MySQL - Using desc on Group by - mysql

I have this query and I would like to use an order by desc on the avg :
select Nomcircuit, avg(Monuments.NBETOILE) as TotalEtoiles from Circuits
inner join CircuitsMonuments on Circuits.Idcircuit = CircuitsMonuments.Idcircuit
inner join Monuments on Monuments.Idmonument = CircuitsMonuments.Idmonument
group by Nomcircuit;
I've tried several things but it just doesn't seem to work.

Just do as you suggested:
SELECT Nomcircuit,
AVG(Monuments.NBETOILE) AS TotalEtoiles
FROM Circuits
INNER JOIN CircuitsMonuments
ON Circuits.Idcircuit = CircuitsMonuments.Idcircuit
INNER JOIN Monuments
ON Monuments.Idmonument = CircuitsMonuments.Idmonument
GROUP BY Nomcircuit
ORDER BY TotalEtoiles DESC

Related

MySQL query with GROUP BY and JOIN

Good afternoon,
I'm trying to get some information from my MySQL database and I'm having problems because I'm not able to have the information needed. I have tried a lot of different approaches and none of them have worked. I hope you can find something because I'm very close to find the solution but something is missing:
MySQL query:
SELECT b.id, b.tipo_perfil, round(avg(b.edad)), COUNT(c.zona), c.zona
FROM analizador_datos_usuario AS a
INNER JOIN analizador_datos_perfil AS b ON (a.id_usuario = b.id_perfil)
INNER JOIN analizador_datos_perfil_historial AS c ON (b.id = c.id_perfil)
WHERE a.id_usuario=21
GROUP BY b.tipo_perfil, c.zona
ORDER BY b.tipo_perfil ASC, count(c.zona) DESC
This query gives me the following information:
Table (in red it's what I need):
Kind regards,
try that :
SELECT b.tipo_perfil, round(avg(b.edad)), COUNT(distinct c.zona), group_concat(distinct b.id separator ' ') as id_list, group_concat(distinct c.zona separator ' ') as zona_list
FROM analizador_datos_usuario AS a
INNER JOIN analizador_datos_perfil AS b ON (a.id_usuario = b.id_perfil)
INNER JOIN analizador_datos_perfil_historial AS c ON (b.id = c.id_perfil)
WHERE a.id_usuario=21
GROUP BY b.tipo_perfil
ORDER BY b.tipo_perfil ASC, count(distinct c.zona) DESC
I think you are getting result what is displayed and you want result which is in red colour.
Try this modified query:-
SELECT b.id, b.tipo_perfil, round(avg(b.edad)), COUNT(c.zona) counted_zone, c.zona
FROM analizador_datos_usuario AS a
INNER JOIN analizador_datos_perfil AS b ON (a.id_usuario = b.id_perfil)
INNER JOIN analizador_datos_perfil_historial AS c ON (b.id = c.id_perfil)
WHERE a.id_usuario=21
GROUP BY b.tipo_perfil, c.zona
Having MAX(counted_zone)
ORDER BY b.tipo_perfil ASC, counted_zone DESC

