In Kohana that was performed as $user->has('departments', array('id' => $dep->id_department))
I dont see the same in Yii2
$customer = Customer::findOne(123);
$order = new Order();
$order->save(); // now its id is - 33
$customer->link('orders', $order); // let think relation is via table
And now I want to check If my $customer HAS this object linked Order::find(33)
I found very ugly way to do this.
$customer ->getOrders()->where(['id' => 33])->exists();
Is there are shorter and pretty solutions, as its in Kohana does ?
Kohana way:
$customer ->has('orders', ['id' => 33])
Related
I use laravel 5.6
I have a json file containing 500 thousand records. I want to create a logic to check whether the id of each record already exists or not in the database. If it doesn't already exist, then there will be a data insert process. If it already exists, there will be a data update process
I have made logic. I just want to make sure whether my logic is effective or not
My logic code like this :
$path = storage_path('data.json');
$json = json_decode(file_get_contents($path), true);
foreach ($json['value'] as $value) {
$data = \DB::table('details')->where('id', '=', $value['Code'])->get();
if ($data->isEmpty()) {
\DB::table('details')->insert(
[
'id' => $value['Code'],
'number' => $value['Number'],
...
]
);
}
else {
\DB::table('details')
->where('id', '=', $value['Code'])
->update([
'id' => $value['Code'],
'number' => $value['Number'],
...
]);
}
}
The code is working. But the process seems really long
Do you have another solution that is better?
updateOrCreate
You may also come across situations where you want to update an existing model or create a new model if none exists. Laravel provides an updateOrCreate method to do this in one step. Like the firstOrCreate method, updateOrCreate persists the model, so there's no need to call save():
// If there's a flight from Oakland to San Diego, set the price to $99.
// If no matching model exists, create one.
$flight = App\Flight::updateOrCreate(
['departure' => 'Oakland', 'destination' => 'San Diego'],
['price' => 99]
);
in your case your code should be like this (create Details model first) :
$path = storage_path('data.json');
$json = json_decode(file_get_contents($path), true);
foreach ($json['value'] as $value) {
Details::updateOrCreate(
[ 'id' => $value['Code'] ],
[ 'number' => $value['Number'], ... ]
);
}
i think that's the best way to do it. Eloquent return's a collection so you cant just validate that your string is null.
I am generating related records search query for Gridview use
I get this error :
SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'dbowner' in where clause is ambiguous
The SQL being executed was: SELECT COUNT(*) FROM tbl_iolcalculation LEFT JOIN tbl_iolcalculation patient ON tbl_iolcalculation.patient_id = patient.id WHERE (dbowner=1) AND (dbowner=1)
I have two related models 1) iolcalculation and patient - each iolcalculation has one patient (iolcalculation.patient_id -> patient.id)
The relevant code in my model IolCalculationSearch is :
public function search($params)
{
$query = IolCalculation::find();
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$dataProvider->sort->attributes['patient.lastname'] = [
'asc' => ['patient.lastname' => SORT_ASC],
'desc' => ['patient.lastname' => SORT_DESC],
];
$query->joinWith(['patient'=> function($query) { $query->from(['patient'=>'tbl_iolcalculation']); } ]);
if (!($this->load($params) && $this->validate())) {
return $dataProvider;
}
$query->andFilterWhere([
'id' => $this->id,
'patient_id' => $this->patient_id,
'preop_id' => $this->preop_id,
'calculation_date' => $this->calculation_date,
'iol_calculated' => $this->iol_calculated,
The reason this error is generated is that each model has an override to the default Where clause as follows, the reason being that multiple users data needs to be segregated from other users, by the field dbowner:
public static function defaultWhere($query) {
parent::init();
$session = new Session();
$session->open();
$query->andWhere(['t.dbowner' => $session['dbowner']]);
}
this is defined in a base model extending ActiveRecord, and then all working models extend this base model
How Can I resolve this ambiguous reference in the MySQL code?
Thanks in advance
$query->andFilterWhere([
// previous filters
self::tableName() . '.structure_id' => $this->structure_id,
// next filters
]);
I think, that you are searching for table aliases.
(https://github.com/yiisoft/yii2/issues/2377)
Like this, of course you have to change the rest of your code:
$query->joinWith(['patient'=> function($query) { $query->from(['patient p2'=>'tbl_iolcalculation']); } ]);
The only way I can get this to work is to override the default scope find I had set up for most models, so that it includes the actual table name as follows - in my model definition:
public static function find() {
$session = new Session();
$session->open();
return parent::find()->where(['tbl_iolcalculation.dbowner'=> $session['dbowner']]);
}
There may be a more elegant way using aliases, so any advice would be appreciated - would be nice to add aliases to where clauses, and I saw that they are working on this....
I've tried to this:
Product::where(['product_id' => $product->id, 'catalog_id' => $key])->first();
This isn't working at all. When I'm doing this:
Product:where('product_id', $product->id)->where('catalog_id', $key)->first();
It just works fine. I've searched in the documentation of Laravel,
and found nothing.
Is there any option to using the where function with an array in it ?
