Showing proper balance ammount - mysql

Question

I have a query where I suppose to show debit, credit & balance. I have no balance column in table. I calculate the balance from debit & credit.
I tried to create a balance column where balance will be stored and display it from table. But if I update or delete any row the balance will not proper.
I found the below code on SO. But it works when there is one row for a one date, multiple columns for a date is not working properly. It display the balance with day by day, I want to display balance with row by row.
MySQL
SELECT
m.`id`,
m.`date`,
m.`credit`,
m.`debit`,
SUM(t.`credit`) - SUM(t.`debit`) AS `balance`
FROM `cash_book` m
JOIN (
SELECT
`id`,
`date`,
`credit`,
`debit`
FROM
`cash_book`
) t ON t.`date` <= m.`date`
WHERE `customer_id` = 1
GROUP BY
m.`id`
ORDER BY m.`date` ASC
It's return the result like this:
Date Debit Credit Balance
2016-11-27 0 2000 2000
2016-12-02 0 500000 585000 //same result for date 2016-12-02
2016-12-02 15000 0 585000 //same result for date 2016-12-02
2016-12-02 0 100000 585000 //same result for date 2016-12-02
2016-12-03 1200 0 583800
2016-12-04 3160 0 580540 //same result for date 2016-12-04
2016-12-04 100 0 580540 //same result for date 2016-12-04
2016-12-05 30 0 580510
2016-12-06 0 150 580660
But I want the result like this:
Date Debit Credit Balance
2016-11-27 0 2000 2000
2016-12-02 0 500000 502000
2016-12-02 15000 0 487000
2016-12-02 0 100000 587000
2016-12-03 1200 0 585800
2016-12-04 3160 0 582640
2016-12-04 100 0 582540
2016-12-05 30 0 582510
2016-12-06 0 150 582660

Answer 1

is it this what you looking for ?
SELECT
`id`,
`date`,
`credit`,
`debit`,
#balance := #balance + credit-debit AS balance
FROM `cash_book`
CROSS JOIN ( SELECT #balance := 0) as init
ORDER BY `date` ASC ;
sample
mysql> SELECT * FROM cash_book;
+------+------------+-------+--------+
| id | date | debit | credit |
+------+------------+-------+--------+
| 1 | 2016-11-27 | 0 | 2000 |
| 2 | 2016-12-04 | 3160 | 0 |
| 3 | 2016-12-02 | 15000 | 0 |
| 4 | 2016-12-03 | 1200 | 0 |
| 5 | 2016-12-05 | 30 | 0 |
| 6 | 2016-11-29 | 0 | 10000 |
| 7 | 2016-01-05 | 0 | 0 |
| 8 | 2016-12-01 | 2000 | 0 |
| 9 | 2016-11-29 | 10000 | 0 |
| 10 | 2016-12-02 | 2000 | 100000 |
| 11 | 2016-12-06 | 2000 | 150 |
| 12 | 2016-12-02 | 2000 | 500000 |
+------+------------+-------+--------+
12 rows in set (0,00 sec)
mysql> SELECT
-> `id`,
-> `date`,
-> `credit`,
-> `debit`,
-> #balance := #balance + credit-debit AS balance
-> FROM `cash_book`
-> CROSS JOIN ( SELECT #balance := 0) as init
-> ORDER BY `date` ASC ;
+------+------------+--------+-------+---------+
| id | date | credit | debit | balance |
+------+------------+--------+-------+---------+
| 7 | 2016-01-05 | 0 | 0 | 0 |
| 1 | 2016-11-27 | 2000 | 0 | 2000 |
| 6 | 2016-11-29 | 10000 | 0 | 12000 |
| 9 | 2016-11-29 | 0 | 10000 | 2000 |
| 8 | 2016-12-01 | 0 | 2000 | 0 |
| 3 | 2016-12-02 | 0 | 15000 | -15000 |
| 10 | 2016-12-02 | 100000 | 2000 | 83000 |
| 12 | 2016-12-02 | 500000 | 2000 | 581000 |
| 4 | 2016-12-03 | 0 | 1200 | 579800 |
| 2 | 2016-12-04 | 0 | 3160 | 576640 |
| 5 | 2016-12-05 | 0 | 30 | 576610 |
| 11 | 2016-12-06 | 150 | 2000 | 574760 |
+------+------------+--------+-------+---------+
12 rows in set (0,00 sec)
mysql>

Answer 2

You can use a subquery in select part like this
SELECT
m.`id`,
m.`date`,
m.`credit`,
m.`debit`,
(select sum(n.`credit`) - sum(n.`debit`)
from `cash_book` n
where n.`id` = m.`id`
and n.`date` <= m.`date`) balance
FROM `cash_book` m
WHERE `customer_id` = 1
ORDER BY m.`date` ASC

Answer 3

try this query
select s.Date,s.Debit,s.credit,ABS(#b := #b + s.debit - s.credit) as balance from (select #b:= 0.0) as dummy cross join cash_book as s order by ID;

Answer 4

In your Query you have used JOIN, That will used to join two or more tables. Here you are using only one table. So no need of JOIN inside the query.
You can use this following simple query,
SELECT
m.id,
m.date,
m.credit,
m.debit,
(SELECT SUM(credit)-SUM(debit)
FROM`cash_book` A
WHERE A.date<=m.Date)
FROM `cash_book` m WHERE m.customer_id = 1 ORDER BY m.Date ASC