Laravel 5.3 Query - Left join some table - mysql

I'm trying to get the most recent record for each candidate_id from a ìnterviews` table.
This is what I want to achive:
I'm using Eloquent on laravel and have already tried this methods (with and without eloquent):
$candidates = DB::table('interviews')->select('interviews.*', 'i2.*')
->leftJoin('interviews as i2',
function ($join) {
$join->on('interviews.candidate_id', '=', 'i2.candidate_id');
$join->on('interviews.created_at', '<', 'i2.created_at');
}
)
->whereNull('i2.candidate_id')
->get();
and with eloquent I've tried this:
$candidates = Interview::leftJoin('interviews as i2',
function ($join) {
$join->on('interviews.candidate_id', '=', 'i2.candidate_id');
$join->on('interviews.created_at', '<', 'i2.created_at');
}
)->whereNull('i2.candidate_id')
->get();
If I change get() to toSql() I have exactly the same query that's shown on the above image, but running on laravel I'm getting always these results (this using the first method, with query builder):
Anyone know why I get this results? Is hard to understand that laravel is doing the same query that I do in HeidiSql but I get diferent results :(
Any tip?
Thanks in advance!

Because you are using ->select('interviews.*', 'i2.*') combined with ->whereNull('i2.candidate_id') I am assuming the second select parameter is overriding all fields on the interviews table with nulls, try reversing the order to ->select('i2.*','interviews.*') or not use the i2.* at all.
This is because the output ignores the alias and only uses the fieldname as element key in the returned collection.
Hope it works.
Perfect case scenario you pick the exact columns you want from each of the joined tables for e.g. it may go like this: table1.id,table1.column1,table1.column2,table2.column2 as smth_so_it_doesnt_override

Related

laravel eloquent join where clause with sub query to use column name comparision not working

I am having issues with laravel eloquent join to compare date in where clause using sub query. below query gives me error unknown column policy_periods.statecode i am using this column in where clause of the join subquery for example App\Elrd::where("state_code",'=',DB::raw(policy_periods.statecode))->where('date',"<=",$mod_rating_eff_date)->max('date')
can you please give me an idea if any solution possible ?
i have already tried whereRaw, whereColumn but none of them is working.
DB::table('policy_periods')
->join('payrolls','payrolls.policy_period_id', '=', 'policy_periods.id')
->leftjoin('elrds', function($join) use($mod_rating_eff_date)
{
$join->on('elrds.state_code', '=', 'policy_periods.statecode');
$join->on('elrds.class_code', '=', 'payrolls.code');
$join->where('elrds.date',App\Elrd::where("state_code",'=',DB::raw(`policy_periods`.`statecode`))->where('date',"<=",$mod_rating_eff_date)->max('date'));
})
->select('payrolls.*','payrolls.elr as payrollelr','policy_periods.id as pid','policy_periods.policy_no',DB::raw('CONCAT(eff_date, "-", exp_date) as dateGroup'),'policy_periods.eff_date','policy_periods.exp_date','policy_periods.statecode as ratingeffPolicyYear','policy_periods.statecode','elrds.class_code','elrds.year','elrds.date','elrds.elr','elrds.dratio')
->where('policy_periods.mod_id',$id)
->get();
When I encounter such issue, the first thing I usually do is to determine if the generated query is what I wanted.
You should log your queries so that you can ensure it.
To do that, a possible solution is to add a log in your AppServiceProvider (in function boot):
DB::listen(function ($query) {
Log::debug('query',[
$query->sql,
$query->bindings,
$query->time
]);
});
That being said, where do these backticks come from?
DB::raw(`policy_periods`.`statecode`)
You could replace it with DB::raw('policy_periods.statecode')
Please tell me if it fixes your issue, or provide the generated SQL query if the problem is not fixed.

how to search by letter in column in database (laravel)

