single query for display two rows and assuming two table - mysql

Question

for example this is my data
info
----
id name eating andSaying
--- ---- ------ ---------
1 aman mango with sister amanzing mango
2 ramesh mango via mouth wow its really good
3 aman guava with jimmy yoyo
4 ramesh pineapple yummy
Now i want a single query where i can fetch those rows who is having common eating value (table name eating) for example where name is aman and ramesh who is having same eating then show the rows
info
-----
id name eating andSaying
--- ---- ------ ---------
1 aman mango with sister amanzing mango
2 ramesh mango via mouth wow its really good
i have tried this query but it is NOT Working
SELECT *
FROM info a1
JOIN info a2
ON a1.name!= a2.name
AND a1.eating (get first array before "space"mango ) = a2.eating(get first array before "space" mango )
How to get the two rows if eating on first letter is same?
it should reflect two rows like this
info
-----
id name eating andSaying
--- ---- ------ ---------
1 aman mango with sister amanzing mango
2 ramesh mango via mouth wow its really good

Answer 1

To get the eating values related to more than one name values you can use:
SELECT eating
FROM info
GROUP BY eating
HAVING COUNT(DISTINCT name) > 1
Output:
eating
------
mango
Use the above query as a derived table and join back to the info table to get the expected result set:
SELECT i1.*
FROM info AS i1
JOIN (
SELECT eating
FROM info
GROUP BY eating
HAVING COUNT(DISTINCT name) > 1
) AS i2 ON i1.eating = i2.eating
Edit:
To get matches depending on the first word of eating field, instead of:
GROUP BY eating
use:
GROUP BY SUBSTRING_INDEX(`eating`, ' ', 1)
So the whole query could look like this:
SELECT i1.*
FROM info AS i1
JOIN (
SELECT SUBSTRING_INDEX(`eating`, ' ', 1) AS eating
FROM info
GROUP BY SUBSTRING_INDEX(`eating`, ' ', 1)
HAVING COUNT(DISTINCT `name`) > 1
) AS i2 ON i1.eating LIKE CONCAT(i2.eating, '%');
Demo here

Answer 2

I've stripped out the irrelevant parts of the problem...
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(name VARCHAR(12) NOT NULL
,eating VARCHAR(12) NOT NULL
,PRIMARY KEY(name,eating)
);
INSERT INTO my_table VALUES
('aman','mango'),
('ramesh','mango'),
('aman','guava'),
('ramesh','pineapple');
SELECT DISTINCT x.*
FROM my_table x
JOIN my_table y
ON y.name <> x.name
AND y.eating = x.eating;
+--------+--------+
| name | eating |
+--------+--------+
| ramesh | mango |
| aman | mango |
+--------+--------+