Rename file with CSV values - csv

Question

I have files that look like that:
1989_Footer.gif
1989_Header.gif
260273_Footer.gif
260273_Header.gif
...
and I have a CSV that looks like this:
1989;10773387
260273;10776516
...
I want to rename the files number with the one given in the CSV. The first number in the CSV is the old number and the second one (after the semicolon) is the new number. How can I achive that without touching the text after the underline?
I thought about getting the file name, then search the number in the CSV and replace it with the value in the same line after the semicolon.

Answer 1

#ECHO OFF
SETLOCAL
SET "sourcedir=U:\sourcedir"
SET "filename1=%sourcedir%\q40908252.txt"
FOR /f "usebackqtokens=1*delims=;" %%a IN ("%filename1%") DO (
FOR /f "tokens=1*delims=_" %%r IN ('dir /b /a-d "%sourcedir%\%%a_*"') DO (
ECHO(REN "%sourcedir%\%%r_%%s" "%%b_%%s"
)
)
GOTO :EOF
You would need to change the setting of sourcedir to suit your circumstances.
I used a file named q40908252.txt containing your data for my testing.
The required REN commands are merely ECHOed for testing purposes. After you've verified that the commands are correct, change ECHO(REN to REN to actually rename the files.
Read the csv file, using ; as the delimiter, placing the from-prefix in %%a and the to-prefix in %%b.
Perform a directory list of files named "%%a_anything" in the source directory, tokenise on _ so that the first token (which must be %%a) goes to %%r and the remainder-of-name to %%s, then rename the file with the prefixes switched.
Assumes that the first _ in the filename will never be a multiple-_

Answer 2

My JREN.BAT regular expression renaming utility can simplify the solution. JREN.BAT is pure script (hybrid batch/JScript) that runs natively on any Windows machine from XP onward - no 3rd party exe file required. Full documentation is available from the command line via jren /?, or jren /?? for paged help.
From within a batch script:
#echo off
for /f "delims=; tokens=1,2" %%A in (rename.csv) do call jren "^%%A_" "%%B_" /fm *.gif
From the command line:
for /f "delims=; tokens=1,2" %A in (rename.csv) do #jren "^%A_" "%B_" /fm *.gif

Answer 3

I would probably do it like that (see the explanatory remarks rem):
#echo off
setlocal EnableExtensions DisableDelayedExpansion
rem // Define constants here:
set "_CSV=%~dpn0.csv" & rem // (path to the CSV file holding the old and new numbers)
set "_LOC=%~dp0" & rem // (path to the directory containing the files to rename)
set "_PAT=*.gif" & rem // (pattern of the file name part after the first `_`)
rem // Walk through the CSV file line by line and read old and new numbers:
for /F "usebackq tokens=1-2 delims=,;" %%K in ("%_CSV%") do (
rem // Search files whose names begin with the old number and an `_`:
for /F "delims=" %%F in ('dir /B /A:-D "%_LOC%\%%K_%_PAT%"') do (
rem // Store current file name into variable:
set "NAME=%%F"
rem // Toggle delayed expansion to not lose any `!` in the file name:
setlocal EnableDelayedExpansion
rem // Rename current file by replacing the old number by the new one:
ECHO ren "%_LOC%\!NAME!" "%%L_!NAME:*_=!"
endlocal
)
)
endlocal
exit /B
Remove the upper-case ECHO command after having successfully tested the script!
The advantage of this method is that it works even in case the file name part after the first _ begins with an _ as well; so a file name 1989__some_name.gif would become renamed to 10773387__some_name.gif, so the two consecutive __ are maintained.