Converting C code to mips gives error - mips

Question

This is the C code that i have been converted so far. it gives me some error that i have been included in the following code. i don't understand which part is wrong in this c to mips conversion?
char ch[10];
int i;
for (i = 0; i != 10; i++)
ch[i] = ch[i] – 32
.data
.text
li $v0 4
syscall
#$s1 = i, $s0 base address of ch
addi $s1, $0, 0 #i =0
addi $t0, $0, 10 #t0 = 10
loop: beq $t0, $s1, end
add $t1, $s1, $s0
lw $t2, 0($t1)
addi $t2, $t2, -32
sw $t2, 0($t1)
addi $s1, $s1, 1
j loop
end:
My output:
Runtime exception at 0x00400018: address out of range 0x00000000

Answer 1

From the C code you are converting a char type array and in MIPS you should use lb instead of lw.
In order to print out you need a main: label and also you should declare an array like .byte or .space
You should usesyscall 11 to print a character or syscall 4 to print
string.
I have added some of these mentioned above to your code hope it helps.
.data
#ch: .byte 'a','b','c','d','e'
ch: .space 10
.text
main:
li $v0, 8 #read character
li $a1, 10 #load the space
la $a0, ch
syscall
li $v0,11 #print character
syscall
li $v0,10 # exit program
syscall
addi $s1, $0, 0 #i = 0
addi $t0, $0, 10 # $t0 = 10
loop: beq $t0, $s1, end
add $t1, $s1, $s0
lb $t2, ch($t1)
addi $t2, $t2, -32
sb $t2, ch($t1)
addi $s1, $s1, 1
j loop
end: