I have an error message on a form that checks for an existing SSN on the BeforeUpdate event of a text box. If it already exists in the database, the user is given a message box to this effect, and has the option to go to the existing record. I'm using this example code here. My code is below.
Private Sub txtSocialSecurityNumber_BeforeUpdate(Cancel As Integer)
'check for existing SSN
Dim SSN As String
Dim strLinkCriteria As String
Dim rsc As Recordset
Set rsc = Me.RecordsetClone
SSN = Me.txtSocialSecurityNumber.Value
strLinkCriteria = "[SocialSecurityNumber] = " & "'" & SSN & "'"
'look for duplicates
If DCount("SocialSecurityNumber", "Person", LinkCriteria) > 0 Then
'Undo duplicate entry
Me.Undo
'error message
intResponse = MsgBox("Social Security Number " & SSN & " already exists in database." & _
vbCrLf & vbCrLf & "Would you like to view the record?", vbYesNo, "Duplicate SSN")
If intResponse = vbYes Then
'go to record
rsc.FindFirst strLinkCriteria
Me.Bookmark = rsc.Bookmark
ElseIf intResponse = vbNo Then
Exit Sub
End If
End If
Set rsc = Nothing
End Sub
According to this code, and several other examples I have looked up, it seems like I'm doing everything right, but I must not be because when I try to run the code and go to the existing record, I get the error "Run-time error '424': Object Required". When I debug, the row rst.FindFirst strLinkCriteria is highlighted, and hovering over it gives me the text strLinkCriteria = "[SocialSecurityNumber] = '123456789'" (123456789 is a known sample SSN in my database). Thank you to Sergey S. for pointing out the spelling error that fixed this section.
When I tell the message box to go to the record with the existing SSN, it gives me Run-time error '3021': No current record. Debug highlights the line Me.Bookmark = rsc.Bookmark with the message rsc.Bookmark = <No current record.>. So it sounds like I'm not assigning the bookmark correctly.
I've never used bookmarks before, so I'm not really sure what I'm doing wrong here. Any help would be appreciated.
You declared rsc, but used rst.
Change your code to
rsc.FindFirst strLinkCriteria
And I'd recommend always use Option Explicit in every module (default can be changed on options), otherwise you'll face with such kind strange errors. With this option the typo would be found by compiller, not at runtime.
I am trying to use the .FindNext (and .FindPrevious) function on an update form "next button" to find the record that meets certain criteria.
Private Sub NextRecord_Click()
Dim foundmatch As Boolean
For x = 0 To 3 Step 1
With Me.RecordsetClone
.FindNext "[Sensitivity] = " & [TempVars]![AccessLevel] + x
If .NoMatch Then
foundmatch = False
Else
Me.Bookmark = .Bookmark
foundmatch = True
Exit For
End If
End With
Next
If foundmatch = False Then
MsgBox "No More Records"
End If
End Sub
Upon a user entering the database the users accesslevel is assigned to a temp variable (1 to 4), and each project has a sensitivity rating of 1 to 4. The code below was used and worked for both next and previous only in finding records when the sensitivity and accesslevel were equal but not for sensitivities below the users access level which they are qualified to see.
Private Sub PrevRecord_Click()
Dim Stringy As String
Stringy = "[Sensitivity] = " & [txtaccess]
With Me.RecordsetClone
.FindPrevious Stringy
If .NoMatch Then
MsgBox "No More Records"
Else
Me.Bookmark = .Bookmark
End If
End With
End Sub
Note: The form is pulled from a query with Sensitivity one of the fields, and [txtaccess] is a text box on the field with the default value set at [TempVars]![AccessLevel]. I've also tried changing it to:
Stringy = "[Sensitivity] >= " & [txtaccess]
but that doesn't work either
I was able to fix the problem by setting applying a filter for sensitivity on the actual forms On_Load event rather than the command button. It now works using a next record command button added with the default code/settings!
My application is
Microsoft Access front end
MySql back end
Code is in vb
I am trying to modify a form that has a few drop down fields [![enter image description here][1]][1]. I need it to require the jobcustomerID before updating. Right now if i add an address first it will tell me to add the customer but gives me an error for "invalid use of null"
Current Code
Private Sub Form_BeforeUpdate(Cancel As Integer)
If IsNull(Me.JobCustomerID) Or Me.JobCustomerID = "" Then
Call MsgBox("You must select a Customer from the list provided", vbExclamation, "REQUIRED ENTRY")
Me.JobCustomerID.SetFocus
Cancel = True
Exit Sub
End If
End Sub
I do have an image of the fields but lack the reputation needed
Try moving the cancellation to the front.
