tables
person_id (primary key)
phs_people (person_id,first_name,last_name)
phs_cutomers (person_id,company_name)
phs_waiters (person_id,commission)
person_id is key between them.
So my question how can retrive customers firstname and last name, waiter firstname and lastname via person_id?
SELECT
c.first_name AS customer_Fist_name,
c.last_name AS Customer_LastName,
c.first_name AS WaiterFirstName,
c.last_name AS Waiter_LastName,
invoice_number, amount_tendered, sale_time, DATE_FORMAT( sale_time, '%d-%m-%Y' ) AS sale_date, phs_sales.sale_id AS sale_id, SUM( item_unit_price * quantity_purchased * ( 1 - discount_percent /100 ) ) AS amount_due
FROM (
phs_sales
)
LEFT JOIN phs_people c ON c.person_id = phs_sales.customer_id
AND person_id = phs_sales.waiter_id
JOIN phs_sales_items ON phs_sales_items.sale_id = phs_sales.sale_id
LEFT JOIN (
SELECT sale_id, SUM( payment_amount ) AS amount_tendered
FROM phs_sales_payments
WHERE payment_type <> 'Check'
GROUP BY sale_id
) AS payments ON payments.sale_id = phs_sales.sale_id
GROUP BY sale_id
ORDER BY sale_time DESC
LIMIT 25
if I execute this query, I get the following error:
customer_Fist_name NULL,Customer_LastName NULL, WaiterFirstName NULL, Waiter_LastName NULL,
You want to do JOIN's two times on the same table but with different values (customer's data and waiter's data), but you just use a JOIN once and give both conditions there.
To fix this, your have to JOIN the phs_people-Table twice like this:
...
LEFT JOIN phs_people AS c1 ON c1.person_id = phs_sales.customer_id
LEFT JOIN phs_people AS c2 ON c2.person_id = phs_sales.waiter_id
...
and then select the correct data like this:
SELECT
c1.first_name AS customer_Fist_name,
c1.last_name AS Customer_LastName,
c2.first_name AS WaiterFirstName,
c2.last_name AS Waiter_LastName,
...
PS: With this query, you should still get multiple NULL-Values, that's because half of your phs_sales-Table is filled with empty fields...
Related
I have 3 tables with structures like this:
store_locations
id store_id zip_code city state last_updated
--------------------------------------------------------------------------------
1 7438 37493 Seattle WA [timestamp]
1 7587 89574 Spokane WA [timestamp]
store_vehicles
id store_id vin_number
--------------------------------------------------------------------------------
1 7438 [some vin number]
1 7587 [some vin number]
store_sold_vehicles
id vin_number
--------------------------------------------------------------------------------
1 [some vin number]
1 [some vin number]
I am trying to output a table with store details including total_sales for that location. Here is the query I'm attempting, but it is not working as I'm missing a GROUP BY statement but don't know how to add it.
SELECT
COUNT(sales.id) AS total_sales,
locations.store_id AS store_id,
locations.zip_code AS zip_code,
locations.city AS city,
locations.state AS state
FROM store_locations locations
INNER JOIN store_vehicles vehicles ON vehicles.store_id = locations.store_id
INNER JOIN store_sold_vehicles sales ON sales.Vin = vehicles.Vin
GROUP BY vehicles.Vin
Is this possible to achieve without multiple queries?
Edit: Expected output would be something like this:
[
'store_id'=>8239,
'zip_code'=>27103,
'city'=>'San Francisco',
'state'=>'CA',
'last_updated'=>[timestamp],
'total_sales'=>121
]
You need to group by store and all non grouped elements:
SELECT
COUNT(sales.id) AS total_sales,
locations.store_id AS store_id,
locations.zip_code AS zip_code,
locations.city AS city,
locations.state AS state
FROM store_locations locations
INNER JOIN store_vehicles vehicles ON vehicles.store_id = locations.store_id
INNER JOIN store_sold_vehicles sales ON sales.Vin = vehicles.Vin
GROUP BY locations.store_id, locations.zip_code, locations.city, locations.state
I think this what you want
SELECT store_locations.store_id , zip_code , city , state , last_updated , total_sales
FROM store_locations JOIN (
SELECT store_id , COUNT(c.id) AS total_sales
FROM store_locations a JOIN store_vehicles b ON a.store_id = b.store_id JOIN store_sold_vehicles c ON b.vin_number = c.vin_number
WHERE store_id = 8239
GROUP BY store_id
) totalsales ON store_locations.store_id = totalsales.store_id
The goal here is to:
1. Fetch the row with the most recent date from EACH store for EACH ingredient.
2. From this result, compare the prices to find the cheapest store for EACH ingredient.
I can accomplish either the first or second goal in separate queries, but not in the same.
