Hello I have a table that Has a movie name, the date it was released, the cost and the revenue. I am trying to write a query to display how many movies were released per month
CREATE TABLE movies_200249154(
movieName VARCHAR(30),
releaseDate DATE,
costInMillions INT (20),
revenueInMillions INT (20)
);
Above is my table
Here is my current query
SELECT DISTINCTROW (monthname(releaseDate)) AS 'Month released', COUNT(*)movieName
FROM movies_200249154
GROUP BY movieName;
Right now my query will display the month, and the count for the movie (always being 1) and shows duplicates. If I use SELECT DISTINCT it only displays 1 movie per month. Seemingly forgetting about the other data.
What I need is for my query to display the month AND the amount of movies released that month. For example it currently repeats June 4 times with a count of 1. The query I need would display June and a count of 4.
Any help is greatly appreciated
You can use MONTH function of MySQL and group by with count to get the required value, e.g.:
SELECT MONTH(releaseDate), count(*)
FROM movies
GROUP BY MONTH(releaseDate);
Related
I'm trying to find the average of net total for a given month, based on previous years to help show things like seasonal trends in sales.
I have a table called "Invoice" which looks similar to the below (slimmed down for the purpose of this post):
ID - int
IssueDate - DATE
NetTotal - Decimal
Status - Enum
The data I'm trying to get, for example would be similar to this:
(sum of invoices in June 2018 + sum of invoices in June 2019 + sum of invoices in June 2020) divided by number of years covered (3) = Overall average for June
But, doing this for the full 12 months of the year based on all the data (not just 2018 through to 2020).
I'm a bit stumped on how to pull this data. I've tried subqueries and even tried using a SUM within an AVG select, but the query either fails or returns incorrect data.
An example of what I've tried:
SELECT MONTHNAME(`Invoice`.`IssueDate`) AS `CalendarMonth`, AVG(`subtotal`)
FROM (SELECT SUM(`Invoice`.`NetTotal`) AS `subtotal`
FROM `Invoice`
GROUP BY EXTRACT(YEAR_MONTH FROM `Invoice`.`IssueDate`)) AS `sub`, `Invoice`
GROUP BY MONTH(`Invoice`.`IssueDate`)
which returns:
I see two parts to this query, but unsure how to structure it:
A sum and count of all data based on the month
An average based on the number of years
I'm not sure where to go from here and would appreciate any pointers.
Ideally, I'd want to get the totals from rows where "Status" = "Paid", but trying to crack the first part first. Walk before running as they say!
Any guidance greatly appreciated!
Basically you want two levels of aggregation:
SELECT mm, AVG(month_total)
FROM (SELECT YEAR(i.IssueDate) as yyyy, MONTH(i.issueDate) as mm,
SUM(i.`NetTotal`) as month_total
FROM Invoice i
GROUP BY yyyy, mm
) ym
GROUP BY mm;
Just for the Average Amount Part You Could use a query like
Select Date From Your_Table Where Date Like '20__-06-%'
You can arrange it into asc desc order.
I'm trying to get time between 2 dates. I've got a table with different holidays, DateTime and userId. There is several different holidays but what counts for me are Christmas and Easter.
I would like to get time from the oldest logged holiday to the newest for every single user. (doesn't matter Christmas or Easter it was)
Now I get only get result for one user.
I tried also WHERE holiday LIKE 'Christmas' OR/AND 'EASTER' but doesn't work properly.
WITH XYZ as(
SELECT userID,
max(dt) as the_oldest,
min(dt) as the_newest,
datediff(max(dt), min(dt))
FROM data
WHERE holiday NOT LIKE 'Halloween')
SELECT * FROM XYZ;
Thanks in advance!
You have to GROUP BY userID so that query will return max and min date for each user.
SELECT userID,
max(dt) as the_newest,
min(dt) as the_oldest,
datediff(max(dt), min(dt))
FROM data
WHERE holiday NOT LIKE 'Halloween'
GROUP BY userID
Please note max(dt) will give newest date and min(dt) oldest. It was opposite in your query.
I have a table "Report" with relevant columns "Date", "Doctor". Each doctor appears several times throughout the table. The following code is what I have at current:
SET #variable = (SELECT Date FROM Report WHERE Doctor='DocName' ORDER BY Date DESC LIMIT 1)
SELECT DATEDIFF(CURDATE(),#variable) AS DiffDate
This gives me the DATEDIFF for one doctor, without name. Is there any way to loop through the table, find the last row/date for each doctor, then perform a DATEDIFF on each individual doctor outputting a list of doctors with their DATEDIFFs (against current date) next to them?