SQl join with count group by

I have two tables
one is
Receivesms(Matchdate,Matchtime,Keyword,SmsMessage,Mobileno)
another is
QAoptios(Keyword,Question,Answeroption,Matchdate,Matchtime)
I need to find the count of SmsMessage which have the value same as Answeroption on same Matchdate,Matchtime and same Keyword. and also i need to filter on Receivesms.Matchdate='2012-12-25 00:00:00.000'
SELECT
q.AnswerOption,
COUNT(SmsMessage) TheCount
FROM Receivesms r
INNER JOIN QAoptions q ON r.Matchdate = q.Matchdate
AND r.Matchtime = q.Matchtime
AND r.Keyword = q.keyword
GROUP BY q.AnswerOption;
use can use:
select count(*) from Recievesms r,QAoptios q
where
r.Matchdate = q.Matchdate
and
r.Matchtime = q.Matchtime
and
r. Keyword =q.Keyword
and
r.SmsMessage = q.Answeroption;
or
select count(*) from from Recievesms as r
inner join
QAoptios as q
on
r.SmsMessage = q.Answeroption;
try this one
SELECT count(*) from Receivesms as a inner join QAoptios as b on a.keyword=b.keyword
and a.matchtime=b.matchtime and a.matchdate=b.matchdate and a.value=b.answeroption
SELECT COUNT(R.SmsMessage)
FROM Receivesms R
INNER JOIN QAoptios Q ON
R.Keyword=Q.Keyword AND
R.Matchdate=Q.Matchdate AND
R.Matchtime=Q.Matchtime AND
R.SmsMessage=Q.AnswerOption
Or you can add GROUP BY clause if you want to show AnswerQuestion, like this:
SELECT Q.AnswerOption, COUNT(R.SmsMessage) as TheCount
FROM Receivesms R
INNER JOIN QAoptios Q ON
R.Keyword=Q.Keyword AND
R.Matchdate=Q.Matchdate AND
R.Matchtime=Q.Matchtime AND
R.SmsMessage=Q.AnswerOption
GROUP BY Q.AnswerOption

mysql join and count

Somehow am not successful with creating the query that I want.
DB is to do with locations, there are the following tables which are relevant
t_location - list of locations incl. field t_location_zipcode, and t_location_id_location
t_zipcodecity - join table just t_zipcodecity_zipcode t_zipcodecity_id_city
t_city - city list with t_city_id_city
t_citystate - join table, t_citystate_id_city, t_citystate_id_state
t_state - list of states with t_state_id_state
Initially I tried to get a list of states with locations using this query:
SELECT DISTINCT `t_state_id_state`
, `t_state_name_full`
FROM (`t_state`)
LEFT JOIN `t_citystate` ON `t_state_id_state` = `t_citystate_id_state`
LEFT JOIN `t_city` ON `t_citystate_id_state` = `t_city_id_city`
LEFT JOIN `t_zipcodecity` ON `t_city_id_city` = `t_zipcodecity_id_city`
LEFT JOIN `t_location` ON `t_zipcodecity_zipcode` = `t_location_zipcode`
ORDER BY `t_state_name_full` asc ­
which works fine.
Now what I also need / want which I am failing dismally at is to get the number of locations in each state. I don't know if it can be done in this one query or if i need another, either way I need help!
you can use a count and a group by. Something like this:
SELECT DISTINCT `t_state_id_state`
, `t_state_name_full`
, COUNT(*)
FROM (`t_state`)
LEFT JOIN `t_citystate` ON `t_state_id_state` = `t_citystate_id_state`
LEFT JOIN `t_city` ON `t_citystate_id_state` = `t_city_id_city`
LEFT JOIN `t_zipcodecity` ON `t_city_id_city` = `t_zipcodecity_id_city`
LEFT JOIN `t_location` ON `t_zipcodecity_zipcode` = `t_location_zipcode`
GROUP BY `t_state_id_state` , `t_state_name_full`
ORDER BY `t_state_name_full` asc
SELECT t_state_id_state
, t_state_name_full
, COUNT(DISTINCT t_location_id_location) AS locations_number
FROM
t_state
LEFT JOIN
t_citystate ON t_state_id_state = t_citystate_id_state
LEFT JOIN
t_city ON t_citystate_id_state = t_city_id_city
LEFT JOIN
t_zipcodecity ON t_city_id_city = t_zipcodecity_id_city
LEFT JOIN
t_location ON t_zipcodecity_zipcode = t_location_zipcode
GROUP BY t_state_id_state
ORDER BY t_state_name_full ASC ­
Ok thats looking good, my bad with the left joins, i was initially trying to get ALL the states which is why i used them. But i change that to use inner joins
SELECT t_state_id_state,
t_state_name_full,
COUNT(DISTINCT t_location_id_location) AS locations_number
FROM t_state
INNER JOIN t_citystate ON t_citystate_id_state = t_state_id_state
INNER JOIN t_city ON t_city_id_city = t_citystate_id_city
INNER JOIN t_zipcodecity ON t_zipcodecity_id_city = t_city_id_city
INNER JOIN t_location ON t_location_zipcode = t_zipcodecity_zipcode
GROUP BY t_state_id_state
ORDER BY t_state_name_full ASC
then i actually end up with a result that looks good !