How can i filter out a selection and then apply another filter on the previous result?
EDIT:
I've been having problems with results that i get from MAX and MIN since it just fetches the rest of the data arbitrarily. To avoid this im supposed to join tables on multiple columns (i guess). Im not sure how this will work with duplicate dates etc.
I've included an image of a query and its output data.
If we use ingredient1 as an example, it exists in three separate stores (in one store twice on different dates).
In this case the cheapest current price for ingredient1 would be store3. If the fourth row dated 2013-05-25 was even cheaper, it would still not "win" due to it being out of date.
(Disregard brandname, they dont really matter in this problem.)
Would appreciate any help/input you can offer!
This question is really interesting!
So, first, we get the row with the most recent date from EACH store for EACH ingredient. (It is possible that the most recent dates from each store can be different.)
Then, we compare the prices from each store (regardless of the date) to find the least price for each ingredient.
The query below uses the GROUP_CONCAT function in good measure. Here's a SO question regarding the use of the function.
SELECT
i.name as ingredient_name
, MIN(store_price.price) as price
, SUBSTRING_INDEX(
GROUP_CONCAT(store_price.date ORDER BY store_price.price),
',',
1
) as date
, SUBSTRING_INDEX(
GROUP_CONCAT(s.name ORDER BY store_price.price),
',',
1
) as store_name
, SUBSTRING_INDEX(
GROUP_CONCAT(b.name ORDER BY store_price.price),
',',
1
) as brand_name
FROM
ingredient i
JOIN
(SELECT
ip.ingredient_id as ingredient_id
, stip.store_id as store_id
, btip.brand_id as brand_id
, CONVERT(SUBSTRING_INDEX(
GROUP_CONCAT(ip.ingredient_price_id ORDER BY ip.date DESC),
',',
1
), UNSIGNED INTEGER) as ingredient_price_id
, MAX(ip.date) as date
, CONVERT(SUBSTRING_INDEX(
GROUP_CONCAT(ip.price ORDER BY ip.date DESC),
',',
1
), DECIMAL(5,2)) as price
FROM ingredient_price ip
JOIN store_to_ingredient_price stip ON ip.ingredient_price_id = stip.ingredient_price_id
JOIN brand_to_ingredient_price btip ON ip.ingredient_price_id = btip.ingredient_price_id
GROUP BY
ip.ingredient_id
, stip.store_id) store_price
ON i.ingredient_id = store_price.ingredient_id
JOIN store s ON s.store_id = store_price.store_id
JOIN brand b ON b.brand_id = store_price.brand_id
GROUP BY
store_price.ingredient_id;
You can check the implementation on this SQL Fiddle.
The version below, which ignores the brand, is slightly smaller:
SELECT
i.name as ingredient_name
, MIN(store_price.price) as price
, SUBSTRING_INDEX(
GROUP_CONCAT(store_price.date ORDER BY store_price.price),
',',
1
) as date
, SUBSTRING_INDEX(
GROUP_CONCAT(s.name ORDER BY store_price.price),
',',
1
) as store_name
FROM
ingredient i
JOIN
(SELECT
ip.ingredient_id as ingredient_id
, stip.store_id as store_id
, CONVERT(SUBSTRING_INDEX(
GROUP_CONCAT(ip.ingredient_price_id ORDER BY ip.date DESC),
',',
1
), UNSIGNED INTEGER) as ingredient_price_id
, MAX(ip.date) as date
, CONVERT(SUBSTRING_INDEX(
GROUP_CONCAT(ip.price ORDER BY ip.date DESC),
',',
1
), DECIMAL(5,2)) as price
FROM ingredient_price ip
JOIN store_to_ingredient_price stip ON ip.ingredient_price_id = stip.ingredient_price_id
GROUP BY
ip.ingredient_id
, stip.store_id) store_price
ON i.ingredient_id = store_price.ingredient_id
JOIN store s ON s.store_id = store_price.store_id
GROUP BY
store_price.ingredient_id;
References:
Simulating First/Last aggregate functions in MySQL
This probably needs a couple of sub queries joined together.
