I have sql query like this
CREATE ALGORITHM=UNDEFINED DEFINER=`root`#`localhost` SQL SECURITY DEFINER VIEW `IPK` AS select
`ipbmst_fakultas`.`Kode` AS `Fakultas`,
`ipbmst_departemen`.`Kode` AS `Departemen`,
`akdmst_mahasiswamagister`.`NIM` AS `NIM`,
`akdmst_mahasiswamagister`.`TahunMasuk` AS `TahunMasuk`,
`akdhis_kelanjutanstudi`.`IPK` AS `IPK`
from (((((`akdmst_mahasiswamagister` join `akdmst_mayor` on((`akdmst_mahasiswamagister`.`MayorID` = `akdmst_mayor`.`ID`)))
join `ipbmst_departemen` on((`akdmst_mayor`.`DepartemenID` = `ipbmst_departemen`.`ID`)))
join `ipbmst_fakultas` on((`ipbmst_departemen`.`FakultasID` = `ipbmst_fakultas`.`ID`)))
join `ipbmst_orang` on((`akdmst_mahasiswamagister`.`NIM` = `ipbmst_orang`.`NIMS2Key`)))
left join `akdhis_kelanjutanstudi` on((`akdhis_kelanjutanstudi`.`NIM` = `ipbmst_orang`.`NIMS2Key`)));
but, when I tried to open the view, the data couldn't be opened. Maybe it is because of "akdhis_kelanjutanstudi" table that consists of more than 300K data. What should I do to solve this? Thank you in advance
Create InDex On Table "akdhis_kelanjutanstudi" Column "NIM"
Or
Try To INSERT In Dynamic table FROM table "akdhis_kelanjutanstudi"
Then Left Join On "Dynamic table"
and use some filter in query..
Related
In MySQL, I have defined a view on two tables as follows:
delimiter $$
CREATE ALGORITHM=UNDEFINED DEFINER=`root`#`localhost`<br/>
SQL SECURITY DEFINER VIEW `test`.`viewinschrijvingen` AS<br/>
select `i`.`student` AS `student`,<br/>
`i`.`opleidingscode` AS `opleidingscode`,<br/>
`i`.`inschrijvingsvorm` AS `inschrijvingsvorm`,<br/>
`i`.`brin` AS `brin`,<br/>
`i`.`brinvolgnummer` AS `brinvolgnummer`,<br/>
`o`.`onderwijsvorm` AS `onderwijsvorm`,<br/>
`o`.`opleidingniveau` AS `opleidingniveau`,<br/>
`o`.`naamopleidingkort` AS `naamopleidingkort`,<br/>
`o`.`instelling` AS `instelling`,<br/>
`o`.`studielast` AS `studielast`,<br/>
date_format(max(str_to_date(`i`.`datuminschrijving`,'%Y-%m-%d')),'%Y-%m-%d') AS `datuminschrijving`,<br/>
`o`.`gemeentenaam` AS `gemeentenaam` from<br/>
(`test`.`inschrijvingen` `i` left outer join `test`.`opleidingen` `o`<br/>
on((`i`.`opleidingscode` = `o`.`opleidingscode`)))<br/>
group by `i`.`opleidingscode`,`i`.`brin`,`i`.`brinvolgnummer`$$<br/>
When I query this view for the information on a specific student:
SELECT * FROM test.viewinschrijvingen WHERE student = '310018717'
the result is empty (no records returned). When I browse through the records in the view, there is no record for student 310018717 (obviously).
