I use hibernate to save data into MySQL, but I got ultraedit.
enter image description here
My code is below:
#Test
public void testA(){
Employee emp = new Employee();
emp.setEmpName("邓海");
emp.setWorkDate(new Date());
Configuration conf = new Configuration();
conf.configure();
SessionFactory sf = conf.buildSessionFactory();
Session session = sf.openSession();
Transaction ts = session.beginTransaction();
session.save(emp);
ts.commit();
session.close();
sf.close();
}
And my .hbm.xml is below:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<hibernate-mapping package="com.ypd.a.entity">
<class name="Employee" table="t_employee">
<id name="empId" column="id">
<generator class="native"/>
</id>
<property name="empName" column="emp_name"></property>
<property name="workDate" column="workDate"></property>
</class>
</hibernate-mapping>
My hibernate.xml is :
hibernate-configuration >
<session-factory>
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://localhost:3306/test</property>
<property name="hibernate.connection.username">root</property>
<property name="hibernate.connection.password">root</property>
<property name="hibernate.dialect">org.hibernate.dialect.MySQL5Dialect</property>
<property name="hibernate.show_sql">true</property>
<property name="javax.persistence.validation.mode">none</property>
<mapping resource="Employee.hbm.xml"></mapping>
</session-factory>
</hibernate-configuration>
Edit
enter image description here
If there is some settings I don't know? please show me the correct setting.
Try this in your sessionFactory:
<property name="hibernate.connection.url">jdbc:mysql://localhost:3306/test?useUnicode=true&characterEncoding=UTF-8</property>
You should appoint out the charset when you communication with the server.
Related
As seen in below code in step1 I'm reading users.xml and writing to database now in step2 I'm reading from userdetails.xml and writing to database but I need step1 auto generated key of tbl_user for step2. How Can I do that?
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:batch="http://www.springframework.org/schema/batch"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/batch
http://www.springframework.org/schema/batch/spring-batch-2.2.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd">
<import resource="../config/context.xml" />
<import resource="../config/database.xml" />
<bean id="xmlItemReader1" class="org.springframework.batch.item.xml.StaxEventItemReader">
<property name="resource" value="file:xml/outputs/users.xml" />
<property name="fragmentRootElementName" value="user" />
<property name="unmarshaller" ref="userUnmarshaller"/>
</bean>
<bean id="xmlItemReader2" class="org.springframework.batch.item.xml.StaxEventItemReader">
<property name="resource" value="file:xml/outputs/userdetails.xml" />
<property name="fragmentRootElementName" value="userdetail" />
<property name="unmarshaller" ref="userUnmarshaller"/>
</bean>
<bean id="itemProcessor1" class="com.qmetry.recovery.mapper.UserItemProcessor" />
<bean id="itemProcessor2" class="com.qmetry.recovery.mapper.UserDetailItemProcessor" />
<job id="testJob2" xmlns="http://www.springframework.org/schema/batch">
<step id="step2_1">
<tasklet transaction-manager="transactionManager">
<chunk reader="xmlItemReader1" writer="databaseItemWriter1" processor="itemProcessor1"
commit-interval="100" />
</tasklet>
<listeners>
<listener ref="testListener" />
</listeners>
</step>
<step id="step2_2">
<tasklet transaction-manager="transactionManager">
<chunk reader="xmlItemReader2" writer="databaseItemWriter2" processor="itemProcessor1"
commit-interval="100" />
</tasklet>
</step>
</job>
<bean id="testListener" class="com.qmetry.recovery.mapper.TestListener" scope="step" />
<bean id="databaseItemWriter1" class="org.springframework.batch.item.database.JdbcBatchItemWriter">
<property name="dataSource" ref="dataSource" />
<property name="sql">
<value>
<![CDATA[
insert into TBL_USER(USERNAME,EMAILID)
values (?, ?)