This isn't tested (as I don't have your table definitions, nor any test data), but something like this:-
SELECT i.name AS ingredient,
ip.price,
ip.date,
s.name AS storename,
b.name AS brandname
FROM ingredient i
INNER JOIN ingredient_price ip
ON ingredient.ingredient_id = ingredient_price.ingredient_id
INNER JOIN store_to_ingredient_price stip
ON ingredient_price.ingredient_price_id = store_to_ingredient_price.ingredient_price_id
INNER JOIN store s
ON store_to_ingredient_price.store_id = store.store_id
INNER JOIN brand_to_ingredient_price btip
ON ingredient_price.ingredient_price_id = brand_to_ingredient_price.ingredient_price_id
INNER JOIN brand b
ON brand_to_ingredient_price.brand_id = brand.brand_id
INNER JOIN
(
SELECT i.ingredient_id,
stip.store_id,
ip.date,
MIN(ip.price) AS lowest_price
FROM ingredient i
INNER JOIN ingredient_price ip
ON ingredient.ingredient_id = ingredient_price.ingredient_id
INNER JOIN store_to_ingredient_price stip
ON ingredient_price.ingredient_price_id = store_to_ingredient_price.ingredient_price_id
INNER JOIN
(
SELECT i.ingredient_id,
stip.store_id,
MAX(ip.date) AS latest_date
FROM ingredient i
INNER JOIN ingredient_price ip
ON ingredient.ingredient_id = ingredient_price.ingredient_id
INNER JOIN store_to_ingredient_price stip
ON ingredient_price.ingredient_price_id = store_to_ingredient_price.ingredient_price_id
GROUP BY ingredient_id, store_id
) Sub1
ON i.ingredient_id = Sub1.ingredient_id
AND stip.store_id = Sub1.store_id
AND ip.date = Sub1.latest_date
GROUP BY i.ingredient_id, stip.store_id, ip.date
) Sub2
ON i.ingredient_id = Sub2.ingredient_id
AND stip.store_id = Sub2.store_id
AND ip.date = Sub2.date
AND ip.price = Sub2.lowest_price
Try this:
SELECT `newest`.ingredient, `newest`.store,
`newest`.brand, `newest`.price, `newest`.`latest_date`
FROM
(SELECT ingredient.name AS ingredient, store.name AS store,
brand.name AS brand, ingredient_price.price,
MAX( ingredient_price.date ) AS `latest_date`
FROM ingredient
LEFT OUTER JOIN ingredient_price
ON ingredient.ingredient_id = ingredient_price.ingredient_id
LEFT OUTER JOIN store_to_ingredient_price
ON ingredient_price.ingredient_price_id = store_to_ingredient_price.ingredient_price_id
LEFT OUTER JOIN store
ON store_to_ingredient_price.store_id = store.store_id
LEFT OUTER JOIN brand_to_ingredient_price
ON ingredient_price.ingredient_price_id = brand_to_ingredient_price.ingredient_price_id
LEFT OUTER JOIN brand
ON brand_to_ingredient_price.brand_id = brand.brand_id
GROUP BY ingredient.name) `newest`
ORDER BY `newest`.price
LIMIT 1
I've spent a couple of days creating this rather complicated SQL statement, and it now gives me exactly what I want. Now I'm wondering if there is a better/simpler way to do it. Also MySQL wont let me CREATE VIEW on this statement
SELECT name, a.user, liste, c.order, total_1kr, total_5kr, total_8kr, total_10kr, total_paid, differens, sbdato, spaid, sbreg, sfdato, sforbrug, sfreg
FROM (SELECT t.user, t.paid AS spaid, t.dato AS sbdato, t.registrant AS sbreg FROM(
SELECT user,MAX(dato) AS maksdato
FROM g_kiosk_f WHERE paid!=0
GROUP BY user) AS x
JOIN g_kiosk_f AS t ON x.user =t.user
AND x.maksdato = t.dato) AS a
JOIN (SELECT s.user, (s.1kr+(s.5kr)*5+(s.8kr)*8+(s.10kr)*10) AS sforbrug, s.dato AS sfdato, s.registrant AS sfreg FROM(
SELECT user,MAX(dato) AS maksdato
FROM g_kiosk_f WHERE 1kr!=0 OR 5kr!=0 OR 8kr!=0 OR 10kr!=0
GROUP BY user) AS y
JOIN g_kiosk_f AS s ON y.user=s.user
AND y.maksdato=s.dato) AS b
JOIN (SELECT t1.name, t2.user, t1.liste, t1.order, sum( t2.1kr ) AS total_1kr, sum( t2.5kr ) *5 AS total_5kr, sum( t2.8kr ) *8 AS total_8kr, sum( t2.10kr ) *10 AS total_10kr, sum( t2.paid ) AS total_paid, ( sum( t2.1kr ) + sum( t2.5kr ) *5 + sum( t2.8kr ) *8 + sum( t2.10kr ) *10 - sum( t2.paid )) AS differens
FROM g_kiosk_users AS t1
INNER JOIN g_kiosk_f AS t2 ON t1.nr = t2.user
GROUP BY t2.user
ORDER BY t1.name ASC) AS c
ON a.user=b.user AND a.user=c.user
I have a table 'g_kiosk_f' containing id (user), date (dato), 5 kinds of transactions (1kr, 5kr, 8kr, 10kr, and paid) a cashier (registrant). Another table, 'g_kiosk_users', contains name and id (nr).
