Improve query of getting row with max value - mysql

Question

I have next tables:
CREATE TABLE IF NOT EXISTS `Customers` (
`id` INT AUTO_INCREMENT,
`name` VARCHAR(20) NOT NULL,
PRIMARY KEY(`id`)
);
CREATE TABLE IF NOT EXISTS `Orders` (
`id` INT AUTO_INCREMENT,
`id_cust` INT NOT NULL,
`descr` VARCHAR(40),
`price` INT NOT NULL,
PRIMARY KEY(`id`),
FOREIGN KEY(`id_cust`) REFERENCES `Customers`(`id`)
);
One customer can have many orders. I want to get id_cust and sum of the orders of who paid the most(one person).
My query:
SELECT cust, max_orders_sum
FROM
(
(
SELECT MAX(orders_sum) AS max_orders_sum
FROM (
SELECT o.id_cust AS cust, SUM(o.price) AS orders_sum
FROM Orders AS o
GROUP BY o.id_cust
) AS same_query0
) AS step1
INNER JOIN
(
SELECT o.id_cust AS cust, SUM(o.price) AS orders_sum
FROM Orders AS o
GROUP BY o.id_cust
) AS same_query1
ON (step1.max_orders_sum = same_query1.orders_sum)
);
Main problem:
as you can see, it has the same parts: same_query0 and same_query1. Is there any way to get rid of them?
Or if you know the better way to reach my goal, please share.
I found one simple solution:
SELECT o.id_cust AS cust, SUM(o.price) AS orders_sum
FROM Orders AS o
GROUP BY o.id_cust
ORDER BY orders_sum DESC LIMIT 1;
But this is not a direct way to solve the problem.

Answer 1

I don't think you can do much better than what you've already done, unless you create a view like
create view v_cust_tot as
select id_cust, sum(price) as cust_tot
from Orders
group by id_cust
With that you'd be able to rewrite your query like this
select id_cust, cust_tot
from v_cust_tot
where cust_tot = (select max(cust_tot) from v_cust_tot)
This would be an improvement just in the compactness of the query, because I think performances would be the same as the execution plan would be almost identical

Answer 2

Another one nice solution:
select id_cust, sum(price) from orders group by id_cust having sum(price) =
(select max(prc) from
(select sum(price) as prc from orders group by id_cust) as tb);