MySQL DISTINCT not Filtering out

I have the folowing sql query:
SELECT DISTINCT(tbl_products.product_id), tbl_products.product_title,
tbl_brands.brand_name, tbl_reviews.review_date_added,
NOW() AS time_now
FROM tbl_products, tbl_reviews, tbl_brands
WHERE tbl_products.product_id = tbl_reviews.product_id AND
tbl_products.brand_id = tbl_brands.brand_id
ORDER BY tbl_reviews.review_date_added DESC
That needs to filter out any duplicate product_id's unfortunatly selecting tbl_reviews.review_date_added makes each record unique which means DISTINCT will not work anymore.
Is there any otherway of doing this query so that product_id is still unique?
I did do the GROUP BY and the problem is I display the tbl_reviews.review_date_added on a website and it selects the oldest date. I need the newest date.
Regards
With the description given, it's a bit hard to be certain, but if review_date_added is the only problem, it seems like you want the MAX() of that date?
If the following doesn't help, please could you give example data, example output, and a description of how you want the output to be created?
SELECT
tbl_products.product_id,
tbl_products.product_title,
tbl_brands.brand_name,
MAX(tbl_reviews.review_date_added) AS review_date_added,
NOW() AS time_now
FROM
tbl_products
INNER JOIN
tbl_reviews
ON tbl_products.product_id = tbl_reviews.product_id
INNER JOIN
tbl_brands
ON tbl_products.brand_id = tbl_brands.brand_id
GROUP BY
tbl_products.product_id,
tbl_products.product_title,
tbl_brands.brand_name
ORDER BY
MAX(tbl_reviews.review_date_added) DESC
Distinct works for the entire row. The parenthesis are just around the field:
distinct (a), b, c === distinct a, b, c
A straightforward solution is group by. You can use min to select the oldest date.
select tbl_products.product_id
, min(tbl_products.product_title)
, min(tbl_brands.brand_name)
, min(tbl_reviews.review_date_added)
, NOW() AS time_now
FROM tbl_products, tbl_reviews, tbl_brands
WHERE tbl_products.product_id = tbl_reviews.product_id AND
tbl_products.brand_id = tbl_brands.brand_id
GROUP BY
tbl_products.product_id
ORDER BY
min(tbl_reviews.review_date_added) DESC
Note that if a product can have multiple brands, this will pick the lowest one.
Try this:
SELECT pr.product_id, pr.product_title,
bd.brand_name,
(SELECT MAX(rev.review_date_added) FROM tbl_reviews rev
WHERE pr.product_id = rev.product_id) AS maxdate,
NOW() AS time_now
FROM tbl_products pr INNER JOIN tbl_reviews re
ON pr.product_id = re.product_id
INNER JOIN tbl_brands bd
ON pr.brand_id = bd.brand_id
GROUP BY pr.product_id
ORDER BY re.review_date_added DESC
or (as suggested by #Hogan)
SELECT pr.product_id, pr.product_title,
bd.brand_name, md.maxdate
NOW() AS time_now
FROM tbl_products pr INNER JOIN tbl_reviews re
ON pr.product_id = re.product_id
INNER JOIN tbl_brands bd
ON pr.brand_id = bd.brand_id
INNER JOIN (SELECT product_id, MAX(review_date_added) AS maxdate
FROM tbl_reviews rev GROUP BY product_id) md
ON pr.product_id = md.product_id
GROUP BY pr.product_id
ORDER BY re.review_date_added DESC
I combined the answer of Andomar with some changes you will find here.
SELECT tbl_products.product_id, tbl_products.product_title,
tbl_products.product_date_added, tbl_brands.brand_name,
MAX(tbl_reviews.review_date_added) AS review_date_added, NOW() AS time_now
FROM tbl_products, tbl_reviews, tbl_brands
WHERE tbl_products.product_id = tbl_reviews.product_id AND
tbl_products.brand_id = tbl_brands.brand_id
GROUP BY tbl_products.product_id
ORDER BY MAX(tbl_reviews.review_date_added) DESC
Works beautifully and shows the newest date at tbl_reviews.review_date_added.
Regards

