If I want to use a background image positioned at 80% on the x-axis, and the image width is 30%, my understanding is that the image should be partially disappearing on the right side (starting at 80% and ending at 110% of the div's width). However, it seems that the browser decides to align the right side of the image at 80% - but if I changed 80 to 20 then it aligns the left side at 20%. This is really strange behavior and a problem for me.
Here's a fiddle to illustrate what I'm talking about:
https://jsfiddle.net/qzbrkbcz/2/
The first background image is correctly positioned and the second is right-aligned.
How do I make sure that background images always have their top left corner positioned at the background-position value?
The background image will position itself according to it's own size. So if you want it to go out of the container, you'll have to use something like background-position: 250% 100%;
https://jsfiddle.net/maxpaj/qzbrkbcz/6/
Good luck :)
Related
I am trying to implement a sidemenu with a background image but I don't understand how to make it responsive also vertically...
I have this image https://ibb.co/Pzyyyh2 whose size is 320x1000px. It's a very tall white image that a certain point becomes black.
I'd like to have this black detail to stay always at a certain point of my sidemenu (the transition from white to black should start before the social link part).
As you can see here, on iPhone X emulator, it works as expected: https://ibb.co/C7Nm6b7.
While on another device such as Moto G4 this happens: https://ibb.co/S7tQwJV
You don't need the white part of the image, if what you're trying to show is the black, then just use the black. If your image is an svg, it will always expand/contract properly, without visible pixelation. The rest of the footer should have a background-color equal to that of your img.
If you want to use skew, then make a first div (the parent/wrapper), then place it right before your footer area. Then inside the wrapper, add the skew-div. Make the parent have overflow:hidden so the excess of the skew-siv doesn't become visible past the borders of the parent.
Like this:
Then, inside your 'magic-div', you'd have the following:
The parent gets width: 100%; and overflow:hidden;. The child skew div inside gets width:100%; too. If you're using background with an svg as suggested earlier, the background-size rule should be 100% auto or cover, depending on the scenario (the widths you're covering + the angle of your skew). Give it a try and let us know how it went.
Okay what i cant seem to figure out is I want any image no matter what size to fit to the browser window EXACTLY corner to corner as a background image. what usually happens is the BG image corners seem to overflow to where they cant be seen. like the browser uses the middle of the image sort of but i need it exact! ANy help, would be greatly apprectiated!!!!....
heres the page link http://www.bxwebdesign.com/stack/index.htm and
http://www.bxwebdesign.com/stack/style.css
You want to use background-size: 100% 100%;. This will fill the element exactly corner to corner with your image.
See https://developer.mozilla.org/en-US/docs/Web/CSS/background-size for documentation on this CSS property.
My <div> background is shows half how can I fix it.
It shift all my background images to left and half right goes white in IE
here is screenshots
http://scrshots.blogspot.in/2014/11/1st-screen-shot.html
If it's a background for whole page try to attache it to body. If it shows only half of image most common problem is something mixed up with divs. If you have more background images try to provide a frame for them (separatly) using divs. Also are you sure that position should be absolute not relative?
body {
background: url(main-bg.jpg) no-repeat
}
I know how to center a web page with CSS, but I have no idea how to center it with an overflow of an oversized image/slider on both the left and right side. A perfect example is Square.com. The image is 1455px, but the window container is set to 1020px. But when you make the window wider,more of the image appears on the left and right, equally. I tried every version of the CSS code I can think of, but no luck. The 1020px container usually cuts off both sides of the image. So I was hoping you guys can help me out with the code that would achieve this result.
You can just set the background-position : center center; and it'll bleed off the ends.
I'm trying to set a background image to fullscreen, and on window resize the image doesn't change actuall pixel size, but get's smaller (crop-like).
This is what I mean: (Try to resize window and notice that the picture gets smaller or larger but doesn't pixelate) http://jsfiddle.net/G7Qc4/
Now, the above works because of the image is a background of a div and I've set:
background-position: center top;
If it was just plain <img> it doesn't work which my question is how can I make it work? If there is any way around?
I am using the nivoSlider which doesn't accept div's for image's so I will have to use <img>.
Thanks alot
If I understand, you want to use an actual tag as a background instead of background-image.
Here is my solution:
http://jsfiddle.net/ttZeM/
It requires knowing the dimensions of the background image.
There is a div holding the background which is absolutely positioned, the site content is absolutely positioned on top of it.
To center the background image, I moved it -500px to the left, which is half it's width. It is inside of a div that is 0px wide, being centered with position:absolute; left:50% a strange technique, but it works if you know the image size.
Also note that the bg_wrap div has overflow:hidden; and width:100%; this means you won't see scrollbars off the edges of the screen.
I hope this is what you were after!
It can be done with CSS3 (background-size: cover), like so: http://jsfiddle.net/mqchen/Kq3pa/