Auto display results using json - json

Question

Currently i'm using json to auto display my reuslt, but i got error say json_encode(): type is unsupported, encoded as null, and i think my problem is view, when i choose in name in dropdown i gives an error json_encode(): type is unsupported, encoded
Model
function get_address($name) {
$vendres = array('name' => $name);
$this->db->select('address');
$this->db->where($vendres);
$this->db->distinct();
$result = $this->db->get('profile');
if($result->num_rows() > 0){
foreach($result->result_array() as $row){
echo $row['address'];
}
}
return $result;
}
Controller
function address() {
$name=$this->input->post('name');
$this->load->model('default/M_profile');
$data['address'] = $this->M_vendor->get_address($name);
$this->output->set_output(json_encode($data));
//echo $data;
return;
}
in view i use dropdown.
$(document).ready(function () {
$('#profile select').change(function () {
var add = $(this).text();
$.ajax({
url: "<?php echo base_url();?>admin/profile/address",
method: "POST",
data: {profile: add},
success: function(add) {
$('#address').val(add);
}
})
});
});
<select name="test">....</select>

Answer 1

You have a lots of errors:
1.In ajax it should be type:'POST'.Not method:'POST'.
2.In controller it should be $this->input->post('profile')
3.In model just return your data using result_array().
MODEL:
function get_address($name) {
$vendres = array('name' => $name);
$this->db->select('address');
$this->db->where($vendres);
$this->db->distinct();
$result = $this->db->get('profile');
if($result->num_rows() > 0){
return $result->result_array();
}
}
}
Controller:
function address() {
$name=$this->input->post('profile');
$this->load->model('default/M_profile');
$data = $this->M_vendor->get_address($name);
echo json_encode($data);
}
View:(Ajax):
<script type="text/javascript">
$(document).ready(function () {
$('#profile select').change(function () {
var add = $(this).text();
$.ajax({
url: "<?php echo base_url('admin/profile/address');?>",
type: "POST",
data: {profile: add},
success: function(add) {
var data = JSON.parse(add);//parse response to convert into onject
console.log(data);//see your result in console
alert(data[0].address);
}
})
});
});
</script>
<select name="test">....</select>
I hope it helps you a lot.

Answer 2

you are echoing the result instead of returning
function get_address($name) {
$vendres = array('name' => $name);
$this->db->select('address');
$this->db->where($vendres);
$this->db->distinct();
$result = $this->db->get('profile');
if($result->num_rows() > 0){
foreach($result->result_array() as $row){
$result[] = $row['address'];
}
}
return $result;
}