I'm trying to scrape the links and titles of the articles on the frontpage of the website https://www.forbes.com/ .
I'm not proficient in html, but I'm been following some beautfiul soup tutorials and have been getting by with the knowledge I'm picking up along the way.
Here is what I have so far:
source = urllib.request.urlopen('https://www.forbes.com').read()
soup = bs.BeautifulSoup(source,'lxml') # Tried 'html.parser' as well
##print(soup.findAll('div',{'class':"c-entry-box--compact c-entry-box--compact--article"}))
for url in soup.findAll('a',{'class':"exit_trigger_set"}):
print (url.get('href'))
Inspecting the site's html, I seem to have the class and 'a' (not sure what you call 'a' in this case) correct.
However, instead of getting all the links of the articles on the frontpage, I'm only getting one.
https://www.amazon.com/Intelligent-REIT-Investor-Wealth-Investment/dp/1119252717
Not sure what I'm doing wrong.
Thank you.
EDIT:
This seems to find some of the top stories but I don't know how to pull out the links only
for i in soup.findAll('h4', {'class': "editable editable-hed"}):
print (i)
Here's how I would do it:
import urllib2
from bs4 import BeautifulSoup
import pandas as pd
source = urllib2.urlopen('https://www.forbes.com')
soup = BeautifulSoup(source,'lxml')
lst = []
for i in soup.findAll('h4', {'class': "editable editable-hed"}):
title = i.text
link = i.find('a')['href'][2:]
title = title.replace('\t','')
title = title.replace('\n','')
title = title.strip()
lst.append({'title':title, 'link':link})
df = pd.DataFrame.from_dict(lst)
And you get 15 articles and their links.
Related
I am using beautiful soup and below is my selector to scrape href.
html = ''' <a data-testid="Link" class="sc-pciXn eUevWj JobTile___StyledJobLink-sc-
1nulpkp-0 gkKKqP JobTile___StyledJobLink-sc-1nulpkp-0 gkKKqP"
href="https://join.com/companies/talpasolutions/4978529-project-customer-
success-manager-heavy-industries-d-f-m">'''
soup = beautifulsoup(HTML , "lxml")
jobs = soup.find_all( "a" ,class_= "sc-pciXn eUevWj JobTile___StyledJobLink-sc-1nulpkp-0
gkKKqP JobTile___StyledJobLink-sc-1nulpkp-0 gkKKqP")
for job in jobs:
job_url = job.get("href")
I am using find_all because there is a total of 3 elements with hrefs.
Above method is working but the website keeps changing the classes on a daily basis. I need a different way to design CSS/XPath
Try:
import requests
from bs4 import BeautifulSoup
url = "https://join.com/companies/talpasolutions"
soup = BeautifulSoup(requests.get(url).content, "lxml")
for a in soup.select("a:has(h3)"):
print(a.get("href"))
Prints:
https://join.com/companies/talpasolutions/4978529-project-customer-success-manager-heavy-industries-d-f-m
https://join.com/companies/talpasolutions/4925936-senior-data-engineer-d-f-m
https://join.com/companies/talpasolutions/4926107-senior-data-scientist-d-f-m
It's my first time working with web scraping so cut me some slack. I'm trying to pull the "card_tag" from a website. I triple checked that the card tag is inside their respected tags as seen in the code.
import requests
from bs4 import BeautifulSoup
result = requests.get("https://www.anime-planet.com/users/mistersenpai/anime/dropped")
src = result.content
soup = BeautifulSoup(src, features="html.parser")
urls = []
for div_tag in soup.find_all('div id="siteContainer"'):
ul_tag = div_tag.find("ul class")
li_tag = ul_tag.find("li")
card_tag = li_tag.find("h3")
urls.append(card_tag)
print(urls)
When I go to print the url list it outputs nothing. You can see the thing I'm looking for by visiting the link as seen in the code and inspecting element on "Blood-C". As you can see it's listed in the tag I'm trying to find, yet my code can't seem to find it.
Any help would be much appreciated.
just minor syntax you need to change with the tags and attributes.
import requests
from bs4 import BeautifulSoup
result = requests.get("https://www.anime-planet.com/users/mistersenpai/anime/dropped")
src = result.content
soup = BeautifulSoup(src, features="html.parser")
urls = []
containers = soup.find_all('div', {'id':'siteContainer'})
for div_tag in containers:
ul_tag = div_tag.find("ul", {'data-type':'anime'})
li_tag = ul_tag.find_all("li")
for each in li_tag:
card_tag = each.find("h3")
urls.append(card_tag)
print(card_tag)
Also, you could just skip all that and go straight to those <h3> tags with the class attribute cardName:
import requests
from bs4 import BeautifulSoup
result = requests.get("https://www.anime-planet.com/users/mistersenpai/anime/dropped")
src = result.content
soup = BeautifulSoup(src, features="html.parser")
urls = []
for card_tag in soup.find_all('h3', {'class':'cardName'}):
print(card_tag)
urls.append(card_tag)
Output:
<h3 class="cardName">Black Butler</h3>
<h3 class="cardName">Blood-C</h3>
<h3 class="cardName">Place to Place</h3>
I am trying to extract the name on this web page: https://steamcommunity.com/market/listings/730/AK-47%20%7C%20Redline%20%28Field-Tested%29
the element i am trying to grab it from is
<h1 class="hover_item_name" id="largeiteminfo_item_name" style="color:
rgb(210, 210, 210);">AK-47 | Redline</h1>
I am able to search for the ID "largeiteminfo_item_name" using selenium and retrieve the text that way but when i duplicate this with bs4 I can't seem to find the text.
