I'm trying to select if a user rating (user.rating) is greater then 6 or if the user has more then 100 transactions (transaction table count). Basically count how many transactions the user has then where (transaction count >= 100 OR user rating >= 6).
SELECT *
FROM `user`
JOIN (SELECT COUNT(*)
FROM transaction
WHERE transaction.user_id=user.id
AND type='L'
AND status='S') AS tcount
WHERE (user.rating >= '6' OR tcount >= '100')
Just another possible answer. I've created simplified schemas to test it, please try it and let me know the result.
SELECT *
FROM user
WHERE user.rating >= 6 OR (SELECT COUNT(*) FROM transaction WHERE user_id = user.id and type = 'L' and status = 'S') >= 100;
Use an alias on COUNT(*)
SELECT *
FROM `user`
JOIN (SELECT user_id, COUNT(*) cnt
FROM transaction
WHERE type='L'
AND status='S'
GROUP BY user_id) AS tcount
ON user.id = tcount.user_id
WHERE (user.rating >= '6' OR tcount.cnt >= '100')
You can write that without the subquery, like this
SELECT u.id
FROM `user` u
JOIN `transaction` t
ON t.user_id=u.id
WHERE t.type = 'L' AND t.status = 'S'
GROUP BY u.id
HAVING sum(case when u.rating >= 6 then 1 end) > 0 OR count(*) >= 100
Related
So currently I have 2 tables called listings and logs table. The listings table holds a products reference number and it's current status. So suppose if it's status was Publish currently and it's sold, the status updates to Sold. Here the refno. in this table is unique since the status can change for 1 product.
Now I have another table called Logs table, this table records all the status changes that have happened for a particular product(referenced by refno) in a particular timeframe. Suppose the Product with refno. 5 was Publish on 1st October and Sold on 2nd October, The logs table will display as:
Refno
status_from
status_to
logtime
5
Stock
Publish
2021-10-01
5
Publish
Sold
2021-10-02
This is how my tables currently look like:
Listings table:('D'=>'Draft','N'=>'Action','Y'=>'Publish')
Logs Table which I'm getting using the following statement:
SELECT refno, logtime, status_from, status_to FROM (
SELECT refno, logtime, status_from, status_to, ROW_NUMBER() OVER(PARTITION BY refno ORDER BY logtime DESC)
AS RN FROM crm_logs WHERE logtime < '2021-10-12 00:00:00' ) r
WHERE r.RN = 1 UNION SELECT refno, logtime, status_from, status_to
FROM crm_logs WHERE logtime <= '2021-10-12 00:00:00' AND logtime >= '2015-10-02 00:00:00'
ORDER BY `refno` ASC
The logs table makes a new record every status change made and passes the current timestamp as the logtime, and the listings table changes/updates the status and updates its update_date. Now to get the total listings as of today I'm using the following statement:
SELECT SUM(status_to = 'D') AS draft, SUM(status_to = 'N') AS action, SUM(status_to = 'Y') AS publish FROM `crm_listings`
And this returns all the count data for status as of the current day.
Now this is where it gets confusing for me. So suppose today the count under action is 10 and tomorrow it'll be 15, and I want to retrieve the total that was present yesterday(10). So for this what I would've to do is take todays total(15) and subtract all the places where a product was changed to draft in between yesterday and today(Total count today in listing table - count(*) where status_to='Action' from logs table). Or vice versa, if yesterday it was 10 under action and today it is 5, it should add the values from the status_from column in logs table
Note: Refno isn't unique in my logs table since a product with the same refno can be marked as publish 1 day and unpublish another, but it is unique in my listings table.
