How to query last 2 business days only - sql-server-2008

Question

I'm running a query that pulls the correct information I'm looking for, but I need it to pull the last 2 business days rather than the last 2 days. This comes into play when it's Monday and my results show information for Monday and Sunday rather than Monday and Friday. How can I change my query to pull in business days only?
USE [LetterGeneration]
SELECT g.LetterGenerationPrintJobId
,CAST(t.[TemplateKey] AS VarChar) AS LetterCode
,convert(char(12),r.CreatedDate,101) AS CreatedDate
,s.LetterGenerationStatusId AS Status
,s.StatusKey AS StatusDesc
,count(g.LetterGenerationId) as LetterCount
,c.BankingDateYorN
FROM [LetterGenerationTemplateRequest] AS r
INNER JOIN [LetterGenerationTemplate] AS t
ON t.[LetterGenerationTemplateId] = r.LetterGenerationTemplateId
INNER JOIN LetterGeneration g
ON g.LetterGenerationTemplateRequestId = r.LetterGenerationTemplateRequestId
INNER JOIN LetterGenerationStatus s
ON g.LetterGenerationStatusId = s.LetterGenerationStatusId
INNER JOIN Enterprise..Calendar C
ON c.BeginDate = g.LetterDate
WHERE ((DATEDIFF(d, r.CreatedDate, GETDATE()) = 0) OR (DATEDIFF(d, r.CreatedDate, GETDATE()) = 1))
--BankingDateYorN = 1
--AND RelativeTimeValue_BusinessDates =-1
AND t.[TemplateKey] NOT LIKE '%PLTV1%'
AND s.LetterGenerationStatusId NOT LIKE '4'
AND s.LetterGenerationStatusId NOT LIKE '16'
AND s.LetterGenerationStatusId NOT LIKE '19'
AND s.LetterGenerationStatusId NOT LIKE '20'
AND s.LetterGenerationStatusId NOT LIKE '38'
GROUP BY r.[LetterGenerationTemplateRequestId]
,r.LetterGenerationTemplateId
,g.Lettergenerationprintjobid
,t.[TemplateKey]
,r.[Loan_no]
,r.CreatedDate
,r.[CreatedBy]
,s.LetterGenerationStatusId
,s.StatusKey
,c.BankingDateYorN
ORDER BY r.CreatedDate DESC
UPDATE: I've recently discovered how to join a calendar table to my current query. The calendar query has a column called BusinessDayYorN with 1's for a business day and 0's for weekends and holidays. I've also updated the old query to now include the join.

Answer 1

select *
from LetterGenerationTemplateRequest
where createddate >= (
getdate() -
case datename(dw,getdate())
when 'Tuesday' then 5
when 'Monday' then 4
else 3
end
)
--and datename(dw,createdDate) not in ('Saturday','Sunday',datename(dw,getdate()))
and datename(dw,createdDate) not in ('Saturday','Sunday')
;

Answer 2

Assuming that you always want to include the last two non-weekend days you can try this:
; with aux as (
select diff = case
when datename(weekday, getdate()) in ('Tuesday', 'Wednesday ', 'Thursday', 'Friday') then 1
else
case datename(weekday, getdate())
when 'Saturday' then 2
when 'Sunday' then 3
when 'Monday' then 4
end
end
)
SELECT --r.[LetterGenerationTemplateRequestId]
--,r.LetterGenerationTemplateId
g.LetterGenerationPrintJobId
,CAST(t.[TemplateKey] AS VarChar) AS LetterCode
,r.[Loan_no]
,convert(char(12),r.CreatedDate,101) AS CreatedDate
-- ,g.ModifiedDate
-- ,convert(varchar(18), g.ModifiedDate - r.CreatedDate, 108) AS TimeSpan
,s.LetterGenerationStatusId AS Status
,s.StatusKey AS StatusDesc
,count(g.LetterGenerationId) as LetterCount
FROM [LetterGenerationTemplateRequest] AS r
INNER JOIN [LetterGenerationTemplate] AS t
ON t.[LetterGenerationTemplateId] = r.LetterGenerationTemplateId
INNER JOIN LetterGeneration g
ON g.LetterGenerationTemplateRequestId = r.LetterGenerationTemplateRequestId
INNER JOIN LetterGenerationStatus s
ON g.LetterGenerationStatusId = s.LetterGenerationStatusId
WHERE
DATEDIFF(day, r.CreatedDate, GETDATE()) <= (select diff from aux)
AND t.[TemplateKey] NOT LIKE '%PLTV1%'
AND s.LetterGenerationStatusId NOT LIKE '4'
AND s.LetterGenerationStatusId NOT LIKE '16'
AND s.LetterGenerationStatusId NOT LIKE '19'
AND s.LetterGenerationStatusId NOT LIKE '20'
AND s.LetterGenerationStatusId NOT LIKE '38'
GROUP BY r.[LetterGenerationTemplateRequestId]
,r.LetterGenerationTemplateId
,g.Lettergenerationprintjobid
,t.[TemplateKey]
,r.[Loan_no]
,r.CreatedDate
-- ,g.ModifiedDate
,r.[CreatedBy]
,s.LetterGenerationStatusId
,s.StatusKey
ORDER BY r.CreatedDate DESC
The CTE aux returns a dataset with only one record and only one field, the value of which is the number of days you need to go back in your WHERE statement.