SELECT from database date where date is today and multiple - mysql

Question

There are a method with SQL to SELECT from one database the date records where the date is today and the date is multiple of two years.
For example, i have a table call "list". That table have two column, 'ID' and 'last_date'. One of this record is: ID = '1' and date = '17-03-2015'
I need to select all record where the date is the date on the table + 2 year. For example today the query will return the ID 1.
Thanks to all.

Answer 1

Use DATE_SUB() to subtract 2 years from today's date, and compare that to the column.
SELECT id
FROM list
WHERE last_date = DATE_SUB(CURDATE(), INTERVAL 2 YEAR);
This is a little better than #Teja's solution because it only has to do the date arithmetic once, rather than for every row in the table. And if there's an index on the last_date column, it will be able to use it to find the rows quickly.

Answer 2

We can write an expression that returns a date value that is exactly two days before today's date:
SELECT DATE(NOW()) + INTERVAL -2 YEAR
We can use an expression in the WHERE clause of a query. If the column in the table we want to check is defined as DATE datatype:
SELECT t.id
FROM mytable t
WHERE t.mydatecol = DATE(NOW()) + INTERVAL -2 YEAR
If it's defined as a DATETIME, the normal pattern would be range check
SELECT t.id
FROM mytable t
WHERE t.mydatecol >= DATE(NOW()) + INTERVAL -2 YEAR
AND t.mydatecol < DATE(NOW()) + INTERVAL -2 YEAR + INTERVAL 1 DAY
If the column is stored as a VARCHAR in a non-canonical format e.g. DD-MM-YYYY then we could either attempt to convert that to a DATE using STR_TO_DATE (which we don't like to do because the query can't make effective use of a index), or we could convert our generated date value into the required string format for an equality comparison:
SELECT t.id
FROM mytable t
WHERE t.ddmmyyyy = DATE_FORMAT(DATE(NOW()) + INTERVAL -2 YEAR,'%d-%m-%Y')
That would get us exact match to '17-03-2015', but not to '17-3-2015'. And we have to do equality test or IN list, we can't do range check, because the value stored in the column isn't canonical.
If we need to look for multiple dates... today, two years ago, four years ago, six years ago, ... we can generate a list of dates and perform a join operation. (Assuming that mydatecol is defined as DATETIME...)
SELECT t.id
FROM ( SELECT DATE(NOW()) + INTERVAL 0 YEAR AS dt
UNION ALL SELECT DATE(NOW()) + INTERVAL -2 YEAR
UNION ALL SELECT DATE(NOW()) + INTERVAL -4 YEAR
UNION ALL SELECT DATE(NOW()) + INTERVAL -6 YEAR
UNION ALL SELECT DATE(NOW()) + INTERVAL -8 YEAR
UNION ALL SELECT DATE(NOW()) + INTERVAL -10 YEAR
UNION ALL SELECT DATE(NOW()) + INTERVAL -12 YEAR
UNION ALL SELECT DATE(NOW()) + INTERVAL -14 YEAR
UNION ALL SELECT DATE(NOW()) + INTERVAL -16 YEAR
UNION ALL SELECT DATE(NOW()) + INTERVAL -18 YEAR
UNION ALL SELECT DATE(NOW()) + INTERVAL -20 YEAR
) l
JOIN mytable t
WHERE t.mydatecol >= l.dt + INTERVAL 0 DAY
AND t.mydatecol < l.dt + INTERVAL 1 DAY