I have 3 tables, "negocio" , "paquete" , "posts".
"negocio" has one "paquete", and "negocio" may have one or more "posts".
I want to bring all negocios that have the same amount of "posts" (that have as value on it's column "posts.tipo_post" the value "Post") records as the value on it's respective "paquete.no_posts"
I was doing something like this, but it returns me an empty set.
SELECT DISTINCT negocio.id, negocio.nombre FROM negocio
INNER JOIN posts ON negocio.id = posts.id_negocio
INNER JOIN paquete ON paquete.id_negocio = negocio.id
WHERE paquete.no_posts = (SELECT COUNT(*) FROM negocio INNER JOIN posts
ON posts.id_negocio = negocio.id WHERE posts.tipo_post = 'Post'
AND posts.estado_post = 'Disenador')
Try giving your count(*) table an alias
SELECT COUNT(*) FROM negocio N INNER JOIN posts P
ON P.id_negocio = N.id WHERE P.tipo_post = 'Post'
AND P.estado_post = 'Disenador'
Related
Hi I am trying to query a table that conatains multiple duplicates on Code,Amount and Status How will I do this if I only one to get a result group according to the client_group name and get the sum of amount under that group
SELECT `client`.`client_group`
, FORMAT(SUM(`Data_result`.`Data_result_amount` ),2) as sum
FROM
`qwer`.`Data_result`
INNER JOIN `qwer`.`Data`
ON (`Data_result`.`Data_result_lead` = `Data`.`Data_id`)
INNER JOIN `qwer`.`Data_status`
ON (`Data_result`.`Data_result_status_id` = `Data_status`.`Data_status_id`)
INNER JOIN `qwer`.`client`
ON (`Data`.`Data_client_id` = `client`.`client_id`)
WHERE `Data_status`.`Data_status_name` IN ('PAID') AND MONTH(`Data_result`.`result_ts`) = MONTH(CURRENT_DATE())
AND YEAR(`Data_result`.`result_ts`) = YEAR(CURRENT_DATE())
GROUP BY `client`.`client_group`
Result of said query:
Table
Try to distinct before run the 'sum' check whether this solve your problem
SELECT `client_group` , FORMAT(SUM(`Data_result_amount` ),2) as sum from (
SELECT DISTINCT `client`.`client_group` , `Data_result`.`Data_result_amount`
FROM
`qwer`.`Data_result`
INNER JOIN `qwer`.`Data`
ON (`Data_result`.`Data_result_lead` = `Data`.`Data_id`)
INNER JOIN `qwer`.`Data_status`
ON (`Data_result`.`Data_result_status_id` = `Data_status`.`Data_status_id`)
INNER JOIN `qwer`.`client`
ON (`Data`.`Data_client_id` = `client`.`client_id`)
WHERE `Data_status`.`Data_status_name` IN ('PAID') AND MONTH(`Data_result`.`result_ts`) = MONTH(CURRENT_DATE())
AND YEAR(`Data_result`.`result_ts`) = YEAR(CURRENT_DATE())
) T
GROUP BY `client_group`
you can check the query here http://sqlfiddle.com/#!9/36a3f8/6
I'm starting out with this query, which gives me back 8 records with a "claimed" status. I'm looking to see if any of the addresses in the invites-from-address column are different from that in the moves-from-address column :
SELECT i.id, i.company_id, i.status,
ia_f.base_street as "invites-from-address", a_f.base_street as "moves-from-address",
ia_t.base_street as "invites-to-address", a_t.base_street as "moves-to-address", i.`mover_first_name`,
i.mover_last_name, i.`to_address_id`
FROM invites i
JOIN moves m ON i.id = m.`claimed_invite_id`
JOIN `invite_addresses` ia_f ON ia_f.id = i.`from_address_id`
JOIN addresses a_f ON a_f.id = m.from_address_id
JOIN `invite_addresses` ia_t ON ia_t.id = i.to_address_id
JOIN addresses a_t ON a_t.id = m.to_address_id
WHERE i.`company_id` = 1040345
GROUP BY id
What I'm trying to do in this query below is to create an average_discrepancy column on the fly that shows the proportion of addresses that differ between invites-from-address and moves-from-address. I was able to successfully check for address discrepancies by using a WHERE clause that checks that ia_f.base_street is not equal to a_f.base_street (which are aliased to the columns invites-from-address and moves-from-address respectively) but when I put this WHERE clause inside the count function in my SELECT cause it doesn't work. Is it because I can't place a WHERE clause inside a SELECT or a count function or both? And is there also a problem with trying to divide the results of two calls to the count function in my SELECT clause ?
