Gulp compile CSS multiple src - gulp

Question

I am using Gulp to compile my bootstrap.less file into a bootstrap.css file. All the bootstrap LESS files are in a "less" folder and all of the CSS files are in a CSS folder. All of the bootstrap less files are #import'd into bootstrap.less and then that file is compiled to bootstrap.css. However I have one custom.less file that is in the bootstrap LESS folder. I would like to compile into a custom.css file in the CSS folder. I cannot get Gulp to do this. Here is my code.
var gulp = require('gulp');
var less = require('gulp-less');
var browserSync = require('browser-sync').create();
gulp.task('less', function() {
return gulp.src(['./less/bootstrap.less', './less/custom.less'])
.pipe(less())
.pipe(gulp.dest("./css"))
.pipe(browserSync.reload({stream: true}));
});
gulp.task('serve', function(){
browserSync.init({
server: {
baseDir: './'
}
});
gulp.watch('./less/*.less', ['less']);
gulp.watch(['./**/*.html', './js/custom.js']).on('change',
browserSync.reload);
});
gulp.task( 'default', ['less', 'serve']);

Answer 1

What I usually do is compile all .less or .scss files into css folder. You will end up with a few empty files (a good example would be .less files that contain variables) but on the other hand you can create a gulp task to clear those files out. I use the following code to compile:
return gulp.src("Styles/scss/*.scss")
.pipe(sourcemaps.init())
.pipe(sass())
.pipe(sourcemaps.write('.'))
.pipe(gulp.dest("Styles/css"))
.pipe(reload({stream: true}));
I'm also generating sourcemaps here but you can remove that. If you would like to discover more checkout this post here
Hope this helps ;)