Link to dbfiddle: https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=01cb3ccfda09f6ddbbbaf02ec92ca894
I am sure it can be simplifed or better. But its my query and logic :
I found status_changes per refno's and calculated total changes from the desired day to present :
select status_logs, sum(cnt_status) to_add from (
SELECT
status_to as status_logs, -1*count(*) cnt_status
FROM logs lm
where
id = (select max(id) from logs l where l.refno = lm.refno) and
logtime >= '2021-10-01 00:00:00'
group by status_to
union all
SELECT
status_from, count(*) cnt_status_from
FROM logs lm
where
id = (select max(id) from logs l where l.refno = lm.refno) and
logtime >= '2021-10-01 00:00:00'
group by status_from ) total_changes
group by status_logs
I matched the keys between listings table and logs table by converting listings table keys :
select
case status
when 'D' THEN 'Draft'
when 'A' THEN 'Action'
when 'Y' THEN 'Publish'
when 'S' THEN 'Sold'
when 'N' THEN 'Let'
END status_l ,COUNT(*) c
from listings
group by status
I joined them and add the calculations to total sum of current data.
I had to use full outer join , so i have one left and one right join with the same subqueries.
Lastly I used distinct , since it will generate same result for each joined query and used ifnull to bring the other tables status to the other column .
select distinct IFNULL(status_l, status_logs) status, counts_at_2021_10_01
from (select l.*,
logs.*,
l.c + ifnull(logs.to_add, 0) counts_at_2021_10_01
from (select case status
when 'D' THEN
'Draft'
when 'A' THEN
'Action'
when 'Y' THEN
'Publish'
when 'S' THEN
'Sold'
when 'N' THEN
'Let'
END status_l,
COUNT(*) c
from listings
group by status) l
left join (
select status_logs, sum(cnt_status) to_add
from (SELECT status_to as status_logs,
-1 * count(*) cnt_status
FROM logs lm
where id = (select max(id)
from logs l
where l.refno = lm.refno)
and logtime >= '2021-10-01 00:00:00'
group by status_to
union all
SELECT status_from, count(*) cnt_status_from
FROM logs lm
where id = (select max(id)
from logs l
where l.refno = lm.refno)
and logtime >= '2021-10-01 00:00:00'
group by status_from) total_changes
group by status_logs) logs
on logs.status_logs = l.status_l
union all
select l.*,
logs.*,
l.c + ifnull(logs.to_add, 0) counts_at_2021_05_01
from (select case status
when 'D' THEN
'Draft'
when 'A' THEN
'Action'
when 'Y' THEN
'Publish'
when 'S' THEN
'Sold'
when 'N' THEN
'Let'
END status_l,
COUNT(*) c
from listings
group by status) l
right join (
select status_logs, sum(cnt_status) to_add
from (SELECT status_to as status_logs,
-1 * count(*) cnt_status
FROM logs lm
where id = (select max(id)
from logs l
where l.refno = lm.refno)
and logtime >= '2021-10-01 00:00:00'
group by status_to
union all
SELECT status_from, count(*) cnt_status_from
FROM logs lm
where id = (select max(id)
from logs l
where l.refno = lm.refno)
and logtime >= '2021-10-01 00:00:00'
group by status_from) total_changes
group by status_logs) logs
on logs.status_logs = l.status_l) l
How can I combine these three queries into one?
SELECT COUNT(*)
FROM Users
WHERE (SELECT COUNT(*) FROM Posts WHERE Posts.OwnerUserId = Users.Id) < 10;
SELECT COUNT(*)
FROM Users
WHERE (SELECT COUNT(*) FROM Posts WHERE Posts.OwnerUserId = Users.Id) BETWEEN 10 AND 20;
SELECT COUNT(*)
FROM Users
WHERE (SELECT COUNT(*) FROM Posts WHERE Posts.OwnerUserId = Users.Id) > 20;
If I follow you correctly, you can use two levels of aggregation. The following query puts each bucket in a separate row:
select
case
when cnt < 10 then '< 10'
when cnt < 20 then '10-20'
else '> 20'
end as bucket,
count(*) cnt
from (
select count(p.owneruserid) cnt
from users u
left join posts p on p.owneruserid = u.id
group by u.id
) t
group by case
when cnt < 10 then '< 10'
when cnt < 20 then '10-20'
else '> 20'
end
Or you can get all three counts on the same row as follows:
select
sum(case when cnt < 10 then 1 else 0 end) as cnt_less_than_10,
sum(case when cnt >= 10 and cnt < 20 then 1 else 0 end) as cnt_10_to_20,
sum(case when cnt > 20 then 1 else 0 end) as cnt_more_than_20
from (
select count(*) cnt
from users u
inner join posts p on p.owneruserid = u.id
group by u.id
) t
I'm stuck at the query where I need to concat IDs of the table. And from that group of IDs, I need to fetch that rows in sub query. But when I try to do so, MySQL consider group_concat() as a string. So that condition becomes false.