However, when I execute the query I used to create the view directly:
select `i`.`student` AS `student`,<br/>
`i`.`opleidingscode` AS `opleidingscode`,<br/>
`i`.`inschrijvingsvorm` AS `inschrijvingsvorm`,<br/>
`i`.`brin` AS `brin`,<br/>
`i`.`brinvolgnummer` AS `brinvolgnummer`,<br/>
`o`.`onderwijsvorm` AS `onderwijsvorm`,<br/>
`o`.`opleidingniveau` AS `opleidingniveau`,<br/>
`o`.`naamopleidingkort` AS `naamopleidingkort`,<br/>
`o`.`instelling` AS `instelling`,<br/>
`o`.`studielast` AS `studielast`,<br/>
date_format(max(str_to_date(`i`.`datuminschrijving`,'%Y-%m-%d')),'%Y-%m-%d') AS `datuminschrijving`,<br/>
`o`.`gemeentenaam` AS `gemeentenaam` from<br/>
(`test`.`inschrijvingen` `i` left outer join `test`.`opleidingen` `o`
on((`i`.`opleidingscode` = `o`.`opleidingscode`)))<br/>
WHERE student = '310018717'<br/>
group by `i`.`opleidingscode`,`i`.`brin`,`i`.`brinvolgnummer`<br/>
I do get a result (1 record, which is the result I expected). Can anybody help me to find what is causing this behaviour?
It probably has to do with your use of MySQL's GROUP BY extension versus the ANSI GROUP BY format. MySQL does not require you to group on every column that is not an aggregate function. For columns that you are not GROUPing on, MySQL can choose whatever value it wants for the column. In your case, you are not using the student field to group and thus it may not be choosing the value you are searching for.
You may want to try this query which uses the ANSI GROUP BY and see if you get the results you want.
delimiter $$
CREATE ALGORITHM=UNDEFINED DEFINER=`root`#`localhost`
SQL SECURITY DEFINER VIEW `test`.`viewinschrijvingen` AS
select
`i`.`student` AS `student`,
`i`.`opleidingscode` AS `opleidingscode`,
`i`.`inschrijvingsvorm` AS `inschrijvingsvorm`,
`i`.`brin` AS `brin`,
`i`.`brinvolgnummer` AS `brinvolgnummer`,
`o`.`onderwijsvorm` AS `onderwijsvorm`,
`o`.`opleidingniveau` AS `opleidingniveau`,
`o`.`naamopleidingkort` AS `naamopleidingkort`,
`o`.`instelling` AS `instelling`,
`o`.`studielast` AS `studielast`,
date_format(max(str_to_date(`i`.`datuminschrijving`,'%Y-%m-%d')),'%Y-%m-%d') AS `datuminschrijving`,
`o`.`gemeentenaam` AS `gemeentenaam`
from `test`.`inschrijvingen` `i`
left outer join `test`.`opleidingen` `o`
on `i`.`opleidingscode` = `o`.`opleidingscode`
group by
`i`.`student`,
`i`.`opleidingscode`,
`i`.`inschrijvingsvorm`,
`i`.`brin` AS `brin`,
`i`.`brinvolgnummer`,
`o`.`onderwijsvorm`,
`o`.`opleidingniveau`,
`o`.`naamopleidingkort`,
`o`.`instelling`,
`o`.`studielast`,
`o`.`gemeentenaam`$$
I've created a View with a SQL query:
CREATE VIEW rightview
AS
SELECT data.accounts.login,data.accounts.password,data.customers.right_
FROM data.accounts join data.customers using (id);
When i cliick on execute the query, it indicates that the View was created successfully. But when I try to display its columns with this query
select * from data.rightview;
I got this error:
Error code 1356, SQL state HY000: View 'data.rightview' references
invalid table(s) or column(s) or function(s) or definer/invoker of
view lack rights to use them
IMHO better will be:
CREATE VIEW rightview
AS
SELECT acc.login, acc.password, cust.right_
FROM data.accounts acc
LEFT JOIN data.customers cust on acc.id=cust.id
if table customers include column ID which is reference to table accounts...
Try using table alias
CREATE VIEW rightview
AS
SELECT account.login,account.password,customer.right_
FROM data.accounts as account join data.customers as customer using (id);
and
select * from rightview;
Try this one..
CREATE VIEW rightview
AS SELECT a.login,a.password,b.right_
FROM accounts a INNER JOIN customers b
on a.id = b.id;
then,
select * from rightview;
will work..
I got same error. I solved coping all code from original view in the original db and pasted into bkp_db creating other view...