You need to use where() individually. If you want to dynamically building the query you can do something like:
$wheres = array('product_id' => $product->id, 'catalog_id' => $key);
$q = new Product;
foreach ( $wheres as $k => $v ) {
$q = $q->where($k, $v);
}
$products = $q->first();
In fact we were all wrong ;)
As of latest version of the framework you can do exactly what you wanted.
Check this commit and update Laravel if you need that feature.
https://github.com/laravel/framework/commit/87b267a232983abdac7c23c2dc6b1b270dd24b8a
Product::whereNested(function($query) use ($key, $product){
$query->where('product_id', $product->id);
$query->where('catalog_id', $key);
})->get();
Laravel's wheres use an and condition by default:
$products = Product::where('this','=','that')->where('something','=','hello')->get();
is somewhat equivalent to:
SELECT * FROM products WHERE this = 'that' AND something = 'hello';
You simply chain the ->where() methods together. No need for an array.
If you want to use an or condition:
$products = Product::where('this','=','that')->orWhere('something','=','hello')->get();
Is there anyone who knows how to do this without the technique of doing it in a one query string. I mean the popular ways I see on the net is by looping in data(the updates) and generating a single update statement and then fire a query. Is it possible for an Eloquent Approach or DB without looping?
This is posible with Eloquent, it might be necessary to enable mass-assignment, but you will get an error if so.
$post_data = Input::all();
$model = Model::find($id);
$model ->fill($post_data);
$model ->save();
or
$post_data = Input::all();
Model::find($id)->update($post_data);
Yes, you can do that but in that case, you have to make the array of data that is a loop is needed to store the data in the array with respective field_name => value of the table.
The following is the example:
$Array = array(); //This is needed to hold data while looping over $YourData
$YourData - is the array of data you want to store in the respective table.
foreach ($YourData as $YourDatakey => $YourDatavalue ){
$Array = [
'table_column_name' => $YourDatavalue['value_from_array'],
'table_column_name' => $YourDatavalue['value_from_array'],
'table_column_name' => $YourDatavalue['value_from_array'],
...... and so on
];
}
$InsertQuery= YourModelName::create($Array);
PS:
YourModelName model file should have the columns in protected
$fillable = ['column1','column2'....];
You should use App\Models\ModelName; at the top of the file.
I need to insert multioptions to a dropdown list, options taken from a table from my database.
I created the elements like:
$this->add(array(
'name' => 'company',
'type' => 'Zend\Form\Element\Select',
//'multiOptions'=> $options,
'options' => array(
'label' => 'Company',
),
'attributes' => array(
'style' => "float:right;",
),
));
I want to choose from a dropdown list some values that are in a table in my database. For example I have the entity Contacts and I need to choose for the contact a company that is in a table named companies in the database.
After reading on zend framework's site, I tried using this code:
$params = array(
'driver'=>'Pdo_Mysql',
'host'=>'localhost',
'username'=>'root',
'password'=>'',
'dbname' =>'myDataBase'
);
$db = new \Zend\Db\Adapter\Adapter($params);
$sql= new Sql($db);
$select = $sql->select();
$select ->from('companies')
->columns(array('id','company_name'))
->order(" 'company_name' ASC");
I also read on some other sites that I could use a function:
$options = $sql->fetchPairs('SELECT id, name FROM country ORDER BY name ASC');
but it seems it doesn't exist anymore in Zend Framework 2.
Please guys, give me a hand. If the code isn't good and you have a better idea, please tell me.
Thanks in advance!
This is just a quick and dirty answer, but i guess it can get you started.
Create a ServiceFactory, this should be done in a separate factory class instead of a closure, but i still use a closure - faster to write ;)
Get the config from the ServiceLocator so you have access to the DB-Params
Create your default SQL Stuff to retriefe the value_options
Populate the value_options using the setValueOptions($valueOptions) function of your given form-element
Module.php getServiceConfig()
return array(
'factories' => array(
'my-form-factory' => function($serviceLocator) {
$form = new My\Form();
$config = $serviceLocator->get('config');
$db = new \Zend\Db\Auth\Adapter\Adapter($config['dbParams']); //or whatever you named the array key
$sql = //do your SQL Stuff
// This is a fake array, it should be your $sql result in the given format
$result = array('value' => 'label', 'value2' => 'label2');
$form->get('elementToPopulate')->setValueOptions($result);
return $form;
}
)
);
SomeController.php someAction()
$form = $this->getServiceLocator()->get('my-form-factory');
return new ViewModel(array(
'form' => $form
));
I hope this gets you started
you have to add that field validation on controller for setting value in it.
$select = $db->select()->where("state_code = ?",$arr["state_code"]);
$resultSet = $cityObj->fetchAll($select);
$cityArr = $resultSet->toArray();
$city_ar = array();
foreach($cityArr as $city){
$city_ar[$city['id']] = $city['company'];
}
$form->company->setMultiOptions($city_ar);
$form->company->setValue($val["company"]);
by using this code drop down of country have the value that are in resultset array ($resultSet).