SELECT i.id, i.company_id, i.status,
count(WHERE ia_f.base_street != a_f.base_street)/count(i.status="claimed") as "average_discrepancy",
ia_f.base_street as "invites-from-address", a_f.base_street as "moves-from-address",
ia_t.base_street as "invites-to-address", a_t.base_street as "moves-to-address",
i.`mover_first_name`,
i.mover_last_name, i.`to_address_id`
FROM invites i
JOIN moves m ON i.id = m.`claimed_invite_id`
JOIN `invite_addresses` ia_f ON ia_f.id = i.`from_address_id`
JOIN addresses a_f ON a_f.id = m.from_address_id
JOIN `invite_addresses` ia_t ON ia_t.id = i.to_address_id
JOIN addresses a_t ON a_t.id = m.to_address_id
WHERE i.`company_id` = 1040345
AND i.status = "claimed"
You need to put this into a SUM instead of a COUNT. Something like this would do the trick:
SELECT i.id, i.company_id, i.status,
SUM(CASE WHEN ia_f.base_street != a_f.base_street THEN 1 ELSE 0 END)/ SUM(CASE WHEN i.status='claimed' THEN 1 ELSE 0 END) as 'average_discrepancy',
ia_f.base_street as 'invites-from-address',
a_f.base_street as 'moves-from-address',
ia_t.base_street as 'invites-to-address',
a_t.base_street as 'moves-to-address',
i.mover_first_name,
i.mover_last_name,
i.to_address_id
FROM invites i
JOIN moves m ON i.id = m.claimed_invite_id
JOIN invite_addresses ia_f ON ia_f.id = i.from_address_id
JOIN addresses a_f ON a_f.id = m.from_address_id
JOIN invite_addresses ia_t ON ia_t.id = i.to_address_id
JOIN addresses a_t ON a_t.id = m.to_address_id
WHERE i.company_id = 1040345
AND i.status = 'claimed'
SELECT `mpeda_fish`.`id`, `mpeda_fish`.`fish` as analysis, sum(mpeda_fishdetails.quantity) as qty
FROM (`mpeda_fishdetails`)
INNER JOIN `mpeda_scientificfish` ON `mpeda_scientificfish`.`id` = `mpeda_fishdetails`.`scientificfish`
INNER JOIN `mpeda_fish` ON `mpeda_fish`.`id` = `mpeda_scientificfish`.`fish`
INNER JOIN `mpeda_fishcatch` ON `mpeda_fishcatch`.`id` = `mpeda_fishdetails`.`fishcatch`
INNER JOIN `mpeda_harbour` ON `mpeda_harbour`.`id` = `mpeda_fishcatch`.`harbour`
WHERE `mpeda_fishcatch`.`status` = 1
ORDER BY `mpeda_fishdetails`.`id` ASC
this query gets 2 columns null value and one column gets data inside why?
You use the SUM() function. In order to get meaningful results you should have a group by clause.