I want a result set showing
the date, registrant and amount of newest transaction where paid!=0
the date, registrant and amount of newest transaction where 1kr!=0, 5kr!=0, 8kr!=0 or 10kr!=0
the total difference of sum(1kr+5kr+8kr+10kr) and sum(paid)
So the result should look something like
Name | id | difference | newest paid date | newest paid registrant | newest paid amount | newest kr date | newest kr registrant | newest kr amount |
In the above I've included the numbers needed to do the difference calculation by hand, because it was needed at some point, but is now obsolete. Does any of this even make sense?
It seems like it should be possible to rewrite you query like this:
SELECT t1.name AS name, a.user AS user, t1.liste, t1.order,
SUM(t2.1kr) AS total_1kr, SUM(t2.5kr) * 5 AS total_5kr,
SUM(t2.8kr) AS total_8kr, SUM(t2.10kr) * 5 AS total_10kr,
SUM(52.paid) AS total_paid,
SUM(t2.1kr + 5 * tt.5kr + 8 * t2.8kr + 10 * t2.10kr)
-SUM(t2.paid) AS differens
a.dato AS sbdato, a.paid AS spaid, a.registrant as sbreg,
b.dato as sfdato,
(b.1kr+(b.5kr)*5+(b.8kr)*8+(b.10kr)*10) AS sforbrug,
b.registrant AS sfreg
FROM g_kiosk_f AS a
INNER JOIN (SELECT user, MAX(dato) FROM g_kiosk_f
WHERE paid != 0
GROUP BY user) AS a2
ON a.user = a2.user AND a.dato = a2.dato
INNER JOIN g_kiosk_f as b ON b.user = a.user
INNER JOIN (SELECT user, MAX(dato) FROM g_kiosk_f
WHERE 1kr!=0 OR 5kr!=0 OR 8kr!=0 OR 10kr!=0
GROUP BY user) AS b2
ON b.user = b2.user AND b.dato = b2.dato
INNER JOIN g_kiosk_f as t2 ON t2.user = a.user
INNER JOIN g_kiosk_users as t1 ON t1.nr = t2.user
GROUP BY a.user
ORDER BY name ASC
I have the following table structure:
Customers - Cust_Orders - Cust_Items - Cust_Payments - Drivers
id id id id id
company cid oid oid name
driver price amount
date qty date
vat
What I want to do is showing last unpaid order marked by a specific driver id + the sum of all unpaid orders for that particular customer except the order that is already selected.
Since there might be more than one cust_items & more than one cust_payments I had to use select from select as otherwise I would have wrong sums & things got messy till I reached a point I forgot what I was doing.
Any Help would be greatly appreciated.
My current SQL which lacks the final part only (sum of other unpaid orders amounts):
SELECT `customers`.`company`,
T1.*,
ROUND( IFNULL( SUM(`cust_payments`.`amount`), 0 ), 2) AS `paid`
FROM (
SELECT `cust_orders`.*,
ROUND( IFNULL( SUM(`cust_items`.`qty` * `cust_items`.`price`), 0 ), 2) AS `total`,
SUM( ( `cust_items`.`price` * `cust_items`.`qty` * `vat` ) / 100) AS `vat`
FROM `cust_orders`
LEFT JOIN `cust_items` ON `cust_orders`.`id` = `cust_items`.`oid`
GROUP BY `cust_orders`.`id`
) `T1`
LEFT JOIN `customers` ON `T1`.`cid` = `customers`.`id`
LEFT JOIN `cust_payments` ON `T1`.`id` = `cust_payments`.`oid`
WHERE `T1`.`driver` = ? GROUP BY `T1`.`id` HAVING (`T1`.`total` - `paid`) > ?
