I have a problem to display some information from my table
Table
I want to count idxdaftar where this have kode with value only 1
or I want to count idxdaftar where this have kode with value 1 and 2
for example
1) the result count(idxdaftar) where kode with value only 1 = 1
2) the result count(idxdaftar) where kode with value 1 and 2 = 1
Help me, please...
You should be more specific about the logic behind it but in you can use conditional count using CASE expression like
sum(case when kode = 1 then 1 else 0 end)
If I got it right, try
select type, count(*)
from (
select idxdaftar, case when count(distinct kode) = count(distinct case when kode = 1 then kode end) then '1' else '1+2' end type
from (
select 50 idxdaftar, 1 kode
union all
select 51 idxdaftar, 1 kode
union all
select 50 idxdaftar, 2 kode
) tab
group by idxdaftar
having count(distinct kode) in (
count(distinct case when kode = 1 then kode end),
count(distinct case when kode in (1,2) then kode end))
) t
group by type
I think this is what you want:
select count(distinct case when kcode in (1, 2) then idxafter end)
from t;
Related
I have a table below:
Item Status1 Status2
-----------------------------
A Good NULL
A Good NULL
A Good NULL
A Bad Good
B Bad Good
B Good NULL
C Good NULL
C Good NULL
C Good NULL
D Bad Good
Now, I'm thinking off writing a query which gives me the result below:
Item Good Bad
-----------------------------
A 4 1
B 2 1
C 3 0
D 1 1
Distinct in the Item column and the count of Good and Bad for each Item where NULL is not counted.
The column name can be of anything (I just kept it as Good and Bad in my second table).
Any suggestions/ideas on how to achieve my desired results?
Use UNION ALL & do aggregation :
select item, sum(status = 'good'), sum(status = 'bad')
from (select item, status1 as status
from table t
union all
select item, status2
from table t
) t
group by item;
You can use union all and conditional aggregation
select item, count(case when status1='good' then 1 end) as good,
count(case when status1='bad' then 1 end) as bad
from
(
select item , status1 from tablename
union all
select item , status2 from tablename
)A group by item
use union and case when
select Item, sum(case when status = 'good' then 1 else 0 end) as good,
sum ( case when status = 'bad' then 1 else 0 end) as bad
from (select Item, Status1 as status
from table_name
union all
select Item, Status2
from table_name
) t
group by Item;
There's no need for UNION, simply apply some logic.
select Item
,sum(case when Status1 = 'Good' then 1 else 0 end +
case when Status2 = 'Good' then 1 else 0 end) as good
,sum(case when Status1 = 'Bad' then 1 else 0 end +
case when Status2 = 'Bad' then 1 else 0 end) as bad
from tab
group by Item
or
select Item
,count(case when Status1 = 'Good' then 1 end) +
count(case when Status2 = 'Good' then 1 end) as good
,count(case when Status1 = 'Bad' then 1 end) +
count(case when Status2 = 'Bad' then 1 end) as good
from tab
group by Item
You can use sub-query and then apply sum function in outer query
select distinct(item) as item, sum(S1G+S2G) as Good,sum(S1B+S2B) as Bad from ( select item, CASE WHEN status1 ='Good' THEN 1 ELSE 0 END as S1G, CASE WHEN status2 ='Good' THEN 1 ELSE 0 END as S2G, CASE WHEN status2 ='Bad' THEN 1 ELSE 0 END as S2B, CASE WHEN status1 ='Bad' THEN 1 ELSE 0 END as S1B from t1 ) as b group by item
Here is demo
i have a query like below
select project_task_id,
status_id,
sum(case when StatusID=1 then 1 else 0 end) as task_id=1,
sum(case whenStatusID=2 then 1 else 0 end) as task_id=2,
sum(case when StatusID=3 then 1 else 0 end) as task_id=3,
sum(case when StatusID=4 then 1 else 0 end) as task_id=4,
sum(case when StatusID=5 then 1 else 0 end) as task_id=5,
sum(case when StatusID=6 then 1 else 0 end) as task_id=6,
sum(case when StatusID=7 then 1 else 0 end) as task_id=7,
from"Projects".work_unit_status
group by project_task_id,status_id;
I'm getting the below attached output:
https://i.stack.imgur.com/1wfD1.png
and I want to get the below expected output:
https://i.stack.imgur.com/Zql9z.png
include zero's if the status_id is blank
please any one help on this
Try this: use the addition of all sum column
select project_task_id,status_id,
isnull(sum(case when StatusID=1 then 1 else 0 end),0)+
isnull(sum(case whenStatusID=2 then 1 else 0 end),0) +
isnullsum(case when StatusID=3 then 1 else 0 end),0) +
isnullsum(case when StatusID=4 then 1 else 0 end),0)+
isnullsum(case when StatusID=5 then 1 else 0 end),0) +
isnullsum(case when StatusID=6 then 1 else 0 end),0) +
isnullsum(case when StatusID=7 then 1 else 0 end),0) as count_status
from"Projects".work_unit_status group by project_task_id,status_id
use in with your case
with t1 as (
select project_task_id,
status_id,
sum(case when StatusID in (1,2,3,4,5,6,7) then 1 else 0)
as sum_s
from "Projects".work_unit_status
group by project_task_id,status_id
) ,
t2 as
(
select * from (
select 1 as statusid
union
select 2
union
select 3
union
select 4
union
select 5
union
select 6
union
select 7 ) t
) select t1.project_task_id,
t2.statusid,
case when t1.sum_s>0 or not null
then sum_s else 0 end as total
t2 full join t1 on t2.statusid=t1.status_id
Without knowing the exact table structure I assumed that status_id and statusId refer to the same column. (If they are different columns, we need to use StatusId in the COUNT.)