Ive tried searching class "item_desc_description" but no text could be found there either. What am I doing wrong?
a = soup.find("h1", {"id": "largeiteminfo_item_name"})
a.get_text()
a = soup.find('div', {'class': 'item_desc_description'})
a.get_text()
I expected "AK-47 | Redline" but received '' for the first try and '\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n' for the second try.
The data you are trying to extract is not present in the HTML page, I guess it might be generated aside with JavaScript (just guessing).
However I managed to find the info in the div "market_listing_nav".
from bs4 import BeautifulSoup as bs4
import requests
lnk = "https://steamcommunity.com/market/listings/730/AK-47%20%7C%20Redline%20%28Field-Tested%29"
res = requests.get(lnk)
soup = bs4(res.text, features="html.parser")
elem = soup.find("div", {"class" : "market_listing_nav"})
print(elem.get_text())
This will output the following
Counter-Strike: Global Offensive
>
AK-47 | Redline (Field-Tested)
Have a look at the web page source for tag with better formatting or just clean up the on generated by my code.
I am trying to pull all the text from the div class 'caselawcontent searchable-content'. This code just prints the HTML without the text from the web page. What am I missing to get the text?
The following link is in the 'finteredcasesdoc.text' file:
http://caselaw.findlaw.com/mo-court-of-appeals/1021163.html
import requests
from bs4 import BeautifulSoup
with open('filteredcasesdoc.txt', 'r') as openfile1:
for line in openfile1:
rulingpage = requests.get(line).text
soup = BeautifulSoup(rulingpage, 'html.parser')
doctext = soup.find('div', class_='caselawcontent searchable-content')
print (doctext)
from bs4 import BeautifulSoup
import requests
url = 'http://caselaw.findlaw.com/mo-court-of-appeals/1021163.html'
soup = BeautifulSoup(requests.get(url).text, 'html.parser')
I've added a much more reliable .find method ( key : value)
whole_section = soup.find('div',{'class':'caselawcontent searchable-content'})
the_title = whole_section.center.h2
#e.g. Missouri Court of Appeals,Southern District,Division Two.
second_title = whole_section.center.h3.p
#e.g. STATE of Missouri, Plaintiff-Appellant v....
number_text = whole_section.center.h3.next_sibling.next_sibling
#e.g.
the_date = number_text.next_sibling.next_sibling
#authors
authors = whole_section.center.next_sibling
para = whole_section.findAll('p')[1:]
#Because we don't want the paragraph h3.p.
# we could aslso do findAll('p',recursive=False) doesnt pickup children
Basically, I've dissected this whole tree
as for the Paragraphs (e.g. Main text, the var para), you'll have to loop
print(authors)
# and you can add .text (e.g. print(authors.text) to get the text without the tag.
# or a simple function that returns only the text
def rettext(something):
return something.text
#Usage: print(rettext(authorts))
Try printing doctext.text. This will get rid of all the HTML tags for you.
from bs4 import BeautifulSoup
cases = []
with open('filteredcasesdoc.txt', 'r') as openfile1:
for url in openfile1:
# GET the HTML page as a string, with HTML tags
rulingpage = requests.get(url).text
soup = BeautifulSoup(rulingpage, 'html.parser')
# find the part of the HTML page we want, as an HTML element
doctext = soup.find('div', class_='caselawcontent searchable-content')
print(doctext.text) # now we have the inner HTML as a string
cases.append(doctext.text) # do something useful with this !
So i'm trying to make a program that tells the user how far away voyager 1 is from the Earth, NASA has this info on their website here http://voyager.jpl.nasa.gov/where/index.html...
I can't seem to manage to get the information within the div, here's the div: <div id="voy1_km">Distance goes here</div>
my current program is as follows : `
import requests
from BeautifulSoup import BeautifulSoup
url = "http://voyager.jpl.nasa.gov/where/index.html"
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html)
test = soup.find('div', {'id' : 'voy1_km'})
print test
So long story short, How do I get the div contents?
as you can see from the webpage itself, the distance keep changing which is actually driven by a Javascript. You can maybe just read the javascrip code so you don't even need to scrape to get the distance... (I hate websites using Javascript as much as you:) )
If you really want to get the number off their website. You can use Selenium.
# pip install selenium
from selenium import webdriver
import time
driver = webdriver.Firefox()
driver.get("http://voyager.jpl.nasa.gov/where/index.html")
time.sleep(5)
elem = driver.find_element_by_class_name("tr_dark")
print elem.text
driver.close()
Here is the output:
Distance from Earth
19,964,147,071 KM
133.45208042 AU
Of course, please refer to the terms&conditions of their website regarding to what level you can scrape their website and distribute the data.
The bigger question is why even bother scraping it. If you dive a bit deeper into the Javascript file, you can repeat its calculation in a very simple manner:
import time
epoch_0 = 1445270400
epoch_1 = 1445356800
dist_0_v1 = 19963672758.0152
dist_1_v1 = 19966727483.2612
current_time = time.time()
current_dist_km_v1 = ( ( ( current_time - epoch_0 ) / ( epoch_1 - epoch_0 ) ) * ( dist_1_v1 - dist_0_v1 ) ) + dist_0_v1
print("{:,.0f} KM".format(current_dist_km_v1))