Multiple not exists in MYSQL to check count of rows - mysql

Question

I am trying to make this query work, here is my logic , I am trying to select record thats there is not at LEAST NOT one of these options:
1). status = Approved AND end_date >now
2). status =Approved AND end_date is NULL
3). status = Pending And end_date is NULL & COUNT(id) =1
4). status =Pending AND end_date >now & COUNT(id) =1
5). status =Pending AND end_date <now & COUNT(id) =1
how to accomplish this , this is what I have so far I am not sure how to check for COUNT(id) = 1 in conditions 3, 4, and 5?
SELECT
*
FROM
outreach
WHERE
NOT EXISTS (
SELECT
*
FROM
outreach_links
WHERE
outreach_links.outreach_id = outreach.id
AND STATUS = "Approved"
AND end_date > now()
)
AND NOT EXISTS (
SELECT
*
FROM
outreach_links
WHERE
outreach_links.outreach_id = outreach.id
AND STATUS = "Approved"
AND end_date IS NULL
)
AND NOT EXISTS (
SELECT
*
FROM
outreach_links
WHERE
outreach_links.outreach_id = outreach.id
AND STATUS = "Pending"
AND end_date > now()
)
AND NOT EXISTS (
SELECT
*
FROM
outreach_links
WHERE
outreach_links.outreach_id = outreach.id
AND STATUS = "Pending"
AND end_date IS NULL
)
AND NOT EXISTS (
SELECT
*
FROM
outreach_links
WHERE
outreach_links.outreach_id = outreach.id
AND STATUS = "Pending"
AND end_date < now()
)

Answer 1

select
o.*,
SUM(if(ol.status = "Approved" and (ol.end_date > now() or end_date is null), 1, 0)) as cond1,
SUM(if(ol.status = "Pending" and (ol.end_date != now() or end_date is null), 1, 0)) as cond2
from
outreach o
left join
outreach_links ol on ol.outreach_id = o.id
group by
o.id
having
cond1 = 0 and cond2 != 1
;
Not sure if that's you are looking for, but you can try it.
cond2 != 1 makes your COUNT(id) = 1 condition (if there are more than one linked id in outreach_links cond2 will be greater than 1)