select count(*)
from rides r
where r.ride_status = 'cancelled'
and r.id IN (group_concat(rides.id))
*************** Original Query Below **************
-- Daily Earnings for 7 days [Final]
select
group_concat(rides.id) as ids,
group_concat(ride_category.name) as rideType,
group_concat(ride_cars.amount + ride_cars.commission) as rideAmount ,
group_concat(ride_types.name) as carType,
count(*) as numberOfRides,
(
select count(*) from rides r where r.ride_status = 'cancelled' and r.id IN (group_concat(rides.id) )
) as cancelledRides,
(
select count(*) from rides r where r.`ride_status` = 'completed' and r.id IN (group_concat(rides.id))
) as completedRides,
group_concat(ride_cars.status) as status,
sum(ride_cars.commission) + sum(ride_cars.amount) as amount,
date_format(from_unixtime(rides.requested_at/1000 + rides.offset*60), '%Y-%m-%d') as requestedDate,
date_format(from_unixtime(rides.requested_at/1000 + rides.offset*60), '%V') as week
from
ride_cars,
rides,
ride_category,
ride_type_cars,
ride_types
where
ride_cars.user_id = 166
AND (rides.ride_status = 'completed' or. rides.ride_status = 'cancelled')
AND ride_cars.ride_id = rides.id
AND (rides.requested_at >= 1559347200000 AND requested_at < 1561852800000)
AND rides.ride_category = ride_category.id
AND ride_cars.car_model_id = ride_type_cars.car_model_id
AND ride_cars.ride_type_id = ride_types.id
group by
requestedDate;
Any solutions will be appreciated.
Try to replace the sub-query
(select count(*) from rides r where r.ride_status = 'cancelled' and r.id IN (group_concat(rides.id) )) as cancelledRides,
with below to count using SUM and CASE, it will make use of the GROUP BY
SUM(CASE WHEN rides.ride_status = 'cancelled' THEN 1 ELSE 0 END) as cancelledRides
and the same for completedRides
And move to using JOIN instead of implicit joins
I have a table called votes with 4 columns: id, name, choice, date.
****id****name****vote******date***
****1*****sam*******A******01-01-17
****2*****sam*******B******01-05-30
****3*****jon*******A******01-01-19
My ultimate goal is to count up all the votes, but I only want to count 1 vote per person, and specifically each person's most recent vote.
In the example above, the result should be 1 vote for A, and 1 vote for B.
Here is what I currently have:
select name,
sum(case when uniques.choice = A then 1 else 0 end) votesA,
sum(case when uniques.choice = B then 1 else 0 end) votesB
FROM (
SELECT id, name, choice, max(date)
FROM votes
GROUP BY name
) uniques;
However, this doesn't work because the subquery is indeed selecting the max date, but it's not including the correct choice that is associated with that max date.
Don't think "group by" to get the most recent vote. Think of join or some other option. Here is one way:
SELECT v.name,
SUM(v.choice = 'A') as votesA,
SUM(v.choice = 'B') as votesB
FROM votes v
WHERE v.date = (SELECT MAX(v2.date) FROM votes v2 WHERE v2.name = v.name)
GROUP BY v.name;
Here is a SQL Fiddle.
