following a hierarchy in beautiful soup - html

Question

I have a HTML file with following format:
<div class="entry">
<p>para1</p>
<p>para2</p>
<p><div class="abc"> Ignore this part1</div> </p>
<p><script class="xyz">Ignore this part2 </script></p>
</div>
Suppose there is only one div tag with class value "entry". I want to print all text inside those p tags which are inside div tag with class value "entry" , except those p tags which are followed by div or script tag. So here I want to print "para1" and "para2" but not "Ignore this part1" and "Ignore this part2"
How do I achieve this using beautiful soup?

Answer 1

Use a lambda expression to filter what you don't need.
Example:
# -*- coding: utf-8 -*-
import requests
from bs4 import BeautifulSoup
example = """<div class="entry">
<p>para1</p>
<p>para2</p>
<p><div class="abc"> Ignore this part1</div> </p>
<p><script class="xyz">Ignore this part2 </script></p>
<p>example para</p>
</div>"""
soup = BeautifulSoup(example, 'html.parser')
entry = soup.find('div', class_="entry")
p = entry.find_all(lambda tag: tag.name == "p" and not (tag.find("div")
or tag.find("script")))
for content in p:
print (content.get_text(strip=True))
Outputs:
para1
para2
example para

Answer 2

Alternativ solution with css selector
A simple solution could be the use of modern css selectors:
soup.select('div.entry p:not(:empty,:has(div,script))')
Example
from bs4 import BeautifulSoup
example = '''<div class="entry">
<p>para1</p>
<p>para2</p>
<p><div class="abc"> Ignore this part1</div> </p>
<p><script class="xyz">Ignore this part2 </script></p>
<p>example para</p>
</div>'''
soup = BeautifulSoup(example, 'html.parser')
for e in soup.select('div.entry p:not(:empty,:has(div,script))'):
print(e.text)
Output
para1
para2
example para