I am passing a value($model->stop) of my form to controller action(search2) via button click.But I can't get that value in the controller.
view:
<?= Html::a(Yii::t('app', 'Search'), ['search2','id' => $model->stop], ['class' => 'btn btn-success'])
Controller:
public function actionSearch2($id)
{
if ($model->load(Yii::$app->request->post())) {
$searchModel = new ScheduleRouteSearch();
$dataProvider1 = $searchModel->search1(Yii::$app->request- >queryParams, $id);
return $this->render('search', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider1,
]);
}
}
Error:
Bad Request (#400)
Missing required parameters: id
The above error occurred while the Web server was processing your request.
Please contact us if you think this is a server error. Thank you.
Help me to solve this.
All your code seems right,
I think problem is with $model->stop value
$model->stop // value might be null --null value also gives missing parameter error
please check.
Related
I hava code like below. It creates a field in database and show in another places. I would like to block create a database field if message field is not exit. Rest fields are taken from system. What is wrong in my code.
$delivery->comments_buro()->create([
'name' => auth()->user()->firstname,
'user_id' => auth()->user()->id,
'message' => $request['repair_report_buro'],
'icon' => 'fa fa-commenting-o',
'style' => $position->style,
]);
Thanks for help.
You need Laravel Validations for that. Please read this: https://laravel.com/docs/5.8/validation
For example:
//controller
public function index(Request $request)
{
$validator = Validator::make($request->all(), [
'message' => 'required|string',
]);
if ($validator->fails()) {
//do validation error handling here
}
// create new row in database.
}
I have a right code. It works with it. I close this question. The right code is:
if(isset($request['repair_report_buro']) && !empty($request['repair_report_buro'])){
$delivery->comments_buro()->create([
'name' => auth()->user()->firstname,
'user_id' => auth()->user()->id,
'message' => $request['repair_report_buro'],
'icon' => 'fa fa-commenting-o',
'style' => $position->style,
]);
}
I would like to arrange my code a little bit better. I have this in view, generated by giiant:
$form->field($model, 'land_id')->dropDownList(ArrayHelper::map(app\models\Land::find()->orderBy('name')->all(), 'id', 'name'), [
'prompt' => Yii::t('app', 'Select'),
'disabled' => (isset($relAttributes) && isset($relAttributes['land_id'])),]);
Somebody has told me here on stackoverflow that it's not really nice. So I would like to transfer this part:
ArrayHelper::map(app\models\Land::find()->orderBy('name')->all(), 'id', 'name'
into model. The same applies to grid filter dropdowns:
'filter' => ArrayHelper::map(\app\models\base\Land::find()->asArray()->all(), 'id', 'name'),
Does it make sense? I think so, I hope so. I've tried to implement it in model Land 2 ways:
public function getAllAsArray() {
return ArrayHelper::map(app\models\Land::find()->orderBy('name')->all(), 'id', 'name');
}
or
public function getAllAsArray() {
return ArrayHelper::map($this->find()->orderBy('name')->all(), 'id', 'name');
}
and I wanted to call it from View/Grid (Zip - Land):
'filter' => $model->land->allAsArray,
but I'm getting the following error:
Undefined variable: model
then tried this way:
'filter' => function ($model) {$model->getLand()->one()->getAllAsArray();},
'filter' => function ($model) {$model->getLand()->getAllAsArray();},
then I get no error messages, but it's also not working.
and in Form (Zip - Land) the same way:
$form->field($model, 'land_id')->dropDownList($model->land->allAsArray(), [
'prompt' => Yii::t('app', 'Select'),
'disabled' => (isset($relAttributes) && isset($relAttributes['land_id'])),]);
but I'm getting the following error:
Call to a member function getAllAsArray() on null
Can you please point me to the right direction? I think I don't understand something basically and this disturbes me. Thank you very much in advance!
