Add an entry to inside table"
this operation called insertion in the database and the keyword database used to insert data is insert into
It is possible to write the INSERT INTO statement in two ways:
1- specifies both the column names and the values to be inserted
INSERT INTO table_name (column1, column2, column3, ...)
VALUES (value1, value2, value3, ...);
you can rearrange the columns orders as you want but must the values be the same order of the columns and you can let any column null if you don't want to insert any data in this column but be careful if you have not null column you must insert in you query
in your case, all the columns you have are not null.
2- if you do not need to specify the column names in the SQL query. make sure the order of the values is in the same order as the columns in the table
INSERT INTO table_name
VALUES (value1, value2, value3, ...);
For your second part of your question which is "Error Code: 1146. Table 'dba_db.distributor_genelogy' doesn't exist"
First, ensure you imported the DB correctly and if yes > write try to use DB name in your query.
select * from DB_Name.Table_Name
Edit:
Try this query format
INSERT INTO distributor_geneology (distributor_gen_id, user_id, id, sponsor_id, rank)
VALUES
(10, '10', 10, 10, 10);
please note I put second value between 2 quotes because you are defining the user_id as varchar which means not an integer so we should put it between qouts

mysql insert record without using 'values'

INSERT INTO class
(name, description, personid)
Select name, description, 12 from Class where PersonID = 3;
Select * from Class
Select * from Person
Why is the values words is missing from above statement? I thought it should be like this insert into tableA('name') values('select name from tableB') ?
INSERT INTO my_table VALUES ()
Insert data one Table to another table
OR
Not Using Value keyword
Insert into Table2 (Name , Address , Mobile) Select Column 1, Column 2 , Column 3 From Table1
There are different techniques of INSERT, the code above is inserting values from the table itself and change only the personid to 12, he use select so that he can copy the data aside from hardcoded personid . that's why you didn't see the VALUES keyword , but that's true.. the basic insert statement we learn from school is INSERT INTO TableName (Col1, Col2... etc) VALUES (Value1, Value2... etc) , INSERTION of data depends on the requirements that you are working on.