If IsNull(Me.JobCustomerID) Or Me.JobCustomerID = "" Then
Cancel = True
MsgBox "You must select a Customer from the list provided", vbExclamation, "REQUIRED ENTRY"
Me.JobCustomerID.SetFocus
Exit Sub
End If
I am using David-W-Fenton's answer to this question to try to allow users to print a report when they click on a control, but I am getting the following error message:
runtime error 2448: you cannot assign a value to this object.
The line of code triggering the error is:
Me.txtPageTo.Value = numPages
Here is the full code of the OnLoad event handler for the form:
Private Sub Form_Load()
Dim varPrinter As Printer
Dim strRowsource As String
Dim strReport As String
If Len(Me.OpenArgs) > 0 Then
strReport = Me.OpenArgs
Me.Tag = strReport
For Each varPrinter In Application.Printers
strRowsource = strRowsource & "; " & varPrinter.DeviceName
Next varPrinter
Me!cmbPrinter.RowSource = Mid(strRowsource, 3)
' first check to see that the report is still open
If (1 = SysCmd(acSysCmdGetObjectState, acReport, strReport)) Then
With Reports(strReport).Printer
Me!cmbPrinter = .DeviceName
Me!optLayout = .Orientation
End With
Dim numPages As String
numPages = Reports(strReport).Pages
Debug.Print "numPages = " & numPages
TypeName(Me.txtPageTo) 'added this line as a test after
Me.txtPageTo.Value = numPages
End If
End If
End Sub
numPages prints out to equal 0 just before the error is thrown, even though the report should have at least one page. Also, the error does not get thrown when the form is already open. The error only gets thrown when the form has to be opened. (Probably because the offending code is in the onload event.)
When I added TypeName(Me.txtPageTo) , it triggered runtime error 2424: The expression you entered has a field, control, or property name that mydatabasename cant find.
I think the problem is that I need to set the control source for txtPageFrom and txtPageTo. But how do I do that? This form will only be loaded by a vba method that is trying to print a report, so the values for txtPageFrom and txtPageTo will come from the calling method, not from some underlying data table. (there is no underlying data table for this dialog form.)
cmbPrinter and optLayout seem to be populating correctly using the code above.
Can anyone show me how to get past the error messages so that the form loads properly?
CORRECT, COMPLETE ANSWER:
The answer to this problem was to greatly simplify the code. The code in the link at the top of this posting is WAY TOO COMPLEX, and tries to reinvent things that are already done well by the tools built into Access and VBA. I was able to print reports without any of the complicated solutions by simply using the following code in the on-click event of a control on a form associated with the report:
Private Sub txtPrintReport_Click()
On Error GoTo Error_Handler
Dim commNum As Long
commNum = Me.CommunicationNumber
Dim strReport As String
Dim strVarName As String
strReport = "rptCommunicationFormForPrinting"
strVarName = "CommunicationNumber"
DoCmd.OpenReport strReport, acViewPreview, , strVarName & " = " & commNum, acWindowNormal, acHidden
DoCmd.RunCommand acCmdPrint
DoCmd.Close acReport, strReport
Exit_Point:
Exit Sub
Error_Handler: 'this handles the case where user clicks cancel button
If Err.Number <> 2501 Then
MsgBox Err.Description, _
vbExclamation, "Error " & Err.Number
End If
DoCmd.Close acReport, strReport
End Sub
That is all the code that was required. Much less than the link at the start of this question. And also much less than the answer below. I am marking John Bingham's answer as the accepted answer because he clearly worked a lot on this, and I am very grateful for that. But I ended up solving the problem with A LOT LESS CODE. My solution does not require the custom dialog form because it uses the Windows print dialog form. As such, the on load event code in my posting (taken from the link above), is not necessary.
The code posted cannot work, because when a form is opened as a dialog:
DoCmd.OpenForm "dlgPrinter", , , , , acDialog, strReport
no other logic after this line is executed until the form has been closed, at which point control returns to the next line after this one, and logic continues on - except of course you can no longer reference anything in that form, because it is now closed.
Ok, now there is a question, where is the button the user clicks to print a report?
What I'm thinking is to split the logic in PrintReport into two methods, one that launches it, and tells the form to configure itself (doing the stuff suggested in the comment), but the rest of PrintReport then needs to happen after the user clicks OK (or Cancel);
So if I assume that you've got a form which can launch one or more reports, and the button is on this form, what I would suggest is this:
In the click event for that button - no changes to what you've got.