]]>
</value>
</property>
<!--We need a custom setter to handle the conversion between Jodatime LocalDate and MySQL DATE BeanPropertyItemSqlParameterSourceProvider-->
<property name="itemPreparedStatementSetter">
<bean class="com.qmetry.recovery.mapper.UserItemPreparedStatementSetter"/>
</property>
</bean>
<bean id="databaseItemWriter2" class="org.springframework.batch.item.database.JdbcBatchItemWriter">
<property name="dataSource" ref="dataSource" />
<property name="sql">
<value>
<![CDATA[
insert into TBL_USERDETAIL(USERID,CONTACT)
values (?, ?)
]]>
</value>
</property>
<!--We need a custom setter to handle the conversion between Jodatime LocalDate and MySQL DATE BeanPropertyItemSqlParameterSourceProvider-->
<property name="itemPreparedStatementSetter">
<bean class="com.qmetry.recovery.mapper.UserDetailItemPreparedStatementSetter"/>
</property>
</bean>
users.xml
<?xml version="1.0" encoding="UTF-8"?><users>
<user>
<userId>1</userId>
<userName>Taher</userName>
<emailId>taher.tinwala#hotmail.com</emailId>
</user>
</users>
userdetails.xml
<?xml version="1.0" encoding="UTF-8"?><userdetails>
<userdetail>
<userDetailId>1</userDetailId>
<userId__TblUser>1</userId__TblUser>
<contact>1111111111</contact>
</userdetail>
<userdetail>
<userDetailId>2</userDetailId>
<userId__TblUser>1</userId__TblUser>
<contact>2222222222</contact>
</userdetail>
<userdetail>
<userDetailId>4</userDetailId>
<userId__TblUser>1</userId__TblUser>
<contact>4444444444</contact>
</userdetail>
</userdetails>
You need to pass data to a future step. For explantory documentation see http://docs.spring.io/spring-batch/trunk/reference/html/patterns.html#passingDataToFutureSteps
I have implemented the example from the documentation and adjusted it to your configuration with some assumptions here and there.
During the read (or the write, it depends when you get the data that you want to pass) in step 1 you need to store the data in the StepExecution. Add to your xmlItemReader the following:
public class YourItemReader implements ItemReader<Object>
private StepExecution stepExecution;
public void read(Object item) throws Exception {
// ...
ExecutionContext stepContext = this.stepExecution.getExecutionContext();
stepContext.put("tbl_user", someObject);
}
#BeforeStep
public void saveStepExecution(StepExecution stepExecution) {
this.stepExecution = stepExecution;
}
Your xml will look like this:
<step id="step2_1">
<tasklet transaction-manager="transactionManager">
<chunk reader="xmlItemReader1" writer="databaseItemWriter1" processor="itemProcessor1" commit-interval="100" />
</tasklet>
<listeners>
<listener ref="testListener" />
<listener ref="promotionListener"/>
</listeners>
</step>
Add the promotionListener bean:
<beans:bean id="promotionListener" class="org.springframework.batch.core.listener.ExecutionContextPromotionListener">
<beans:property name="keys" value="tbl_key"/>
</beans:bean>
And finally you need to retrieve the value in step 2. Again asuming you need it in the reader of step 2 you reader in step 2 needs the following code added:
public class YourItemReader2 implements ItemReader<Object>
private Object someObject;
#BeforeStep
public void retrieveInterstepData(StepExecution stepExecution) {
JobExecution jobExecution = stepExecution.getJobExecution();
ExecutionContext jobContext = jobExecution.getExecutionContext();
this.someObject = jobContext.get("tbl_key");
}
Now you have acces to the value read in step 1.