ORDER BY `T1`.`id` DESC LIMIT 1
Can you try
SELECT
x.id,
x.company,
y.id,
y.cid,
y.driver,
y.date,
#ut:=ROUND(SUM(z.qty*z.price),2) AS unpaid_total,
#uv:=SUM((#ut*z.vat)/100) AS unpaid_vat,
#st:=ROUND(SUM(b.qty*b.price),2)-#ut AS sum_total,
SUM((#st*b.vat)/100)-#uv AS sum_vat
FROM Customers x
INNER JOIN Cust_Orders y ON x.id=y.cid
INNER JOIN Cust_Items z ON y.id=z.oid
LEFT JOIN Cust_Orders a ON x.id=a.cid
LEFT JOIN Cust_Items b ON a.id=b.oid
WHERE
y.driver=? AND
NOT EXISTS (SELECT * FROM Cust_Payments WHERE oid=y.id) AND
NOT EXISTS (SELECT * FROM Cust_Payments WHERE oid=a.id)
GROUP BY x.id,x.company, y.id, y.cid, y.driver, y.date
I'm selecting total count of villages, total count of population from my tables to build statistics. However, there is something wrong. It returns me everything (530 pop (there are 530 pop in total), (106 villages (there are 106 users in total)) in first row, next rows are NULLs
SELECT s1_users.id userid, (
SELECT count( s1_vdata.wref )
FROM s1_vdata, s1_users
WHERE s1_vdata.owner = userid
)totalvillages, (
SELECT SUM( s1_vdata.pop )
FROM s1_users, s1_vdata
WHERE s1_vdata.owner = userid
)pop
FROM s1_users
WHERE s1_users.dp >=0
ORDER BY s1_users.dp DESC
Try removing s1_users from inner SELECTS
You're already using INNER JOINs. Whan you list tables separated with comma, it is a shortcut for INNER JOIN.
Now, the most obvious answer is that your subqueries using aggregating functions (COUNT and SUM) are missing a GROUP BY clauses.
SELECT s1_users.id userid, (
SELECT count( s1_vdata.wref )
FROM s1_vdata, s1_users
WHERE s1_vdata.owner = userid
GROUP BY s1_vdata.owner
)totalvillages, (
SELECT SUM( s1_vdata.pop )
FROM s1_users, s1_vdata
WHERE s1_vdata.owner = userid
GROUP BY s1_vdata.owner
)pop
FROM s1_users
WHERE s1_users.dp >=0
ORDER BY s1_users.dp DESC
However, using subqeries in column list is really inefficient. It casues subqueries to be run once for each row in outer query.
Try like this instead
SELECT
s1_users.id AS userid,
COUNT(s1_vdata.wref) AS totalvillages,
SUM(s1.vdata.pop) AS pop
FROM
s1_users, s1_vdata --I'm cheating here! There's hidden INNER JOIN in this line ;P
WHERE
s1_users.dp >= 0
AND s1_users.id = s1_vdata.owner
GROUP BY
s1_users.id
ORDER BY
s1_users.dp DESC
SELECT s1_users.id AS userid,
(
SELECT COUNT(*)
FROM s1_vdata
WHERE s1_vdata.owner = userid
) AS totalvillages,
(
SELECT SUM(pop)
FROM s1_vdata
WHERE s1_vdata.owner = userid
) AS pop
FROM s1_users
WHERE dp >= 0
ORDER BY
dp DESC
Note that this is less efficient than this query:
SELECT s1_users.id AS user_id, COUNT(s1_vdata.owner), SUM(s1_vdata.pop)
FROM s1_users
LEFT JOIN
s1_vdata
ON s1_vdata.owner = s1_users.id
GROUP BY
s1_users.id
ORDER BY
dp DESC
since the aggregation needs to be done twice in the former.
SELECT userid,totalvillages,pop from
(
SELECT s1_users.id as userid, count( s1_vdata.wref ) as totalvillages
FROM s1_vdata, s1_users
WHERE s1_vdata.owner = userid
GROUP BY s1_users.id) tabl1 INNER JOIN
(
SELECT s1_users.id as userid, SUM( s1_vdata.pop ) as pop
FROM s1_users, s1_vdata
WHERE s1_vdata.owner = userid
GROUP BY s1_users.id) tabl2 on tabl1.userid = tabl2.userid