SQL showing all weeks(52) in current year - mysql

Question

how can I show all weeks(52) in current year
I have made this query:
SELECT
COALESCE(IF(DATE_FORMAT(q.date_add, '%Y-%u') IS NULL,
(DATE_FORMAT(q.date_add, '%Y-%u')),
DATE_FORMAT(q.date_add, '%Y WEEK %u'))) AS CurrentDate,
COALESCE(IF(SUM(q.totalExcl) IS NULL,
0,
SUM(q.totalExcl))) AS total
FROM
expoled.ps_oxoquotation_quotationstate_history h
RIGHT JOIN
expoled.ps_oxoquotation_quotation q ON h.idQuotation = q.idQuotation
LEFT JOIN
expoled.ps_employee e ON h.idEmployee = e.id_employee
INNER JOIN
expoled.ps_sv_employee_meta m ON h.idEmployee = m.id_employee
WHERE
h.idEmployee = 39
AND YEAR(q.date_add) = YEAR(UTC_TIMESTAMP())
AND h.idQuotationState = 3
GROUP BY IFNULL(CurrentDate, '')
I think I need to do something in here:
SELECT
IFNULL(DATE_FORMAT(q.date_add, '%Y WEEK %u'), 0) AS CurrentDate,
IFNULL(SUM(q.totalExcl),0) AS total
FROM
I have tryed to put IFNULL but that gave me the same result
this is what I'm getting right now:
It show the current weeks from 5 to week 16.
There is also nothing in Week 1 till Week 4 because there is no data in. And there it needs to show just a simple zero(0)
So what I want is it needs to show standard from Week 1 till week 52 and if there is no data just 0
The query is working right now without any errors.

Answer 1

To obtain a fixed number of weeks, without a particular table, I tried this.
Table XX1 is just to make the test, you can substitute with one of your table. If it has a number of records >=366 you can eliminate the CROSS JOIN.
CREATE TABLE XX1 (id INT);
INSERT INTO XX1 VALUES (1);
INSERT INTO XX1 VALUES (2);
INSERT INTO XX1 VALUES (3);
INSERT INTO XX1 VALUES (4);
INSERT INTO XX1 VALUES (5);
SELECT DISTINCT DATE_FORMAT(RN, '%Y w%u') AS CURR_WEEK
FROM
(SELECT #RN:=DATE_ADD(str_to_date( CONCAT(YEAR(UTC_TIMESTAMP()) ,'0101'), '%Y%m%d'), INTERVAL -1 DAY) AS RN
UNION ALL
SELECT #RN:=DATE_ADD(#RN, INTERVAL 1 DAY) AS RN
FROM (SELECT 1 AS DUM FROM XX1
CROSS JOIN XX1 X2
CROSS JOIN XX1 X3
CROSS JOIN XX1 X4
) Y LIMIT 366
) X
WHERE YEAR(RN)=YEAR(UTC_TIMESTAMP())
ORDER BY 1;
DROP TABLE XX1 ;
Output:
CURR_WEEK
1 2017 w00
2 2017 w01
3 2017 w02
4 2017 w03
5 2017 w04
...
51 2017 w50
52 2017 w51
53 2017 w52
I think you could use this in place of your query (I couldn't do any test on your query of course)
Other (and hope last) version:
SELECT Y.CURR_WEEK,
COALESCE(SUM(qh.totalExcl), 0) AS total
FROM
(SELECT DISTINCT DATE_FORMAT(RN, '%Y-%u') AS CURR_WEEK
FROM
(SELECT #RN:=DATE_ADD(str_to_date( CONCAT(YEAR(UTC_TIMESTAMP()) ,'0101'), '%Y%m%d'), INTERVAL -1 DAY) AS RN
UNION ALL
SELECT #RN:=DATE_ADD(#RN, INTERVAL 1 DAY) AS RN
FROM XX1
CROSS JOIN XX1 X2
CROSS JOIN XX1 X3
CROSS JOIN XX1 X4
) X
WHERE YEAR(RN)=YEAR(UTC_TIMESTAMP())
) Y
LEFT JOIN (SELECT q.date_add, q.totalExcl, h.idEmployee
FROM expoled.ps_oxoquotation_quotation q
INNER JOIN expoled.ps_oxoquotation_quotationstate_history h ON h.idQuotation = q.idQuotation
WHERE h.idEmployee = 39 AND h.idQuotationState = 3) qh ON DATE_FORMAT(qh.date_add, '%Y-%u')=Y.CURR_WEEK
/* are these useless? */
LEFT JOIN expoled.ps_employee e ON qh.idEmployee = e.id_employee
LEFT JOIN expoled.ps_sv_employee_meta m ON qh.idEmployee = m.id_employee
GROUP BY Y.CURR_WEEK

Answer 2

In MariaDB, it is really easy to build a table of weeks:
mysql> SELECT ('2017-01-02' + INTERVAL seq WEEK) AS wk FROM seq_0_to_53;
+------------+
| wk |
+------------+
| 2017-01-02 |
| 2017-01-09 |
| 2017-01-16 |
| 2017-01-23 |
| 2017-01-30 |
| 2017-02-06 |
| 2017-02-13 |
| 2017-02-20 |
...
Based on that, you can:
JOIN to your table and use wk as needed.
Change the starting date to align with Sunday instead of Monday (or whatever)
Go for as many weeks as you like
Restrict the range after the fact with WHERE wk BETWEEN ...
By fetching something like CONCAT('2017 WEEK ', seq) AS iso you can get the syntax you requested.