SELECT `mpeda_fish`.`id`, `mpeda_fish`.`fish` as analysis, sum(mpeda_fishdetails.quantity) as qty
FROM (`mpeda_fishdetails`)
INNER JOIN `mpeda_scientificfish` ON `mpeda_scientificfish`.`id` = `mpeda_fishdetails`.`scientificfish`
INNER JOIN `mpeda_fish` ON `mpeda_fish`.`id` = `mpeda_scientificfish`.`fish`
INNER JOIN `mpeda_fishcatch` ON `mpeda_fishcatch`.`id` = `mpeda_fishdetails`.`fishcatch`
INNER JOIN `mpeda_harbour` ON `mpeda_harbour`.`id` = `mpeda_fishcatch`.`harbour`
WHERE `mpeda_fishcatch`.`status` = 1
GROUP BY `mpeda_fish`.`id`, `mpeda_fish`.`fish`
ORDER BY `mpeda_fishdetails`.`id` ASC
These are my tables:
Cadastros (id, nome)
Convenios (id, nome)
Especialidades (id, nome)
Facilidades (id, nome)
And the join tables:
cadastros_convenios
cadastros_especialidades
cadastros_facilidades
The table I'm querying for: Cadastros
I'm using MySQL.
The system will allow the user to select multiple "Convenios", "Especialidades" and "Facilidades". Think of each of these tables as a different type of "tag". The user will be able to select multiple "tags" of each type.
What I want is to select only the results in Cadastros table that are related with ALL the "tags" from the 3 different tables provided. Please note it's not an "OR" relation. It should only return the row from Cadastros if it has a matching link table row for EVERY "tag" provided.
Here is what I have so far:
SELECT Cadastro.*, Convenio.* FROM Cadastros AS Cadastro
INNER JOIN cadastros_convenios AS CadastrosConvenio ON(Cadastro.id = CadastrosConvenio.cadastro_id)
INNER JOIN Convenios AS Convenio ON (CadastrosConvenio.convenio_id = Convenio.id AND Convenio.id IN(2,3))
INNER JOIN cadastros_especialidades AS CadastrosEspecialidade ON (Cadastro.id = CadastrosEspecialidade.cadastro_id)
INNER JOIN Especialidades AS Especialidade ON(CadastrosEspecialidade.especialidade_id = Especialidade.id AND Especialidade.id IN(1))
INNER JOIN cadastros_facilidades AS CadastrosFacilidade ON (Cadastro.id = CadastrosFacilidade.cadastro_id)
INNER JOIN Facilidades AS Facilidade ON(CadastrosFacilidade.facilidade_id = Facilidade.id AND Facilidade.id IN(1,2))
GROUP BY Cadastro.id
HAVING COUNT(*) = 5;
I'm using the HAVING clause to try to filter the results based on the number of times it shows (meaning the number of times it has been successfully "INNER JOINED"). So in every case, the count should be equal to the number of different filters I added. So if I add 3 different "tags", the count should be 3. If I add 5 different tags, the count should be 5 and so on. It works fine for a single relation (a single pair of inner joins). When I add the other 2 relations it starts to lose control.
EDIT
Here is something that I believe is working (thanks #Tomalak for pointing out the solution with sub-queries):
SELECT Cadastro.*, Convenio.*, Especialidade.*, Facilidade.* FROM Cadastros AS Cadastro
INNER JOIN cadastros_convenios AS CadastrosConvenio ON(Cadastro.id = CadastrosConvenio.cadastro_id)
INNER JOIN Convenios AS Convenio ON (CadastrosConvenio.convenio_id = Convenio.id)
INNER JOIN cadastros_especialidades AS CadastrosEspecialidade ON (Cadastro.id = CadastrosEspecialidade.cadastro_id)
INNER JOIN Especialidades AS Especialidade ON(CadastrosEspecialidade.especialidade_id = Especialidade.id)
INNER JOIN cadastros_facilidades AS CadastrosFacilidade ON (Cadastro.id = CadastrosFacilidade.cadastro_id)
INNER JOIN Facilidades AS Facilidade ON(CadastrosFacilidade.facilidade_id = Facilidade.id)
WHERE
(SELECT COUNT(*) FROM cadastros_convenios WHERE cadastro_id = Cadastro.id AND convenio_id IN(1, 2, 3)) = 3
AND
(SELECT COUNT(*) FROM cadastros_especialidades WHERE cadastro_id = Cadastro.id AND especialidade_id IN(3)) = 1
AND
(SELECT COUNT(*) FROM cadastros_facilidades WHERE cadastro_id = Cadastro.id AND facilidade_id IN(2, 3)) = 2
GROUP BY Cadastro.id
But I'm concerned about performance. It looks like these 3 sub-queries in the WHERE clause are gonna be over-executed...