EDIT - adding some example configuration for an extra read step:
After step 1 add a simple step 2 with the following reader to get the new value from the database
<bean id="itemReader" class="org.springframework.batch.item.database.JdbcCursorItemReader"
scope="step">
<property name="dataSource" ref="dataSource" />
<property name="sql">
<value>
<![CDATA[
YOUR SELECT STATEMENT
]]>
</value>
</property>
<property name="rowMapper" ref="rowMapper" />
</bean>
And a simple rowMapper bean
<bean id="rowMapper" class="exampleRowMapper" />
You will have to write your exampleRowMapper obviously to reflect the data your fetching. For example:
public class ExampleRowMapper implements ParameterizedRowMapper<String> {
#Override
public String mapRow(ResultSet rs, int rowNum) throws SQLException {
return String.valueOf(rs.getString(1));
}
}
In your dummywriter you add the stepexecution and you will store your value in the step execution context.:
public class DummyItemWriter implements ItemWriter<Object> {
private StepExecution stepExecution;
#Override
public void write(List<? extends Object> item) throws Exception {
ExecutionContext stepContext = this.stepExecution.getExecutionContext();
stepContext.put("someKey", someObject);
}
}
And the bean for the writer:
<bean id="savingDummyWriter" class="your.package.DummyItemWriter" />
And wrap the reader and writer in a step.
<step id="step2">
<tasklet>
<chunk reader="itemReader" writer="dummyItemWriter" commit-interval="1" />
</tasklet>
<listeners>
<listener ref="promotionListener"/>
</listeners>
</step>
I'm integrate spring with hibernate , I'm using dropwizard configaration files as : persistence file have the configuration files are in resources folder no issue with loading xml files. There is issue with found table .
persistence.xml file as :
<persistence-unit name="bfm" transaction-type="RESOURCE_LOCAL" >
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.bcits.parkingmanagement.model.User</class>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<!-- Configuring JDBC properties -->
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/anuj" />
<property name="javax.persistence.jdbc.user" value="root" />
<property name="javax.persistence.jdbc.password" value="root" />
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
</persistence-unit>
</persistence>
In spring application config xml as : there I show only hibernate configuration
<context:annotation-config />
<context:component-scan base-package="com.bcits.parkingmanagement.model" />
<jdbc:embedded-database id="dataSource" type="HSQL" />
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceXmlLocation" value="classpath:spring/persistence.xml" />
<property name="dataSource" ref="dataSource"/>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="entityManager"
class="org.springframework.orm.jpa.support.SharedEntityManagerBean">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
Table User missing
javax.persistence.PersistenceException: [PersistenceUnit: bfm] Unable to build EntityManagerFactory
org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1562)
... 18 more
Caused by: org.hibernate.HibernateException: Missing table: user
Please anyone help me how can I resolve this error. I want to configuration of spring with hibernate.I thing it is connect to database but can't found table. Table name and colume name exactly same. Database name also correct and no issue with username and password of database .
User model is: Here User is model name and user is table which have two column one is user_id and user_name. Issue is that i had used user instead of User in query. Because User is model name and user is table name .Correct model is given below
#NamedQueries({
#NamedQuery( name="getUserName" , query="select name from User")
})
#Entity
#Table( name ="user")
public class User {
#Id
#Column( name="user_id")
private int id;
#Column( name="user_name")
private String name;
//getter setter
}
I've been trying to start up Tapestry with Hibernate through SQL Server 2008. I followed the tapestry and hibernate guide at the start, but when I got to the mapping part, I got this class not found exception, that further throws could not parse mapping document from resource exception, and so far I could not find a solution for this.
This is the mapping file:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="com.example.tutorial.entities.Address.java" table="address">
<id name="id">
<column name="id"/>
<generator class="increment"/>
</id>
<property name="honorific" type="java.lang.String"/>
<property name="firstName" type="java.lang.String"/>
<property name="lastName" type="java.lang.String"/>
<property name="street1" type="java.lang.String"/>
<property name="street2" type="java.lang.String"/>
<property name="city" type="java.lang.String"/>
<property name="state" type="java.lang.String"/>
<property name="zip" type="java.lang.String"/>
<property name="email" type="java.lang.String"/>
<property name="phone" type="java.lang.Integer"/>
</class>
and this is the hibernate.cfg.xml:
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="hibernate.connection.driver_class">com.microsoft.sqlserver.jdbc.SQLServerDriver</property>
<property name="hibernate.connection.url">jdbc:sqlserver://localhost/testdb;integratedSecurity=true</property>
<property name="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</property>
<property name="hibernate.connection.username">not required</property>
<property name="hibernate.connection.password"></property>
<property name="hbm2ddl.auto">update</property>
<property name="hibernate.show_sql">true</property>
<property name="hibernate.format_sql">true</property>
<mapping resource="mappings/hibernate.hbm.xml" />
</session-factory>
This is the full error trace:
https://docs.google.com/file/d/0B0_KI_Lyv76_b05WTkZxVG1XLTA/edit?usp=sharing
Any suggestions are welcome.
