I have query :-
select
CustomerName,
Scenario,
StepNo,
InTransit,
IsAlef,
RunNo,
count(1) as Total
from RequestInfo
group by CustomerName,
Scenario,StepNo,InTransit,
IsAlef,RunNo
order by Total DESC LIMIT 1;
which gives me output :-
+--------------+-------------+--------+-----------+--------+-------+-------+
| CustomerName | Scenario | StepNo | InTransit | IsAlef | RunNo | Total |
+--------------+-------------+--------+-----------+--------+-------+-------+
| MMT | HotelBrowse | 1 | No | No | 2 | 226 |
+--------------+-------------+--------+-----------+--------+-------+-------+
the actual table is :-
+--------------+-------------+--------+-----------+--------+-------+----------+
| CustomerName | Scenario | StepNo | InTransit | IsAlef | RunNo | count(1) |
+--------------+-------------+--------+-----------+--------+-------+----------+
| MMT | HotelBrowse | 1 | No | No | 1 | 206 |
| MMT | HotelBrowse | 1 | No | No | 2 | 226 |
| MMT | HotelBrowse | 1 | No | No | 3 | 206 |
| YATRA | HotelBrowse | 1 | No | No | 1 | 298 |
| YATRA | HotelBrowse | 1 | No | No | 2 | 206 |
| YATRA | HotelBrowse | 1 | No | No | 3 | 147 |
+--------------+-------------+--------+-----------+--------+-------+----------+
but i want output like below:-
+--------------+-------------+--------+-----------+--------+-------+----------+
| CustomerName | Scenario | StepNo | InTransit | IsAlef | RunNo | count(1) |
+--------------+-------------+--------+-----------+--------+-------+----------+
| MMT | HotelBrowse | 1 | No | No | 2 | 226 |
| YATRA | HotelBrowse | 1 | No | No | 1 | 298 |
+--------------+-------------+--------+-----------+--------+-------+----------+
The idea is to get the rows with max count numbers of the last column "Total".
Check This.
select R1.* from RequestInfo R1
inner join
(
select CustomerName,MAX( `count(1)`) `count(1)`
from RequestInfo
group by CustomerName
)R2 on R1.CustomerName=R2.CustomerName and R1.`count(1)`=R2.`count(1)`
Demo : sqlfiddle here
Please try below query
select a.* from RequestInfo a,
(select CustomerName,max(Total) as total from RequestInfo group by CustomerName ) b
where a.customername=b.customername
and a.total=b.total;
Just set your 'TOTAL DESC LIMIT' as '2'
SELECT CustomerName, Scenario,StepNo,InTransit,IsAlef,RunNo, count(1) AS
Total FROM RequestInfo GROUP BY
CustomerName, Scenario,StepNo,InTransit,IsAlef,RunNo ORDER BY Total DESC LIMIT 2;
error because count is reserved keyword in mysql so you can write between count(1) not only count without acute
your query like this
select CustomerName,Scenario,StepNo,InTransit,IsAlef,RunNo,`count(1)` as Total from customer group by CustomerName;
check here
Related
I came across this SQL at work, This was written by my colleague. Although there are better solutions, I’m just curious,and now I have simplified it as follows:
-- Calculate the total of the 'APPROVING' salary and the 'AGENT' salary already actual paid
SELECT ifnull(sum(l.salary),0) +
(SELECT ifnull(sum(l1.salary),0)
FROM salary_header h1 JOIN salary_lines l1
ON h1.salary_id = l1.salary_id
WHERE h1.status='APPROVING' AND l1.project_id = l.project_id)
FROM salary_pay_headers h JOIN salary_pay_lines l
ON h.salary_pay_id = l.salary_pay_id
WHERE h.pay_type='AGENT'
AND l.project_id=9904
mysql> select * from salary_header;
+-----------+-----------+
| salary_id | status |
+-----------+-----------+
| 1 | APPROVING |
| 2 | PAID |
+-----------+-----------+
mysql> select * from salary_lines;
+----------------+-----------+------------+--------+
| salary_line_id | salary_id | project_id | salary |
+----------------+-----------+------------+--------+
| 1 | 2 | 9905 | 200.00 |
+----------------+-----------+------------+--------+
mysql> select * from salary_pay_headers;
+---------------+----------+
| salary_pay_id | pay_type |
+---------------+----------+
| 1 | AGENT |
| 2 | OTHER |
+---------------+----------+
mysql> select * from salary_pay_lines;
+--------------------+---------------+------------+--------+
| salary_pay_line_id | salary_pay_id | project_id | salary |
+--------------------+---------------+------------+--------+
| 1 | 1 | 9904 | 3.05 |
| 2 | 1 | 9904 | 201.37 |
| 3 | 1 | 9904 | 6.10 |
| 4 | 1 | 9904 | 10.17 |
| 5 | 1 | 9904 | 6.44 |
| 6 | 1 | 9904 | 9.15 |
| 8 | 3 | 9905 | 100.00 |
+--------------------+---------------+------------+--------+
Its result is not 3.05+201.37+6.10+10.17+6.44+9.15=236.28 as I expected，but 236.28+200=436.28，obviously that one in the salary_line is not filtered out. I have spent the whole afternoon on this problem, so I really want to know the execution order of this SQL.