Another solution
It joins subsequent tables only if the previous joins were a success (if no rows match one of the joins, the next joins are gonna be joining an empty result-set) (thanks #DRapp for this one)
SELECT STRAIGHT_JOIN
Cadastro.*
FROM
( SELECT Qualify1.cadastro_id
from
( SELECT cc1.cadastro_id
FROM cadastros_convenios cc1
WHERE cc1.convenio_id IN (1, 2, 3)
GROUP by cc1.cadastro_id
having COUNT(*) = 3 ) Qualify1
JOIN
( SELECT ce1.cadastro_id
FROM cadastros_especialidades ce1
WHERE ce1.especialidade_id IN( 3 )
GROUP by ce1.cadastro_id
having COUNT(*) = 1 ) Qualify2
ON (Qualify1.cadastro_id = Qualify2.cadastro_id)
JOIN
( SELECT cf1.cadastro_id
FROM cadastros_facilidades cf1
WHERE cf1.facilidade_id IN (2, 3)
GROUP BY cf1.cadastro_id
having COUNT(*) = 2 ) Qualify3
ON (Qualify2.cadastro_id = Qualify3.cadastro_id) ) FullSet
JOIN Cadastros AS Cadastro
ON FullSet.cadastro_id = Cadastro.id
INNER JOIN cadastros_convenios AS CC
ON (Cadastro.id = CC.cadastro_id)
INNER JOIN Convenios AS Convenio
ON (CC.convenio_id = Convenio.id)
INNER JOIN cadastros_especialidades AS CE
ON (Cadastro.id = CE.cadastro_id)
INNER JOIN Especialidades AS Especialidade
ON (CE.especialidade_id = Especialidade.id)
INNER JOIN cadastros_facilidades AS CF
ON (Cadastro.id = CF.cadastro_id)
INNER JOIN Facilidades AS Facilidade
ON (CF.facilidade_id = Facilidade.id)
GROUP BY Cadastro.id
Emphasis mine
"It should only return the row from Cadastros if it has a matching row for EVERY "tag" provided."
"where there is a matching row"-problems are easily solved with EXISTS.
EDIT After some clarification, I see that using EXISTS is not enough. Comparing the actual row counts is necessary:
SELECT
*
FROM
Cadastros c
WHERE
(SELECT COUNT(*) FROM cadastros_facilidades WHERE cadastro_id = c.id AND id IN (2,3)) = 2
AND
(SELECT COUNT(*) FROM cadastros_especialidades WHERE cadastro_id = c.id AND id IN (1)) = 1
AND
(SELECT COUNT(*) FROM cadastros_facilidades WHERE cadastro_id = c.id AND id IN (1,2)) = 2
The indexes on the link tables should be (cadastro_id, id) for this query.
Depending on the size of the tables (records), WHERE-based subqueries, running a test on every row CAN SIGNIFICANTLY hit performance. I have restructured it which MIGHT better help, but only you would be able to confirm. The premise here is to have the first table based on getting distinct IDs that meet the criteria, join THAT set to the next qualifier criteria... joined to the FINAL set. Once that has been determined, use THAT to join to your main table and its subsequent links to get the details you are expecting. You also had an overall group by by the ID which will eliminate all other nested entries as found in the support details table.
All that said, lets take a look at this scenario. Start with the table that would be EXPECTED TO HAVE THE LOWEST RESULT SET to join to the next and next. if cadastros_convenios has IDs that match all the criteria include IDs 1-100, great, we know at MOST, we'll have 100 ids.
Now, these 100 entries are immediately JOINED to the 2nd qualifying criteria... of which, say it only matches ever other... for simplicity, we are now matched on 50 of the 100.
Finally, JOIN to the 3rd qualifier based on the 50 that qualified and you get 30 entries. So, within these 3 queries you are now filtered down to 30 entries with all the qualifying criteria handled up front. NOW, join to the Cadastros and then subsequent tables for the details based ONLY on the 30 that qualified.