I want to find by letter customer's first_name on my 'customers' table.
And the only thing that I get is an empty array.
For instance, I put in the parameter 'q' value 'E' to get customer Elena from my database by I get an only empty array.
I use the following code to get first_name :
$search = Input::get('q');
if($search)
{
$customers = Customer::all()->where('full_name', 'LIKE', "%{$search}%");
return ($customers);
}
Can someone help me?
Your query don't work because you are calling the all() method before the where(). That's actually not wrong, but it have different behavior.
When you call all(), it actually does the SQL query. After that, any chained methods are being called into a Eloquent Collection class, and it also have a where method, but that's simpler since it runs on PHO instead of running on SQL.
Since the collection's where() method doesn't support LIKE operator, it's probably searching for a value that is exactly %E%.
Hope it can help you understanding why your query doesn't work as expected.
Try this
$customers = Customer::where('full_name', 'LIKE', "%{$search}%")->get();
Laravel Eloquent

Eloquent select statement based on a condition in another table

I have an laravel eloquent select statement which looks like this:
$test = Test::with(['a.b.companies']) .. and so on
Now, I want to return results for this query based on some company names in companies table.
I tried to write a where clause with various trial and errors but it doesn't work. I am new to laravel and mysql. Any help in the right direction will be good. thanks.
You may use where, for more reference : - Eloquent ORM
$test = Test::where('company_name1', '=', $company_name1)->orWhere('company_name2', '=', $company_name2)->get();

How to format Laravel Eloquent query with optional sections

Im new to Laravel, but am struggling with how Eloquent queries can have optional sections.
I have the following Eloquent query at the moment:
Posts::where('approved', '=', 'Y')->orderBy('created_at', 'DESC')->take($noofposts)->skip($skipno)->get();
That works fine. However I now need to add two optional sections, which i'd like to do without having to duplicate the query each time.
I need to add AND WHERE userid=$x (looped for one or more times) if $x (which is an array) is present, if its not it should ignore then ... and finally add AND (WHERE status=$y[0] OR $status=$y[1] OR $status=$y[2]) - again if the status flags are not set, then just ignore.
Basically if no flags are set I end up with the original query, but if they are we get
Posts::where('approved', '=', 'Y')->where('userid', '=', '2')->where('userid', '=', '23')->where('status', '=', 'K')->orWhere('status', '=', 'N')->orderBy('created_at', 'DESC')->take($noofposts)->skip($skipno)->get();
I can work it out perfectly in normal PHP, but cannot understand how it would work in Laravel Eloquent.
Can anyone point me in the right direction? Neither the user guide nor any website examples seem to look at this kind of scenario!
Fist, instead of chaining orWhere I would use the whereIn function of Eloquent.
whereIn('status', $y);
The problem is, if $y is empty, the request won't work. (I think it just crashes)
So if you want to avoid controls and keep your code clean you can add a query scope in you Post model.
http://laravel.com/docs/4.2/eloquent#query-scopes
scopeOptionalWhereIn($query, $field, $array){
if(!empty($array))
return $query->whereIn($field, $array);
return $query; //return unchanged query
}
Then you can use this scope in your query:
Posts::where('approved', '=', 'Y')
->optionalWhereIn('status', $y)
->orderBy('created_at', 'DESC')
->take($noofposts)
->skip($skipno)->get();
You can probably use the same scope to deal with the userid conditions.

Laravel query build based on relation

I have such query:
Tournament::has('participations', '<', '2')->get();
How can I replace constant number '2' on tournament's column named slots ?? I would like retrieve only these tournaments which have least participants than slots in tournament.
Let's start by using the column name instead of "2". Like you would do in "normal" SQL
Tournament::has('participations', '<', 'slots')->get();
Now, you don't even have to try that because it won't work. But why's that? Because Laravel treats slots like a string and escapes it so SQL does as well.
What you need to do, is use DB::raw(). raw makes sure Laravel changes nothing and just injects it into the SQL query
Tournament::has('participations', '<', DB::raw('slots'))->get();
Update
After some trying out I found this: (Its not very pretty but the only way I got it working)
$subquery = function($q) use ($uid){
$q->where('player_id', $uid);
}
Tournament::whereHas('participations', $subquery)
->whereHas('participations', $subquery, '<', DB::raw('slots'))
->get();
The first whereAs checks for count(*) > 0, the second count(*) < slots and the subquery filters by player id.