this is all data from current table
SELECT
id,harga,kode_tahun_ajaran
FROM
tblharga
+----+---------+-------------------+
| id | harga | kode_tahun_ajaran |
+----+---------+-------------------+
| 1 | 400000 | THN2018/2019 |
| 2 | 50000 | THN2018/2019 |
| 3 | 1000000 | THN2018/2019 |
| 4 | 900000 | THN2018/2019 |
| 5 | 500000 | THN2017/2018 |
| 6 | 600000 | THN2018/2019 |
+----+---------+-------------------+
and i run this code to get the last harga with grouping the kode_tahun_ajaran
SELECT
id,harga,kode_tahun_ajaran
FROM
tblharga
GROUP BY
kode_tahun_ajaran
ORDER BY id DESC
+----+--------+-------------------+
| id | harga | kode_tahun_ajaran |
+----+--------+-------------------+
| 5 | 500000 | THN2017/2018 |
| 1 | 400000 | THN2018/2019 |
+----+--------+-------------------+
the harga column should take the last data which is 600000 because of the order by code.
how can I retrieve the latest data by grouping it another way?
thanks in advance.
You can try below
SELECT
id,harga,kode_tahun_ajaran
FROM
tblharga where id in (select max(id) from tblharga group by kode_tahun_ajaran)
select id,S.kode_tahun_ajaran,harga
from tblharga S inner join
( select kode_tahun_ajaran,max(id) maxid from tblharga group by kode_tahun_ajaran) T
where T.kode_tahun_ajaran=S.kode_tahun_ajaran and maxid=id;
Parts of the table that I am looking into is as follow:
table: store_inventories
+---------+----------+-------+----------+
| stor_id | title_id | qty | minStock |
+---------+----------+-------+----------+
| 8042 | TC7777 | 630 | 630 |
| 8042 | TH1217 | 0 | 630 |
| 9012 | AK1231 | -100 | 13 |
| 9012 | AK4153 | 5 | 1 |
| 9012 | BU2075 | 39 | 7 |
| 7131 | AW1234 | 10277 | 2055 |
| 7131 | AW5678 | 13150 | 2630 |
| 7131 | BU1032 | 545 | 109 |
| 7131 | BU2075 | 35 | 7 |
How can I select title_id from this table with where conditions that will meet both (not either) stor_ids 9012 and 7131.
The result should be
+----------+
| title_id |
+----------+
| BU2075 |
I tried inner join and using and statement but they either returning wrong result or empty set.
Use WHERE clause to filter the stor_ids and HAVING to count the instances of the rows return in the WHERE clause.
SELECT title_id
FROM store_inventories
WHERE stor_ids IN (9012, 7131) --
GROUP BY title_id
HAVING COUNT(*) = 2
Use DISTINCT if there title can have multiple rows of the same store.
HAVING COUNT(DISTINCT stor_ids) = 2
Here's a Demo.
You can try with a Join of subqueries:
SELECT a.title_id
FROM (select title_id
from store_inventories
where stor_id=9012) a
JOIN (select title_id
from store_inventories
where stor_id=7131) b
ON (a.title_id=b.title_id)
I have the following table:
+------------+--------+-----+
| reg_dat | status | id |
+------------+--------+-----+
| 2016-01-31 | 10 | 1 |
| 2017-06-31 | 12 | 1 |
| 2015-01-31 | 12 | 4 |
| 2017-01-25 | 5 | 4 |
| 2017-01-11 | 3 | 2 |
+------------+--------+-----+
I would like to do a mysql query to group the rows by id and keeping only the more recent date... so the output should be the following:
+------------+--------+-----+
| reg_dat | status | id |
+------------+--------+-----+
| 2017-06-31 | 12 | 1 |
| 2017-01-25 | 5 | 4 |
| 2017-01-11 | 3 | 2 |
+------------+--------+-----+
Unfortunately my code doesn't work...
select *
from table
group by id
order by id, reg_dat DESC
Have you some suggestions?
You can do that using a JOIN and a subquery
SELECT t.reg_dat, t.status, t.id
FROM table t
JOIN (SELECT max(reg_dat) max_date, id FROM table GROUP BY id) t1
ON t.reg_dat = t1.max_date AND t.id = t1.id
How do I solve this one? None of my queries works and I've tried few.