Thanks in advance!
you can use group by to get only 1 row per doctor and max to select latest date:
select `Doctor`, DATEDIFF(CURDATE(),max(`Date`))
from `Report`
group by `Doctor`
I'm looking to make some bar graphs to count item sales by day, month, and year. The problem that I'm encountering is that my simple MySQL queries only return counts where there are values to count. It doesn't magically fill in dates where dates don't exist and item sales=0. This is causing me problems when trying to populate a table, for example, because all weeks in a given year aren't represented, only the weeks where items were sold are represented.
My tables and fields are as follows:
items table: account_id and item_id
// table keeping track of owners' items
items_purchased table: purchaser_account_id, item_id, purchase_date
// table keeping track of purchases by other users
calendar table: datefield
//table with all the dates incremented every day for many years
here's the 1st query I was referring to above:
SELECT COUNT(*) as item_sales, DATE(purchase_date) as date
FROM items_purchased join items on items_purchased.item_id=items.item_id
where items.account_id=125
GROUP BY DATE(purchase_date)
I've read that I should join a calendar table with the tables where the counting takes place. I've done that but now I can't get the first query to play nice this 2nd query because the join in the first query eliminates dates from the query result where item sales are 0.
here's the 2nd query which needs to be merged with the 1st query somehow to produce the results i'm looking for:
SELECT calendar.datefield AS date, IFNULL(SUM(purchaseyesno),0) AS item_sales
FROM items_purchased join items on items_purchased.item_id=items.item_id
RIGHT JOIN calendar ON (DATE(items_purchased.purchase_date) = calendar.datefield)
WHERE (calendar.datefield BETWEEN (SELECT MIN(DATE(purchase_date))
FROM items_purchased) AND (SELECT MAX(DATE(purchase_date)) FROM items_purchased))
GROUP BY date
// this lists the sales/day
// to make it per week, change the group by to this: GROUP BY week(date)
The failure of this 2nd query is that it doesn't count item_sales by account_id (the person trying to sell the item to the purchaser_account_id users). The 1st query does but it doesn't have all dates where the item sales=0. So yeah, frustrating.
Here's how I'd like the resulting data to look (NOTE: these are what account_id=125 has sold, other people many have different numbers during this time frame):
2012-01-01 1
2012-01-08 1
2012-01-15 0
2012-01-22 2
2012-01-29 0
Here's what the 1st query current looks like:
2012-01-01 1
2012-01-08 1
2012-01-22 2
If someone could provide some advice on this I would be hugely grateful.
I'm not quite sure about the problem you're getting as I don't know the actual tables and data they contain that generates those results (that would help a lot!). However, let's try something. Use this condition:
where (items.account_id = 125 or items.account_id is null) and (other-conditions)
Your first query is perfectly acceptable. The fact is you don't have data in the mysql table and therefore it can't group any data together. This is fine. You can account for this in your code so that if the date does not exist, then obviously there's no data to graph. You can better account for this by ordering the date value so you can loop through it accordingly and look for missed days.
Also, to avoid doing the DATE() function, you can change the GROUP BY to GROUP BY date (because you have in your fields selected DATE(pruchase_date) as date)
I have some data which I want to retrieve, but I want to have it grouped by a specific number of seconds. For example if my table looks like this:
| id | user | pass | created |
The created column is INT and holds a timestamp (number of seconds from 1970).
I would want the number of users that are created between last month and the current date, but show them grouped by let's say 7*24*3600 (a week). So if in the range there are 1000 new users, have them show up how many registered each week (100 the first week, 450 the second, 50 the third and 400 the 4th week -- something like this).
I've tried grouping the results by created / 7*24*3600, but that's not working.
How should my query look like?
You need to use integer division div otherwise the result will turn into a real and none of the weeks will resolve to the same value.
SELECT
(created div (7*24*60*60)) as weeknumber
, count(*) as NewUserCount
FROM users
WHERE weeknumber > 1
GROUP BY weeknumber
See: http://dev.mysql.com/doc/refman/5.0/en/arithmetic-functions.html
You've got to keep the integer part only of that division. You can do it with the floor() function.
Have you tried select floor(created/604800) as week_no, count(*) from users group by floor(created/604800) ?
I assume you've got the "select users created in the last month" part sorted out.
Okay here are the possible options you may try:
GROUP BY DAY
select count(*), DATE_FORMAT(created_at,"%Y-%m-%d") as created_day FROM widgets GROUP BY created_day
GROUP BY MONTH
select count(*), DATE_FORMAT(created_at,"%Y-%m") as created_month FROM widgets GROUP BY created_month
GROUP BY YEAR
select count(*), DATE_FORMAT(created_at,"%Y") as created_year FROM widgets GROUP BY created_year