Based on the expected output, you want to count the status_id and group by project_task_id. To make sure that every status is represented for every task, first, we need to create a subquery of all possible project_task_id/status_id combinations. Then we use that with the aggregate values of the original table.
select
ps.project_task_id,
ps.status_id,
count(w.status_id) as total
from (
select distinct
project_task_id,
s.status_id
from work_unit_status
cross join (select distinct status_id from work_unit_status) s
) ps
left join work_unit_status w
on ps.project_task_id = w.project_task_id and ps.status_id = w.status_id
group by
ps.project_task_id,
ps.status_id
If you really need to hardcode the statuses from 1 to 7, use the query below.
select
ps.project_task_id,
ps.status_id,
count(w.status_id) as total
from (
select distinct
project_task_id,
s.status_id
from work_unit_status
cross join (
select 1 as status_id
union select 2
union select 3
union select 4
union select 5
union select 6
union select 7
) s
) ps
left join work_unit_status w
on ps.project_task_id = w.project_task_id and ps.status_id = w.status_id
group by
ps.project_task_id,
ps.status_id
order by
ps.project_task_id,
ps.status_id
I am getting problem in record using following query
SELECT user_id FROM temp
WHERE
(value = 1 AND field_id = 11) AND
value = 1 AND field_id = 12
Here is the table.
I should get record of 101 user_id.
Any one idea on this?
You need to aggregate by user:
SELECT user_id
FROM temp
GROUP BY user_id
HAVING
SUM(CASE WHEN value = 1 AND field_id = 11 THEN 1 ELSE 0 END) > 0 AND
SUM(CASE WHEN value = 1 AND field_id = 12 THEN 1 ELSE 0 END) > 0;
try this sql select DISTINCT user_id from temp where value=1 and (field_id=12 or field_id=11)
You can also use where clause :
select user_id
from table t
where value = 1 and field_id in (11, 12)
group by user_id
having count(distinct field_id) = 2;
Lets consider this query
select class_id,case when event_id=2 then sum(time_spent) end as timespent ,case when event_id=3 then sum(timespent) end as visitedtimespent from class group by class_id,event_id;
output is looking like
class_id timespent visitedtimespent
1 2000 NULL
1 NULL 10
2 4000 NULL
2 NULL 5
when I use this query
select class_id,case when event_id=2 then sum(time_spent) end as timespent ,case when event_id=3 then sum(time_spent) end as timespent from class group by class_id;
output is looking like
class_id timespent visitedtimespent
1 2000 NULL
2 4000 NULL
but I expected this output
class_id timespent visitedtimespent
1 2000 10
2 4000 5
how can I achieve this?
select class_id,
sum(case when event_id=2 then time_spent else 0 end) as timespent,
sum(case when event_id=3 then time_spent else 0 end) as visitedtimespent
from class
group by class_id
sum the case.
select class_id,
sum(case when event_id=2 then time_spent end) as timespent ,
sum(case when event_id=3 then time_spent end) as visitedtimespent
from class group by class_id;
to explain the difference:
case when id... then sum(value) is equivalent to
select case when id then value from
(
select id, sum(value) as value from table
)subquery
which is an illegal grouping(ID is not aggregated or included in grouping, so the ID value will be chosen at random between all existing entries), and your ID information will be lost. IF you then apply a case to the ID info, you will not get relevant results.
I will simplfy this:
I have two SQL expressions which works OK:
First:
select count(*) as number1
from T1
where DATE1>'2012-01-01' and DATE2<'2012-12-31'
Result:13
select count(*) as number2
from T1
where DATE3>DATE2 and CURDATE()>DATE2
Result:5
But when I try to insert those two COUNTS in GROUP BY I am getting as resulyt always 13!!!
SELECT NAME,
COUNT(case when DATE1>'2012-01-01' and DATE2<'2012-12-31' then 1 else 0 end) as number1,
COUNT (case when (DATE3>DATE2 and CURDATE()>DATE2) then 1 else 0 end) as number 2
from T1
I am getting as result:
NAME NUMBER1 NUMBER2
A 5 5
B 4 4
C 4 4
But I should get:
NAME NUMBER1 NUMBER2
A 5 4
B 4 0
C 4 1
So that SUM of columns be 13 and 5 like in first two queries . What am I doing wrong?
Thank you
COUNT(expression) counts not null expressions. You can modify your query by changing the ELSE 0 to ELSE NULL or by removing it (the ELSE NULL is implied at CASE expressions):
SELECT name,
COUNT(CASE WHEN date1 > '2012-01-01' AND date2 < '2012-12-31'
THEN 1 END
) AS number1,
COUNT(CASE WHEN date3 > date2 AND CURDATE() > date2
THEN 1 END
) AS number2
FROM T1
GROUP BY name ;
Do not use count here.Use Sum. If you want to use the count then put null in else instead of 0
try:
SELECT NAME,
(select count(*) from T1 where DATE1>'2012-01-01' and DATE2<'2012-12-31') AS number1,
(select count(*) from T1 where DATE3>DATE2 and CURDATE()>DATE2) AS number2
FROM T1
GROUP BY NAME
Try this:
SELECT name,
SUM(CASE WHEN DATE1>'2012-01-01' AND DATE2<'2012-12-31' THEN 1 ELSE 0 END) AS number1,
SUM(CASE WHEN (DATE3>DATE2 AND CURDATE()>DATE2) THEN 1 ELSE 0 END) AS number2
FROM T1 GROUP BY name