Since your original query would eventually TRY EVERY "ID" for the criteria, why not pre-qualify it up front with ONE query and get just those that hit, then move on.
SELECT STRAIGHT_JOIN
Cadastro.*,
Convenio.*,
Especialidade.*,
Facilidade.*
FROM
( SELECT Qualify1.cadastro_id
from
( SELECT cc1.cadastro_id
FROM cadastros_convenios cc1
WHERE cc1.convenio_id IN (1, 2, 3)
GROUP by cc1.cadastro_id
having COUNT(*) = 3 ) Qualify1
JOIN
( SELECT ce1.cadastro_id
FROM cadastros_especialidades ce1
WHERE ce1.especialidade_id IN( 3 )
GROUP by ce1.cadastro_id
having COUNT(*) = 1 ) Qualify2
ON Qualify1.cadastro_id = Qualify2.cadastro_id
JOIN
( SELECT cf1.cadastro_id
FROM cadastros_facilidades cf1
WHERE cf1.facilidade_id IN (2, 3)
GROUP BY cf1.cadastro_id
having COUNT(*) = 2 ) Qualify3
ON Qualify2.cadastro_id = Qualify3.cadastro_id ) FullSet
JOIN Cadastros AS Cadastro
ON FullSet.Cadastro_id = Cadastro.Cadastro_id
INNER JOIN cadastros_convenios AS CC
ON Cadastro.id = CC.cadastro_id
INNER JOIN Convenios AS C
ON CC.convenio_id = C.id
INNER JOIN cadastros_especialidades AS CE
ON Cadastro.id = CE.cadastro_id
INNER JOIN Especialidades AS E
ON CE.especialidade_id = E.id
INNER JOIN cadastros_facilidades AS CF
ON Cadastro.id = CF.cadastro_id
INNER JOIN Facilidades AS F
ON CF.facilidade_id = F.id
I want to list all teams, then count how many times each team appears in my second table. Some users are not in the second table, so the count would be zero. The problem is when I use the count function it only lists users that are in the second table. How do I count, and list 0 if they dont appear in second table?
$query = "SELECT t.id as id, t.t_name as name, t.t_city as city, (count(pd.rs)) as pd FROM #__bl_regions as r, #__bl_teams as t, #__bl_paid as pd WHERE t.id != 0 AND t.id != 1 AND (t.id IN($teams)) AND r.id = ".$t_id." AND pd.rs = 1 AND pd.t_id = ".$t_id." ORDER BY t.t_name";
$db->setQuery($query);
$players = $db->loadObjectList();
Tried Left Join
Ok, so because I am including 3 tables I believe I have to use 2 queries. Same thing is still happening, only listing schools with count. #__bl_paid is the table I want to count, #__bl_teams is the table I want to list all.
$query = "SELECT t.id as id FROM #__bl_regions as r, #__bl_teams as t WHERE t.id != 0 AND t.id != 1 AND (t.id IN($teams)) AND r.id = ".$t_id." ORDER BY t.t_name";
$db->setQuery($query);
$players1 = $db->loadResultArray();
if ($players1){
$players2 = implode(",",$players1);
}else{
$players2 = 0;
}
$query = "SELECT t.id as id, t.t_name as name, t.t_city as city, coalesce((count(pd.rs)),0) as pdc FROM #__bl_paid as pd LEFT JOIN #__bl_teams as t ON pd.t_id = t.id WHERE (t.id IN($players2)) ORDER BY t.t_name";
$db->setQuery($query);
$players = $db->loadObjectList();
You need two pieces to get what you want:
an outer join -- left join is the typical MySQL version used
a way to detect if a column is null, and if so, supply a different value. I often use coalesce
An inner join drops rows that don't have matches in the other table; a left join is similar to an inner join, but preserves all the rows in the left table, and supplies columns with null if there's no matching row in the right table.
Here's an example:
select column1, coalesce(column2, 0) as `newcolumn2`
from lefttable
left join righttable
on lefttable.something = righttable.something
What this will do: whenever column2 is null, it will be replaced with 0.
You should use LEFT JOIN statement instead of INNER JOIN.