my hibernate.cfg.xml is this :
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://localhost:3306/****</property>
<property name="hibernate.connection.username">***</property>
<property name="hibernate.connection.password">*****</property>
<property name="hibernate.query.factory_class">org.hibernate.hql.classic.ClassicQueryTranslatorFactor y</property>
<property name="connection.pool_size">1</property>
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="show_sql">false</property>
<property name="hbm2ddl.auto">create</property>
<!-- Enable Hibernate's automatic session context management -->
<property name="current_session_context_class">thread</property>
<!-- JDBC connection pool (use the built-in) -->
<property name="connection.pool_size">1</property>
<mapping class="entities.MisurazioneOraria"/>
<mapping class=....
....>
<listener type="post-insert" class="MisurazioneOrariaInsertListener"/>
</session-factory>
</hibernate-configuration>
i try to do query from this line code that is the listener :
ArrayList<MisurazioneOraria> mis = (ArrayList<MisurazioneOraria>) session.createQuery("from (misurazione_oraria) where sensore_idsensore = :idsensore").setParameter("idsensore", m.getSensore().getIdSensore()).list();
and the error is that :
mag 27, 2012 6:30:33 PM org.hibernate.event.def.AbstractFlushingEventListener performExecutions
Grave: Could not synchronize database state with session
org.hibernate.QueryException: in expected: misurazione_oraria [from (misurazione_oraria) where sensore_idsensore = :idsensore]
my mysql version is 5.5.23. thanks for the help.
Your entity class is named MisurazioneOraria, not misurazione_oraria. HQL uses entities and fields/properties. It doesn't use table and column names.
Read the HQL documentation.
Moreover, Query.list() returns a List, and not necessarily an ArrayList. You shouldn't cast the result of the query to ArrayList.
change it to
List<MisurazioneOraria> mis = session.createQuery("from MisurazioneOraria where idSensore = :idsensore").setParameter("idsensore", m.getSensore().getIdSensore()).list();
I'm using SQL Server 2008 with Hibernate 3.0 at data access layer of my application. The problem is that I'm unable to read from database.
Here is my Hibernate config;
<property name="connection.driver_class"> com.microsoft.sqlserver.jdbc.SQLServerDriver</property>
<property name="connection.url">jdbc:sqlserver://localhost;databaseName=test;integratedSecurity=true;</property>
<property name="connection.username">not required</property>
<property name="connection.password"></property>
<property name="dialect">org.hibernate.dialect.SQLServer2008Dialect</property
<property name="hibernate.hbm2ddl.auto">update</property>
<mapping resource="user.hbm.xml"/>
Here is user.hbm.xml
<class name="ammar.User" table="user" schema="dbo" catalog="test">
<id name="userId" type="int" column="userId" >
<generator class="assigned"/>
</id>
<property name="userName">
<column name="userName" />
</property>
</class>
And here is code I'm using to get data from database.
SessionFactory sF = new Configuration().configure().buildSessionFactory();
Session session = sF.openSession();
User user = (User) session.get(User.class, 1);
if(user!=null)
System.out.println(user.getUserName());
else
System.out.println("Not Found");
SQLGrammarException as well as SQLServerException occurs when I run this.
Urgent reply is needed.
Solved. Actually 'user' a is reserved word in SQL Server 2008. Anyhow, Thanks to #ManuPK.