In that buttons form, add this:
Public Sub DialogAccept()
With Forms!dlgPrinter
If .Tag <> "Cancel" Then
Set Reports(strReport).Printer = Application.Printers((!cmbPrinter))
Reports(strReport).Printer.Orientation = !optLayout
Application.Echo False
DoCmd.SelectObject acReport, strReport
DoCmd.PrintOut acPages, !txtPageFrom, !txtPageTo
PrintReport = True
End If
End With
DoCmd.Close acForm, "dlgPrinter"
DoCmd.Close acReport, strReport
Application.Echo True
End Sub
Change PrintReport to:
Public Function PrintReport(strReport As String, strVarName As String, numVal As Long) As Boolean
' open report in PREVIEW mode but HIDDEN
DoCmd.OpenReport strReport, acViewPreview, , strVarName & " = " & numVal, acHidden
'DoCmd.OpenReport strReport, acViewPreview, , , acHidden
' open the dialog form to let the user choose printing options
DoCmd.OpenForm "dlgPrinter", , , , , , strReport
Forms!dlgPrinter.Configure
End Function
In the OK/Cancel button click events on dlgPrinter put (after existing code, but removing any instances of "Docmd.close"):
Forms!Calling_Form_Name.DialogAccept
This then calls that method, to do the stuff that is meant to happen after the user says "I'm done with the dialog".
Finally add the configure method to dlgPrinter:
Public Sub Configure()
With Reports(Me.Tag).Printer
Me!cmbPrinter = .DeviceName
Me!optLayout = .Orientation
End With
Dim numPages As String
numPages = Reports(Me.Tag).Pages
Debug.Print "numPages = " & numPages
TypeName(Me.txtPageTo) 'added this line as a test after
Me.txtPageTo.Value = numPages
End Sub
And remove this code section from Form_Load.
Hoep this helps.
Lastly, if the form on which the button launching dlgPrinter can vary, change this line:
DoCmd.OpenForm "dlgPrinter", , , , , acDialog, strReport
to:
DoCmd.OpenForm "dlgPrinter", , , , , acDialog, strReport & ";" & me.Name
In form_load of dlgPrinter, break up me.Openargs using left() & mid() with instr(), and save me.Name into the tag of something on the form (which you're not already using the tag of).
In the OK/Cancel button click events, change the code above to:
Forms(Object.Tag).DialogAccept
Can someone please help me on this find specific record Edit through MS access Forms
I have Frmfind form where I have one filed "ticket#" is a input text box
another filed was button "find"
When I enter ticket# which is primary key for my table. I need get the the specific ticket# record should be opened in FormEdit mode using VBA code...
So I have another form "frmEdit" of specific record which has to be called from frmfind -> specific input..
note: Ticket# is column in my table whcih it is primary to have the ticket#.
Code:
Option Compare Database
Private Sub find_Click()
If IsNull(Me.Text79) Or Me.Text79 = "" Then
MsgBox "You must enter a Ticket #", vbOKOnly, "Required Data"
Me.Text79.SetFocus
Exit Sub
End If
If [Ticket#] = Me.Text79.Value Then
MsgBox "Record found"
DoCmd.Close
DoCmd.OpenForm "frmEdit"
Else
MsgBox "not matching record"
Me.Text79.SetFocus
End If
End Sub
Private Sub Form_Open(cancel As Integer)
'On open set focus to text box
Me.Text79.SetFocus
End Sub
You can use this code:
Private Sub Command112_Click()
Me.txtSeach.SetFocus
On Error Resume Next
DoCmd.OpenForm "frmEdit", , , "TicketNumber = '" & Nz(Me.text79, "") & "'"
End Sub
Note in above if TicketNumber is in fact a number column and not text, then remove the single quotes and use this:
DoCmd.OpenForm "aa", , , "TicketNumber = " & Nz(Me.text79, "")
Then for your message, just place that code in the forms on-open event that has a cancel:
eg:
Private Sub Form_Open(Cancel As Integer)
If IsNull(Me!TicketNumberID) Then
MsgBox "Please enter a valid Ticket #", vbOKOnly, "Required Data"
Cancel = True
End If
End Sub
The above assumes your search column is ticket number.
You can also use dlookup(), or even dcount(). I think above is less code, but:
Dim strWhere As String
strWhere = "TicketNumber = " & Me.text79
If DCount("*", "tblBookings", strWhere) > 0 Then
code for Record found goes here
Else
code reocrd not found code here
End If
So either way should suffice here.