Your answer are close but need to JOIN self
Subquery get Max date by name then JOIN self.
select
sum(case when T.vote = 'A' then 1 else 0 end) votesA,
sum(case when T.vote = 'B' then 1 else 0 end) votesB
FROM (
SELECT name,Max(date) as date
FROM T
GROUP BY name
) AS T1 INNER JOIN T ON T1.date = T.date
SQLFiddle
Try this
SELECT
choice,
COUNT(1)
FROM
votes v
INNER JOIN
(
SELECT
id,
max(date)
FROM
votes
GROUP BY
name
) tmp ON
v.id = tmp.id
GROUP BY
choice;
Something like this (if you really need count only last vote of person)
SELECT
sum(case when vote='A' then cnt else 0 end) voteA,
sum(case when vote='B' then cnt else 0 end) voteB
FROM
(SELECT vote,count(distinct name) cnt
FROM (
SELECT name,vote,date,max(date) over (partition by name) maxd
FROM votes
)
WHERE date=maxd
GROUP BY vote
)
PS. MySQL v 8
select
name,
sum( case when choice = 'A' then 1 else 0 end) voteA,
sum( case when choice = 'B' then 1 else 0 end) voteB
from
(
select id, name, choice
from votes
where date = (select max(date) from votes t2
where t2.name = votes.name )
) t
group by name
Or output just one row for the total counts of VoteA and VoteB:
select
sum( case when choice = 'A' then 1 else 0 end) voteA,
sum( case when choice = 'B' then 1 else 0 end) voteB
from
(
select id, name, choice
from votes
where date = (select max(date) from votes t2
where t2.name = votes.name )
) t
Based on #d-shish solution, and since introduction (in MySQL 5.7) of ONLY_FULL_GROUP_BY, the GROUP BY statement must be placed in subquery like this :
SELECT v.`name`,
SUM(v.`choice` = 'A') as `votesA`,
SUM(v.`choice` = 'B') as `votesB`
FROM `votes` v
WHERE (
SELECT MAX(v2.`date`)
FROM `votes` v2
WHERE v2.`name` = v.`name`
GROUP BY v.`name` # << after
) = v.`date`
# GROUP BY v.`name` << before
Otherwise, it won't work anymore !
My table contains votes of users for different items. It has the following columns:
id, user_id, item_id, vote, utc_time
Only id is a unique field and the combination of user_id and utc_time is probably also unique. But user can cast votes for any item many times.
A vote is not a number but rather has one of several possible values (e.g., "awful", "bad", "good", "excellent").
I need to count how many different users cast their last vote for a given #item# as "excellent", as "good", etc. So assuming I have only four different possible vote values, I need to get four records with the following fields:
vote, count_of_users
I understand how to count all votes, not only last votes of users:
SELECT vote, COUNT(id) FROM votes WHERE item_id=#item# GROUP BY vote;
But I cannot figure out how to count only the votes where utc_time = MAX(utc_time) for each user... Thanks for your help.
This question is connected to the previous question of mine: Select one row with MAX(column) for known other several columns without subquery
try this solution if it fits with you,
SELECT a.item_ID,
SUM(CASE WHEN a.vote = 'awful' THEN 1 ELSE 0 END) awful,
SUM(CASE WHEN a.vote = 'bad' THEN 1 ELSE 0 END) bad,
SUM(CASE WHEN a.vote = 'good' THEN 1 ELSE 0 END) good,
SUM(CASE WHEN a.vote = 'excellent' THEN 1 ELSE 0 END) excellent
FROM tableName a
INNER JOIN
(
SELECT user_ID, MAX(utc_time) max_time
FROM tableName
GROUP BY user_ID
) b ON a.user_ID = b.user_ID AND
a.utc_time = b.max_time
-- WHERE a.item_ID = 'valueHere'
GROUP BY a.item_ID
UPDATE 1
SELECT a.item_ID,
a.vote,
COUNT(*) totalCount
FROM tableName a
INNER JOIN
(
SELECT user_ID, MAX(utc_time) max_time
FROM tableName
WHERE item_id = 'valueHere'
GROUP BY user_ID
) b ON a.user_ID = b.user_ID AND
a.utc_time = b.max_time
GROUP BY a.vote