MySQL sum of sub queries

I have quite a long query that is causing me some problems. For the first sub-query I keep getting the error: "MySQL server version for the right syntax to use near 'SELECT project.project_total_num_hours_quoted FROM project inner join time_recor' at line 5".
The subquery in question is:
sum(SELECT
project.project_total_num_hours_quoted
FROM
project inner join time_recording using(project_id)
WHERE
project.company_id = company.company_id
AND project_is_retainer != 1
AND time_recording.time_recording_event_start_datetime >= '2011-01-01' AND time_recording.time_recording_event_stop_datetime <= '2011-03-01'
group by project_id
) AS hours_quoted,
This returns a set of results. In the larger query I simply want to have the sum.
SELECT
SUM((unix_timestamp(time_recording.time_recording_event_stop_datetime)-unix_timestamp(time_recording.time_recording_event_start_datetime))/3600) AS total_time,
company.company_label,
sum(SELECT
project.project_total_num_hours_quoted
FROM
project inner join time_recording using(project_id)
WHERE
project.company_id = company.company_id
AND project_is_retainer != 1
AND time_recording.time_recording_event_start_datetime >= '2011-01-01' AND time_recording.time_recording_event_stop_datetime <= '2011-03-01'
group by project_id
) AS hours_quoted,
(SELECT SUM(project.project_total_num_hours_quoted)
FROM project
INNER JOIN time_recording ON project.project_id = time_recording.project_id
WHERE time_recording.time_recording_event_start_datetime>='2011-01-01'
AND project_is_retainer!=1
AND time_recording.time_recording_event_stop_datetime<='2011-03-01'
AND project.company_id!=1
) AS total_hours_quoted,
(
SELECT
SUM((unix_timestamp(time_recording.time_recording_event_stop_datetime)-unix_timestamp(time_recording.time_recording_event_start_datetime))/3600)
FROM time_recording
INNER JOIN project ON time_recording.project_id = project.project_id
WHERE project.company_id!=1
AND project_is_retainer!=1
AND time_recording.time_recording_event_start_datetime>='2011-01-01'
AND time_recording.time_recording_event_stop_datetime<='2011-03-01'
)
AS total_hours
FROM time_recording
INNER JOIN project ON time_recording.project_id = project.project_id
INNER JOIN company ON project.company_id = company.company_id
WHERE company.company_id!=1
AND project_is_retainer!=1
AND time_recording.time_recording_event_start_datetime>='2011-01-01'
AND time_recording.time_recording_event_stop_datetime<='2011-03-01'
GROUP BY company.company_id
ORDER BY total_time desc
LIMIT 7
In your first subquery, you don't need the group by if you sum it in the outer query. And you are missing the ON clause.
SELECT project.project_total_num_hours_quoted
FROM project inner join time_recording
ON project.id=time_recording.project_id
WHERE
project.company_id = company.company_id
AND project_is_retainer != 1
AND time_recording.time_recording_event_start_datetime >= '2011-01-01'
AND time_recording.time_recording_event_stop_datetime <= '2011-03-01'
I would strongly recommend scrapping this and starting again.
Several, if not all, the subselects could be merged into a single SELECT statement. The outer SELECT is an aggregate operation which selects non-aggregated values not included in the GROUP BY clause. MySQL does not optimize push-predicates. And you've got redundant joins in the query.