I need a one-liner to provision users in my databases. I'm running MySQL 5.6. Here is what I'm setting the password as a variable so that I can pass it dynamically (obviously it won't always be 'password').
mysql_password="password"
mysql -u ted -e "SET PASSWORD FOR 'ted'#'localhost' = PASSWORD($mysql_password);"
I'm getting the following error when I run this:
ERROR 1064 (42000) at line 1: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'password)' at line 1
What is wrong with the statement? Can it be corrected or is another solution available so I accomplish this via Bash?
You need to surround the variable by single quotes:
mysql -u root -e "SET PASSWORD FOR 'ted'#'localhost' = PASSWORD('$mysql_password');"
Related
How do I pass variables that I would have created in linux shell to the mysql command.
For example:
# carname=tesla-new
# echo $carname
I want to use the $car-name variable when passing arguments to MySQL commands.
This variable will come in as input from loop while iterating through a list of values.
mysql -u wp-supportuser -h xx.xxx.xxx.xxx -p<mypassword>! -e 'DROP DATABASE ${carname};'
I need the hyphon(-) in the variable's value, else my application will accept. We get the below error when the above command is run:
mysql: > [Warning] Using a password on the command line interface can be insecure. ERROR 1064 (42000) at line 1: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-wp' at line 1
How will I be able to achieve this?
It is a MySQL error, because MySQL does not support the usage of hyphen by itself. Instead, you need to enclose it into
`
characters. You can use it if you wrap your command inside apostrophes, like:
mysql -u wp-supportuser -h xx.xxx.xxx.xxx -p<mypassword> -e 'drop database `$carname`;
This question already exists:
Why am I getting the error 1064 (42000) while importing using MariaDB/“mysql shell”?
Closed 5 years ago.
Whenever type mysql -u username [-p password] database_name < tatoeba_database.sql
I get
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that
corresponds to your MariaDB server version for the right syntax to use near 'mys
ql -u root tatoeba < tatoeba_database.sql' at line 1
MariaDB [tatoeba]>
Is there another way to do such thing Am I missing something?
P.S. I'm following this article: https://github.com/Tatoeba/tatoeba2/wiki/How-to-install-Tatoeba
Remove [-p password]
mysql -u username -p database_name < tatoeba_database.sql
and enter the password manually
It appears that you type your command in MariaDB prompt (that is, you start mysql client first and then use the command above). It's incorrect. You either need to execute it from the shell prompt, or, if you want to start mysql client first, lose the whole thing and run instead
source tatoeba_database.sql
I am currently working on a shell script.
I want to modify the contains of the column "balance" in "Student" table as "balance=balance-$deduct" in shell script.
I am executing following line in shell
mysql -h "$host" -u "$user" --password="$pass" --database="$db" -e "UPDATE student SET balance=balance-$deduct WHERE pid=$pid";
Here i specified the host, username and password properly and i have one numeric value stored in $deduct
but when i execute the script i am getting following error:
ERROR 1064 (42000) at line 1: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE pid=132054' at line 1
where I am wrong here?
thanks
You don't need --database=
mysql -h "$host" --user="$user" --password="$pass" "$db" -e "UPDATE student SET balance=balance-$deduct WHERE pid=$pid";
You can also do Use $db in you query
Just remove --database=
It should work.
I am trying to execute a particular mysql command from the command line. When I do so, it fails, but if I execute the exact same command from within mysql interactive, it works.
Here is the command line version which fails:
$ mysql -uscott -p -e "GRANT ALL PRIVILEGES ON `myuser\_%`.* TO 'myuser'#'localhost';"
The error given is:
ERROR 1064 (42000) at line 1: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '* TO 'myuser'#'localhost'' at line 1
Copying and pasting just the mysql command into mysql works:
mysql> GRANT ALL PRIVILEGES ON `myuser\_%`.* TO 'myuser'#'localhost';
I have taken this command verbatim from phpmyadmin when creating a user for a database. How can I fix it so it works from the command line?
The * is being expanded by your shell (bash?).
You can fix this by using single quotes around the SQL statement instead of double or escaping the * with a \
I'm trying to run an update query on a db server via bash command.
I have to update an IP field (which is sorted as a string) but i'm getting a syntax error...
ssh admin#192.168.3.240 "/usr/local/mysql/bin/mysql -D SMARTPARK -u parkuser -ppass -e 'update client SET online=0 where client_ip='192.168.42.11''"
I'm getting as error
ERROR 1064 (42000) at line 1: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.42.11' at line 1
which is the error?
Try to escape " character with \" to make sure you don't escape from the string you're sending to your DB.
In other words, try to put the following in the bash file you're executing:
ssh admin#192.168.3.240 "/usr/local/mysql/bin/mysql -D SMARTPARK -u parkuser -ppass -e \"update client SET online=0 where client_ip='192.168.42.11'\""