Land model
public static function getAllAsArray() {
return ArrayHelper::map(Land::find()->orderBy('name')->all(), 'id', 'name');
}
index
use app\models\Land;
'filter' => Land::getAllAsArray(),
form
use app\models\Land;
$form->field($model, 'land_id')->dropDownList(Land::getAllAsArray(), [
'prompt' => Yii::t('app', 'Select'),
'disabled' => (isset($relAttributes) && isset($relAttributes['land_id']))]);
I am trying to implement login functionality in CakePHP3 by following all prescribed ways. I have already tried many alternatives apart from main method found on Authentication page of official Cake website.
The error, I am receiving is "Invalid username or password". Below is a snapshot of code, I have used. Please note, I have followed proper naming conventions of CakePHP so no config issue should be there. Plus the issue is in 3.x version so don't answer for older versions please.
File: UsersController > Login Action
public function login() {
if($this->Auth->user()){
$this->Flash->error(__('You are already logged in!'));
return $this->redirect($this->Auth->redirectUrl());
}
if ($this->request->is('post')) {
$user = $this->Auth->identify();
if ($user) {
$this->Auth->setUser($user);
$this->Flash->success(__('You\'re successfully logged-in.'));
return $this->redirect($this->Auth->redirectUrl());
}
$this->Flash->error(__('Username or password is incorrect'));
}
}
File: AppController > Initialize Function
public function initialize()
{
parent::initialize();
$this->loadComponent('Flash');
$this->loadComponent('Auth', [
'loginAction' => [
'controller' => 'Users',
'action' => 'login',
],
'authError' => 'Did you really think you are allowed to see that?',
'authenticate' => [
'Form' => [
'fields' => ['username' => 'username']
]
],
'storage' => 'Session'
]);
$this->Auth->allow(['display']);
$this->Auth->allow(['register']);
}
File: Login View
<?php
echo $this->Form->create();
echo $this->Form->input('username');
echo $this->Form->input('password');
echo $this->Form->button('Login', ['class' => 'btn']);
echo $this->Form->end();
?>
Hope, I haven't missed anything but still it is not working as intended.
Any suggestion will be appreciated.
TIA
It is not working without PasswordHasher in Auth component.
You should add it in /src/Model/Entity/User.php
Add below code at the end. Also add use Cake\Auth\DefaultPasswordHasher;
protected function _setPassword($value){
$hasher = new DefaultPasswordHasher();
return $hasher->hash($value);
}
After this add new user and try to login with it.
Is your user entity using the DefaultPasswordHasher in the file src/Model/Entity/User.php?
Just a thought...
I want to get value of field in controller.
could you please help me?
here is my form code:
<?php
$form = ActiveForm::begin([
'id' => 'request-form',
'action' => 'site/request_page',
'method' => 'post',
'fieldConfig' => ['autoPlaceholder' => false]
]);
?>
<?= $form->field($model, 'workroom_id')->label(FALSE) ?>
and this is my controller code:
public function actionRequest_page() {
echo Yii::$app->request->post('workroom_id');
die();
}
But I got nothing in result.
write workroom_id in safe rule like this-
public function rules()
{
return [
[['workroom_id'],'safe']
];
}
Use bellow code -
echo Yii::$app->request->post('MODEL_NAME')['workroom_id'];
You should expand your action form-attribute. By using Url::to() for instance. As in echo \yii\helpers\Url::to(['site/request_page']);
And access your post data differently. Try var_dump(Yii::$app->request->post()); to see what your form data looks like. The other answer shows how to access it correctly.
The docs have an excellent starting place for working with forms.
I've joined 2 tables like following:
$model = SalesEntry::find()
->joinWith('salesItems')
->all();
then in view used DataProvider like following:
GridView::widget([
'dataProvider' => $model,
'columns' => [
'date', // sample field from first table to see if ok
],
]);
and I’ve got following error:
Call to a member function getCount() on a non-object
What am I doing wrong here?
That is because an ActiveQuery instance is not a DataProvider, which the widget expects. You need to wrap it in an ActiveDataProvider for it to work:
GridView::widget([
'dataProvider' => new \yii\data\ActiveDataProvider(['query' => $model]),
' columns' => [
'date', // sample field from first table to see if ok
],
]);
DataProvider in GridView should be an instance of yii\data\DataProviderInterface
See docs.