I've got to return details of two doctors who ordered the most analysis including the number of analysis they have ordered. That last part of the sentence is what really drives me mad.
To work with I've got these two tables:
mysql> select * from DOCTORES;
+-----------+---------------------------+--------------+-----------+
| DNI_DOC | NOMBRE_DOC | ESPECIALIDAD | TELEFONO |
+-----------+---------------------------+--------------+-----------+
| 22888444O | MATEO DÍAZ, RAMÓN | 3 | 659876457 |
| 22909456Y | HERAS PRADO, ANTONIA | 1 | 676234598 |
| 23456398F | GÓMEZ DAVID, ADRIÁN | 1 | 646768454 |
| 25349857H | BURGOS CASA, CANDY | 2 | 659758476 |
| 55776898K | RAMÓN CORONADO,LUIS | 3 | 654364736 |
| 78988484B | CONRADO ALONSO, JOSE | 2 | 645878745 |
| 88647389P | DOMÍNGUEZ GÓMEZ, MANUEL | 1 | 623787343 |
+-----------+---------------------------+--------------+-----------+
and:
mysql> select * from PETICIONES;
+--------+------------+--------+-----------+-----------+
| ID_PET | FECHA_PET | ID_ANA | DNI_PAC | DNI_DOC |
+--------+------------+--------+-----------+-----------+
| 1 | 2008-01-03 | 2 | 71515623A | 23456398F |
| 2 | 2008-05-10 | 2 | 33788976F | 55776898K |
| 3 | 2008-05-08 | 3 | 79876867X | 23456398F |
| 4 | 2008-05-11 | 4 | 44787345H | 55776898K |
| 5 | 2008-05-12 | 2 | 19887234W | 25349857H |
| 6 | 2008-05-05 | 4 | 22897576R | 55776898K |
| 7 | 2008-03-15 | 5 | 44787345H | 88647389P |
| 8 | 2008-03-19 | 1 | 71515623A | 23456398F |
| 9 | 2008-03-26 | 2 | 71515623A | 78988484B |
| 10 | 2008-03-15 | 2 | 19887234W | 88647389P |
| 11 | 2008-03-15 | 3 | 33788976F | 55776898K |
| 12 | 2008-03-26 | 2 | 44787345H | 23456398F |
+--------+------------+--------+-----------+-----------+
I tried this:
select
NOMBRE_DOC
from
DOCTORES
where
DNI_DOC IN (select DNI_DOC
from PETICIONES
group by ID_ANA
order by count(*) desc
limit 2)
group by
DNI_DOC;
and that:
SELECT
DNI_DOC, ID_ANA, COUNT(ID_ANA) AS count
FROM
TIPOS_ANALISIS
WHERE
ID_ANA = (SELECT ID_ANA
FROM
(SELECT
ID_ANA, COUNT(ID_ANA) as AnaCount
FROM
PETICIONES
GROUP BY
by ID_ANA
ORDER BY
AnaCount DESC
LIMIT 1) t1)
GROUP
BY ID_ANA;
and that:
select a.* from DOCTORES a
-> where a.DNI_DOC = ( SELECT b.DNI_DOC from PETICIONES b
-> group by d.ID_ANA
-> order by count(ID_ANA) DESC
-> limit 2 );
you can't even imagine how frustrating it is when you say it's a simple query... Why it isn't simple to me is a mystery (provided that I am really not a dummy).
Expected output would be something like this:
+-----------+---------------------------+--------------+-----------+
| DNI_DOC | NOMBRE_DOC | ID_ANA | count |
+-----------+---------------------------+--------------+-----------+
| 22888444O | MATEO DÍAZ, RAMÓN | 3 | 6 |
+-----------+---------------------------+--------------+-----------+
I believe you are severely overcomplicating this. Join the 2 tables on DNI_DOC field, group by the doctor's id and name (and any other details you may want to include in the select list), and count the number of distinct ID_ANAs.
SELECT d.DNI_DOC, d.NOMBRE_DOC, COUNT(distinct ID_ANA) AS count
FROM DOCTORES d
INNER JOIN PETICIONES t ON d.DNI_DOC=t.DNI_DOC
GROUP BY d.DNI_DOC, d.NOMBRE_DOC
ORDER BY COUNT(distinct ID_ANA) DESC
LIMIT 2
If you need the total number of peticiones per doctor, then remove the distinct from the count.
Here is what I would do :
select d.*, count(p.ID_PET) as TOTAL_PETICIONES from DOCTORES d
inner join PETICIONES p on p.DNI_DOC = d.DNI_DOC
group by d.DNI_DOC
order by count(ID_ANA) DESC
limit 2
This is not tested and write here so please correct me for typos ;)
Using a join will provide a nice output. Grouping by DOCTORES to be able to count the PETICIONES per DOCtORES
EDIT : Something like that. The output won't be good because I have issues to understand the column content.