I have 2 table and there's a column which contains comma separated value and I want to count all same value of that column, here's the sample table:
Client table
ID | Name | Procedure
1 | Joe | Samp1,Samp2
2 | Doe | Samp1,Samp2,Samp3
3 | Noe | Samp1,Samp2
Desire Output
Summary table ( For Procedure )
ID | NAME | COUNT
1 | Samp1 | 3
2 | Samp2 | 3
3 | Samp3 | 1
Now, do you have any idea or suggestion so i can make it happen ? like add new table or is this possible with single query ?
Try this query
SELECT LENGTH(COLUMN) - LENGTH(REPLACE(COLUMN, ',', '')) FROM TABLE_NAME
Related
Here is my table:
| ID | NUMBER |
| 1 | 523 |
| 2 | 293 |
| 3 | 948 |
And now, I want to get all NUMBER values but I want to add in result two numbers - 48 - (without upadting existing results). So finally I want print these results:
| NUMBER |
| 48523 |
| 48293 |
| 48948 |
So I need a query, something like this:
SELECT '48' + `number` FROM `table`
but this query doesn't work fine (this query only update column name from NUMBER to 48 + NUMBER).
Any ideas?
Thanks.
You need CONCAT
SELECT CONCAT('48' , `number`) AS number FROM table
Demo
I have two mysql tables record_items,property_values with the following structure.
table : property_values (column REC is foreign key to record_items)
id(PK)|REC(FK)| property | value|
1 | 1 | name | A |
2 | 1 | age | 10 |
3 | 2 | name | B |
4 | 3 | name | C |
5 | 3 | age | 9 |
table: record_items
id(PK) |col1|col2 |col3|
1 | v11| v12 | v13|
2 | v21| v22 | v23|
3 | v31| v32 | v33|
4 | v41| v42 | v43|
5 | v51| v52 | v53|
record_items table contains only basic information about the record, where as property_values table keeps record_item as a foreign key and each property and its value is saved in a separate row.
Now I want to get the record_items sorted based on a particular property, say by age.
My HQL query will be like
Select distinct rec from PropertyValues where property="age" order by value;
But this query will be skipping record 2 since it don't have an entry for property age.
I expect the result to have the records which contains age property in sort order appended by those which don't have age property at all. How can I query that?
Here is a raw MySQL query which should do the trick:
SELECT t1.*
FROM record_items t1
LEFT JOIN property_values t2
ON t1.id = t2.REC AND
t2.property = 'age'
ORDER BY CASE WHEN t2.value IS NULL THEN 1 ELSE 0 END, t2.Value
I notice that your Value column in property_values is mixing numeric and text data. This won't work well for sorting purposes.
Demo here
I'm having a problem with building a query.
What I have is this in THE db
--------------------------------------
Id |name | profilenr | nr
--------------------------------------
1 | Harry| admin-124 | NULL
2 | Barry| admin-267 | NULL
6 | gerry| user-689 | NULL
9 | larry| user-435 | NULL
What I want to do is:
Getting only the numbers from the profilenr column and put them in the nr column of each profile that starts whit admin- .
In this example only for harry 124 in colum nr
And for Barry only 267 in colum nr.
I know this is possible but don't know how to build the query for this.
May be more like this:
update my_table update
set nr = substr(profilenr, locate('-', profilenr)+1, 3)
where profilenr like 'admin-%';
You can use a substr and locate
update my_table
set nr = substr(profilenr, locate('-',profilenr)+1, 3);
I'm not very good at joining tables in mysql and I'm still learning,
So I wanted to ask, when joining two tables....
I have 2 tables
So for the first table I want to join the 2 of its columns (id & path) on the second table.
But on the second table there's no column name id and path, there is a column name pathid & value. The field of the pathid column is the same as the id.
it looks like this.
first table
| id | path |
---------------------
| 1 | country/usa |
| 2 | country/jpn |
| 3 | country/kor |
second table
| pathid | value |
-------------------
| 3 | 500 |
| 1 | 10000 |
| 2 | 2000 |
So on the first table, it indicates that for usa the id is 1, japan is 2, korea is 3.
And on the table it says that for pathid no. 3 ( which is the id for korea) the value is 500 and so on with the others.
I want it to look like this. So then the path will be joined on the second table on its corresponding value. How can I do this on mysql? Thank You
Desired Result
| id | path | value |
------------------------------
| 1 | country/usa | 10000 |
| 2 | country/jpn | 2000 |
| 3 | country/kor | 500 |
You can join on the columns irrespective of the column name as long as the data type match.
SELECT id, path, value
FROM firstTable, secondTable
WHERE id = pathid
If you have same column names on both tables then you need to qualify the name using alias. Say the column names for id were same on both tables then whenever you use id you should mention which table you are referring to. other wise it will complain about the ambiguity.
SELECT s.id, path, value
FROM firstTable f, secondTable s
WHERE f.id = s.pathid
Note that I ommited s. on other columns in select, it will work as long as the second table doesn't have columns with same name.
I have table like:
user :
uid | course_id | subjects
---------------------------
1 | 1 | html,php
2 | 1 | java,html,sql
3 | 1 | java
4 | 1 | fashion,html,php,sql,java
I want to run a query which can return most liked subjects in query and then second most and so on...
For Example :
select * from user where subjects like '%java%' or '%php%' or '%html%';
this query will return data like this:
uid | course_id | subjects
---------------------------
2 | 1 | java,html,sql
3 | 1 | java
4 | 1 | fashion,html,php,sql,java
but i want output like this :
uid | course_id | subjects
---------------------------
4 | 1 | fashion,html,php,sql,java
2 | 1 | java,html,sql
1 | 1 | html,php
3 | 1 | java
so the most matched subjects 1st then 2nd most matched subjects and so on....
Is there any modification in my query so that i can get this type of sorted output.
Never, never, never store multiple values in one column!
Like you see now this will only give you headaches. Normalize your user table. Then you can select normally.
It should look like this
uid | course_id | subjects
---------------------------
1 | 1 | html
1 | 1 | php
2 | 1 | java
2 | 1 | html
2 | 1 | sql
3 | 1 | java
...
or better introduce an new table subjects and then make a mapping table called course_subjects
subject
id | name
------------
1 | html
2 | sql
3 | java
...
course_subjects
uid | course_id | subject_id
---------------------------
1 | 1 | 1
1 | 1 | 2
...
Based on the way you want your results, it looks like you want to order by the number of subjects (or tags) within subject. This can be accomplished by counting the number of , (commas).
The way to count the number of occurances of a character is to subtract the original length by the length when the character is removed.
Example:
SELECT *
FROM USER
WHERE subjects LIKE '%java%'
OR '%php%'
OR '%html%'
ORDER BY ( Length(subjects) - Length(Replace(subjects, ',', '')) ) DESC;
SQLFiddle: http://sqlfiddle.com/#!2/cc793/4
Result:
UID COURSE_ID SUBJECTS
4 1 fashion,html,php,sql,java
2 1 java,html,sql
3 1 java
Note:
As juergen says it is a bad idea to store multiple values in one column.
With MyISAM storage engine you can do match against.
The simplest example:
SELECT *,
MATCH (subjects) AGAINST ('java php html') AS relevance
FROM `user`
WHERE MATCH (subjects) AGAINST ('java php html')
ORDER BY relevance DESC
In MySQL 5.6 full-text search is available with InnoDB too but needs a bit extra to make it work. For more info checkout the following post: http://www.mysqlperformanceblog.com/2013/03/04/innodb-full-text-search-in-mysql-5-6-part-2-the-queries/