Is it possible to write this sql query without alias? I am using a PHP script that doesn't covers alias so I have problem with that.
If this is possible please provide me with some help
This is the code:
SELECT
time1.Time, time2.Time, time1.Signal, v.name, v.lastname, k.vehicle, time1.Reg
FROM
data time1
INNER JOIN data time2
ON time1.id != time2.id
AND time1.serial= time2.serial
INNER JOIN drivers v
ON time1.FK_ID_driver=v.ID_driver
INNER JOIN vehicles k
ON time1.Reg=k.Reg
WHERE
TIMEDIFF(time2.Time, time1.Time) BETWEEN '00:15:00' AND '00:30:00';
You can't easily achieve what you want, since you are joining the same table twice, and SQL needs an alias to disambiguate them.
You could, however, create a view for table data, and use the view instead of the table name in one of the data joins.
Example:
select data.time,
vData.time,
data.Signal,
drivers.name,
drivers.lastname,
vehicles.vehicle,
data.Reg
from data
inner join vData on data.id != vData.id and data.serial = vData.serial
inner join drivers on data.FK_ID_driver = drivers.ID_driver
inner join vehicles on data.Reg = vehicles.Reg
where TIMEDIFF(vData.time, data.time) between '00:15:00' and '00:30:00';
Can anyone help me on how could I have an conditional statement on the MySQL stored procedure?
I have this as sample query,
If my stored procedure parameter isFirstTask = true then I will use LEFT JOIN else I will use INNER JOIN
SELECT *
FROM jobdetails jd
INNER JOIN taskslogs tl ON jd.jobID = tl.jobid;
The question is how could change the INNER JOIN into LEFT JOIN without repeating the whole query just to replace one word. Assuming that my query is bulk. Is it possible? Some idea please.
SELECT *
FROM jobdetails jd
LEFT JOIN taskslogs tl ON jd.jobID=tl.jobid
WHERE IF(isFirstTask = TRUE, TRUE, tl.jobid IS NOT NULL);
you can build the query as a string inside the stored procedure. While building the query, check the value of your parameter and decide which JOIN to use. Hope this helps.
I have four tables, user, user_billingprofile, user_shippingprofile, and user_address.
user: userId, dateCreated
user_billingprofile: userId, address
user_shippingprofile: userId, address
user_address: random address crap
Here is the query I have to get a users billing and shipping profiles in one shot.
SELECT * FROM `user`
JOIN `user_billingprofile` ON `user`.`userId` = `user_billingprofile`.`userId`
JOIN `user_address` ON `user_billingprofile`.`currentAddress` = `user_address`.`addressId`
JOIN `user_shippingprofile` ON `user_shippingprofile`.`currentAddress` = `user_address`.`addressId`
JOIN `user_address` ON `user_shippingprofile`.`currentAddress` = `user_address`.`addressId`
I get the error: #1066 - Not unique table/alias: 'user_address'.
Is there a way to take a simple join where a table is accessed twice in the same query, and separate the two results? Preferably with some kind of table prefix...
I'm a bit lost here. I know I could do this in two sepparate queries quite easily, but i'd like to learn how to do stuff like this in one shot.
Any help/suggestions/direction is greatly appreciated, thank you!.
Can you post the structure of your tables? Based on your query I'd say you need to consider changing it up a bit.
That said you can fix your current query by adding a table alias like so:
SELECT * FROM `user`
JOIN `user_billingprofile` ON `user`.`userId` = `user_billingprofile`.`userId`
JOIN `user_address` AS user_billing_address ON `user_billingprofile`.`currentAddress` = `user_address`.`addressId`
JOIN `user_shippingprofile` ON `user_shippingprofile`.`currentAddress` = `user_address`.`addressId`
JOIN `user_address` AS user_shipping_address ON `user_shippingprofile`.`currentAddress` = `user_address`.`addressId`
Note the AS clause I added. You'll probably need to alias the columns too (instead of SELECT * you likely will need SELECT user_shipping_address.address AS user_shipping_address_value, user_billing_address.address AS user_billing_address_value ... )
Hope that helps!